Need to Partition network each insertion of new data?

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• Hello. I just know that the muse and I need an organization of customers in alphabetical order. The problem is that you will always get new clients. I need to know how to insert a new customer (square), and it is already in alphabetical order on the page.

  Hello.

  I just know that the muse and I need guests alphabetical organization. The problem is that you will always get new clients. I need to know how to insert a new customer (square), and it is already in alphabetical order on the page. The site will be as in the link below, and each customer will have a window of these: http://www.connary.com/. I look back.

  A hug, Murilo.

  I believe you are referring to the rectangles of tile as visitors on the page? not exactly customer database?

  You can add rectangle with different effects with rollover State of mouse and about adding new, you must do this manually in design mode.

  Thank you

  Sanjit

• Need to truncate the table before loading new data

  I use sqlldr control file to load a flat file to a table. This file will be provided each month and is a complete replacement file. I need to automate the process to truncate the data already present in the table before loading new records. I can do this in the same ctl file as load or do I need a separate batch file?
  
  He is the current ctl file:
  
  DOWNLOAD THE DATA
  INFILE ' D:\DATA\OHNFILES\OHN_PROVIDER_DATA. TXT'
  INSERT
  PRESERVE SPACES
  IN THE WEB OF THE TABLE. OHN_OK_SELECT
  (
  Position of CHKPPO (0001:0003).
  Position of the EFFECTIVEDATE (0004:0011).
  Position of TERMDATE (0012:0019),.
  CRED_ID position (0020:0024).
  LASTNAME position (0025:0099),
  Position of FIRSTNAME (0100:0124),
  Position of MIDDLENAME (0125:0149),
  Position of PROFESSIONALDEGREE (0150:0164),
  Position of PRIMARYSPECIALTYID (0165:0214),
  Position of PRIMARYSUBSPECIALTYID (0215:0264),
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  Position of OKLICENSENO (0315:0329),
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  Position of the STATE (0526:0527),
  Position of code POSTAL (0528:0537),
  Position of TELEPHONE number (0538:0549),
  Position of FAX number (0550:0561),
  Position of EMAILADDRESS (0562:0611),
  Position of the COUNTY (0612:0631),
  BILLINGADDRESS position (0632:0731),
  BLDGSUITEPO_BOX1 position (0732:0766).
  Ville1 position (0767:0791).
  STATE1 position (0792:0793).
  POSTALCODE1 position (0794:0803).
  Telephone1 position (0804:0815).
  Position of telecopie1 (0816:0827),
  EMAILADDRESS1 position (0828:0877).
  MAILINGADDRESS position (0878:0977),
  BLDGSUITEPO_BOX2 position (0978:1012).
  CITY2 position (1013:1037),
  STATE2 position (1038:1039).
  POSTALCODE2 position (1040:1049).
  Telephone2 position (1050:1061).
  Telecopieur2 position (1062:1073).
  EMAILADDRESS2 position (1074:1123).
  Position of the OST (1124:1163),
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  )

  customer wrote:
  I use sqlldr control file to load a flat file to a table. This file will be provided each month and is a complete replacement file. I need to automate the process to truncate the data already present in the table before loading new records. I can do this in the same ctl file as load or do I need a separate batch file?

  Same file. Say "TRUNCATE" instead of "INSERT".

  LOAD DATA
  INFILE 'D:\DATA\OHNFILES\OHN_PROVIDER_DATA.TXT'
  TRUNCATE
  PRESERVE BLANKS
  INTO TABLE WEB.OHN_OK_SELECT
  ( ...
  

  Published by: Frank Kulash, on September 3, 2009 15:12

• need, update the message after inserting the trigger data

  Hi all

  CREATE OR REPLACE TRIGGER xxc_student

  AFTER INSERTION

  WE raise

  BEGIN

  Dbms_output.put_line ('end of Inserted');

  END;

  And I want to insert data into the table:

  INSERT INTO student (name) VALUES ("ABC");

  INSERT INTO student (name) VALUES ("CCC");

  INSERT INTO student (name) VALUES ('DDD');

  INSERT INTO student (name) VALUES ("EEA").

  COMMIT;

  I have the following results:

  1 row inserted

  end of Inserted

  1 row inserted

  end of Inserted

  1 row inserted

  end of Inserted

  1 row inserted

  end of Inserted

  ENGAGE

  And I would have

  1 row inserted

  1 row inserted

  1 row inserted

  1 row inserted

  end of Inserted

  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

  Thank you

  No, this isn't possible; e by a trigger.  Relax, you have created is a statement after trigger, so it fires after the insert statement is complete.  In the first example, you have 4 separate SQL statements, so the trigger is activated after each statement.  In your second example, you have a single SQL statement that affects the 4 lines, if the trigger is activated once the end of the statement.

  The number of inserted rows is reported since sqlplus (the client), based on what the engine SQL in the database said he did.  Since there is only a single statement engine SQL reports 4 lines inserted at the client, not four row insertions.

  What problem are you trying to solve with this approach?  In General, dbms_output is not much used in production code, except occasioanlly as a simple debugging tool.

  John

• Insert a new cell in the Excel spreadsheet

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• ADF: How to set default values for the attributes of each Insert online?

  Hello

  I am new to the ADF. I'm developing a simple Application from merger where a column of af: table has to be displayed with the user name (default) on each insertion.

  I tried using below EL:

  < af:inputText value = "#{null == row.bindings.SalesPeople.inputValue?" "{userBean.strUserName: row.bindings.SalesPeople.inputValue}"...

  And I am able to display the logged in user name by default on the side of the user interface, but the name of the user isn't getting recorded in the database.

  The action that I used to insert a new line is "CreateInsert".

