How to remove a virtual column in a table

Similar Questions

• How to remove a line empty in a table

  How to remove a line empty in a table?
  This is how to remove only a line including all columns as null values...
  Please help me

  Sounds strange, but you can use COALESCE to achieve this.

  ME_XE?create table all_nullz (col1 number, col2 number, col3 number);
  
  Table created.
  
  Elapsed: 00:00:00.20ME_XE?ME_XE?insert into all_nullz values (1,2,3);
  
  1 row created.
  
  Elapsed: 00:00:00.12ME_XE?insert into all_nullz values (null, null, null);
  
  1 row created.
  
  Elapsed: 00:00:00.06ME_XE?ME_XE?delete from all_nullz where coalesce(col1,col2,col3) is null;
  
  1 row deleted.
  
  Elapsed: 00:00:00.26ME_XE?
  

• How to add the new column in existing table to our desired location?

  How to add the new column in existing table to our desired location?

  For example, I have to add the new column 'course' before the salary column in the emp table.

  I think the best way is to add the column at the end of the table and create a new view with the order of the columns...

  Another option...

  places the data into a temporary table and recreate the table with the correct order of the columns, and then insert data to the table from the temporary table

  Refer

  Add column (from table) in the desired position

  Example:

  CREATE TABLE temp_my_user LIKE)

  SELECT * FROM password);

  DROP TABLE password;

  (Password) CREATE TABLE

  userID NUMBER

  , first name VARCAHR2 (25)

  , middleInitial VARCHAR2 (1)

  (, name VARCHAR2 (25));

  INSERT INTO password (userID, firstName, lastName)

  (SELECT username

  first name

  lastName

  OF temp_my_user);

  DROP TABLE temp_user;

• How to remove select data in the control table

  This problem makes me headache.

  I'm new to labview, when data in a table. a lot of lines and columns. How can remove on the line that I chose. the other lines are remain unchanged.

  I really need help.thanks in advance. It is best to attach the labview program.my is 2009

  That kind of thing does not work with the table that's why I suggested to go for the multicolumn list box. You can do simple.

  

  Good luck

• How to create a status column in the table

  Hello everyone

  I am trying to create a column of the table status in frontview Panel. I enclose a picture with her to say clearly what I say.plz tell me how to create the active status column in the table.

  I want to show green for safety stock and red for safety stock below.

  
  

• How to find the NULL columns in the table?

  Hello
  
  Please provide the query to search for null columns in the table. Here, all the rows in the table have same column as null. It will not change.
  
  Table
  ---------------
  C1 c2 c3 c4
  X C 10
  T D 20
  
  I want to know that C2 is the nullable column.
  Thanks in advance!
  
  Kind regards
  Florian...

  A variance more

  create or replace function is_nulled_column(tab varchar2, col varchar2) return varchar2 is
  cnt number:=1;
  begin
    execute immediate 'select count(1) from '||tab||' where '||col||' is not null and rownum=1' into cnt;
    return case when cnt=0 then 'Y' else 'N' end;
  end;
  

  and use:

  select
   c.OWNER,c.TABLE_NAME,c.COLUMN_NAME,c.NULLABLE,is_nulled_column(c.TABLE_NAME,c.COLUMN_NAME) all_nulls
  from all_tab_columns c
  where c.OWNER=user
  and c.TABLE_NAME like '%'
  order by c.OWNER,c.TABLE_NAME,c.COLUMN_ID
  

• How to remove Windows Virtual PC - XP compatibility mode

  Hi all.  I have loaded the software virtual windows xp on my computer and it works fine.

  Unfortunately, it does not provide the solution I was looking for.

  Question: How do I remove Windows Vitrual PC?

  Go in Panel > programs and features , then click on view installed updates .  Windows Virtual PC will appear in the Microsoft Windows . Boulder computer Maven
  Most Microsoft Valuable Professional

• How to remove some virtual drives of portable Satellite

  MY TOSHIBA HAS A LOT OF VIRTUAL DRIVES, THAT IT LEAVES ONLY 1 FREE SPACE TO PLUG A USB BACKUP DEVICE.

  I CAN'T SEEM TO RECORD INFORMATION TO ONE OF THESE READERS, NO MATTER WHAT I TRY!

  HOW CAN I GET RID OF ALL OR PART OF THESE READERS VIRTUAL SO-CALLED OR GET A JOB?

  Hello

  Could you please put more details?
  What is your laptop model and what operating system are you using?

