How to store the difference between two timestamps as a number?

Similar Questions

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• How to tell the difference between two dates

  Hello:
  
  I have a question on how to get the difference in quantities for two dates in the replies and dashboard.
  
  This is the scenario. I have two guests date and three columns. The first column must be the sum of the amounts for the first quick date. The second column should be the sum of the amounts for the second fast date. And the third column is the difference between the first two columns.
  
  Basically, I'm trying to do something similar to a function of sum of two lines but trying to get the difference between the two rows. Any help to solve this problem would be appreciated.

  Use the COLUMN FILTERS level...

  the first column with the first variable of date quick presentation of the filter

  Similarly, the second column in the second variable of quick overview of date filter

  Kind regards
  Rambeau

• How to calculate the difference between two times by the NUMBERS

  I'm so bothered by the fact that I can't understand that.

  Cell B2 - 08:00

  Cell C2 - 10:50

  (How can cell D2 - I get this cell to calculate the difference and say 02:50?)

  I know it's probably one of the most basic operations, but for the life of me I can't understand it. The cells B2 and C2 are formatted for a 24-hour clock. But if I tell the system to just subtract the two, I get "0,118. Everything I find on the forum search goes beyond what I need. Can someone help me?

  Thank you

  Hi sapirs,

  Departure and arrival of the cells are in Date and time with Date format: no and time: 24-hour clock.

  

  Formula in D2 (fill down)

  = C2−B2

  

  The results become a duration format, but under automatic (numbers automatically worth this format)

  

  If you wish, you can change the cells of lasting results.

  What Data Format have your result cells?

  Kind regards

  Ian.

• Type of data resulting from the difference between two timestamps

  Hi, I have a simple question.
  I have two TIMESTAMP A and B variables. Now I want to subtract one B - A. What type of data as a result of this subtraction?
  Would Shouln t TIMESTAMP again?
  
  Consider this example:
  

  DECLARE
     vdat_Begin        TIMESTAMP;
     vdat_End          TIMESTAMP;
     vdat_Difference   TIMESTAMP;
  BEGIN
     vdat_Difference := vdat_End - vdat_Begin;   -- this doesn't work
     vdat_Difference := TO_TIMESTAMP(vdat_End - vdat_Begin);   -- this works
  END;
  /
  
  PLS-00382: expression is of wrong type

  Thanks for help.

  xxsawer wrote:
  Hi, I have a simple question.
  I have two TIMESTAMP A and B variables. Now I want to subtract one B - A. What type of data as a result of this subtraction?
  Would Shouln t TIMESTAMP again?

  Consider this example:

  DECLARE
  vdat_Begin        TIMESTAMP;
  vdat_End          TIMESTAMP;
  vdat_Difference   TIMESTAMP;
  BEGIN
  vdat_Difference := vdat_End - vdat_Begin;   -- this doesn't work
  vdat_Difference := TO_TIMESTAMP(vdat_End - vdat_Begin);   -- this works
  END;
  /
  
  PLS-00382: expression is of wrong type
  

  Thanks for help.

  No, as stated, there will be an interval.

• calculate the difference between two timestamps

  Hello
  I'm new in PL/SQL and have the following problem. In our application, there are events that insert records into a table with a parameter "processing_date" of type DATE (when they will be processed). For a new type of events, I have to plan the 'processing_date' at 18:00 on the day of insertion, if the event has happened until 18:00 and sysdate if event occurs after 18:00.
  In a pseudo-code that will be
  IF to_char(SYSDATE,'HH24:MI:SS') > 17:59 min 59 s ' THEN - the event took place after 18:00
  processind_date: = sysdate;
  Else - the event has happened until 18:00
  processing_date: = current_timestamp + ('timestamp at 18:00 ' - current_timestamp); -> processing_date: = today at 18:00
  END IF;
  
  I'll appreciate any help.
  
  Thank you.

  dariusgeo wrote:
  processing_date: = current_timestamp + ('timestamp at 18:00 ' - current_timestamp); -> processing_date: = today at 18:00

  For 18:00 of the current date, you can do:

   processing_date := TRUNC(SYSDATE)+18/24;
  

  TRUNC will be truncates the current date ' 00:00:00 '.
  Add 18/24 means add 18 hours (1 day / 24 * 18).

