OR 9401 at starting out a value greater than 4 000 000 000

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• Read byte with a value up to 127 lire byte with an ASCII value greater than 7F (127 dec)

  Hello

  I have to read a byte with a value greater than 127, Labview turn 27.

  In help I saw that Labview provides a description of ASCII that pour values ranging up to ' 127.

  What do I need to do?

  LabVIEW 6.1

  Windows XP

  Hello

  I want to read a byte with a maximum value of 127, but Labiew reurn arround 27 value

  How do I do?

  

  Rigid wrote:

  Thanks for your help. I'm not changing lyke I understand (my English is poor quiet...)

  I have another program that communicate with the instrument. I know byte (6) must be greater than 18 (greater than 7F actually).

  But with Labview, I'm only 18.

  While it might be higher than 18 x, an I8 is signed, and therefore it cannot be greater than x7F - it has a range of-128 to 127. A U8 is not signed, and it's why he has a range from 0 to xFF. However, x 18 is the same if you treat as signed or not signed. I don't see how LabVIEW can read a wrong value on the serial port. Are you sure you're looking at the correct byte? Your code shows that you split the chain twice. Are you sure that you do this properly?

  Given that you use on Windows you can recheck the chain received using PortMon. Allows you to see what is actually received by the driver for the serial port on Windows.

  P.S. I actually meant the whole byte function.

• Validation rule of error to a value greater than $999,999,999,999.99.

  A validation rule of error for an input value of the user of something higher to $999,999,999,999.99 seems to work only when the amount is 1,000,000,000,100.00 in Oracle policy Automation when written as a Word document rule.

  If the value is implemented at the level of the attribute, then it works for the maximum value of $999,999,999,999.99. And immediately places an error for any value greater than $999,999,999,999.99 even a value of $1,000,000,000,000 is picked up. However, it will be against best practices which is the mixture of source and validation rules.

  I tried all kinds of conditions such as rounding, truncation etc and none seem to work correctly outside validation of the attribute levels.

  @

  Looks like you have to face a maximum value for the validation.

  Do you really need set a very high maximum value? I suggest you enter a maximum value that is a little less than 999,999,999,999.99

  See you soon

  Frank

• [10g] way to find the least value greater than a value?

  I have a simple (I think) question...
  
  Part 1:
  Is there a way to determine the least value among a set of values, which is greater than 0?
  
  A few examples:

  Set of values:
  {0,1,2,3}
  Return value:
  1
  
  Set of values:
  {0,5,10,20,100}
  Return value:
  5
  
  Set of values:
  {1,4,9,11}
  Return value:
  1

  Part 2:
  Same thing, but greater than some given value, 0 is not necessary.
  

  Set of values:
  {0,1,2,3}
  Parameter value: 
  2
  Return value:
  3
  
  Set of values:
  {0,5,10,20,100}
  Parameter value: 
  2
  Return value:
  5
  
  Set of values:
  {1,4,9,11}
  Parameter value: 
  2
  Return value:
  4

  In particular, I'm looking for an effective way to achieve this. I think I can do it with a set of CASE statements, but it becomes really complex values compare more than you.
  
  My first thought was to use the function LESS, but which does not allow me a way to use a parameter.
  
  Any suggestions?

  Hello

  Thanks for posting the sample data.
  I know that it takes hard work to do, but it's really help people who want to help you. Sometimes, it can help you, too, giving you new perspectives on what the problem really is. As often do not, when I am confused by something and need help, I discovered an answer while assembling a test script and write a description of the problem.

  You can use the function LESS, with CASE expressions as arguments, to do what you want:

  SELECT     ord_nbr
  ,     seq_nbr
  ,     time_spent /
       CASE
            WHEN     comp_qty > plan_qty
            THEN     LEAST ( CASE  WHEN ord_qty - scrap_qty > 0 THEN ord_qty - scrap_qty ELSE 1E99 END
                       , CASE  WHEN plan_qty              > 0 THEN plan_qty           ELSE 1E99 END
                       , CASE  WHEN comp_qty            > 0 THEN comp_qty         ELSE 1E99 END
                       )
       END     AS unit_time
  FROM     ord_detail
  ;
  

  This means that your actual data are never as large as 1E99, and at least one of the three expressions will be greater than 0.
  If or any of these assumptions are false, I'm sure we can find a solution, but it will probably be even messier.

  It should work in Oracle 8.1.

