Medium-sized random numbers

Similar Questions

• Random numbers appearing in messages

  I am running Firefox 4.0.1 on 64-bit Windows 7 and every time that I post on a forum or send a Gmail account, it adds random numbers at the end of my entry. I tried using Chrome and it doesn't do this, what's the problem?

  You paste content or add a signature?

  Start Firefox in Firefox to solve the issues in Safe Mode to check if one of the extensions of the origin of the problem (switch to the DEFAULT theme: Firefox (Tools) > Add-ons > appearance/themes).

  • Makes no changes on the start safe mode window.
  • https://support.Mozilla.com/kb/safe+mode
  • https://support.Mozilla.com/kb/troubleshooting+extensions+and+themes

• The value of the seed of the generator of random numbers in Matlab node

  Hi all

  I need to use random variables inside a Matlab Labview Commsuite node. I generate with the randn() function. Is it possible to put the seed of the random number generator such as the random numbers are reproducible?

  Hi Steve,.

  You can use randn ('seed', seeds) to initialize the random number generator. The seed must be a positive integer value. For example, randn ('seed', 3). In addition, this seed is global within the entire application. This means that if the randn() function is called MathScript multi-node that could run in parallel, random results are not guaranteed to be the same after you change any part of your code. But you should always get the same results for repeated passages of the same code.

• How to generate random numbers from 1 to 5

  How to generate random numbers from 1 to 5

  -1110340081

  Thank you I ended up

• How the random numbers will be generated

  The "dice" in LabVIEW function is ised to generate random numbers between 0 and 1. If I create a [100000] array with random numbers between 0 and 100, the appearance of 1 to 100 is the same (about 1000 times each), but the appearance of the 0 is only 500.

  So my question is, on the basis of which will be generated random numbers?

  Mitu salvation,

  It is not a problem of the RNG, it's a problem of your function rounded!

  "To U8" allows you to convert the entire random DBL. ToU8 rounds up to the next integer. So all the number of 0-0.5 will get rounded to 0, but all the numbers from 0.5 to 1.5 will get rounded to 1. If you have twice the range of a number rounded to 1 at the beach of rounding to zero - the same goes for your "end of range" with rounding to 100. 100 should be also less likelihood (in your VI) to appear...

  To get the same probability, you should (explicitly) roundpupils before converting in U8!

  BTW. You can also search the forum to get the same answer by searching for "random"...

• I'm trying to generate a table of random numbers 30. After each 5 readings a new vi must open and indicate to the user than 5 readings were made. and continue with the generation of the table again.

  because I don't have a sensor now, I am currently generating a table of random numbers 30. After each 5 readings a warning should be given to the user 5 readngs are completed. This cycle must be repeated. the size of the table is 30.

  Please help me, waiting for response as soon as possible.

  Once I have the transducer, I'll take 30 analog samples and then after each 5 smaples this wraning will be displayed din a new VI

  Use a while loop with a delay time representing your sampling interval.

  Use is equal to the count Terminal to see if 4, then 4th iteration = 5th sample.

  Use a box structure. The real deal will only run on the 4th iteration.

  In the case of true place a Subvi with your message of your choice in the front panel. Go to the properties of the VI window and set ' open the front panel when it is called.

  The condition to closing of attention is not given to your description.

  Consider that rather than usign a Subvi to do this, you can use the "dialog box one/two/three button" or "display message" live in the palette "user interface and dialogue."

  Please try it out and send your own VI. Do not provide us with a working solution.

  Kind regards

• Division of random numbers, see if the result is an integer.

  Simple and yet impossible to find an easy way around it.

  I have 2 RANDOM numbers, I'm dividing them, and I want to see if the result is an integer or not. Basically, I need to know if the divison of random numbers 2 is an integer.

  Who wants KUDOS?

  /SPAW

  Use Quotient and remains, check if the remainder is 0.

• How LabVIEW can generate random numbers according to any pdf or histogram?

  I would like to know if there is a VI that generates a set of random numbers according to any probability density, the probability mass function or the graph histogram (this without explicitly knowing the function).

  Thank you.

  Acoustic wrote:

  I would like to know if there is a VI that generates a set of random numbers according to any probability density, the probability mass function or the graph histogram (this without explicitly knowing the function).

  If you have a given arbitrary distribution, you can simulate random data of thesholding mapping in the integral standard service with a simple random number 0... 1.

