How to re-scan the relationship between computer ip addresses and network names

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• I'm looking for the relationship between the unit ORGANIZATION and self-service workflow?

  Hi all:
  I have 3 UO and 3 files of wft different workflow self-service in the my HR system. How can I know the relationship between the unit ORGANIZATION and self-service workflow? I mean what wft file corresponds to an ORGANIZATIONAL unit?
  
  my environment is oracle 11.5.9. self-service 4.1 | workflow Builder 2.6
  
  for example:
  OR 1 = > HRSSA1.wft
  
  OR 2 = > HRSSA3.wft
  
  OR 3 = > HRSSA2.wft
  
  I'm looking for this relationship?
  
  
  Concerning
  Terry

  Terry,

  I mean what wft file corresponds to an ORGANIZATIONAL unit?

  Open the workflow designer using wft files and see if you can find any reference to these OUs.

  Thank you
  Hussein

• How to find the relationship between the tables

  Hello
  I am working in Oracle R12
  
  How to find the relationship between these tables INV_MIN_MAX_TEMP, po_requisition_lines_all and Per_all_people_f
  
  These two tables, I joined with po_requisition_lines_all and Per_all_people_f To_person_id of PO and anyone HR table but I can't able to join this table with other tables INV_MIN_MAX_TEMP
  
  concerning
  Srikkanth

  solved

• How to establish the relationship between the tables contact and Global (entity) in Oracle Service Cloud to preconfigure data

  Hello

  We strive to integrate the OPA attributes to the Cloud Service Oracle tables to store session data for the customer portal users.

  We tried mapping the attributes of the OPA with relevant tables of cloud Service Oracle? Is there any installation of additional data to create to retrieve the session data for the particular user / contact?

  We managed to save tha data in arrays of cloud Service for users of ananymous and also well regarding customers portal users but to preconfigure data do we need to do any additional configuration / mapping to the contact table?

  Please help on the establishment of the relationship between the contact and Global (new table created in cloud Service) tables.

  Thank you

  Vivek

  Hi Vivek,

  To load data from the Contact in the the OPA policy template, you must configure the widget of the OPA. For instructions, see the following articles:

  - Incorporate an interview that uses data portals in Oracle Service Cloud Customer Portal

  - Deploy and configure the sample OPA widget

  - Insert the widget to sample in a customer portal page

  Obviously, you need to do the mapping in OPM as well, but even if the mapping is correct, you will not be able to load the Contact data unless the widget of the OPA is implemented.

  See you soon,.

  Jasmine

• Explain the relationship between libraries, albums and photos in pictures.  Where are the images stored?

  Looking for info on the relationship between libraries, albums and photos in the Photos app.  I can create several libraries containing photos and unique albums.  Can I put the same photo in libraries and the different albums?  By making a copy it creates a link to the original or a new photo?  Where are located the photo files?  When scanning photo to my Mac Pro files are placed in a folder structure, copy these photos in an album Photos using the original file or he places a copy in a database?

  Bottomline, I'm frustrated by the method of collection, the albums, the place and date.  I want store related photos in a separate album.   Example: A library for a family, containing albums of members of their family. Maybe the photos have duplicate in different albums.

  Some of your questions are answered by Leonie contributor in this thread:

  Re: Too many libraries...

  More answers can be found by using help in Photos app, or in general to help the Viewer.

  Apple Support website has links to information in articles; a search on the web is sometimes useful

  to locate the Apple pages faster than the company's site. Others in line include:

  Photos for OS X FAQ:

  http://www.IMore.com/photos-OS-x-FAQ

  How to use the Photos for OS x:

  http://www.IMore.com/how-use-photos-OS-x-ultimate-guide

  Good luck!

• What gets the relationship between the number of blocks and coherent?

  SQL> CREATE TABLE TEST(ID INT ,NAME VARCHAR2(10));
  
  SQL> CREATE INDEX IND_IDN ON TEST(ID);
  
  SQL> BEGIN
    2  FOR I IN 1 .. 1000
    3  LOOP
    4  EXECUTE IMMEDIATE 'INSERT INTO TEST VALUES('||I||',''LONION'')';
    5  END LOOP;
    6  COMMIT;
    7  END;
    8  /
  
  SQL> EXEC DBMS_STATS.GATHER_TABLE_STATS(USER,'TEST',CASCADE=>TRUE);
  
  SQL> SELECT DISTINCT DBMS_ROWID.rowid_block_number(ROWID) BLOCKS FROM TEST;
  BLOCKS
  -----------
  61762
  61764
  61763         
  
             >> above , there have 3 blocks in table TEST .
  