  Kind regards.
  Al

  Published by: Alberto Faenza 22 may 2013 22:07

• How to calculate the difference between two numbers in text fields

  Hello, I am fairly new to this, and I am certain that I will be bothered by the simple answer is

  I do a simple calculation... total of total assets - liabilities = net worth

  I have my total assets and my total work of the liability, but is not a subtraction option in the properties of a text field for the Net of a field value.

  I don't know... not any script Java can any who help out me?

  Thank you

  Judy

  You can use the option of simplified field notation, but first your input fields names must be changed so that they do not contain spaces or punctuation. For example:

  TotalAssets - TotalLiabilities

  If you want to use JavaScript, what will be needed if you ever in more complicated calculations, you can use something like the following as the custom fields (net value) calculation script:

  (function () {}

  Get the values of the field as numbers

  var v1 = + getField("total_assets").value;

  var v2 = + getField("total_liabilities").value;

  calculate the value of this field

  Event.Value = v1 - v2;

  })();

  There are no restrictions on domain names when using JavaScript.

• difference between two timestamps

  Hi gurus,

  I have a procedure which has 2 input parameters of type timestamp. I need to find the difference between these two stamps and be converted to a timestamp and return. Help, please

  Diifernce between two timestamps is interval. You can not convert the difference between two timestamp timestamp and it makes no sense. What you expect:

  25/06/2014 11:25:37.524000 - 13:07:22.987654 20/06/2014

  SY.

• How to tell the difference between recommended, and optional updates long after they have installed bene?

  I have a Vistaprogram of the window running on my Toshiba laptop.

  In the past, I've confirmed that optional udates be installed. Please help: now I want to uninstall optional updates because my computer is slow.  How to tell the difference between recommended, and optional updates long after they have installed bene?

  Hey monkey 44,

  I suggest you view the history in Windows Update:

  http://Windows.Microsoft.com/en-us/Windows-Vista/see-which-Windows-updates-are-installed

  Those listed as recommended is technically optional.

  Before you delete updates the computer, I suggest you try the steps from the following link to improve performance and check if that helps:

  http://Windows.Microsoft.com/en-us/Windows-Vista/ways-to-improve-your-computers-performance

  I hope this helps.

• How to find the difference between standard edition and standard edition one

  How to find the difference between oracle database standard edition and standard edition one 64 bit
  
  (a) using sql
  (b) using the configuration/installation files

  How to find the difference between oracle database standard edition and standard edition one 64 bit

  (a) using sql

  Select * the option of $ v;

  (b) using the configuration/installation files

  opatch lsinventory-details

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• How can I compare the differences between two files After Effects?

  I have a major problem.  I was working on special effects for a film.  In After Effects, when I change siggificant, I often have to register under and create a new name so I can go back to the old work if necessary.  It comes in a case, I have come back from earlier works.  If I use these two files After Effects allows you to create multiple clips of effects.  And I do not remember just where you look at it, it is better.  Does anyone know a good way to compare the differences between the files?

  One thing to keep this conversation on the right way: I know that I did a stupid thing.  I've never done this before so can we please not spend a lot of time on how to avoid this problem and stick to how we solve this problem?

  If you encounter difficulties to identify differences in the old and new versions, you can use this procedure:

  To avoid confusion, I'll call your former company and your most recent compositions CompB comps.

  CompA drag "New Comp" icon in the project window.  This will create a new temporary layout that contains the nested CompA.

  Drag in your new COMP CompB temporary ensure it aligns image for image with CompA.

  Place the top layer (CompB) difference.

  Now, when you play through the comp, you'll see differences in color at a time where the comparison and CompB are not identical.

• FormCalc - how to calculate the difference between the two fields datetime in hh: mm?

  Hello!

  I am building a form of time sheet in which I need to calculate the difference between the start and end times and present the result.

  I'm trying to do with FormCalc but if it is easier with JS is ok too.

