Number of uses with values of 2 tables
Maybe I'm not thinking clearly. It's something I should know how to do lol.
I'm wanting something like that
Select feature_type, count (g3e_fid) separate count, feature_type_eng_desc b$ gc_apipe a, b ref_apipe_types where a.feature_type = b.feature_type_eng (+) group by feature_type;
But I can't make it work.
It works very well
Select feature_type, count (g3e_fid) separate count in Group b$ gc_apipe by feature_type;
FEATURE_TYPE | COUNTY |
AD | 8 |
UNPR_IN_HALF | 986 |
PROT_IN_HALF | 1 |
UNPR_OUT_HALF | 1 |
PROT_OUT_HALF | 1 |
AP | 315 |
and this is
Select distinct feature_type, feature_type_eng_desc from gc_apipe $ b a, b ref_apipe_types where a.feature_type = b.feature_type_eng;
FEATURE_TYPE | FEATURE_TYPE_ENG_DESC |
UNPR_IN_HALF | NOT PROTECTED INSIDE OF 0.5 IN. |
PROT_OUT_HALF | PROTECTED OUTSIDE OF 0.5 IN. |
UNPR_OUT_HALF | NOT PROTECTED OUTSIDE OF 0.5 IN. |
PROT_IN_HALF | PROTECTED INSIDE OF 0.5 IN. |
Notice that Feature_type AD and AP are not in the last table, I need to show those too.
Hello
The results I get are quite different from what you get. I get exactly what you asked in response #7, i.e.:
FEATURE_TYPE NTC FEATURE_TYPE_ENG_DESC
------------------------- ---------- ------------------------------
UNPR_IN_HALF 3 UNPROTECTED INSIDE OF 0.5 IN.
AD 2
AP 2
PROT_IN_HALF 1, PROTECTED INSIDE OF 0.5 IN.
If you get results like what you posted in response #9, then I think you are using different data, where ref_apipe_types.feature_type_eng is probably not unique. You can make the main SELECT DISTINCTquery.
Tags: Database
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Andreas Groenevelt says:
A few days ago, I asked a question on the community, but it turned out that there was something wrong with my account and they have removed the item, so I'll just post the solution I found here now:
Something was wrong with the whole site: AP invoice tolerance
I don't post anything substantive until we find out what is happening.
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