lag function, part two

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  Hi all

  I want to understand the inner workings of the Lag function in Oracle, which could help to solve my problem.

  I have the table as the structure below.

  P_ID	ENTRY_TIMESTAMP	SIZE	C_ID
  15287	1 NOVEMBER 15 05.45.00 PM	30	92
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• LAG function alternative queries

  Dear all,

  WITH t AS

  (SELECT 1 AS num, "test1" AS status

  OF THE DOUBLE

  UNION ALL

  SELECT 2 AS num, "test2" LIKE status

  OF THE DOUBLE

  UNION ALL

  SELECT 3 AS num, "test3" LIKE status

  OF THE DOUBLE

  UNION ALL

  SELECT the 4 ACEs num, "test4" LIKE status

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  T

  Please help me to write search above without LAG function like oracle forms10g unsupported feature LAG.

  Hello, you can join the table itself for the results. This will work only if you have a number in ascending order.

  WITH t AS

  (SELECT 1 AS num, "test1" AS status

  OF THE DOUBLE

  UNION ALL

  SELECT 2 AS num, "test2" LIKE status

  OF THE DOUBLE

  UNION ALL

  SELECT 3 AS num, "test3" LIKE status

  OF THE DOUBLE

  UNION ALL

  SELECT the 4 ACEs num, "test4" LIKE status

  OF THE DOUBLE

  UNION ALL

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  THE DOUBLE)

  T1.status, t2.status SELECT previous_status

  T t1, t t2

  where t2.num (+) = t1.num - 1

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  Best regards, Andrei

• Lag function

  Oracle version: 11.0.2.0.2.0

  Dear all

  I have a question where I am using tables Tab1 and Tab2

  Struncture of tab1 is

  Store_no NUMBER,

  Sell_date DATE

  Sell quantity number,

  number of item_no

  to tab2

  Number of Item_no

  date date1,

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  I need know the total price of the article sold for 2 days (current as previous)

  Select the store, sell_date, item_no, sell_qty * item_price, lag (sell_qty * item_price, 1) on the partition by (store_no, item_no order of sell_date)

  of tab1, tab2

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  and sell_date = date1

  Question1) tables have millions of lines... The lag function is causing the query to run for hours...

  Could you please suggest if we capture these sorts of queries where Lag/lead are used.

  Your query does not much sense. Analytical functions are applied to already recovered lines, and since you have sell_date = date1, all you get is one day sales. All you need is:

  Select the store

  Max (sell_date),

  tab1.item_no,

  sum (case sell_date when date1 then sell_qty * end item_price) day_sales_amount,.

  sum (case sell_date when date1 - sell_qty then 1 * item_price end) prev_day_sales_amount

  of tab1.

  tab2

  where tab1.item_no = tab2.item_no

  and sell_date in the fields (date1, date1 - 1).

  Store group,

  tab1.item_no;

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• LAG function to get the value of the measurement for parent

  Hello
  
  I'm interested if there is no function in OLAP DML, which is similar to the function of TROLLING. LAG function returns the measured value for the previous dimension member (or a few members of the back dimension). I would like to know if this function exists which does not return a meaningless measurement for the dimension member value, but the measured value for the parent of the live dimension member.
  
  Thanks in advance
  
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  _parentrel relationship identifies the parent of each Member of the dimension of a hierarchy.

  use:
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  You can search the user's Guide the OLAP DML for many examples of the use of the OLAP DML commands/functions/objects in expressions.
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• Questions of DST, part two

  Oracle 11.20.1.0 SE - One
  Oracle Linux 5.6 x 86-64
  
  Cut to the Chase. Most of our tasks in the Scheduler is set so that start_date, last_start_date, and next_run_date all specify them the zone with a fixed offset. As a result, the first execution after the time change DST, they ran an hour initially, but then calculation for the next execution corrected and they found running at the scheduled time.
  
  Finally, almost.
  
  We have two application schemas that have Task Scheduler.
  
  Jobs in a schema is featured as above.
  
  But all the work of the other schema to continue to run an hour earlier.
  
  the above can be seen in the result of this query:

  select
       instance_name
  ,     systimestamp
  from
       v$instance;
  --
  select 
       owner
  ,     job_name
  ,     log_date
  ,     status
  from
       dba_scheduler_job_log
  here   log_date > sysdate - 10
    and   owner not in ('EXFSYS',
                        'ORACLE_OCM',
                        'PERFSTAT',
                        'SYS'
                        )
  order by
       owner
  ,     job_name
  ,     log_date
  ;

  Very easy to simply go to the bottom of the column LOG_DATE and see time to change.
  
  For my first two questions is - can someone explain the behavior above, in particular the inconsistency in a single schema 'cure' jobs themselves after the first run after the time change, but another schema employment continuing to run an hour earlier.
  
  I don't know if she's wearing on her or not, but most of the jobs (two patterns) is provided with a local function to "frequency" that uses a decimal representation of the time (ie: WEEKLY(.4583,'SATURDAY'))
  
  
  And a second question - what are the things that affect the representation of time zone in the start_date when defining a new job? Our programmer creates / manages jobs using SQL Navigator, and there is no provision in the GUI it to specify a specific time zone or (offset vs name) method to represent a time zone. I read that there are some influences on the client side, but have not restored that right away.