  So that's what I did on the total field, by using the calculate on a NUMERIC field called decimalValue event:

  elapsed = Time2Num (endTime.formattedValue, "HH: mm")-Time2Num (startTime.formattedValue, "HH: mm")

  And then I tried to convert a time field:

  Total = decimalValue.rawValue;

  $.formattedValue = Num2Time (total, "HH: mm")

  Well, it doesn't work, it gives me crazy results in the datetime (total) field. If I type 09:00 and 09:30, the final result is... 22:30. Huh?

  Please, could someone help me understand how this thing works?

  Thanks a lot for the tips!

  Marcos

  Hi Marcos,

  Here are some examples:

  https://Acrobat.com/#d=kCPIgVkd09qrx6h-WRXxbQ

  https://Acrobat.com/#d=EsWqBMBt3sgEXnMSsK5pRA

  Hope that helps,

  Niall

• The most elegant way to get the difference between two tables - not least!

  Hello
  
  
  Simplified example of what I'm trying to achieve - I have two tables ORIGINAL and REVISED.
  
  
  My aim is to compare the two, such as; -
  
  
  When there is data in the two tables I get the difference between the Budget column, and if there is no difference, so I don't want no lines.
  
  When data exists in the ORIGINAL, but not in review, I want to the inverse of the current value of the Budget column.
  
  Where the data exist in REVISED I want the REVISED value.
  
  I can see how I can do this, see below, but is there a more elegant solution?
  
  
  
  
  Data for the ORIGINAL table
  

  select '801040' entity, '2186' expense_type, 234000 budget
  from dual
  union all
  select '801040' entity, '3001' expense_type, 1000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P135' expense_type, 43000 budget
  from dual

  Data for the REVISED table
  

  select '801040' entity, '2186' expense_type, 235000 budget
  from dual
  union all
  select '801040' entity, 'P132' expense_type, 34000 budget
  from dual
  union all
  select '801040' entity, 'P139' expense_type, 56000 budget
  from dual

  Desired output
  
  
  
  ENTITY EXPENSE_TYPE DIFFERENCE
  ------ ------------ ----------
  801040 2186 1000
  801040 3001-1000
  801040 P135-43000
  801040 P139 56000
  
  5 selected lines.
  
  
  
  Code current to achieve this, is there a better way?
  

  select original.entity
  ,      original.expense_type
  ,       (nvl(revised.budget,0) - original.budget) as difference
  from   original
  ,      revised
  where  original.entity = revised.entity(+)
  and    original.expense_type = revised.expense_type(+)
  and   (nvl(revised.budget,0) - original.budget) != 0
  union all
  select  revised.entity
  ,       revised.expense_type
  ,       revised.budget as difference
  from   revised
  where  not exists
  (select 'x'
  from   original
  where  original.entity = revised.entity
  and    original.expense_type = revised.expense_type)
  and    revised.budget != 0

  Thanks a lot for your comments,.
  
  
  Robert.
  
  Published by: Robert Angel on January 17, 2012 03:31 to change is not equal to! = - Thanks for the heads up

  SQL> with original
    2  as
    3  (
    4    select '801040' entity, '2186' expense_type, 234000 budget
    5    from dual
    6    union all
    7    select '801040' entity, '3001' expense_type, 1000 budget
    8    from dual
    9    union all
   10    select '801040' entity, 'P132' expense_type, 34000 budget
   11    from dual
   12    union all
   13    select '801040' entity, 'P135' expense_type, 43000 budget
   14    from dual
   15  )
   16  , revised
   17  as
   18  (
   19    select '801040' entity, '2186' expense_type, 235000 budget
   20    from dual
   21    union all
   22    select '801040' entity, 'P132' expense_type, 34000 budget
   23    from dual
   24    union all
   25    select '801040' entity, 'P139' expense_type, 56000 budget
   26    from dual
   27  )
   28  select *
   29    from (
   30          select nvl(o.entity, r.entity) entity,
   31                 nvl(o.expense_type, r.expense_type) expense_type,
   32                 nvl(r.budget,0) - nvl(o.budget,0) budget
   33            from original o
   34            full join revised r
   35              on o.entity = r.entity
   36             and o.expense_type = r.expense_type
   37         )
   38   where budget <> 0
   39  /
  
  ENTITY EXPE     BUDGET
  ------ ---- ----------
  801040 2186       1000
  801040 P135     -43000
  801040 3001      -1000
  801040 P139      56000
  
  SQL>