PerlRegEx in FC-RegEx

Similar Questions

• Another RegEX question

  Hi, I have a question about the regular expression: If you look at the attached code you will find two examples. It is an old piece of code, but now I have to fix a bug that was discovered after a few years of use. Task: If the entry is for example C1 - C4, the algorithm needs generate a table of C1, C2, C3, C4. This should work on any digit and letter. Examples: R1 - R5, K569-K799, S2 - S3. This works very well for [letter] [number], but my regex won't work for the case now, I have to solve. If the entry is C1A1-C1A4 the output should be C1A2 C1A1, C1A3, C1A4, but I don't know what should look like the new RegEx so that it still works on [letter] [number] [letter] [number].

  You can not only use [0-9] + $ to return only the number of the end of the string?

  Regular correspondence Expression.vi will return all the foregoing the final number in 'before the game '.

  I'm sorry that I can't look at your code since I don't have a LabVIEW 2011 on my system.

  Rob

• Regex question

  Someday I'll learn Regex. However, that day is not yet. What I have to do is choose the string in square brackets [abcde] returns abcde. I thought it would be something like------[(.+)------] but I can't run in LabVIEW. Suggestions?

  You have the regular expression on the right. Here is the code that I tested. (One of the constants represent values in controls and indicators)

  

• Regex find number at end of string

  Hi guys,.

  I try to learn regex, but it's hard and I'm stuck to a simple task:

  Let's say I have this string:

  "C1".

  I would like to find what is the number to the end of the line. I can do with this regular expression ' [0-9] + $".

  Now if this chain was formed with a small error, say a character 'space' after the number:

  "C1".

  My regex would not '1 '.

  What should I change in my regex to find the last number in the string, even if it has an error?

  P.S. The string can contain several numbers, such as "C5_IND1". My regex must return '1 '.

  Use the look early.  I sounds like you want the last number which is not followed by another number:

  (\d+) (?!. * \d)

• How to extract the corresponding regex string

  Hello

  I am trying to extract text from a long string using QRegEx. Here's my regex:

  Rx QRegExp ("^. *(192|210). * key =? *");

  QString url = ""https://192.168.1.10/files/30/encrypt/key=s6h779bf " "

  rx.setPatternSyntax (QRegExp::Wildcard);

  rx.indexIn (str, 0);

  qDebug()<>

  qDebug()<>

  However, it is does not match anything.

  If I change the regular expression of "(192|210)." * key =? ' * ' can he match but I can't get the string after the = key

  You use a regular expression capture if you want that the parameter "key."

  QRegExp rx("^.*(192|210).*key=(.*)?");
  
  qDebug() << rx.cap(1);  // here's the first octet of your IP
  qDebug() << rx.cap(2);  // key parameter (optional)
  

  Your regex could do with a lot of improvement in my humble opinion. You might want to consuder the class QUrl that does what you want already:

  QUrl url("https://192.168.1.10/files/30/encrypt/key=s6h779bf");
  
  qDebug() << url.queryItemValue("key");
  

  Tip: rubular is a handy Tester on the regex web which makes this kind of thing much easier to debug

  http://rubular.com/

• Widget API Find: regex case sensitive does not work

  I try to use the blackberry.find and the blackberry.pim.Contact Widget API to search for a contact.

  I need the contact can be found if the specified filter string is anywhere in the field, regardless of case.  (I need the query to be case insensitive).

  I have a contact, field firstName = 'Norman '.

  I use method REGEX (the only one that might work in this case, I think), with these expressions regex to match "Norman":

  «. * Norm.*' matches

  «. * norm.*"does not match

  So I tried the regex (? I) indicator in the expression, and the discovery does not at all.

  var fe = new blackberry.find.FilterExpression("firstName", "REGEX", ".*(?i)norm.*"); // causes blackberry.pim.Contact.find() to fail
  

  The API doc says "Please refer to java.lang.String.matches () API for more information on the creation of the regular expression correct... "Well, case has been there for some time.

  Case is not supported? If not, well... which sucks.

  I had asked one of the guys on the team who had some difficulty getting case capacity for work.  It came with a work around that is just a bit hacky, but did the trick

  var hack = "";
  var searchText = searchField.value;for (var i = 0; i < searchField.value.length; i++)
  {
    hack = hack + "[" + searchField.value[i].toLowerCase() + searchField.value[i].toUpperCase() + "]";
  }
  
  var fe = new blackberry.find.FilterExpression("firstName", "REGEX", hack + "[a-zA-Z_0-9_\\s]*");
  
  var contacts = blackberry.pim.Contact.find(fe, "firstName", null, null, true);
  

  They created a character set which contained both lowercase and uppercase letter.

• Regex string for SMTP command

  Hello world

  I would like to create a signature to look for SMTP "mail from the command:<>'.»» Is this the right regex statement get this traffic?

  [Mm] [Aa] [Ii] [he's] [Ff] [Rr] [Oo] [Mm] [:] [<>]

  I usually use the hexadecimal equivalent of the space, but that's just personal preference because it makes it easier to read for me (and I don't inadvertently add random spaces where I don't want them).

  [Mm] [Aa] [Ii] \X20 [he's] [Ff] [Rr] [Oo] [Mm] [:] [<>]

  Realize that [<>] is a character class and means "<" or="" "="">" as would correspond to the place, so the regex you propose:

  post:

  or

  mail to: >

  If you want to find:

  mail to:<> (no value between the curly brackets) then the following:

  [Mm] [Aa] [Ii] \X20 [he's] [Ff] [Rr] [Oo] [Mm] [:] [<][>]

• Without RegEx how?

  find multiple instances of a string, for example the word 'src' inside another string.

  using IndexOf I can find the first occurrence of 'src' and use substrings, as suggested by me simon in another thread, closely related to this.