  It would be useful for other suggestions

• How to remove tabular form column position of underscore

  Hi guys,.

  I use APEX 4.1, I want to delete tabular form underscore column heading, you could you please guide me how to do this?

  See you soon,.

  San

  San wrote:

  Hey sorry, I couldn't find the #TEMPLATE_CSS # in my page template.

  I use two Tabs - model level of right sidebar (optional / based on a table)

  I was using 4.2. 4.1 Add

  After

  in the page header.

• How to remove a virtual computer in WS 8 draws it from 'my computer '.

  Salvation;

  I recently did some "house keeping" system by removing some old VMS (Windows 7 64-bit). I finished remove disk outside the workstation 8 thinking that I could just delete the list of workstation.

  I opened the 8.0.6, workstation and I went to the tab 'my computer '. Maybe I'm not remembering correctly, but I expect to be able to right click on the entry for the virtual machine and 'remove' from the list.

  Instead, right click only gives me the choice of 'open '. Open does not work of course because the virtual machine isn't there anymore.

  Am I missing something? What is the way to remove a deleted virtual machine? (Or even if not deleted one by the way).

  Even for machines that I still, I can't find an option 'remove '. (I see the closest thing is to Manage / "remove disc", which is more drastic than just detached from the list).

  Thank you;

  OK, I forgot that there is a separate pane 'library' (I normally hidden). I thought that the 'My computer' tab has been where I removed the VMs when it was really the library list, with that I needed to work.

• How to remove the virtual computer on a data store

  I'm moving VM (by the data store) to my new cluster data store and as I release a DS I have delete and create new with VMFS5.  I just emptied a data store but when I run the following command it shows again two VM on the same DS so when I navigate on the DS it is empty.

  Get-datastore-name "DS_NAME | Get - vm | FT name

  How to see where/how/why these two VMs are on the DS when it seems to be empty, and I'm assuming that PowerCLI is my best result. Of course, I don't want to just delete the DS as possible casue a problem with these virtual machines.  When I look at the settings them of each virtual machine they show that they are on a store of separate data and not that I'm trying to delete.

  Any help is appreciated

  Thank you

  Sean

  You can do:

  Notice-EEG-Id | Get-VIObjectByVIView

  or:

  Get - VM | Get-Datastore

• How to remove a virtual machine that has lost the storage

  Hello

  I want to remove the drive a virtual machine that has lost its storage. This storage kept OS files and so on. The problem is that because it is lost I can't access most options since they are grey (eg. delete disk). I can't get out of the inventory, but I want to remove it completely. It is impossible to recover the storage that was missing. What is a way to remove it?

  Thanks adavance

  It's because everything else for the virtual machine has been wrapped in storage.

• How to remove duplicates from the PL - SQL table?

  Hi gurus,
  
  I have a PL - SQL table with the following structure
  Authors (SR_NO, Auth_Code, Change_Date, cost)
  
  This table is filled using a slider. However, this table can have a few lines in double (for column (Auth_Code)
  for example

  SR_NO      Auth_Code       Change_Date                       Cost
  1               A1             14-FEB-09 08.18.47 AM          11.00
  2               A2             14-FEB-09 08.18.56 AM       2839.00
  3               A1             15-FEB-09 08.00.02 AM      1299.00
  4               A1             15-FEB-09 07.00.00 AM        789.00
  5               A3             14-FEB-09 08.18.56 AM        312.00
  6               A4             14-FEB-09 08.19.02 AM        233.00

  I need to get the above result set select the separate lines of Auth_Code including the Change_Date is maximum (and store in another PL - SQL table for treatment later or even the removal of this table will be also!)
  
  of the data A1 is duplicated and a maximum Change_Date above = 15 February 09 08.00.02 AM.
  Where my PL - SQL Table that results must have given below
  

  SR_NO      Auth_Code       Change_Date                       Cost
  2               A2             14-FEB-09 08.18.56 AM       2839.00
  3               A1             15-FEB-09 08.00.02 AM      1299.00
  5               A3             14-FEB-09 08.18.56 AM        312.00
  6               A4             14-FEB-09 08.19.02 AM        233.00

  I'm not very aware of the PL - SQL tables and there is no chance to change the existing cursor that fills the data in this table PL - SQL.
  I guess that I need to compare each record of PL - SQL table with others, but do not know how to do this.
  
  Could you please help?

