How to get the last row and the sum of all columns in a query

Hello

is there a way to get the last record for a column and the sum of all the Archives to another column in the same query.

Best regards

You must set your needs correctly volunteers to help here...

Your data are not good enough to bring you a precise solution. Purpose, you do not have a column, which draws a distinction between the first and the last entry.

The solution becomes easy based on your design.

I introduced a grouping called 'id' column and a time column called 'time_of_insert' (only this way you can say with confidence that you can differentiate between the first and last (also a foolproof solution) - you can possibly use sequence (instead of date but if you say that you can insert two lines at the same time) ((and then likely sequence would be a better choice to differentiate instead of a timestamp field) etc...)

With your sample data, something like this can be done to get the desired results.

-----------------------------------------------------------------------------------------------------------------------

WITH dataset AS

(SELECT 1 id, 10 used, 8 remain, systimestamp + 1/24 time_of_insert FROM DUAL

UNION ALL

SELECT the 1 id, 1, 7, systimestamp + 2/24 FROM DUAL

UNION ALL

SELECT the id 1, 2, 5, systimestamp + 3/24 FROM DUAL

UNION ALL

SELECT 1 id, 1, 0, systimestamp + 4/24 FROM DUAL

UNION ALL

SELECT 1 id, 0, 0, systimestamp + 5/24 FROM DUAL

UNION ALL

SELECT the 1 id, 1, 4, systimestamp + 6/24 FROM DUAL)

SELECT *.

(SELECT SUM (used) ON sum_all)

FIRST_VALUE (stay)

COURSES (PARTITION BY id ORDER BY time_of_insert DESC)

last_row

Of THE dataset)

WHERE ROWNUM = 1;

Output:

------------------------

SUM_ALL LAST_ROW

------------------------------

15 4

See you soon,.

Manik.

Tags: Database

Similar Questions

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Hi, anyone knows how to get the value of a column in sql query?

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OK, I have the solution

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Dear gurus... I need to get the sum of a column of the first row of my result set to the previous line based on a condition. I read analytical functions for this but they provide the sum of the first rank to Current Row through declaration "rows between Unbounded preceding and current line. Y at - it a statement that calculates the sum as "rows between Unbounded preceding and previous row?
Hello

kamranpathan wrote:
Dear gurus... I need to get the sum of a column of the first row of my result set to the previous line based on a condition. I read analytical functions for this but they provide the sum of the first rank to Current Row through declaration "rows between Unbounded preceding and current line.

If you do not explicitly give a windowing clause, then you get the default windowing clause you indicated.
If you want another clause of windowing, ionclude in the analytic function call.

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```
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```
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I hope that answers your question.
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Published by: Frank Kulash, Sep 17, 2011 17:04
I just saw Etbin responses.
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How to get the sum of "(qty*rate) as salesValue 'as TotalSalesValue cust_id agenda?"

Mr President.
I have to take the column values from3, or 4 tables and two of them need to be multiplied, then get the sum of this value multiplied by using Group by and order clause.
as below
cust_id prod name Qty. rate value totalValue
01 one 01 500 500
01 b 02 400 800 1300
How to get there
Select
cstmr.cust_id CustId,
PRDT. Name AutoCAD,
SL.sal_qty SalQty,
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SL.sal_qty * SL.unit_sal_price as SalVal,
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Concerning

Your expected results include values that are not in your input data - there is no M.BOARD product, for example. This is an adaptation of Manik code that will give you the subtotals for each customer:

SELECT client_name c.nom,

product_name p.Name,

SL.sal_qty,

SL.unit_sal_price,

SL.sal_qty * SL.unit_sal_price AS salesvalue,

CASE

WHEN ROW_NUMBER () OVER (partition by order of c.cust_id p.prod_id desc, sl.sal_id desc) = 1 THEN

SUM (sl.sal_qty * sl.unit_sal_price) OVER (PARTITION BY c.cust_id)

END totals

FROM customer c INNER JOIN sales s ON s.cust_id = c.cust_id

INNER JOIN salesline sl ON sl.sal_id = s.sal_id

INNER JOIN product p ON p.prod_id = sl.prod_id

ORDER BY c.cust_id, p.prod_id, sl.sal_id

You could get the grand total of lines by the Union in a second query, or by doing something smart using ROLLUP. But I leave that to you because I think you should at least do some of your own homework.

cust_id	prod name	Qty.	rate	value	totalValue
01	one	01	500	500
01	b	02	400	800	1300

Get the sum of all Member of a hierarchy.