  Try

  SELECT CAST (SYSDATE AS TIMESTAMP WITH TIME ZONE) FROM dual;
  

  you will see the time zone.

  Or a more detailed example

  ALTER SESSION SET TIME_ZONE='Europe/Prague';
  SELECT dbms_scheduler.stime, sysdate, systimestamp, current_timestamp,CAST (SYSDATE AS TIMESTAMP WITH TIME ZONE), CAST (to_date('1.1.2012','dd.mm.yyyy') AS TIMESTAMP WITH TIME ZONE) FROM dual;
  
  ALTER SESSION SET time_zone='Asia/Bangkok';
  SELECT dbms_scheduler.stime, sysdate, systimestamp, current_timestamp,CAST (SYSDATE AS TIMESTAMP WITH TIME ZONE), CAST (to_date('1.1.2012','dd.mm.yyyy') AS TIMESTAMP WITH TIME ZONE) FROM dual;
  
  ALTER SESSION SET time_zone='-6:00';
  SELECT dbms_scheduler.stime, sysdate, systimestamp, current_timestamp,CAST (SYSDATE AS TIMESTAMP WITH TIME ZONE), CAST (to_date('1.1.2012','dd.mm.yyyy') AS TIMESTAMP WITH TIME ZONE) FROM dual;
  

  You can see that DATE to TIMESTAMP WITH TIME ZONE conversion session TIME_ZONE.

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  1 January 2010 0815' - '01-jan-2010 1715' and I need to calculate the time between two dates
  
  How can I create a procedure
  
  Thanks I advance
  
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• get my head wrapped around the LAG function

  Oracle 11.2.0.4 Std Ed

  drop table change_hist;

  create table change_hist (file_name varchar2 (30),)

  date of sample_date,

  number of blocks

  );

  insert into change_hist values (to_date('2015-07-01','yyyy-mm-dd'), 'file1', 5);

  insert into change_hist values (to_date('2015-07-02','yyyy-mm-dd'), 'file1', 5);

  insert into change_hist values (to_date('2015-07-03','yyyy-mm-dd'), 'file1', 6);

  insert into change_hist values (to_date('2015-07-04','yyyy-mm-dd'), 'file1', 6);

  insert into change_hist values (to_date('2015-07-05','yyyy-mm-dd'), 'file1', 6);

  insert into change_hist values (to_date('2015-07-01','yyyy-mm-dd'), 'file2', 5);

  insert into change_hist values (to_date('2015-07-02','yyyy-mm-dd'), 'file2', 5);

  insert into change_hist values (to_date('2015-07-03','yyyy-mm-dd'), 'file2', 5);

  insert into change_hist values (to_date('2015-07-04','yyyy-mm-dd'), 'file2', 5);

  insert into change_hist values (to_date('2015-07-05','yyyy-mm-dd'), 'file2', 5);

  insert into change_hist values ('file3', to_date('2015-07-01','yyyy-mm-dd'), 5);

  insert into change_hist values ('file3', to_date('2015-07-02','yyyy-mm-dd'), 6);

  insert into change_hist values ('file3', to_date('2015-07-03','yyyy-mm-dd'), 6);

  insert into change_hist values ('file3', to_date('2015-07-04','yyyy-mm-dd'), 6);

  insert into change_hist values ('file3', to_date('2015-07-05','yyyy-mm-dd'), 6);

  Desired result

  file_name sample_date prev_value curr_value

  File1 2015-07-03 5 6

  File2 2015-07-02 5 6

  My first attempt...

  SQL > select file_name,.

  2 sample_date,

  3 lag (blocks, 1) (order sample_date) as prev_blocks

  4 change_hist;

  FILE_NAME SAMPLE_DA PREV_BLOCKS

  ------------------------------ --------- -----------

  July 1, 15 file1

  July 1, 15 5 file3

  July 1, 15 5 File2

  File2 2 July 15 5

  File1 2 July 15 5

  file3 2 July 15 5

  File1 July 3, 15 6

  File2 July 3, 15 6

  file3 July 3, 15 5

  File1 4 July 15 6

  file3 4 July 15 6

  FILE_NAME SAMPLE_DA PREV_BLOCKS

  ------------------------------ --------- -----------

  File2 4 July 15 6

  File2 July 5 15 5

  File1 July 5 15 5

  file3 5 July 15 6

  15 selected lines.

  SQL >

  SQL > spo off

    1  select * from (select file_name, sample_date, lag(blocks) over (partition by file_name order by sample_date) prev,
  blocks
    2  from change_hist)
    3* where prev != blocks
  SQL> /                                                                                                             
  
  FILE_NAME                      SAMPLE_DA      PREV    BLOCKS
  ------------------------------ --------- ---------- ----------
  file1                          03-JUL-15          5          6
  file3                          02-JUL-15          5          6                                                    
  

  You know... you need to partition the file name

  Edit: in the interest of beat some people with a force equal regardless of their status, you didn't really know we tell how to achieve these results, so I could refer to the FAQ on how to ask a question