Need a little help with a photo effect, examples on the inside.

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  Backblaze in particular, but it would be for any backup or future software I guess.

  Tags are stored in the file in your catalog. If you want to have them available after a disk crash, you should make regular, automated backups of your catalog on a different physical disk files. You can enable this in Lightroom via settings-> General-> Backup catalog. Note: you should always take backups of your photos, this feature in Lightroom doesn't have backups of your photos.

  If at some point you consider moving away from Lightroom, you can also write tags to the photos themselves (or in the case of RAW for the XMP sidecar files). This can be done by selecting all the photos and metadata-> saves the metadata of files (Note: this will take a lot of time if you have selected a large number of photos). You can also turn on the option to automatically catalog settings-->--> write metadata changes automatically to XMP. Any tags written via this method is readable by any other photo app that I know.

• So I need a little help with the Flash colors

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• Need a little help with AE

  Hi all, I'm having a small problem with After Effects. I'm a Design student computer games of second year and I'm trying to wrap my different modules for the year.

  One of my modules 3D and animation, I made my last animation output as PNG. There are tired of running at 24 frames per second depending on the 22 second audio clip. When I put the images in After Effects as a sequence PNG sequence is only 18 seconds long and makes out in 18 seconds.

  I put the composition 22 seconds long and do speed 24 seconds when I started the comp. I have a layer of PNG (images you will see) and a second layer of PNG (a rendered 3D Studio Max Zdepth) to create a depth of field effect.

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  Make sure that you are interpreting the film sequence of still images at a good rate. Read this page.

• I need a little help with the INSTR function

  Hello everyone,
  
  im still new to pl sql and experienced an issue with the INSTR function. I need to analyze some values of a CLOB containing the xml code and use INSTR to determine the beginning and end of the value, I would like to analyze.
  
  the data I need is in a <!-[CDATA [[Some Text]]]-> block. up to this point, I managed to take the start of the word, but I can't seem to capture the end of the CDATA block. I use this statement:
  
  POS: = INSTR (TO_CHAR (input_clob) [,'] ', pos2 + 6, 1);
  
  but it doesn't have the desired effect. [It seems to sort of go back to the length of the string, while the]-sign is actually in the xml file. my result would look to "Some Text]]--> < xmlxml >... < / xmlxml >...» ». [I tried to escape by writing ' \] "but if I do, the function returns zero and my parsed string is left blank.
  
  Unfortunately I can't use regular expressions, because I work with oracle 9.2i. Anyone know what I'm doing wrong?
  
  Thank you
  
  Edited by: user8719779 the 25.08.2009 02:23

  with my_tab as (select ''||chr(10)||
                         '  '||chr(10)||
                         '   '||chr(10)||
                         '  '||chr(10)||
                         '' col1 from dual)
  -- end of mimicking your data; USE SQL below:
  select substr(col1, instr(col1, '', 1, 1) - instr(col1, 'Hello guys I have a small question and seems to have struck a written block and I was wondering if someone can help me.
  I have the tables as such
  
  
  CREATE TABLE "JAMTESTTRANS"
    (
      "LITERAL1" VARCHAR2(6 BYTE),
      "AMOUNT"   NUMBER(17,2)
    )
    
  
  
    CREATE TABLE "JAMTEST"
    (
      "LITERAL1"      VARCHAR2(6 BYTE),
      "LITERAL1_PRED" VARCHAR2(6 BYTE),
    )
  
  
  --here is the data
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('67120',  '6712')
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('6712',   '671')
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('67130',  '6713')
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('6713',    '671')
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('671', '67')
  
  
  INSERT INTO "JAMTESTTRANS" (LITERAL1, AMOUNT) VALUES ('67120', '50')
  INSERT INTO "JAMTESTTRANS" (LITERAL1, AMOUNT) VALUES ('67130', '90')
  INSERT INTO "JAMTESTTRANS" (LITERAL1, AMOUNT) VALUES ('67120', '20')
  INSERT INTO "JAMTESTTRANS" (LITERAL1, AMOUNT) VALUES ('67120', '10')
  now I want to do is end up with the sum of 67
  Since 67120 and 67130, both have the predecessor of 671 I would look for a level and get the $ 67.
  Can't seem to get it.
  Any help would be grateful.
  
  
  
  
  desired output
  LITERAL1                AMOUNT
  67                          170
  
   
  I know I have to use connect by before somewhere, but how? »			 
  Hi, Miguel.
  mlov83 wrote:
  Frank, good to see you answer this question. you are brilliant my friend but what if I did
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('40500', '4050')
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('4050', '405')
  INSERT INTO "JAMTEST" (LITERAL1, LITERAL1_PRED) VALUES ('405', '40')
  
  Be sure to post the results desired from these sample data.
  Did you mean view all additional lines for jamtesttrans? The solutions I posted earlier will only display nodes that have descendants in jamtesttrans. If you want to include these lines in the output (list NULL until the amount total, perhaps), then do an outer join between the two tables.
  Do you need to CONNECT BY, or you can, just by looking at the values of literal1, if one is one descendant of the other?
  If you really need to CONNECT BY, then you might want this:
  WITH     got_tree     AS
  (
       SELECT     CONNECT_BY_ROOT     literal1_pred     AS root
       ,     literal1
       FROM     jamtest
       START WITH     literal1_pred     IN ('40', '67')
       CONNECT BY     literal1_pred     = PRIOR literal1
  )
  SELECT    t.root
  ,       SUM (j.amount)  AS total_amount
  FROM               got_tree       t
  LEFT OUTER JOIN       jamtesttrans       j  ON  t.literal1  = j.literal1
  GROUP BY  t.root
  ;
  
  Required guess that will give you a list containing between 1 and 50 roots (like ' 40 'and ' 67') at a time. If this isn't what you want, then explain what you want.
  now, I want to be able to have the total to 67, but also for 40? I know I've done my first much simpler test then is my real job. but the real table im working with a over 1mill records I don't think I can post here :-D
  No, it's not practical post 1 000 000 lines of data. Do you really need to? Can't give you an example of what you need with no more than 10 lines of each table?