  SQL> SET AUTOTRACE TRACEONLY;                                     
  
  SQL> SELECT * FROM TEST;
  
  Execution Plan
  ----------------------------------------------------------                      
  Plan hash value: 1357081020                                                     
                                                                                  
  --------------------------------------------------------------------------      
  | Id  | Operation         | Name | Rows  | Bytes | Cost (%CPU)| Time     |      
  --------------------------------------------------------------------------      
  |   0 | SELECT STATEMENT  |      |  1000 | 10000 |     2   (0)| 00:00:01 |      
  |   1 |  TABLE ACCESS FULL| TEST |  1000 | 10000 |     2   (0)| 00:00:01 |      
  --------------------------------------------------------------------------      
  
  
  Statistics information
  ----------------------------------------------------------                      
            0  recursive calls                                                    
            0  db block gets                                                      
           72  consistent gets                                    >>  there have 72  consistent gets                  
            0  physical reads                                                     
            0  redo size                                                          
        24957  bytes sent via SQL*Net to client                                   
         1111  bytes received via SQL*Net from client                             
           68  SQL*Net roundtrips to/from client                                  
            0  sorts (memory)                                                     
            0  sorts (disk)                                                       
         1000  rows processed                                                     
  
  SQL> SELECT /*+ INDEX_FFS(TEST IND_IDN)*/ * FROM TEST WHERE ID IS NOT NULL;
  
  Execution Plan
  ----------------------------------------------------------                      
  Plan hash value: 1357081020                                                     
                                                                                  
  --------------------------------------------------------------------------      
  | Id  | Operation         | Name | Rows  | Bytes | Cost (%CPU)| Time     |      
  --------------------------------------------------------------------------      
  |   0 | SELECT STATEMENT  |      |  1000 | 10000 |     2   (0)| 00:00:01 |      
  |*  1 |  TABLE ACCESS FULL| TEST |  1000 | 10000 |     2   (0)| 00:00:01 |      
  --------------------------------------------------------------------------      
                                                                                  
  Predicate Information (identified by operation id):                             
  ---------------------------------------------------                             
                                                                                  
     1 - filter("ID" IS NOT NULL)                                                 
  
  
  Statistics information
  ----------------------------------------------------------                      
            1  recursive calls                                                    
            0  db block gets                                                      
           72  consistent gets                                   >>  there have 72  consistent gets                  
            0  physical reads                                                     
            0  redo size                                                          
        17759  bytes sent via SQL*Net to client                                   
         1111  bytes received via SQL*Net from client                             
           68  SQL*Net roundtrips to/from client                                  
            0  sorts (memory)                                                     
            0  sorts (disk)                                                       
         1000  rows processed                                                     
  
                                           
  
  SQL> SELECT COUNT(*) FROM TEST;
  
  Execution Plan
  ----------------------------------------------------------                      
  Plan hash value: 1950795681                                                     
                                                                                  
  -------------------------------------------------------------------             
  | Id  | Operation          | Name | Rows  | Cost (%CPU)| Time     |             
  -------------------------------------------------------------------             
  |   0 | SELECT STATEMENT   |      |     1 |     2   (0)| 00:00:01 |             
  |   1 |  SORT AGGREGATE    |      |     1 |            |          |             
  |   2 |   TABLE ACCESS FULL| TEST |  1000 |     2   (0)| 00:00:01 |             
  -------------------------------------------------------------------             
  
  Statistics information
  ----------------------------------------------------------                      
            0  recursive calls                                                    
            0  db block gets                                                      
            5  consistent gets                                      >>  there have 5  consistent gets               
            0  physical reads                                                     
            0  redo size                                                          
          408  bytes sent via SQL*Net to client                                   
          385  bytes received via SQL*Net from client                             
            2  SQL*Net roundtrips to/from client                                  
            0  sorts (memory)                                                     
            0  sorts (disk)                                                       
            1  rows processed                                                     
  
                                                
  