  This old post of mine should show you the General procedure and more details. (Is there even an former example). Of course, make sure that the desired function is all positive, of course.

  

  

• How can I generate multiple unique random numbers?

  Hello

  I am trying to generate multiple random numbers between a given set of numbers (1-52) and do not have the same number generated twice within this group. I can compare the numbers of last and next with the function to compare, but how would I go about comparison of all numbers generated without using a huge list of shift registers...

  Any help/ideas are welcome and appreciated.

  Jason

  Solved my problem. IM passing the random number through a registry to offset to each case and build a table every time. I then searches the table for the new random number. If the number is not found I get a value of-1, another thing is an index value of 0-everything. If a comparator greater than (-1) indicates that the same number is in the table and then I can raise this matter until the same number is not found.

  Kind regards

  Jason

• I want just a bunch of random numbers (about 120 of them) from the list, select 'all' and get the computer to rearrange in CNC

  I try both notepad and wordpad. I'm in Winows XP 2003.  I want just a bunch of random numbers (about 120 of them) from the list, select "all" and reorganize in order digital computer. I can't understand how I've done it before. Google says select the balls feature, but all that is put a point in front of a certain number. There is no arrow down to select. No A - Z. No 1,2,3. what Miss me? is the Notepad or wordpad not the place to do that?

  Use Excel.

• 3 random numbers anyway

  Hey guys, thanks for the help so far. My most recent problem is that I'm doing the 3 different random numbers between 1-5. But when I tested it keep everything 3 seems to be the same number (1,1,1 or 2,2,2 etc.) please look at my code and help me if you can, thanks guys (or girls)!

  It's just the excerpt from the class:

  ' Public Sub fieldChanged (field field, int context)
  {
  {if(Field==buyin1)}
         
         
  Gen1 random = new Random (System.currentTimeMillis ());
         
         
         
  for (int i = 0; i)< 50;="" i++="" )="">
  lotto1 = gen1.nextInt (5) + 1;
  }
  If (lotto1 == first) {}
  gains = 1;
  }
  Gen2 random = new Random (System.currentTimeMillis ());
  for (int i = 0; i)< 50;="" i++="" )="">
  lotto2 = gen2.nextInt (5) + 1;
  }
  {if(lotto2==second)}
  {if(winnings==1)}
  earnings = 2;
  }
  else {}
  gains = 1;
  }
  }
  Gen3 random = new Random (System.currentTimeMillis ());
  for (int i = 0; i)< 50;="" i++="" )="">
  lotto3 = gen3.nextInt (5) + 1;
  }
  {if(lotto3==Third)}
  {if(winnings==1)}
  earnings = 2;
  }
  else {if(winnings==2)
  gains = 3;
  }
  else {}
  gains = 1;
  }
  }
  }

  Hello

  You can use only a single object Ramdom (gen) instead of three objects (gen1, gen2, gen3). Perhaps remove loops as well. Following code will work for you:

  import java.util.Random;
  ......
  Random gen = new Random(System.currentTimeMillis());
          int lotto1 = gen.nextInt(5) + 1;
          int lotto2 = gen.nextInt(5) + 1;
          int lotto3 = gen.nextInt(5) + 1;
  

• Random numbers, not so much to chance

  I use a simple piece of code I found online to create a random number between two numbers

  new Random().nextInt(6-1)+1);
  

  I am trying to create random numbers for dice.

  Everything seems to work fine, but the numbers are not that random. I have a loop configuration to display the code above 50 times and it will make a loop over and over again the same number. Here is an example of the results

  1,1,1,1,1,1,4,4,4,4,2,2,2,2,2,1,1,1,1,1

  Therefore, it is quite difficult to create a type of yahtzee game when you always roll a yahtzee on the first roll lol.

  Is there something I'm missing here?

  I agree that the Random function generates only numbers random nickname and there are interesting ways of the algorithm of seeds, I believe that in this case, the problem is that Random is not used correctly.  I think that random is intended to be used as shown in the following fragment.  I also think that random is perfectly satisfactory for use in this case, so I would not personally recommend looking for another algorithm.