  < af:commandButton text = 'Add new record' id = "cb1" actionListener = "#{bindings." CreateInsert.execute}"partialSubmit ="true"/ >

  Please help me how to solve this problem...

  Thank you

  Alexander

  Thank you all,

  I was able to solve this problem in action appellant and here is the code snippet

  actionListener = "#{bindings." CreateInsert.execute}"action =" #{testBean.getSalesPeople} ' "

  partialSubmit = "true" / >

  ----

  public void getSalesPeople() {}

  	Links DCBindingContainer = (DCBindingContainer) BindingContext.getCurrent () .getCurrentBindingsEntry ();
  	UserInfoBean userBean = (UserInfoBean) JSFUtils.getManagedBeanValue ("userBean");
  	DCIteratorBinding quoteIter = bindings.findIteratorBinding("SalesQuoteView1Iterator");
  	RowSetIterator quoteRSIter = quoteIter.getRowSetIterator ();
  	RowKeySet rowKeySet = m_SalesQuoteTbl.getSelectedRowKeys ();
  	If (rowKeySet! = null & rowKeySet.size () > 0) {}
  	Iterator rksIterator = rowKeySet.iterator ();
  	The list rowKey = (List) rksIterator.next ();
  	Key = (Key) rowKey.get (0);
  	Line currentRow = quoteRSIter.getRow (key);
  	currentRow.setAttribute ("Sales", userBean.getStrUserName ());
  }

  Appreciate your point of view on my solution.

  Thank you

  Alexandre Ali

• [vCenter 5] Partitioned network concept

  Hi all

  I am in trouble: I'm just trying to understand the partitioned network!
  1 cluster, 4 ESXi 5.0, 4 VM, 2 heartbeat data warehouses.
  Everything is OK: 1 master, 3 slave, 4 VM 'protected '.
  (Mon test: sur l'hôte 1 esclave, je suis réseau débranché mgmt: vSphere HA État: «Connected (esclave) ') "to"Partitioned"(I can RTC in the fdm.log on Master, data warehouses Heartbeat works)... but after a few seconds, he changed his State for 'isolated '.
  Why? Host is still alive via Heartbeat data warehouses ("[ClusterDatastore::UpdateSlaveHeartbeats] (VMFS) ' host-121 @ 9 c: 8e:99:28:6f:c0 is ALIVE '")
  The host must not remain in the State "partitioned"?
  (I read the vSphere 5.0 high availability Deep Dive)
  Thanks for your help
  Concerning

  No, a host can really be partitioned in this case, it will stay in "partitioned" State This can happen, for example, if you have a cluster extended - if the network connection between the 2 sites goes down, while there will be 2 sets of the cluster hosts that can communicate with each other, but not with hosts on the other site. No host is isolated, but each site is separated from the other. In this case, each partition will elect its own master and each master will be guests in the other partition as "partitioned". When the network connection is facing upward, a master will be "abdicating" and become a slave to the other.

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• Failed to insert a new line with a column generated sequence id

  Hello
  
  I'm trying to insert a new row in a table containing a column of sequence according to db, used as the primary key.
  
  Here is the code for the custom method of the corresponding AM I use to insert the new line:
  
  Line row2 = getCaAppointments1 () .createRow ();
  row2.SetAttribute ("Member ID", Member ID);
  row2.SetAttribute ("Status", "Planned");
  row2.SetAttribute ("CreatedBy", coachId);
  row2.SetAttribute ("CreationDate", date);
  AppointmentId will be generated by the sequence
  DBSequence newId = row2.getAttribute("AppointmentId") (DBSequence);
  SequenceImpl s = new SequenceImpl ("XX_CA_APPOINTMENT_ID", getDBTransaction());
  Long next = newId.getSequenceNumber () .longValue ();
  System.out.println ("Got sequence as id:" + newId);
  row2.SetAttribute ("AppointmentId", newId);
  row2.SetAttribute ("CoachId", coachId);
  row2.SetAttribute ("Type", "0");
  row2.SetAttribute ("AppointmentNumber", 0);
  row2.SetAttribute ("PlannedDate", Department of justice);
  getCaAppointments1 (.insertRow (row2));
  
  I put the attribute EO 'AppointmentId' to use a DBSequence. I tried different combinations to get the sequence Id and insert a line. Nothing worked well and I'm unable to insert a new line.
  
  If I avoid using the attribute 'AppointmentId' and that you try to insert a row, it will fail with the error below:
  
  ORA-01400: cannot insert NULL into ('APPS'. "" "" XX_CA_APPOINTMENTS '. "" APPOINTMENT_ID") ORA-06512: at line 1
  
  Tried to insert the new row using BCTester but I am struck by the same error it (I was unable to change the value of the "AppointmentId" column when inserting the line because this column is read-only and it showed as - 2 value).
  
  I guess, since the attribute of column/is already marked to use a DBSequence, the value should be assigned by default and I shouldn't hit "cannot insert the value NULL to the column.
  Did I miss something necessary to trigger the sequence to automatically generate new Id and assign it to the new line before it is created?
  
  Please let me know the fix.
  
  Thanks in advance
  Rouhaud

  Hello

  Oracle changes this behavior each version, so I hope that its still OK.
  If you have a trigger on the table that inserts the value of the id if none is preset, then mark it as DBSequence, or be it the number.

  Now for your entity, just generate the impl class and override the method create, kind of old school, I know, but it never fails.
  In the create just add the code to your sequence you had:

  SequenceImpl seqImpl = new SequenceImpl("", thisTransaction);
  Number idValue= s.getSequenceNumber();
  setAttribute("Id", idValue);
  

  -Anton

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