Hello
I want to get the sum of each Member in a hierarchy.
The hierarchy is defined in the strdet table:

create table strdet

(costcenterms varchar2(20),     // parent

 costcenterdet varchar2(20),    // child

 lev varchar2(1))

The values for each object/material by costcenter (child) is defined in the details_det table:

create table details_det

(costcenterms varchar2(20),

 eppid varchar2(30) ,

 purchcontyear0 number(4,1) )

Some examples of data:

insert into strdet values ('1' , '1.1','2')

/

insert into strdet values ('1' , '1.2','2')

/

insert into strdet values ('1.1' , '1.1.1','3')

/

insert into strdet values ('1.1' , '1.1.2','3')

/

insert into strdet values ('1.2' , '1.2.1','3')

/

insert into strdet values ('1.2' , '1.2.2','3')

/

insert into strdet values ('1.2' , '1.2.3','3')

/

insert into strdet values ('1.1.1' , '1.1.1.1','4')

/

insert into strdet values ('1.1.1' , '1.1.1.2','4')

/

insert into strdet values ('1.1.2' , '1.1.2.1','4')

/

insert into strdet values ('1.2.1' , '1.2.1.1','4')

/

insert into strdet values ('1.2.1' , '1.2.1.2','4')

/

COMMIT;

insert into details_det values('1.1.1.1','epp1',10);

insert into details_det values('1.1.1.1','epp2',20);

insert into details_det values('1.1.1.1','epp3',0);

insert into details_det values('1.1.1.2','epp1',0);

insert into details_det values('1.1.2.1','epp2',5);

insert into details_det values('1.1.2.1','epp4',15);

insert into details_det values('1.2.1.1','epp1',65);

insert into details_det values('1.2.1.1','epp2',95);

insert into details_det values('1.2.1.2','epp1',5);

commit;

The desired sql stmt output should be like this:

costcenter             val

--------------             ------

1                        220 

1.1                       55

1.2                     165

1.1.1                    30

1.1.2                    20

1.2.1                  165

I wrote the following, so far...

SQL> select distinct s.costcenterms , sum(purchcontyear0) over(partition by s.costcenterms order by s.costcenterms)

  2        from details_det d , strdet s

  3        where s.costcenterdet=d.costcenterms(+)

  4        start with s.costcenterms='1'

  5             connect by  s.costcenterms = prior s.costcenterdet

  6        order by s.costcenterms

  7  /

 

COSTCENTERMS                                                 SUM(PURCHCONTYEAR0)OVER(PARTIT

------------------------------------------------------------ ------------------------------

1.2                                                          

1.2.1                                                                                   165

1.1.1                                                                                    30

1.1.2                                                                                    20

1                                                            

1.1                                                          

 

6 rows selected

How should I modify the above sql stmt to get the result you want...?

Note: I use OracleDB 10 g. v.2

Thank you very much
SIM

sgalaxy wrote:
Anyway, since I want to use the sql stmt to define a materialized view, all versions of data of hierarchical queries are not allowed... (oracle ora-30361 error...).

No error on my:

Connected to:
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Production
With the Partitioning, OLAP and Data Mining options

SQL> create materialized view x_mv
  2  as
  3  select  grp,
  4          sum(purchcontyear0)
  5    from  (
  6           select  connect_by_root s.costcenterms grp,
  7                   d.purchcontyear0
  8             from  strdet s,
  9                   details_det d
 10                   where s.costcenterdet=d.costcenterms(+)
 11                   connect by s.costcenterms = prior s.costcenterdet
 12          )
 13    group by grp
 14  /

Materialized view created.

SQL> select  *
  2    from  x_mv
  3    order by grp
  4  /

GRP                  SUM(PURCHCONTYEAR0)
-------------------- -------------------
1                                    215
1.1                                   50
1.1.1                                 30
1.1.2                                 20
1.2                                  165
1.2.1                                165

6 rows selected.

SQL>

SY.

try to get the SUM of all of the charges with the having clause

Hi Oracle users.

I'm trying to accomplish to get a sum of a series of charges and it should be easy, but I can't get it.

For example, I have the following.

Select ACCTLOC,  count(ACCTLOC) AS TOTALP
FROM BOX_ACCTS_TBL 
 WHERE TIME_REQ > SYSDATE-120
 Group By ACCTLOC
  having (count(ACCTLOC) > 1)
 
 the results are
 
ACCTLOC   TOTALP
 
Philly     15970
NY          8623
Tacoma        3
SanFran     195
Hartford    5
Miami       4374

How can I get the SUM of this group? Do I put this in PL SQL and do a procedure to carry out the selection? Is this the way to go on this?
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Thank you!

with

query_result as

(select 'Philly' acctloc, 15970 totalp Union double all the)

Select "NY", 8623 Union double all the

Select "Tacoma", 3 double Union all

Select "SanFran", 195 double Union all

Select "Hartford", 5 Union double all the

Select 'Miami', double 4374

)