  SQL> SELECT COUNT(*) FROM TEST WHERE ID IS NOT NULL;
  
  Execution Plan
  ----------------------------------------------------------                      
  Plan hash value: 735384656                                                      
                                                                                  
  --------------------------------------------------------------------------------
  -                                                                               
                                                                                  
  | Id  | Operation             | Name    | Rows  | Bytes | Cost (%CPU)| Time     
  |                                                                               
                                                                                  
  --------------------------------------------------------------------------------
  -                                                                               
                                                                                  
  |   0 | SELECT STATEMENT      |         |     1 |     4 |     2   (0)| 00:00:01 
  |                                                                               
                                                                                  
  |   1 |  SORT AGGREGATE       |         |     1 |     4 |            |          
  |                                                                               
                                                                                  
  |*  2 |   INDEX FAST FULL SCAN| IND_IDN |  1000 |  4000 |     2   (0)| 00:00:01 
  |                                                                               
                                                                                  
  --------------------------------------------------------------------------------
  -                                                                               
                                                                                                                                                              
  Predicate Information (identified by operation id):                             
  ---------------------------------------------------                             
                                                                                  
     2 - filter("ID" IS NOT NULL)                                                 
  
  
  Statistics information
  ----------------------------------------------------------                      
            0  recursive calls                                                    
            0  db block gets                                                      
            5  consistent gets                                                >>  there have 5 consistent gets     
            0  physical reads                                                     
            0  redo size                                                          
          408  bytes sent via SQL*Net to client                                   
          385  bytes received via SQL*Net from client                             
            2  SQL*Net roundtrips to/from client                                  
            0  sorts (memory)                                                     
            0  sorts (disk)                                                       
            1  rows processed                                                     
  
                                            
  
  SQL> SELECT COUNT(ID) FROM TEST WHERE ID IS NOT NULL;
  
  Execution Plan
  ----------------------------------------------------------                      
  Plan hash value: 735384656                                                      
                                                                                  
  --------------------------------------------------------------------------------
  -                                                                               
                                                                                  
  | Id  | Operation             | Name    | Rows  | Bytes | Cost (%CPU)| Time     
  |                                                                               
                                                                                  
  --------------------------------------------------------------------------------
  -                                                                               
                                                                                  
  |   0 | SELECT STATEMENT      |         |     1 |     4 |     2   (0)| 00:00:01 
  |                                                                               
                                                                                  
  |   1 |  SORT AGGREGATE       |         |     1 |     4 |            |          
  |                                                                               
                                                                                  
  |*  2 |   INDEX FAST FULL SCAN| IND_IDN |  1000 |  4000 |     2   (0)| 00:00:01 
  |                                                                               
                                                                                  
  --------------------------------------------------------------------------------
  -                                                                               
                                                                                                                                                            
  Predicate Information (identified by operation id):                             
  ---------------------------------------------------                             
                                                                                  
     2 - filter("ID" IS NOT NULL)                                                 
  
  
  Statistics information
  ----------------------------------------------------------                      
            0  recursive calls                                                    
            0  db block gets                                                      
            5  consistent gets                                        >>  there have 5  consistent gets             
            0  physical reads                                                     
            0  redo size                                                          
          409  bytes sent via SQL*Net to client                                   
          385  bytes received via SQL*Net from client                             
            2  SQL*Net roundtrips to/from client                                  
            0  sorts (memory)                                                     
            0  sorts (disk)                                                       
            1  rows processed                                                     

  QUESTION:
  
  What gets the relationship between the number of blocks and coherent? How to calculate become consistent?

  You can see that your uniform is getting down to 6 to 12, is it not? Reading of the below thread Asktom.
  http://asktom.Oracle.com/pls/Apex/f?p=100:11:0:P11_QUESTION_ID:880343948514

  Aman...

• HOW smart card smart card slots look like? What are the differences between smart card slots and cards express?

  HOW smart card smart card slots look like? What are the differences between smart card slots and cards express?

  Hi Smitty,

  Yes, so ExpressCard is an interface that has a USB port to this topic where I can plug in external devices to be attached to my computer right? I did a search on google but could not find photo Card Slot smart. I need a picture to get an idea of how look like a smart card Slot.