• Validation of numeric field to a value greater than zero

  Hello
  
  I am new to the technology of the ADF. I have a text field for which I have to do the validation as it must be digital and there should be greater than zero if it is not null. Please help me on how to do this as part of the ADF. Technology using 11.1 ADF and JSF

  Hello

  This should help: http://jdevadf.oracle.com/adf-richclient-demo/docs/tagdoc/af_validateLongRange.html

• Simultaneous request fails even if I set a value greater than max degrees...

  Hello
  I get the following in a concurrent request error message...
  "This request has completed with an error and produces the following execution message:
  ORA-01631: extended max (600) reached in the APPLSYS table. WF_LOCAL_ROLES_STAGE ".
  
  Then I issued the command: alter table applsys.wf_local_roles_stage storage (maxextents 650)
  
  and gets it to sql statement...
  I confirm this via the sql stmt:
  Select max_extents from all_tables where table_name = 'WF_LOCAL_ROLES_STAGE '.
  
  Subsequently, I re - submit the same application of conc... and it turns bad again the error message that I wrote above...
  "This request has completed with an error and produces the following execution message:
  ORA-01631: extended max (600) reached in the APPLSYS table. WF_LOCAL_ROLES_STAGE ".
  
  When I run the command: select max_extents from all_tables where table_name = 'WF_LOCAL_ROLES_STAGE '.
  the result is-> 600 (the value has been restored to the former)...
  
  What may be the cause...?
  
  Note: I use EBS 11.5.10, DB 10.2.0.4
  Also, I tried maxextents on greater value value again to an unlimited number... and although the command gets (alter table applsys.wf_local_roles_stage (maxextents xxxx) storage) demand of the conc. fails due to max (600) met in the APPLSYS table extensions. WF_LOCAL_ROLES_STAGE.
  
  Thank you
  SIM

  SIM,

  Please see the following document.

  Note: 397283.1 - simultaneous use synchronize Wf Local Tables errors with ORA-01631
  https://metalink2.Oracle.com/MetaLink/PLSQL/ml2_documents.showDocument?p_database_id=not&P_ID=397283.1

  Kind regards
  Hussein

• formatting time to a value greater than 23:59

  Hi all
  I have the following problem:
  in my database I'm ranger schedules of the buses in time stamp formats. If we assume, journey begins to a stop from the station at 23:59 and ends the next day at 00 h 10, this value has the day successive.
  So far so good.
  Now I want to export this table in a specific format, where only the hours, the minutes and the seconds are relevant. Is it now a way to tell oracle to store this value instead of 00:10 24:10?
  
  Thanks a lot for your help
  
  Markus
  
  Published by: markusin on November 26, 2009 05:23

  markusin wrote:
  Thanks a lot for your answer. the only problem always arises when the trip ends at 01:00 or later, it would not be replaced. But, I can solve this problem by myself now.

  No problem:

  select  to_char(start_dt,'dd-mm-yyyy hh24:mi') start_dt,
          to_char(end_dt,'dd-mm-yyyy hh24:mi') end_dt,
          to_char(start_dt,'hh24:mi') start_hhmi,
          case
            when trunc(end_dt) > trunc(start_dt) then to_char(24 + to_char(end_dt,'hh24'),'FM00') || to_char(end_dt,':mi')
            else to_char(end_dt,'hh24:mi')
          end end_hhmi
    from (
          select trunc(sysdate) - 1/24/60 start_dt,trunc(sysdate) + 70/24/60 end_dt from dual union all
          select trunc(sysdate) + 1/24/60  start_dt,trunc(sysdate) + 10/24/60 end_dt from dual
         )
  /
  
  START_DT         END_DT               START_HHMI END_HHMI
  ---------------- -------------------- ---------- ----------
  25-11-2009 23:59 26-11-2009 01:10     23:59      25:10
  26-11-2009 00:01 26-11-2009 00:10     00:01      00:10
  
  SQL> 
  

  SY.

• Retrieve the index of a table with a value greater than zero

  How is it possible to extract the indices of the elements above zero in a 2D array?

  Example:

  Table:

  0 12 11 33 0

  1 0 0 0 0

  2 99 0 9 0

  Need to get 12,11,33 table indexes and so on...

  Nghtcrwlr,

  Attached is the first thing that comes to mind.

  Dan

• Read/write file binary change greater than 128 bytes.

  Hi all, maybe a strange question, but I'm scratching my head on this one. There is undocumented behavior in the function of read/write binary file, where U8 a value greater than 128/0 x 80 get automatically converted to 0x3F value?

