Need help with ordering high voltage

Hello

NI PCIe-6341 card is already installed. And I want to order a power supply voltage (CZE1000R) to generate the high voltage (DC). The goal is to fully control the high voltage. For example, the voltage can chang from zero to 30 kV in 5 or 10 seconds and be stable to 30 kV to 30 minutes and then go down smoothly at 20 kV in 5 minutes and finally back to zero. Could someone help me with this task? Thank you.

Hi, apok,

I used the 'panels-test' on 'measurement and automation explorer. And I see signals on an oscilloscope.

Thank your for your help.

But when I try to test the "tension cntrl.vi" it has not worked.

On the manual, he said:

"

Programming with external voltage:

Disconnect between TB1-2 and TB1 - 3 riders. Connect signal 0 - 10V between TB1-3 and TB1-6 (common)".

This means that I need to plug TB1 - 3 and TB1 - 6 and out of the acronym to TB1-3?

Tags: NI Hardware

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(     parent_part     CHAR(25)
,     child_part     CHAR(25)
,     line_nbr     NUMBER(5)
,     qty_per          NUMBER(9,5)
);

INSERT INTO bill_test1 VALUES ('ABC-1','ABC-10',100,1);
INSERT INTO bill_test1 VALUES ('ABC-1','ABC-20',200,2);
INSERT INTO bill_test1 VALUES ('ABC-1','ABC-30',300,3);
INSERT INTO bill_test1 VALUES ('ABC-1','HARDWARE-1',401,10);
INSERT INTO bill_test1 VALUES ('ABC-1','HARDWARE-2',402,5);
INSERT INTO bill_test1 VALUES ('ABC-10','ABC-155',100,2);
INSERT INTO bill_test1 VALUES ('ABC-10','HARDWARE-1',200,1);
INSERT INTO bill_test1 VALUES ('ABC-155','RAW-2',100,4.8);
INSERT INTO bill_test1 VALUES ('ABC-155','HARDWARE-3',200,3);
INSERT INTO bill_test1 VALUES ('ABC-20','RAW-1',100,10.2);
INSERT INTO bill_test1 VALUES ('ABC-30','RAW-3',100,3);
    And the following query gives me exactly what I want, in the order I want. However, I wonder if there is a way to get this order without creating the column SEQ, given that I don't need in my results
    SELECT     part_nbr
,     parent_part
,     child_part
FROM     (
     SELECT     CONNECT_BY_ROOT b.parent_part                         AS part_nbr
     ,     b.parent_part
     ,     b.child_part
     ,     SYS_CONNECT_BY_PATH(b.line_nbr,' ')                    AS seq
     FROM     bill_test1 b
     ,     dual
     CONNECT BY     parent_part     = PRIOR child_part
     )
WHERE          part_nbr     = 'ABC-1'
ORDER BY     seq
;

Results of above query, except with SEQ included in SELECT (just to show what I'm sorting off of):
PART_NBR                     PARENT_PART                  CHILD_PART                   SEQ
---------------------------- ---------------------------- ---------------------------- -----------------
ABC-1                        ABC-1                        ABC-10                        100
ABC-1                        ABC-10                       ABC-155                       100 100
ABC-1                        ABC-155                      RAW-2                         100 100 100
ABC-1                        ABC-155                      HARDWARE-3                    100 100 200
ABC-1                        ABC-10                       HARDWARE-1                    100 200
ABC-1                        ABC-1                        ABC-20                        200
ABC-1                        ABC-20                       RAW-1                         200 100
ABC-1                        ABC-1                        ABC-30                        300
ABC-1                        ABC-30                       RAW-3                         300 100
ABC-1                        ABC-1                        HARDWARE-1                    401
ABC-1                        ABC-1                        HARDWARE-2                    402

    Hello

    As long as there is that a single root, brothers and SŒURS of ORDER BY, you say, but you can not do in a subquery (well, you can, but usually there is no interest in a subquery). If the CONNECT BY in a subquery, there is no guarantee that the main request will preserve the hierarchical order which provides the subquery.

    The query you posted does not require a query of Tahina, so you can say:

    SELECT     CONNECT_BY_ROOT b.parent_part                         AS part_nbr
,     b.parent_part
,     b.child_part
--,     SYS_CONNECT_BY_PATH(b.line_nbr,' ')                    AS seq
FROM     bill_test1 b
WHERE          CONNECT_BY_ROOT b.parent_part     = 'ABC-1'
CONNECT BY     parent_part     = PRIOR child_part
ORDER SIBLINGS BY     b.line_nbr
;

    I said the query you posted does not require a subquery. It also does not require double, so I guess that what you posted is a simplification of what you are really doing, and that could have a subquery. In particular, if you want to GROUP BY part_nbr, you need the subquery. We can use CONNECT_BY_ROOT expression in the WHERE clause (or, come to think of it, use a START WITH clause instead WHERE), but, for some reason, we cannot use CONNECT_BY_ROOT in a clause GROUP BY; We need to calculate CONNECT_BY_ROOT in a subquery, give it a name (like part_nbr) and Super GROUP OF this column in a query.

    This requires that there is that one node root. ORDER OF brothers and SŒURS means just that: children of a common parent will appear in the order, but the root nodes, which have no parents, may not be in order.

    Here's what I meant by using START WITH place WHERE:

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,     b.parent_part
,     b.child_part
--,     SYS_CONNECT_BY_PATH(b.line_nbr,' ')                    AS seq
FROM     bill_test1 b
START WITH     b.parent_part     = 'ABC-1'
CONNECT BY     parent_part     = PRIOR child_part
ORDER SIBLINGS BY     b.line_nbr
;

    This should be much more effective, because it reduces the results before waste you your time by getting their descendants.
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    By using a WHERE clause here is similar by sending me an e-mail to all members of society, saying: "come to a meeting one my office at 3:00" and then, as people get here, tell everyone except you could go back.

    Brothers and SŒURS ORDER BY was introduced in Oracle 9.

    Published by: Frank Kulash, December 9, 2010 14:39
    Added version with the START WITH clause

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    with t as
(
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 union all
 select 123 id, 'ca' lstatus from dual
 union all
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 union all
 select 345 id, 'ca' lstatus from dual
 union all
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 union all
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 union all
 select 1011 id, 'fac' lstatus from dual
union all
 select 1011 id, 'xyz' lstatus from dual
)select id,lstatus,row_number() over(partition by id order by lstatus)rw
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123         ca          1
123         fac         2
345         ca          1
345         brwr         2
567         brwr         1
789         brwr         1
1011         fac        1
1011  xyz         2
    That is, my first priority is to 'ca', then 'College '.

    I am aware that this can be done through the use of CASE within the order by clause
    but could not find the logic of the apt.

    Please help me.

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(
 select 123 id, 'brwr' lstatus from dual
 union all
 select 123 id, 'ca' lstatus from dual
 union all
 select 123 id, 'fac' lstatus from dual
 union all
 select 345 id, 'ca' lstatus from dual
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 select 345 id, 'brwr' lstatus from dual
 union all
 select 567 id, 'brwr' lstatus from dual
 union all
 select 789 id, 'brwr' lstatus from dual
 union all
 select 1011 id, 'fac' lstatus from dual
union all
 select 1011 id, 'xyz' lstatus from dual
)select id,lstatus,row_number() over(partition by id order by (case  when lstatus <> 'brwr' THEN UPPER(lstatus) else lstatus end)) rw
 from t;

    Basically, it shows how to use the CASE statement. You can change based on your actual data.

    Concerning
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