  Next time try BING...

  http://tinyurl.com/95rgwxw
  http://tinyurl.com/9plc7zt

  http://tinyurl.com/8h96qsr

  Scroll to the left view (image 5)

  http://support.Dell.com/support/eDOCS/systems/latd610/en/ug_en/about.htm

• How can I fix the link between adobe and windows if I see .pdf not win32 application

  How can I fix the link between adobe and windows if I see .pdf not win32 application, without the disc?

  "Adobe" is the name of the company that provides a great many different applications.

  Adobe Reader is free and allows you to view pdf files.

  Adobe Acrobat is expensive and allows you to create, edit and view pdf files.

  Assuming that you are referring to the reader, uninstall all the versions of it using the control panel > add or remove programs.  Then either

  1. go to http://get.adobe.com/reader/?promoid=BUIGO and download the current version (remember to uncheck the box to install McAfee Security Scan Plus.

  or

  2. go to http://www.foxitsoftware.com/Secure_PDF_Reader/ and download Foxit Reader, a small pdf reader and many more.

  Then, install the reader that you have downloaded.

• How I can scan the registry valuHi, how I can scan the Windows 7 registry value and how do I come to know if the registry value is same as it has been installed previously?

  Hello

  How can I scan the Windows 7 registry value and how do I come to know if the registry value is same as it has been installed previously?

  Hello
   
  The Windows registry is a vast and vital part of the computer, which continues to evolve being modified or deleted or new entries are created all the time.
   
  Case where the registry keys of change.
   
  At startup
   
  So that updates
   
  While making customization or custom settings in windows
   
  While to install the software
  Virus... etc.
   
   
  Each click Open and save is related to the registry.
   
  This is something very tedous to verify the integrity of a registry of windows with all of the above modifications being carried out.
   
  You can back up the registry of the computer after you install Windows new and update with all Windows updates and the custom software, into a registry backup or create a system image / restore point.
   
  Please visit these links for more information.

  Windows registry Description of the audit of the Windows Registry tool (Scanreg.exe) How do I add, edit or delete subkeys in registry and values by using a registration entries (.reg) file Hope this information helps

   
   
   

• What are the relationships between the logging and IKM?

  What is the best method to use in the following scenario:
  I have about 20 tables with the large amount of data sources.
  I need to create interfaces that join the source tables in target tables.
  The tables are inserted every few seconds with about hundreds of thousands lines.
  There may be a gap of a few seconds between the insertion of different tables that could be attached.
  The source and target tables are on the same Oracle instance and schema.
  I want to understand the role of: 'Logging CDC' and "IKM - incremental" and
  How can I use it in my script?
  In general, what are the relationships between "Logging" and 'IKM '?
  Use both? Or maybe it's better deelte and insert the target tables?
  
  I want to understand what is the role of "Logging CDC"?
  Can 'IKM - incremental' work without "logging"?
  Must 'Logging' have PK on the tables?
  What should I do if I can't say PK (there may be several identical lines)?
  
  Yael thanks in advance

  user604062 wrote:
  Hello
  Thanks for your quick response!

  No probs - its still fresh in memory I did a major project on this topic last year (400 tables, millions of lines per day (inserts, updates, deletes), sup-5 minute latency). The problem is it isn't that well written on the web, that you have read the blog of the example I linked to in my first answer? See also here: http://odiexperts.com/changed-data-capture-cdc/

  Always on logging:
  My source table is inserted all the time.
  The interface to join the source table in the target table.

  In ODI, the correct term would be your source table "fits" in the table target, unless you mean literally that want to join the the source with the taget table table? My question if you want to do with the result of the join?

  What exactly the "journaling" CDC updates?
  It updates the model of ODI? interfaces? The source of data in the model of ODI? The target table?

  Logging CDC configures and deploys the data capture mechanism (Triggers or log based capture, IE Logminer/streams/Goldengate) - it is not updated the model as such, she pointed out the metadata of the model of ODI repositoty as a CDC data store, allowing you, the developer say ODI to use log data if you wish (reported in the interface) There is no change in the target table, you get an indicator of metadata (IND_UPD) against a line during the integration (in C$ and I have tables$) that tells you if its insertion (I) and update (U) or deletion (D). It had ' lines allow you to synchronize the deletions, but yoy say its inserts only then you probably used use this option. "
  So the only changes are the source table to your interface, another diary data (if you use logging) or the table of the actual source (if not using the logging).

