If string with length length change

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• escape character must be the string of length 1 (error ORA-01425)

  Hi all!
  
  I get this error message (SQL error: ORA-01425: escape character must be the string of length 1) when querying an oracle 9i database with:
  
  SELECT * FROM table WHERE column LIKE '%' ESCAPE ' \';
  
  Bar which makes it a double backslash (included with apostrophes) would solve the problem, however, with this change, the request is more executable in a 10g database.
  
  Is there a way to make the executable SQL above (with a single backslash escape) code in both (and latest) versions, without changing it? Maybe a server definition database that could solve this problem...
  
  Suggestions for the problem described are greatly appreciated!
  
  Thank you

  col2 NVARCHAR2 (100)

  OK, you should have mentioned before using unicode ;)

  However, should not always identical fields be treated identically in any database?...

  Yes, they should :(

  In any case the escape string should obviously be treated as unicode so the right way, I guess, would be

    select * from mytable where col2 like N'%' escape N'\'; 
  

  Note the front N ' \' to make the unicode string.

• Search strings / with some applied condition

  Hello comrades,.

  I am writing an extendscript which is supposed to loop through all of the PGF and find all the strings / with a certain condition applied (say, comment).

  The problem is that in the script guide, I couldn't find a function that retrieves the status of character property. I tried to use the function "charAt() (i)" js, but it doesn't seem to work in ARE. No idea how to implement such a function?

  Here's the 1st draft of the script.

  var doc is app. ActiveDoc;

  If doc. {ObjectValid()}

  checkCondFMt (doc);

  }

  else {}

  Alert ("no open section");

  }

  function checkCondFMt (doc) {}

  FMP var is doc. MainFlowInDoc.FirstTextFrameInFlow.FirstPgf;

  var CondObj is doc. GetNamedObject ("Comment");

  While (FMP. {ObjectValid()})

  var textItems is bmp. GetText(Constants.FTI_String |) Constants.FTI_LineEnd);

  var b = new TextRange();

  TR. Beg.obj = tr.end.obj = textItems;

  TR. Beg.offset = 0;

  for (var i = 0; i < tr.len; i ++) {}

  var c = tr.charAt (i);

  var PgfProps is doc. GetTextVal c [i], Constants.FO_CondFmt;

  Alert (PgfProps.Name);

  }

  PGF = bmp. NextPgfInFlow;

  }

  }

  Thanks in advance for your comments!

  OK, I see the problem now. JavaScript doesn't have a "block scope" for its variables. She carried the function, so your 'i' variable is used in more than a loop. You must use a different variable for the inner loop:

  for (var j = 0; j < oCond.length; j += 1) {
      if (oCond[j].Name == CondObj.Name) {
          applyCharFmt(textRange, doc);
      }
  }
  

  In the code example above, I use 'j' for a counter for the inner loop.

  In general, you can avoid problems of this kind to declare all your variables at the top of the function:

  function functionName (param1, param2) {
  
      var i, j, textlist; // etc.
  
      // function code...
  }
  

  That makes it easier to 'follow' variables and make sure that you do not use one more than once.

  -Rick

• Split string with regular model and expression(10g)

  Hello world
  
  Could I ask you, your opinion on this query (tuning)?
  
  
  SQL * more: version 10.1.0.4.2 - Production on Tue October 21 10:40:07 2008
  
  Copyright (c) 1982, 2005, Oracle. All rights reserved.
  
  
  Connected to:
  Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - 64 bit Production
  With partitioning, OLAP and Data Mining options
  
  
  SQL > select * from test_1;
  
  NR X
  ---------- -----------------------------------------------------------------------------------------
  1 F01
  2 F02
  3 D01:D02
  4 F03:G45:D34
  5 G56:Y45:U89:E56
  
  
  SQL > SELECT NR, STRING
  2 FROM TEST_1
  MODEL 3
  4 RETURN THE UPDATED LINES
  5 PARTITION BY (NR)
  6 DIMENSION (POSITION 0)
  MEASURES 7 (CAST (' ' AS VARCHAR2 (50)) AS STRING, X, LENGTH (REGEXP_REPLACE (X,'[^:] + ",")) + 1 NB_MOT)
  8 RULES
  9 (STRING [FOR POSITION 1 TO INCREMENT 1 NVL(NB_MOT[0],1)] =
  10 CASES WHERE NB_MOT [0] IS NULL THEN X [0] ELSE REGEXP_SUBSTR (X [0], "[^:] +', 1, CV (POSITION)") END)
  11 ORDER BY 1;
  
  STRING OF NR
  ---------- --------------------------------------------------
  1 F01
  2 F02
  3 D01
  3 D02
  4 G45
  4 F03
  4 D34
  5 G56
  5 Y45
  U89 5
  5 E56
  
  11 row (s) selected (s).
  