Select acctloc, totalp, sum (totalp) on the_sum, avg (totalp) (on the_avg), ratio_to_report (totalp) (percentages))

of query_result

ACCTLOC	TOTALP	THE_SUM	THE_AVG	PERCENTAGES
Philly	15970	29170	4861.66666666666666666666666666666666667	.547480287967089475488515598217346588961
NY	8623	29170	4861.66666666666666666666666666666666667	.295611930065135413095646211861501542681
Tacoma	3	29170	4861.66666666666666666666666666666666667	.000102845389098388755570791909496057593
SanFran	195	29170	4861.66666666666666666666666666666666667	.006684950291395269112101474117243743572
Hartford	5	29170	4861.66666666666666666666666666666666667	.000171408981830647925951319849160095989
Miami	4374	29170	4861.66666666666666666666666666666666667	.149948577305450805622214604045251971203

Concerning

Etbin

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got it to work

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$totalRows_rsSum = mysql_num_rows ($rsSum);

$grandTotal = 0;

Use a loop here

{If ($row_rsSum = mysql_fetch_assoc ($rsSum))

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$row ['utilityAmount'] ;// and view the contents of the line

$row ['SUM (utilityAmount)'; / / and display the contents of the line

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Thank you all in advance for watching in my post.
Select count (*)
Of
(.. .your question here...) ;

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sum(INVOICE_MISR) INVOICE_MISR,
sum(INVOICE_INSURANCE) INVOICE_INSURANCE,
sum(INVOICE_HAIAH)INVOICE_HAIAH
from investor a , invoice b , company c , DEPARTMENT d
where a.INVESTOR_CODE = b.INVESTOR_CODE
and b.COMPANY_CODE = c.COMPANY_CODE
and b.DEPARTMENT_CODE  = d.DEPARTMENT_CODE
and trunc(invoice_date) >= '14-AUG-07'
exists(select 1 from OPERATION_LINE_SMAEDAY ols where ols.INVOICE_NO  = b.INVOICE_NO and ols.INVOICE_type  = b.INVOICE_type  )
group by  b.INVESTOR_CODE , a.INVESTOR_NAME , b.DEPARTMENT_CODE , b.INVOICE_NO , b.INVOICE_TYPE , trunc(b.INVOICE_date) , b.INVOICE_TYPE,c.COMPANY_SHORT_NAME
order by b.INVESTOR_CODE  , INVOICE_date;

For this table, the following query will do the grouping and order it as you want. You will still combine it with the previous query using the original paintings.

SQL> select investor_code
  2       , investor_name
  3       , department_code
  4       , invoice_no
  5       , invoice_type
  6       , invoice_date
  7       , company_short_name
  8       , sum(invoice_commission)
  9       , sum(invoice_keeping)
 10       , sum(invoice_stamp)
 11       , sum(invoice_other)
 12       , sum(invoice_misr)
 13       , sum(invoice_insurance)
 14       , sum(invoice_haiah)
 15    from samedaydata
 16   group by investor_code
 17       , investor_name
 18       , rollup
 19         ( ( department_code
 20           , invoice_no
 21           , invoice_type
 22           , invoice_date
 23           , company_short_name
 24           )
 25         )
 26   order by investor_code
 27       , department_code
 28       , invoice_no
 29  /

INVESTOR_CODE INVESTOR_NAME   DEPARTMENT_CODE INVOICE_NO INVOIC INVOICE_DATE        COMPANY_SHORT_NAME   SUM(INVOICE_COMMISSION)
------------- --------------- --------------- ---------- ------ ------------------- -------------------- -----------------------
SUM(INVOICE_KEEPING) SUM(INVOICE_STAMP) SUM(INVOICE_OTHER) SUM(INVOICE_MISR) SUM(INVOICE_INSURANCE) SUM(INVOICE_HAIAH)
-------------------- ------------------ ------------------ ----------------- ---------------------- ------------------
       240007 john                          2        123 sell   23-04-2010 00:00:00 OTC                                     27.5
                 3.4                  6                  4                 0                      2                 10

       240007 john                          2        124 buy    22-04-2010 00:00:00 ORACLE                                  29.6
                 2.4                  6                  4                 0                      2                 10

       240007 john                          2        125 sell   01-01-2010 00:00:00 ORACLE                                  63.5
                 2.4                  6                  4                 7                      2                 10

       240007 john                                                                                                         120.6
                 8.2                 18                 12                 7                      6                 30

       240008 paul                          3        256 sell   19-12-2010 00:00:00 OTC                                     93.5
                 8.4                  6                  4                 0                      2                 10

       240008 paul                          3        266 buy    06-03-2010 00:00:00 CBANK                                   83.2
                 3.4                  6                  3                 0                      2                  9

       240008 paul                          3        322 buy    23-04-2010 00:00:00 CBANK                                   43.4
                 2.4                  3                  4                 0                      2                  3

       240008 paul                          3        423 sell   23-04-2010 00:00:00 OTT                                     24.5
                 2.4                  2                  4                 0                      8                 10

       240008 paul                                                                                                         244.6
                16.6                 17                 15                 0                     14                 32

9 rows selected.

Kind regards
Rob.

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