  This is the main thing that I don't understand!

  I hope I made a little clearer.

  Try the following as a quick test:

  Reverse a source table an engineer and the target (at least) table.
  Import the update incremental LKM and IKM.
  Import of the JKM you want to use.

  Create an interface between the source and the target without any deployed JKM.
  Configure the options of JKM on the model, the "Start log" to start the process of capture - this is quite a complex stage and a lot of things to understand what is happening in the source database, better to check code ODI sends to the database and to review the documentation of Oracle database for a description of what his weight (instantiate Tables (, sets of creating change, creation of subscribers etc. establishment of newspaper groups, creating views Journalising etc.) -you will need to consult your Source DBA database initially as ODI wants to make many changes to the source DB (in mode Archivelog process max, parallelism, size, Java etc.)

  Now, edit your interface and mark the table source for use "Journalized data bank.
  Restart your interface
  Compare the difference in the generated code in the journal of the operator, see the differences of the operator.

  >

  Thank you, Yael

• How can I change the cursor in an individual account (and not the owner) a computer to my client?

  How can I change the cursor in an individual account (and not the owner) a computer to my client?

  Hi MichaelConner1,

  You can keep the individual mouse for each user account on the computer.

  Log on to each user account and then change the mouse pointer scheme using the link below and check if it helps.

  http://www.Microsoft.com/enable/training/WindowsXP/pointerscheme.aspx

• What is the relationship between the source code (LKS) file and the process file (L4P)?

  I know that Lookout produces a file of source code with an LKS extension when you save a file to process.  Can someone explain the relationship between the two files, especially while the (L4P) process is running?

  1. Is this just a backup file can be recompiled in a process file?
  2. A file corrupt LKS cause strange problems with operation process file?

  I currently have a very strange intermittent behavior with a process file run.  I first thought that the problem was associated with my Fieldpoint and/or their configuration modules.  Since then, I found that my process file has a file corrupt LKS.  I repaired and recompiled my LKS file to a new file to process.  I still don't know if I have solved the problem or not.  So, the problem is intermittent, I did that about 20-30 SECONDS to resolve the problems there before he goes.  Then he can not show up again for another 2-3 days.

  The .lks file is just the source code of your process. It can be opened by a different version of lookout, but does not have the .l4p file.

  The .lks file is not be used while a process is running. Lookout does not read the file more after his execution. So it should not affect the running process.

  What kind of problem, is it?

• Hello out there! I am trying to understand the relationship between the products. I am a current user of 13 items and sought to CC Photoshop with Lightroom. Always use elements like the storage tool to catalog my photos or it get replaced?

  Hello out there! I am trying to understand the relationship between the products. I am a current user of 13 items and sought to CC Photoshop with Lightroom. Always use elements like the storage tool to catalog my photos or it get replaced?

  It's kind of ridiculous. All I want to do is ask a question and there is no place to connect with anyone. Sucks!

  Hi charlesf,

  If you choose to go to CC Photoshop with Lightroom, Photoshop Elements would not be replaced.

  CC of Photoshop and Photoshop Elements are different programs, so the two will remain separate on your machine and catalogue items would not hit at all.

  Let us know if you have any other questions.

  Kind regards

  Claes

• How can we change the spacing between lines of text?

  6 How do I change the spcing between the lines of text using Dreamweaver. Do not see as an option in the menu of page properties.

  Try the line-height CSS property.

  --

  Kenneth Kawamoto

  [link removed by Moderator]

• The scale and the relationship between the problem of points

  I had a few problems with setting the scale of the objects and their appearance before and after the scaling.

  The relationship between the points change when I change things, and it's a little embarrassing.

  Before that I put across that circle with an arrow, it looked like this:

  

  Then after that I put across it, the lines on the arrow were not in place:

  

  It happens very often when I am scaling of paths in illustrator. Is there something I can do to prevent it? Often I make things evolve upwards or downwards and it is a little painful when I know I'm going to screw up the path.

  

  

  Go to the drop down at the top right of the Panel processing and disable "Align new objects to the pixel grid."

  Edit: If you select 'Web' in the new Document dialog box, "Align new objects of pixel grid" is enabled by default, at the bottom of the box. You can choose to disable it there before OK-ing the creation of the document.