  
  Execution plan
  ----------------------------------------------------------
  0 SELECT STATEMENT Optimizer = ALL_ROWS (cost = 5 card = 5 bytes = 325
  )
  
  1 0 SORTING (ORDER BY) (cost = 5 card = 5 bytes = 325)
  2 1 MODEL (ORDERED) SQL (cost = 5 card = 5 bytes = 325)
  3 2 TABLE ACCESS (FULL) 'TEST_1' (TABLE) (cost = 4 = 5 bytes map = 325)
  
  
  
  Kind regards
  Salim.

  Why?

  How long takes now?

  Can you explain?

  Kind regards.

  LOULOU.

• How to convert the string with numbers in U8 with ascii

  Hello

  I have a string with only numbers 0. 9 paper.

  Now, I want to convert to table-U8.

  He works here, but now the problem: How can I change each character to its ascii value?

  Example:

  entry: 123 (string)

  output: x 31, x 32, x 33 (U8-array)

  Thanks for the help

  It's very easy

  String to Byte Array Function
  Have the Palette: string/array/path Conversion functions

  Converts a string to an array of unsigned bytes. Each byte in the array has the ASCII value of the character corresponding to the string.

• How to convert the string with numbers in the table of Boolean 2D

  Hello

  I have input a string with comma separated numbers 1,192 (starting at 1).

  This string must be converted to a table 2D-boolean. Each number that appears should be true, not true rest.

  The 2D table consists of 4 times of 0.47 Boolean values.

  1.48--> [0.47] numbers [0]
  49.96--> [0.47] numbers [1]
  Numbers 97.144--> [0.47] [2]
  145.192--> [0.47] numbers [3]

  If a '1, 49, 97 145' input string put all [0] [0.3] true.

  How can it be easy/fast resolved?

  Thanks for help

  Break the string of numbers in a table of numbers.  (Spreasheet String to Array).

  In a loop For, index with each issue of this table.  Use in the range and Coerce to see if it is in the range of numbers.  (You can put this in a loop For as auto good indexing through the ranges).  If it's in the range, then use subset replace table to activate the corresponding item in a real.  If this is not the case, do nothing.  Maintain the table of Boolean in a shift register.

  Repeat this step for each number in your table.

  (What is a class assignment?)

• Number of strings with decimal

  Hello community,

  I would like to convert numbers to the string with decimal separators. So if the number is 52351 then the string I need is 52 351

  Another example 18653284.9653235 becomes 18,653,284.9653235

  What would be the best way to do it?

  Thank you!

  Read this thread: https://forums.ni.com/t5/LabVIEW/comma-separator-for-large-numbers-how-to/m-p/2123090/highlight/true...

  Not the first person to wish for this idea.

• How to concatenate the string with a digital command?

  Hello

  How to concatenate the string with a digital command?

  Thank you.

  

  I think I forgot to add the semicolon, what you can do is, drag the CONCATENATE function and add semicolon.

• How the filter string with don't cares...?

  Hello

  I need help on getting filter string with cares. Attached is a VI for ref.

  If anyone has chain, analysis of expertise; I need your help.

  Thank you

  SB_LV

  Another fun one

• Initialization of a string with a UTF-8 character

  It doesn't seem like it should be that hard, but I am trying to initialize a string with a UTF-8 character (specifically a degree after a few numbers symbol).

  I tried:

  Dim myString As String = new String ("\uc2b0", "UTF - 8");

  as well as a few permutations but did not have luck...

  Java strings are in Unicode, UTF - 8 is a way to represent these characters in a stream of bytes.

  Take a look at the following code, it might be useful: I suggest to put point break in the line add and take a look at the content of the two strings.

  No compiled code, could not work, I hope you get the idea...

