How to get the last parameter of exprision regular
Hi all!I need to extract the last date in the string.
Here my code
Pattern pattern = Pattern.compile("(19|20)\\d\\d([- \\\\/.](0[1-9]|1[012])[- \\\\/.](0[1-9]|[12][0-9]|3[01]))?");
Matcher matcher = pattern.matcher(text);
while(matcher.find()) {
System.out.println(matcher.group());
How can I get the last dateExample->
Hello all the date is 2010-12-12 the date is 2010-10-10
and I want to get-> 2010-10-10
Thank you!
Just assign the value of the find to a variable declared outside the loop. The variable will hold the last game when you exit the loop.
Kaj
Tags: Java
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