  Hello

  Like this?:

  Connected to Oracle Database 10g Express Edition Release 10.2.0.1.0
  Connected as hr
  
  SQL>
  SQL> with data as(
    2  select 1 as SR_NO, 'A1' as Auth_Code, to_date('14-FEB-09 08.18.47', 'dd-mon-yy hh24:mi:ss') as change_date,    11.00 as cost from dual union all
    3  select 2 as SR_NO, 'A2' as Auth_Code, to_date('14-FEB-09 08.18.56', 'dd-mon-yy hh24:mi:ss') as change_date,  2839.00 as cost from dual union all
    4  select 3 as SR_NO, 'A1' as Auth_Code, to_date('15-FEB-09 08.00.02', 'dd-mon-yy hh24:mi:ss') as change_date,  1299.00 as cost from dual union all
    5  select 4 as SR_NO, 'A1' as Auth_Code, to_date('15-FEB-09 07.00.00', 'dd-mon-yy hh24:mi:ss') as change_date,   789.00 as cost from dual union all
    6  select 5 as SR_NO, 'A3' as Auth_Code, to_date('14-FEB-09 08.18.56', 'dd-mon-yy hh24:mi:ss') as change_date,   312.00 as cost from dual union all
    7  select 6 as SR_NO, 'A4' as Auth_Code, to_date('14-FEB-09 08.19.02', 'dd-mon-yy hh24:mi:ss') as change_date,   233.00 as cost from dual)
    8  select * from data d where change_date = (select max(change_date) from data d2 where d.auth_code = d2.auth_code);
  
       SR_NO AUTH_CODE CHANGE_DATE       COST
  ---------- --------- ----------- ----------
           2 A2        14/02/2009        2839
           3 A1        15/02/2009        1299
           5 A3        14/02/2009         312
           6 A4        14/02/2009         233
  
  SQL>
  

  Kind regards

• How can I move a column in a table please

  www.hunterstables.co.UK/Pricelist/HTML

  I have a 'List of Extra Awards' table and would spend the two columns.  I tried dragging, but that doesn't seem to work, can anyone help me please.

  The first column is wood skates, then the price.  I would like to move the column ' awards more towards the right and the same thing with 'channels towing, and then the price. "

  This looks a little too crumpled upward.

  Thank you.

  Karen

  Hello Karen,

  my eyes, to first 'restore' your line "EXTRA LIST OF PRICES (including VAT)" in a table of 5 cells. For this I line copy two would remove entries and copy 'EXTRAS, (TTC) PRICE LIST' in the first column. After that, you can delete aso.

  I got this:

  EXTRA (TTC) PRICE LIST
  	Skates of wood 24 ft	£160	Full score (PLY)	£140
  	Wood skids 36 ft	£210	Partition of half (PLY)	£85
  	12 ft metal skates	£250	8 ft wooden door	£150
  	18 ft metal skates	£300	8 ' galvanized grid	£140
  	Skates metal 24 ft	£350	Upper door	£60
  	Skates metal 36 ft	£550	Talk about Grill	£180
  	OSB Kick boards 11mm	£55 per box of 12 feet	Metal Chew strips	£12 each
  	Kick 18mm OSB boards	£70 per 12 foot box	Gutter 12	£46
  	PLY Kick boards of 12mm	£100 per box of 12 feet	2 sliding rails	£30
  	Skylight	£36	Grass on the ground anchors	£50

  Here you can play with percentages.

  Hans-Günter

• How to hide/show the column in a table

  Hello world
  
  I have a table based on the table "Dept".

  Dept_id
  supervisor_name

  Dept_id is the LOV, and it has value (11, 12,...) (20),
  Here, when the Dept_id value is selected as 20, then the field "supervisor_name" must be posted, for the rest of the values, that it must be hidden.
  How this can be done using Jquery?
  Thank you.
  Concerning

  Look at this http://apex.oracle.com/pls/apex/f?p=46417:26

  Test/test connection

  JavaScript Code: Add in the page header > javascript

  function test(pThis) {
   //get the curren row index on change
   var currIndex = $('select[name="'+pThis.name+'"]').index($x(pThis.id));
   if (pThis.value=='20') {
    $('input[name="f01"]')[currIndex].style.display = 'block';
   }
   else {
    $('input[name="f01"]')[currIndex].style.display = 'none';
   }
  }
  

  In the element, add attributes column deptno

  onchange="javascript:test(this);"