  I try to use LabVIEW to generate a binary file custom that we'll load in an EEPROM, so all data in the binary file is stored as values of U8. I have a "template" file, and eventually I'll take the logic implemented to replace the fields with the data from the true value. However, I am struck by the anomaly that when I just read the file in LabVIEW and then réécrirait, all the values 0x80 and more are truncated to 0x3F value. Has anyone seen this before, and is there a solution?

  I noticed writing the value 0 x 80 directly to one generates a binary file (such as a U8) 0 x 90, 0 x 70 being written in the binary file. It is also rather undesirable, as it adds additional bytes in the bytestream, and the bytes of EEPROM must be in exact locations.

  

  

  Join your data file.

  This program is to give the images below?  Are you sure that LabVIEW is to write the bytes differently?  I really doubt that.

• Remove some fonts ligatures if follow-up greater than 0

  I import files with certain fonts with follow-up set to different sizes. Some fonts with some ligatures do not work when monitoring is a value greater than 0 without first turning off the Standard Ligatures. I use a script that checks to see if these certain fonts are active and if yes then disable ligatures for this font.

  My knowledge of javascript is very basic and I have created this script from especially copy and paste and change things, I found in the guide to script. So, I'm sure that my code could use some better organize. I got it first with a bunch of cases identified and then discovered that I could use the | use multiple values so I thought this might be a better way to write it?

  I want to add another if the statement that first checks to see if these fonts have followed together whatever it is greater than 0, and if yes, then turn off ligatures, but if not keep as their market. They work a lot when the tracking is at 0 and I would like to be able to use them again instead of completely disable the.

  var docRef = app.activeDocument;
  
      for (var w = 0; w < docRef.textFrames.length; w++) {
          var textRef = docRef.textFrames[w];
          if ((textRef.textRange.characterAttributes.textFont == textFonts.getByName('Skitch')) ||
              (textRef.textRange.characterAttributes.textFont == textFonts.getByName('AmarelinhaBold')) ||
              (textRef.textRange.characterAttributes.textFont == textFonts.getByName('Amarelinha')) ||
              (textRef.textRange.characterAttributes.textFont == textFonts.getByName('Zalderdash')) ) {
              textRef.textRange.characterAttributes.ligature = false;
          }
      }
  
  redraw();
  
  
  

  Again, I am very new to javascript, but I think that this should be a fairly simple addition? I honestly don't know even if the redraw(); is it necessary? Finally, I want to add to another script to import.

  Thanks for your time!

  It's ok, to optimize well enough, you can make a variable of any object that is called repeatedly, for example characterAttributes, moreover, there is that one way to know if you must redraw(), remove it and if you see that your code works, then it is not necessary

  var docRef = app.activeDocument; 
  
  for (var w = 0; w < docRef.textFrames.length; w++) {
      var textRef = docRef.textFrames[w];
  
      var charAttributes = textRef.textRange.characterAttributes;
      var textfont = charAttributes.textFont;
  
      if ((textfont == textFonts.getByName('Skitch')) ||
          (textfont == textFonts.getByName('AmarelinhaBold')) ||
          (textfont == textFonts.getByName('Amarelinha')) ||
          (textfont == textFonts.getByName('Zalderdash')) ) {
          if (charAttributes.tracking >= 1) {
              charAttributes.ligature = false;
          }
      }
  }
  

• How to create a default profile for all users of a computer under Windows 7/Vista for Firefox versions greater than 8? I would that all new users on a computer to get the same values by default, homepage, bookmarks, etc...

  I found some help on older versions of Firefox, but I can't seem to find anything for the latest versions greater than 8. There must be a way to do this for imaging large scale.

  Have you created a defaults\profile in the folder of the program Firefox (C:\Program Files\Mozilla Firefox\)?

  All files in this folder will be moved into each newly created profile folder.

  To give the prefs a default, it is best to do this via a mozilla.cfg file.

  Use a mozilla.cfg file in the Firefox program folder to lock the prefs or specify default values.
  
  Place a local file - settings.js in the defaults\pref folder where you will also find the channel - prefs.js to specify using mozilla.cfg file.

  pref("general.config.filename", "mozilla.cfg");
  pref("general.config.obscure_value", 0); // use this to disable the byte-shift
  

  See:

  • http://KB.mozillazine.org/Locking_preferences

  You can use these functions in mozilla.cfg:

  defaultPref();  // set new default value
  pref();         // set pref, but allow changes in current session
  lockPref();     // lock pref, disallow changes
  

• relaxation led when the value is greater than

  Hey everybody! I have to do a project and im stuck because I'm a noobler with regard to labview. I'm using labview 6 and got to watch the pressure and temperature of a reactor in time. I need to create a system in which if a value is greater than it triggers an alarm (perhaps led can show it) or is less than a certain limit. I mean it should trigger an alarm when the temperature or pressure is beyond 100 and less than 10. And after that to generate a text document in which it is specified the time and date at which these values were exceeded. I also use randomly generated values. Can I get help please? I'm not manage it by myself)

  Line and force. as Norbert said.

