How to get the last day of a month for every 2 months for a given period?

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• How to get the last day of the week?

  HII
  
  I can get the week number of calendar for a given date using
  
  SELECT to_char (to_date('04/04/2011','MM/DD/YYYY'), 'WW') FROM dual
  
  can any body tell me, how to get the last day of the week?
  
  and the answer should be: 04/08/2011(8th april)
  Thank you
  San
  
  Published by: sandeep9 on April 4, 2011 03:50

  Perhaps this...

  SQL> select trunc(sysdate,'WW')+6 from dual;
  
  TRUNC(SYSDATE,'WW')+
  --------------------
  08-APR-2011 00:00:00
  
  SQL>
  

• How to get the second Monday of each month in a given date range?

  In Oracle forms, how to get the second Monday of each month in a given date range?

  I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?

  WITH month_range AS

  (

  SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month

  , TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month

  OF the double

  )

  SELECT NEXT_DAY (6 + ADD_MONTHS (first_month

  , LEVEL - 1

  )

  , 'MONDAY '.

  ) AS second_monday

  OF month_range

  CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)

  ;

  Thanks in advance.

  Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

  SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

  THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

  END AS second_day

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to get the last day of the year

  Hi all
  
  Thanks in advance...
  
  How do I get the last day of the year that I'm passing date at run time.
  
  I can manage to get the first day of the year by
  SELECT TRUNC(SYSDATE,'YEAR') AS FDAY_YEAR
  of the double
  
  Thanks in advance
  
  Concerning
  Sachin

    1*  select ADD_MONTHS(trunc(sysdate,'yyyy'),12)-1 dd from dual
  SQL> /
  
  DD
  -----------
  31-DEC-2010
  

• How to get the last day of the weekend rather than a month

  Hi all

  Is the request appropriate and preferable to use to get the last business day of the month below?

  SELECT to_date('13.08.2014','dd.mm.yyyy') + MAX(RNUM) LastDay(nonweekend)
     FROM   (SELECT ROWNUM RNUM
            FROM   ALL_OBJECTS where rownum <=31)
    WHERE   ROWNUM <= 31 ANd
       TO_CHAR(to_date('13.08.2014','dd.mm.yyyy') + RNUM, 'DY','NLS_DATE_LANGUAGE=ENGLISH' ) NOT IN ('SAT' , 'SUN')
       and to_date('13.08.2014','dd.mm.yyyy') + RNUM <= last_day(to_date('13.08.2014','dd.mm.yyyy'))
  

  I have to use this motion for production.

  East - recommended to use?

  You can change your query this way:

  WITH t AS (SELECT trunc (to_date ('& calc_date', 'dd.mm.yyyy'), 'mm') + level - 1 calc_date)

  OF THE DOUBLE

  CONNECT BY LEVEL<= last_day(to_date('&calc_date',="" 'dd.mm.yyyy'))="" -="" trunc(to_date('&calc_date',="" 'dd.mm.yyyy'),="" 'mm')="" +="">

  )

  Select max (calc_date)

  t

  where to_char (calc_date, 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') NOT IN ("SAT", "Sun");

• How to get the same day of a month each year in the DB (update a flag)

  Hello
  
  I'm trying to make a update for a table of flag request in our database that contains the dates and the Pavilion columns. Currently the system have dates for the next ten years. The flags are updated with the values 0 or 1, if a particular date falls under the criteria required.
  
  I need to update the column flag for the same day of the month of each year. for example, 2nd Sunday of October. The value must be updated in all the years in the table. Currently I use the following query to update of the current year.
  
  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7;
  
  and for the next year as
  
  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = add_months (NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7, + 12)-1;
  
  This isn't a great way to do it because he does not take care of leap years, and it does not scan and update values across the table for all the years correctly.
  
  Can someone help me fix this please.

  Welcome to the forum!

  Whenever you provide post your Oracle version 4-digit (result of SELECT * FROM V$ VERSION)
  >
  and for the next year as

  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = add_months (NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7, + 12)-1;
  >
  Why do you use "2013" in the TO_DATE for the year next rather than use simply '2014 '?

  You said it works
  >
  UPDATE FILTERCALENDAR SET YEAR_WINDOW = 1 WHERE c_date = NEXT_DAY (TO_DATE('OCT-2013','MON-YYYY'), 'SUNDAY') + (2-1) * 7;
  >
  Just interview the years from your table (list of the separate years) and use the query above on them.

  SELECT DISTINCT TO_CHAR(c_date, 'yyyy') FROM FILTERCALENDAR
  

  Or use this predicate

  WHERE c_date = next_day(last_day(add_months (c_date, -1)), 'SUNDAY') + 7
     AND TO_CHAR(c_date, 'mm') = '10'
  

  1 TO_CHAR ensures that the line has a month to October.
  2 ADD_MONTHS goes to Sept. 1.
  3 LAST_DAY going until the last day of September.
  4 NEXT_DAY goes to the first Sunday in October
  5 + 7 is going to the second Sunday in October

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

• How to get the last business day of the previous month?

  Hi all

  We need the user as below,

  If the user select 18 June 2015 ' quick dashboard as the input value, and then they want to see last month last day of work (business date: 29-may-2015) amount in report, if you have an idea please share with us.thanks

  Note:

  use under request we can able to get the last day of the previous month, we want to for the last business day of the last month, based on the date of entry of the user?

  TIMESTAMPADD (SQL_TSI_DAY,-(1), TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH ("DIM_TIME". ("" DataDate ") *-(1) + 1,"DIM_TIME ". (("" DataDate "))

  Thank you

  Deva

  Try this,

  case when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 1 then timestampadd (sql_tsi_day, (Dayofmonth(Date '2015-06-15') *-1)-2, Date '' 2015-06-15) when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 7 then timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1-1, Date '' 2015-06-15) another timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15') end

  As Ftsiot said in this post, it will work only to exclude the sat and Sun. Another one if you want to exclude regional holiday, you may need a calendar in DB table.

  Thank you

  AJ

• How to get sales last day of the previous month

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  Please guys if you have any solution and I really advise thanks to you.

  Not exactly under what circumstances specific as you try to reach this goal, but suppose you have a few guest dashboard where you select a day and you have a report with a measure where you want to show the sales of the last day of the previous month based on the selected date in the dash prompt.

  If you change the formula of this measure to something like:

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• Get the last day of the month

  Hello

  How can I get the (day number of the) last day of a given month and year?

  So, if

  year 2015 = and month = 1, the output should be 31

  year = 2012 and month = 2 while production is expected to be 29

  year 2013 = and month = 2 while production is expected to be 28

  etc.

  Y at - it no OBIEE to achieve? If not, then a command SQL Oracle is very good too (I prefer OBIEE however)

  Thanks in advance,

  Erik

  You start from the first day of the month, you add 1 month [TIMESTAMPADD (SQL_TSI_MONTH, 1, 'your date')], you must subtract 1 day [TIMESTAMPADD (SQL_TSI_DAY,-1, 'your date')] and use the DAYOFMONTH function to get the number of the last day of the month [DAYOFMONTH ('your ' date')].

  All these calls nesting together and you're there.

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• How to get the first day of the week on the calendar?

  Hello

  I'm storing calendar weeks in my database. for example 30/2013.

  How can I get the first day of this week (Monday)? in this case, it is 22.07.2013

  THX

  Anja

  with your_table as)
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  )

  Select
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  || (substr (your_column,-4), 'MMDDYYYY'), 'IW')
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  Post edited by: chris227
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• How to get the last parameter of exprision regular

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  If this answer is useful or appropriate, please mark. Thank you.