Partition wise joined possible with partitions of the interval?

Hello

I want to know the score wise join (NTC) is possible with interval partitioning - I can't find an explicit statement that he isn't, but I can't make it work - I did a simple test case to illustrate the issue.

below, I have 2 create table scripts - 1 for the case of interval and 1 for the case of hash - I then a simple query on these 2 objects which should produce a NTC.

In the case of hash, it works very well (see screenshot 2nd with a set of slaves), the first screenshot shows the case of the interval where I find myself with 2 sets of slaves and no NTC.

No idea if this is possible and I just missed something?

(for the test case choose the names of schema/storage appropriate for your system)

Oh and version (I almost forgot... :-))-East 11.2.0.4.1 SLES 11)

See you soon,.

Rich

-case interval

CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.

TABLESPACE "SB_DWH_INTEGRATION".

PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)

(PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")

in select * from DBA_OBJECTS where object_id is not null;

CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".

TABLESPACE "SB_DWH_INTEGRATION".

PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)

(PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")

in select * from DBA_OBJECTS where object_id is not null;

-case of hash

CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.

TABLESPACE "SB_DWH_INTEGRATION".

8 partitions PARTITION OF HASH ("OBJECT_ID")

store in ("SB_DWH_INTEGRATION")

in select * from DBA_OBJECTS where object_id is not null;

CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".

TABLESPACE "SB_DWH_INTEGRATION".

8 partitions PARTITION OF HASH ("OBJECT_ID")

store in ("SB_DWH_INTEGRATION")

in select * from DBA_OBJECTS where object_id is not null;

-query to run

Select / * + PARALLEL(TEST2,8) PARALLEL(TEST1,8) * / *.

of 'SB_DWH_IN '. "" TEST2 ","SB_DWH_IN ". "' TEST1 '.

where TEST1.object_id = test2.object_id

nonPWJ.PNG

pwjenabled.PNG

It is planned and a consequence of the estimate of the number of parallel slaves.

To the parallel 41 each slave made 3 passes (i.e. sleeves 3 partitions).

Add a partition (by table), and a set of slaves will have to manage a 4th pass: the cost of the query using NTC would increase from 33 percent even if the modification of the data is less than 0.8%.

I guess that in the production Oracle distributes your lines of 1 M for a hash join.

Because the decision is encrypted, it is possible that a very extreme tilt in partition in the table sizes billion line might overthrow the optimizer in a non - NTC join - but I have not tested that.

If you want to force the plan John Watson suggestion for a hint of pq_distribute is relevant.  To cover all the bases and call your tables SMALL and LARGE

/*+

leading (FAT kid)

USE_HASH (large)

no_swap_join_inputs (large)

PQ_DISTRIBUTE (wide none none)

*/

If it's legal, that should do it.

Concerning

Jonathan Lewis

Tags: Database

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