  You won't get much sympathy on overloaded around here.  Three things occurred to me that I read your messages:

  1. You will be in trouble when you get a job if you think that you will be not always charged.
  2. If I help you, you'll probably end up working for me and I still have to do your homework.
  3. You'll be fine.  Engineers outsource their work all the time.

  

• IMAQ_USB - 1074396024 (coverage Minimum value must be greater than zero)

  Hello

  I have problems to use a USB WebCam when I try to run an executable file in a PC that not have installed LabVIEW. The error code that is displayed is 1074396024 (coverage Minimum value must be greater than zero).

  When I run it on a PC that installed, LabVIEW everythings works great!

  Someone has an idea to help me? The sample program is attached.

  Thks

  Hey neat,

  To run your executable file in a free LabVIEW PC, you must install LAbVIEW Run-Time Engine and Vision Run-Time Engine.

  http://digital.NI.com/public.nsf/allkb/3EB8C8AFC1593B4A8625712E0002869B

  Engine performance vision application for permit.

  Best regards

  Abel Souza

  Engineering applications

  National Instruments Brazil

• Display a value in the column only if the number is greater than 1

  I need to return a value in the only if column the the count is greater than 1 for the same column.

  Example table:

  FOOD_TYPE	Agenda	COST_TO_BUY	SELL_PRICE
  Ice cream	Chocolate	0.50	2.00
  Ice cream	Vanilla	0.50	2.00
  Ice cream	Strawberry	0.50	2.00
  Chicken	Wings	2.00	5.00
  Bovine meat	Steaks	8.00	15 h 00
  Bovine meat	Roast	10 h 00	6:00 pm

  In this example, I want to choose the POINT of FOOD_TYPE, SUM (COST_TO_BUY) AND SUM (SELL_PRICE), but I want only to select the ITEM if there is more than 1 points in the FOOD_TYPE.

  I tried all kinds of grouping and even including a case statement in select it as follows:

  CASE

  WHEN (COUNT (DISTINCT POINT) > 1)

  THEN THE POINT

  ELSE "

  END

  However, this is denied when I group because it forces me to use the POINT as a group and I can't use the set statement in the GROUP BY because it has an aggregate function.

  Help, please!

  with

  power as

  (select food_type 'Beef', 'Steaks' article, cost_to_buy 8.00 15.00 sell_price of all the double union)

  Select 'Beef', 'Roast', 10.00, 18.00 double Union all

  Select 'Chicken', 'Wings', 2.00, 5.00 double Union all

  Select 'Ice Cream', 'Chocolate', 0.50, 2.00 double Union all

  Select "Ice Cream", "Vanilla", 0.50, 2.00 double Union all

  Select "Ice Cream", "Strawberry", 0.50, 2.00 double

  )

  Select food_type 'Type of food. "

  cases where the head (separate) over (partition food_type) > 1 then end point "Item,"

  TO_CHAR (cost_to_buy, 'fm990.00') "Purchase cost"

  TO_CHAR (sell_price, 'fm990.00') 'selling price '.

  food

  food_type desc order

  Food Type	Item	Purchase cost	Sell Price
  Ice cream	Chocolate	0.50	2.00
  Ice cream	Strawberry	0.50	2.00
  Ice cream	Vanilla	0.50	2.00
  Chicken	-	2.00	5.00
  Bovine meat	Roast	10 h 00	6:00 pm
  Bovine meat	Steaks	8.00	15 h 00

  Concerning

  Etbin

• Help! Has made the Creative Cloud 2015 update and it started as a trial version? Monthly payment has been subscribed, why he started out as a trial subscription? I turned off my computer and turned on, and the creative cloud everything has been deleted! I

  Help! The creative cloud from 2015 to day and it started as a trial version? My monthly payment was agreed, why he started out as a trial version? When I turned off my Mac and it went across Creative cloud was gone! Please help me as I have a business to run and I do NOT see support for this phone!

  Hello Jane,.

  I checked your ID Adobe given on the forums, I am unable to find any subscription purchased on this e-mail.

  Is there another email associated with your purchase?

  Please follow the steps in the link using your Adobe Id, which you bought the subscription:

  Connect and disconnect activate Cloud Creative applications

  Please let us know if there is no more need help.

  Concerning

  Bianka Attre