How to get the month previous year?

Similar Questions

• get the month and year of date type

  Hi all
  I need to get the month and year of type date.
  
  For example

  select to_date('2011-01-17', 'yyyy-mm-dd') from dual;

  Required result:

  01-2011

  Any ideas?
  
  Thanks in advance,
  Bahchevanov.

  select to_char(to_date('2011-01-17', 'yyyy-mm-dd'),'mm-yyyy') from dual;
  

  HTH

• How to get the Nth largest year in the query

  Hi friends,
  
  This is the query that I have and I want the Nth largest years wages in this table
  If this table is retruning year like 2010,2009,2008,2007 etc.
  
  SELECT *.
  FROM (SELECT the YEAR, MONTH, employee_number, POSITION, payroll_name, dept, status, termination_date, full_name,)
  ROW_NUMBER () OVER (PARTITION BY employee_number, basic_salary ORDER BY YEAR, MONTH) top3,
  DECODE (basic_salary,
  100000, 4500,
  24000, 1921
  basic_salary
  ) basic_salary
  OF kdd_pay_hr_sal_vw
  WHERE employee_number =: p_emp_num
  order by year desc)
  WHERE top3 < = 1
  --------------------------------------------------------
  
  MONTH YEAR EMPLOYEE_NUMBER POSITION STATUS FULL_NAME TOP3 BASIC_SALARY TERMINATION_DATE DEPT
  04 2010 4741 senior oracle Engineer 690-computer used JIHAD ABBAS HARB 1.00 1,600.00
  
  
  
  How to do it pls help

  Hello

  You must remove partition by clause basic_salary. And you must order by year and month of the desc.

  Try this,

  SELECT *
    FROM (  SELECT MONTH
                  ,YEAR
                  ,employee_number
                  ,POSITION
                  ,payroll_name
                  ,dept
                  ,status
                  ,termination_date
                  ,full_name
                  ,ROW_NUMBER ()
                      OVER (PARTITION BY employee_number ORDER BY YEAR DESC, MONTH DESC)
                      top3
                  ,DECODE (basic_salary,  100000, 4500,  24000, 1921,  basic_salary)
                      basic_salary
              FROM kdd_pay_hr_sal_vw
             WHERE employee_number = :p_emp_num
          ORDER BY YEAR DESC)
   WHERE top3 = 1
  

  G.

• to get the month and year separated

  Hello
  
  I have the entry_date_fin of column (type of data-varchar2 (8))
  
  with values like Apr.-2008
  Feb-2009 etc.
  
  can I get the distinct month and year separated

  i tried select to_date(entry_date_fin,'MM') FROM  xyz  doesnt wrk

  kindly guide me

  Although you are (wrongly, IMO) storage of dates as strings, just use string manipulation...

  SQL> with t as (select 'FEB-2008' as txt from dual)
    2  --
    3  select substr(txt,1,3) as mnth
    4        ,substr(txt,5) as yr
    5  from t
    6  /
  
  MNT YR
  --- ----
  FEB 2008
  
  SQL>
  

• How to get the Date, month, year of the DateTimePicker

  Hi, I am using the DateTimePicker.

  There are several question about this command:

  1. how to get the Date, month and year?

  -With the help of myDateTime.value, I get this string ' Wed May 08 14:45 ICT 2013 '-> I have to manually analyze this? Because I need in format yyyy/mm/dd. Or can set the format of dateTimePicker.value?

  2 format on dateTimePicker self (on the user interface) is d/m/YY, I can't change to another format?

  Thank you

  dateTimePicker.value return a QDateTime not a string.

  https://developer.BlackBerry.com/Cascades/reference/bb__cascades__datetimepicker.html#property-value

  See more:

  https://developer.BlackBerry.com/Cascades/reference/QDateTime.html#date

  https://developer.BlackBerry.com/Cascades/reference/QDate.html

  You can get

  day = dateTimePicker.value.date().day()
  month = dateTimePicker.value.date().month()
  year= dateTimePicker.value.date().year()
  dateYYYYMMDD = dateTimePicker.value.date().toString(Qt::ISODate)
  dateYYYYMMDD2 = dateTimePicker.value.date().toString("YYYY/MM/DD")
  dateYYYYMMDD3 = dateTimePicker.value.toString("YYYY/MM/DD")
  

• How to get the maximum number of days in a month?

  How to get the maximum number of days in a month?

  I use a dateField. where I can get the month. Now, I want to get the maximum number of days in a month.

  How can I get it?

  Please help me. and thanks in advance... []

  NET. RIM. Device.API.util
  Class DateTimeUtilities

  getNumberOfDaysInMonth (int month, int year)
  Returns the number of days in the specified month

  It took me like 10 seconds to find it in the API, I guess you spent more time writing the post...

• Get the number of days in a month based on the month and year of fields

  I have a column in my form which lists the days in a month. I want to configure a hidden field that calculates the total number of days in a month, based on the month and year of the field inputs. The number of days will determine what appears on the column. For example, if I put 4 months, and 2016 in the field of the year, I get 30 in the hidden field. Thus, on the column 'Day', I'll have numbers 1-30. Or if I put 2 months and 2016 in the field of the year, I get the 29 in the hidden field. If the numbers 1-29 appears in the column 'day '.

