Need help with the insert statement

Hello

I have a question on how to write a SQL statement.

This is the table of "base":
CREATE TABLE TEMP_TBL
(
id_nr NUMBER,
DATE_DOK DATE,
DATE_DUE DATE,
DATE_DOK_PAY DATE,
DEB NUMBER,
KRD NUMBER
);

insert into temp_tbl (ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('1',TO_DATE('11.01.2011','DD.MM.YYYY'),TO_DATE('25.02.2011','DD.MM.YYYY'),NULL,'423,24','0');
insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('2',TO_DATE('16.12.2011','DD.MM.YYYY'),TO_DATE('13.06.2011','DD.MM.YYYY'),NULL,'91270,15','0');
insert into temp_tbl(ID_NR,DATE_DOK,DATE_DUE,DATE_DOK_PAY,DEB,KRD)values('3',TO_DATE('27.09.2011','DD.MM.YYYY'),TO_DATE('27.09.2011','DD.MM.YYYY'),NULL,'0','2000');
and it comes to resoult in the target table. SQL statement must take care of the insert in a base of the target table table (example below is already provided with test data).
create table table_sod
(

      id_nr number
     ,date_from date
     ,date_to date
     ,deb_krd number

);

One thing to note here :  values in column deb_krd under insert 1 and 4 must be summarized in insert 4.

insert into table_sod (id_nr,date_from,date_to,deb_krd) values('1',null,to_date('25.02.2011','dd.mm.yyyy'),'423,24');
insert into table_sod(id_nr,date_from,date_to,deb_krd) values('2',to_date('26.02.2011','dd.mm.yyyy'),to_date('13.06.2011','dd.mm.yyyy'),'423,24');
insert into table_sod(id_nr,date_from,date_to,deb_krd)values('3',null,to_date('13.06.2011','dd.mm.yyyy'),'91270,15');
insert into table_sod(id_nr,date_from,date_to,deb_krd)values('4',to_date('14.06.2011','dd.mm.yyyy')to_date('27.09.2011','dd.mm.yyyy'),'91693,39');
insert into table_sod(id_nr,date_from,date_to,deb_krd)values('5',null,to_date('27.09.2011','dd.mm.yyyy'),'2000');
If someone could give me a helping hand how write correct insert statement I would be really gratefull.

Thank you for your time!

I came here with my own assumptions with this

SQL> select rownum id_nr
  2       , date_from
  3       , date_to
  4       , case when date_from is null then deb
  5              else sum(case when date_from is not null then deb else 0end) over(order by id_nr, no)
  6         end deb_krd
  7    from (
  8            select id_nr
  9                 , case when lg_dt is null or ld_dt = date_due then  null else lg_dt+1 end date_from
 10                 , ld_dt date_to
 11                 , case when deb = 0 then krd else deb end deb
 12                 , no
 13              from (
 14                      select t1.*
 15                           , lead(t1.date_due) over(order by t1.id_nr, t2.no) ld_dt
 16                           , lag(t1.date_due) over(order by t1.id_nr, t2.no) lg_dt
 17                           , t2.no
 18                        from temp_tbl t1
 19                       cross
 20                       join (select 1 no from dual union all select 2 no from dual) t2
 21                       order by id_nr, no
 22                   )
 23             where ld_dt is not null
 24         )
 25  /

     ID_NR DATE_FROM DATE_TO      DEB_KRD
---------- --------- --------- ----------
         1           25-FEB-11      42324
         2 26-FEB-11 13-JUN-11      42324
         3           13-JUN-11    9127015
         4 14-JUN-11 27-SEP-11    9169339
         5           27-SEP-11       2000
 

Tags: Database

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    Screen Shot 2015-08-06 at 12.26.48.pngScreen Shot 2015-08-06 at 12.00.10.pngScreen Shot 2015-08-06 at 12.01.16.png

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    Screen Shot 2015-08-06 at 12.44.21.pngScreen Shot 2015-08-06 at 12.44.36.png

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