How to get the Date, month, year of the DateTimePicker
Hi, I am using the DateTimePicker.
There are several question about this command:
1. how to get the Date, month and year?
-With the help of myDateTime.value, I get this string ' Wed May 08 14:45 ICT 2013 '-> I have to manually analyze this? Because I need in format yyyy/mm/dd. Or can set the format of dateTimePicker.value?
2 format on dateTimePicker self (on the user interface) is d/m/YY, I can't change to another format?
Thank you
dateTimePicker.value return a QDateTime not a string.
https://developer.BlackBerry.com/Cascades/reference/bb__cascades__datetimepicker.html#property-value
See more:
https://developer.BlackBerry.com/Cascades/reference/QDateTime.html#date
https://developer.BlackBerry.com/Cascades/reference/QDate.html
You can get
day = dateTimePicker.value.date().day() month = dateTimePicker.value.date().month() year= dateTimePicker.value.date().year() dateYYYYMMDD = dateTimePicker.value.date().toString(Qt::ISODate) dateYYYYMMDD2 = dateTimePicker.value.date().toString("YYYY/MM/DD") dateYYYYMMDD3 = dateTimePicker.value.toString("YYYY/MM/DD")
Tags: BlackBerry Developers
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user4587979 wrote:
Hi FrankYes, but I had more than 2 tables with item_characteristics, type_characteristics
If there are other tables involved, then CREATE TABLE and INSERT statements for them (for the relevant columns only). You must not post a lot of examples of data; usually just a couple of lines per table is enough to show the problem.
Also post the results desired from these data.What I try to do is, I'm comparing new_value in log_item_characteristics (whichever is most recent) with CHR_VALUE in the item_characteristics and the needs of different output values
I am trying to query is not giving desired out put
Point out some places where the output is wrong and explain how you get good results in these places, using specific examples from the data sample.
select lic.PIRM_ID, ic.CHR_ID, lic.CHARACTERISTIC_NAME, lic.TYPE_NAME, ic.CHR_VALUE, lic.NEW_VALUE, lic.MODIFIED_BY, lic.MODIFIED_ON, ic.CREATED_BY, ic.CREATED_ON,ic.MODIFIED_BY, ic.MODIFIED_ON from log_item_characteristics lic, item_characteristics ic,type_characteristics tc where lic.TYPE_NAME=tc.TYPE_NAME and lic.CHARACTERISTIC_NAME=tc.CHR_NAME and lic.PIRM_ID=ic.PIRM_ID and tc.CHR_ID=ic.CHR_ID and ic.CHR_VALUE <> lic.NEW_VALUE and lic.pirm_id in ('0307490N','0307521C') order by lic.pirm_id
Thank you; It is useful to see the existing query. Really, you have to format your code.
Please can you help me
What you've posted so far is like saying "I'm going 200 meters to the North, and then 500 meters East, but I'm not getting where I want to go." I would have a better chance to help you if you said, 'I'm out of my house, at 100, Elm Street and try to get to the supermarket at Broadway 279. I'm going 200 meters to the North... ', or, even better. "I want to buy a newspaper and some orange juice, so I thought I'd go to a convenience store. I start at my house, at 100, Elm Street... »
Always post some examples of data (CREATE TABLE and INSERT statements, as you did in your first post) and the desired results from these data. Explain how you get these results from these data. -
How to get the date in the exact day in the field when another?
Hello
Please help me how to get the day of the week using another date field.
In fact, a field (week_day) has 1,2,3,4,5,6,7 here 1-, 2 - KILL like this.
another field has the date. After this date, go to this particular week and need to pick up the date of the Etiquettemois above. It should be this week there himself.
Thanks in advance!
Kind regards
Florian...
Published by: Florian on October 29, 2010 03:07Maybe it's
select trunc(date_field,'D') + week_field - 1 from table
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