  Random myGenerator = new Random(System.currentTimeMillis());
  String thrown = ""; // Yes, this should be a StringBuffer....
  for ( int i = 0; i < 50; i++ ) {
      thrown = thrown + Integer.toString(myGenerator.nextInt(6)+1) + ", ";
  }
  System.out.println("Thrown: " + thrown);
  

  Here is the result of a few tracks:

  Lift: 5, 6, 2, 3, 1, 5, 3, 5, 4, 1, 5, 6, 3, 3, 6, 6, 5, 5, 3, 5, 1, 6, 6, 2, 1, 5, 5, 1, 6, 5, 5, 2, 5, 3, 6, 6, 5, 3, 5, 1, 2, 5, 1, 6, 2, 3, 1, 3, 2, 6,
  Lift: 4, 1, 4, 1, 5, 3, 5, 3, 2, 4, 3, 2, 5, 3, 4, 4, 3, 4, 2, 3, 2, 3, 1, 2, 2, 4, 5, 1, 5, 6, 2, 6, 6, 1, 1, 4, 5, 3, 4, 5, 6, 6, 6, 5, 6, 6, 2, 4, 5, 4,

  Edit: updated to fix the sample code fragment andgive output.

• random numbers that appear as you type

  I started to get random numbers, mainly of the 5 and 6 s, appearing during the seizure... anyone have ideas what is the cause and remedy > dave

  There might be problem with your keyboard, if it is the desktop PC, use another keyboard and see if you face the same issue or not.

  Also, in some portable, they have ability to enable some of the alphabet to numberic when you enable specific key, check and see if this feature is enabled.

• 6 random numbers without repetition

  I'm doing a generator of 6 random numbers between 1 and 48. When the user clicks a button randomly 6 numbers appear in 6 different textFeilds. The problem is that I don't want the same number twice. How can I generate 6 different random numbers without using back and out of the service?

  import flash.events.Event;

  Stop();

  btn.addEventListener (MouseEvent.CLICK, random1);

  function random1 {(evt:Event)}

  display1. Text = "";

  Display2.text = "";

  Display3.text = "";

  display4. Text = "";

  display5. Text = "";

  display6. Text = "";

  var r1 = Math.floor (Math.random () *(1+48-1)) + 1;

  var r2 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A3 = Math.floor (Math.random () *(1+48-1)) + 1;

  var r4 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A5 = Math.floor (Math.random () *(1+48-1)) + 1;

  var A6 = Math.floor (Math.random () *(1+48-1)) + 1;

  If (r2 = r1 | r3 == r2 | r4 == r3 | r5 == r4 | r6 = r5) {}

  return;

  }

  var list: Array = new Array();

  Liste.push (R1, R2, R3, R4, R5, R6);

  Liste.sort (Array.Numeric);

  display1. Text = String (list [0]);

  Display2.Text = String (list [1]);

  Display3.Text = String (list [2]);

  display4. Text = String (list [3]);

  display5. Text = String (list [4]);

  display6. Text = String (list [5]);

  }

  Here is the code for the approach mentioned with your included textfields

  btn.addEventListener (MouseEvent.CLICK, random1);

  function random1 {(evt:Event)}

  var nums:Array = new Array();

  Complete the table of numbers

  for (var i: uint = 1; i<=48;>
  Nums.push (i);
  }

  Shuffle (NUMS);

  Take the first six of the mixed table

  var list: Array = nums.splice (0.6);

  assign values to the textfields

  for (var j: uint = 1; j<=6;>
  This ["Display" + String (j)] .text = String (list [j]);
  }
  }

  function shuffle(a:Array) {}
  var p:int;
  var t: *;
  var ivar:int;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

• random numbers in a textfield?

  Hi all thx for reading and I hope you can help

  I create a game for children, which shows them how to tell the time

  I need to put two random numbers in a textfield one for hours and one for the minutes

  so that I can get the app to say show me 13:45, for example

  However, I don't want to include the time of 12:00, because that's where the clock will start and defeated the purpose

  the clock is 24 hours, from 1 to 24 hours

  00-60 minutes

  Ive looked everywhere on how to do it but could not find an answer

  at the moment I have a textfield that displays the time as the user adds hours etc that I intend to hide

  while I can tell if this textfield random number is equal to the textfield time then correct display and so on

  How could I go about this?

  any help is appreciated

  Thank you

  fonzio

  Then just replace 0 with 24

  return (hour == 0 ? 24 : hour) + ":" + (minute < 10 ? "0" : "") + minute;
  

  --

  Kenneth Kawamoto

  http://www.materiaprima.co.UK/