  Found this on some forum javascript code:

  //Month is 1 based
function daysInMonth(month,year) {
   return new Date(year, month, 0).getDate();
}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

  I do not know how to convert this code in JavaScript to adobe and don't really know how to use it. All I know how to do is to configure the field values for the field month and year as variables. I am a novice programmer and would appreciate it really all the help I can get. Thank you in advance!

  The code seems to be JavaScript and runs as needed by using the JavaScript console.

  I would like to consider making more general code, so if you have a date string that includes at least the month and year we could just call the function and get the number of days for that month.

  The following script will calculate the number of days in a month, by using at least the month and year values can display the result on the JavaScript console and all of the value field for the field that has this code as the custom calculation Script.

  function daysInMonth (oDate) {}
  return new Date (oDate.getFullYear (), oDate.getMonth () + 1, 0) .getDate ();
  }

  nMonth var = this.getField("Month").valueAsString; get the value of month;
  nYear var = this.getField("Year").valueAsString; get the value of the year;

  Event.Value = "";

  If (nMonth! = "" & nYear!) = "") {}
  var MyDate = util.scand ("' / mm/yyyy ', nMonth +" / "+ nYear); convert to date object;
  var nDaysInMonth = daysInMonth (MyDate); get the number of days;

  Console.Open (); Open the JavaScript console;

  Console.clear(); clear the console;

  Console.println ("Days in" + nMonth + ":" + nDaysInMonth); show days in month;

  Event.Value = nDaysInMonth; Set the value of the field;

  }

• How to get the date for the first Monday of each month

  Dear members,
  
  How to get the date for the first Monday of each month.
  
  I wrote the following code
  
  SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL
  
  But he looks at complex bith.
  
  Abhishek
  
  Published by: 9999999 on 8 March 2013 04:30

  Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

  select  sysdate current_date,
          trunc(trunc(sysdate,'mm') + 6,'iw') first_monday_the_month
    from  dual
  /
  
  CURRENT_D FIRST_MON
  --------- ---------
  08-MAR-13 04-MAR-13
  
  SQL> 
  

  Here is the list of the first Monday of the month of this year:

  with t as(
            select  add_months(date '2013-1-1',level-1) dt
              from  dual
              connect by level <= 12
           )
  select  dt first_of_the_month,
          trunc(dt + 6,'iw') first_monday_the_month
    from  t
  /
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-JAN-13 07-JAN-13
  01-FEB-13 04-FEB-13
  01-MAR-13 04-MAR-13
  01-APR-13 01-APR-13
  01-MAY-13 06-MAY-13
  01-JUN-13 03-JUN-13
  01-JUL-13 01-JUL-13
  01-AUG-13 05-AUG-13
  01-SEP-13 02-SEP-13
  01-OCT-13 07-OCT-13
  01-NOV-13 04-NOV-13
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-DEC-13 02-DEC-13
  
  12 rows selected.
  
  SQL> 
  

  SY.

• How to get the product key I purchased previously?

  How to get the product key I purchased previously?

  Depends entirely on how you bought it in the 1st place.

  A boxed product should have the key on the DVD case, which is the only trace.

  An update Anytime, you should have the key in an e-mail message from Microsoft. If you log in the website to store, you should be able to find the email conversation.

  If another provider such as a key, then you will need to go back to them.

  If your Windows starts now while you can use a keyfinder utility to read the registry key.

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

• How to get the second and third weekend of every month over a period of time?

  Hello

  No idea how to get the second and third weekend of every month on a given period without use of CLAUSE?

  Thanks in advance.

  Try it below,

  SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'SAT '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 1

  WHERE TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'Sun '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 6

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), "SAT") + 1

  END as second_weekendday,

  BOX WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'SAT '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 7

  WHERE TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'Sun '.

  THEN ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)) + 7

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), "SAT") + 7

  END AS third_weekendday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to get the second Monday of each month in a given date range?

  In Oracle forms, how to get the second Monday of each month in a given date range?

  I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?

  WITH month_range AS

  (

  SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month

  , TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month

  OF the double

  )

  SELECT NEXT_DAY (6 + ADD_MONTHS (first_month

  , LEVEL - 1

  )

  , 'MONDAY '.

  ) AS second_monday

  OF month_range

  CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)

  ;

  Thanks in advance.

  Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

  SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

  THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

  END AS second_day

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How can I order a list first for the year and sort the months each year?

  Hello

  I created a report that lists a number of items grouped by month, although elements it since 2012 so together and you spend your order is strange because the groups to report on 2 months.

  example:

  2013 - 01-50

  01/2012 - 56

  02/2013 - 45

  02/2012 - 54

  .

  .

  .

  How do I ordernar first a year and and sort the months each year?

  Sort by DATE... not VARCHAR2

  It is a thing of database, not an APEX.

  In your select statement to the report, the column for DATE information must be one data type DATE or another...

  MK

  PS - TRUNC (a_date_column, 'MONTH')

• Select SQL - last day of the month, a year from now

  Hello
  How do we get the last day of the month, a year from now.
  
  For example-sysdate-12/2/2009
  Result - 31/12/2009
  
  Thank you

  Hello

  SELECT  LAST_DAY ( ADD_MONTHS ( SYSDATE
                                , 12
              )           )
  FROM    dual;
  

  Remember, all DATEs, including the results of this query, include the hours minutes and seconds.
  The hours, the minutes and the seconds returned by the above expression are the same as SYSDATE: If you run it at 15:43:30 today, it returns 15:43:30 on December 31, 2010. This can be important if you want to use an expression like this as the cut-off point in a WHERE clause.