  Char [] testchars = new char [] {'\u00B0', '\u0020'};
  String displayString = "undefined";
  Byte [] testBytes = new byte [] {(byte) (byte), 0xC2 0xB0, 0x20};
  String displayString2 = "no set2";
  try {}
  displayString = new String (testchars);
  displayString2 = new String(testBytes,"UTF-8");
  } catch (Exception e) {}
  }
  BasicEditField bef = new BasicEditField ("Test2:", displayString + ":" + displayString2);
  This.Add (BEF);

• How to concatenate strings with the lines of a text file

  Hello
  I tried concatenate strings with the lines of a text file, but something is wrong with my code and I belive is the agruments I use in the cycle for. If anyone can help me I will appreciate it very much.
  My code is:
  [code]@echo off
  the value "input=C:\Users\123\Desktop\List.txt".
  for /f "usebackq tokens = *" % in (' input % ') do)
  the value 'str1 = C:\some directory\ ".
  the value ' str2 = %% ~ F '.
  the value "str3 = .pdf".
  the value "str4 = str1% str2% str3%.
  echo.%STR4%
  ) [/ code]
  and the text file is something like:
  121122 [code]
  122233
  123344
  124455 [/ code]
  But I get only one wrong answer and I have to run it like 3 times to get a real result and it is a mistake, the first two are empty spaces and gives the third one as the last line of the text file but repeated n times, where n is the number of lines in the text file.
  Result:
  [code] C:\Users\123\Desktop>concatenate.bat
  C:\Users\123\Desktop>concatenate.bat
  C:\Users\123\Desktop>concatenate.bat
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\some directory\124455.pdf
  C:\Users\123\Desktop>[/code]
  So if anyone has an idea about what is wrong please let me know.
  Concerning
  -Victor-

  Hi Victor,

  This forum is dedicated to the support of the Office of consumer Windows (fonts, colors, personal settings).  Since your question is about programming and usually outside the context of most of the customers, I suggest you post your question in the forums as http://msdn.microsoft.com - the Microsoft network to users will be more adapted to help you in your quest.

• How to capture the data of type string with agent script and then compared to an alarm

  Hello...

  How to capture the string with agent of script data and then create a rule to compare the string data to generate alarm?

  Thank you!...

  Start here:

  http://en.community.Dell.com/TechCenter/performance-monitoring/Foglight-administrators/w/Admins-wiki/6155.custom-script-agent-1-leverage-an-existing-monitoring-script-to-push-data-into-Foglight

• dbms_random string with restrictions

  Hello. I want to generate a random string with certain restrictions. I need return numbers between 0-9 and letters from A - F. For those of you asking why the specific request, I need to create a string that is compatible with the unique identifier of the SQL SERVER. Jacky ideas how to add restrictions in the following lines.
  

  SELECT dbms_random.string('X', 32) AS Random_String
             INTO v_rand_string
             FROM dual;

  You have to use DBMS_RANDOM (which will inevitably generate duplicates)? If you try to be compatible with the unique identifier for SQL Server, why not use SYS_GUID, which is

  SELECT sys_guid()
    FROM dual
  

  Justin

• Solution to have keyframes to ripple with length of shooting.

  If someone has a quick solution for this, it would be greatly appreciated...

  I have a clip in my calendar which is 2 seconds long, and I have this clip from 50 on the scale of 100% for the duration of the shooting.

  Now, I want to make this clip only 1 second long, but keep scale from 50 to 100% for the duration of the clip.

  Is there a setting key frames ripple with the length of the clip? I'm scratching my head trying to find a solution. now I have to manually move the keyframes to adjust the length of the fastener.

  You can also embed the clip on the timeline (right click on the selected clip, choose the nest in the menu drop-down) and then change the duration of this nest. Keyframes move accordingly.

  If you need to change the contents of the nest, double-click it.

  MtD

• Array.length changes not really after the item deleted?

  Frame 1, I loaded 9 clips (pieces of a chart) and their names of the instance (piece1, exhibit2 etc.) are in a table, arrPieces.   In 3, I'm trying to remove them, but I discovered that I had a problem with my while loop.   I removed the loop and discovered that the problem is really that the size of the array does not reduce after that I deleted an item.   I could not find it in the documentation.  Is this true?  I do not suspect.

  That's what I've stripped the code in frame 3 down for:

  trace (arrPieces.Length);     9 as planned
  var whichPiece = Math.floor (Math.random () * 9) + 1;
  arrPieces.splice(whichPiece,1);
  trace (whichPiece);   as expected
  trace (arrPieces);   as expected
  trace (arrPieces.Length);   still gives 9 - should not
  Stop();

  Something obvious, I suppose, but I can't.   Help appreciated.

  Marion

  I don't know what you've changed things in, but you can still get the random index duplicate values, though that if you are splicing to the table, then it should not matter.

  I don't know what else is going on in your code, or if you really need to remove the elements in the array, but you might consider randomizing just the array and then read through it, from 0 to 8.