  But this forces me to find several instances of a string within a larger string and insert substrings in an efficient manner, without RegEx features.

  Clues?

  I can make it through if statements and that work my way towards the end of the string, but that seems a lot more code it should be necessary.

  Instead of getting this RegEx program that has been proposed, I found this perfect alternative.

  public static String replace(String _text, String _searchStr, String _replacementStr)
      {
          //String buffer to store str
          StringBuffer sb = new StringBuffer();
          // Search for search
          int searchStringPos = _text.indexOf(_searchStr);
          int startPos = 0;
          int searchStringLength = _searchStr.length();
          // Iterate to add string
          while (searchStringPos != -1)
          {
          sb.append(_text.substring(startPos, searchStringPos)).append(_replacementStr);
          startPos = searchStringPos + searchStringLength;
          searchStringPos = _text.indexOf(_searchStr, startPos);
          }
          // Create string
          sb.append(_text.substring(startPos,_text.length()));
          return sb.toString();
      }
  

  So there go.

• No Regex?

  OK, so after having poking around seeking support of Regex on BlackBerry, I came across the model repository... I don't understand! It seems to me that with this repository you are adding patterns matching so that the operating system can recognize them?

  How can I use in my code?

  All I want to do is to perform simple regex matches and replaced so that I can format of phone numbers...

  Get a phone like that number.

  String PhoneNum = "17775551212"; or "91 7775551212" or "" etc.

  Perform a Regex

  Output: 91-777-555-1212

  right now I use IndexOf(), a method for changing channels and SubString() but its ugly!

  Thank you!

  Try the regexp - me project

  http://code.Google.com/p/RegExp-me/

• IPS Regex for Boolean 'AND '.

  Hello

  Anyone know the regex string to Boolean operator "AND". I got to know OR operator has string ' |. ' But impossible to find the string for the AND operator.

  any help would be appreciated.

  Hi Ganesh,

  Say, in your example, if channels color and green separated by AAAA, you can write a regular expression like 'ColorAAAAGreen '.

  If you are not sure what characters can be between color and green, you can have a regex like "color [\x00-\xff] * Green. It fires if you see followed green color in the traffic flow. But this includes a wildcard character and could be memory. multiple string engine is preferable in this case.

  So depending on the traffic as you get closer, you can hardcode strings in the regex and features AND.

  HTH,

  Radhika

• Deciphering GIS RegEx

  I need corrective help on the use of regular expressions in integrated sigs.

  In particular, I am referring to the expressions used in the GIS 3115 (Sendmail header overflow). I see many false positives and I try to understand what the signature is looking for.

  These are the expressions:

  (\x3c >) {20}

  \x26lt;>\x26lt;>\x26lt; >...

  Can you help me?

  Thank you

  Don

  Your expressions above, I guess you are using sensors 4.x and look subsignature 3 of the signature 3115. This signature is looking for the following:

  (<>){20}

  It is essentially"<><><>... "repeated 20 times or more. "" (\x3c >) {20} "is the same thing as above. \x3C is the same as "<". we="" had="" to="" do="" this="" because="" of="" a="" regex="" quirk.="" the="" "\x26lt;="">\x26lt;>\x26lt;" >... "" should look to "<><><>... ». He is a victim of our XML data file that can not handle some characters correctly. This is a bug of display. I'll look to this problem.

  Regarding false positives, if you can capture a few iplogs and send them to [email protected] / * /, I'll look into the cause. I need to see the traffic to say what exactly happens.

• VCS Regex ([email protected] / * /)

  Hello, I noticed that when I try to call an IP address of a client Jabber video on the iPad, than if I just dial one IP address, it adds the SIP client Jabber domain name to the IP address and the call fails because it does not recognize this address format.  I know that I can call by putting an alias in front of the intellectual property and it work, but what a transformation regex would I need to integrate into our VCS for the call to work if users want to just put the single IP address?

  I want to take @and make it just .  How can I make this possible using the regex?

  Thanks, Patrick

  (\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3)} (@domain.com)

  Then replace with \1, which is the first capturing group that must be the IPv4 address.

  You might want to put a? After the domain.com) bit so that becomes optional when it stops to send in the future.

  Sent by Cisco Support technique iPhone App

• REGEX and URI scheme

  I am trying to reverse the effect of the following regex following;

  . {[Office@{User.EmailAddress['^.+?@'= "]}

  This particular regex comes from the RFSO for provisioning of Jabber. What I want to do is to remove the domain of the email address or leave all the characters before the @.

  Thank you.

  Sent by Cisco Support technique iPhone App

  The Regex paper available at https://supportforums.cisco.com/docs/DOC-25084 could be useful for you.

  BTW, Note If you use the commissioning, please be sure to remove domain for all search rule as supply/presence etc. use full URL format for the management of signal.

• Regex newbie

  Hello, looking for basic using regex.

  I can do the sharing by using the CASE statements, but how can I use it with regex.

  How can I separate the below address in separate columns and regex substr, replace S by SOUTH, with NORTH etc and orientation N (N, S, E, W) may appear anywhere.

  1850 S LAKEWOOD RD NW

  PATTON 300 CL SO

  
  

  Results as

  SUFDIR, SUFTYPE, STRID, VECTOR, STREET

  1850, LAKEWOOD, RD, TO THE SOUTH, NW

  300, PATTON, CL, WEST, SOUTHWEST
  

  
  

  Any help would be appreciated. Apologies if this isn't the right forum.

  Thank you.
  

  
  

  Any help would be appreciated. Apologies if this isn't the right forum.

  OK - you have the wrong forum.

  This forum is ONLY for Sql Developer questions.

  Please mark the thread ANSWERED and repost it in Sql and Pl/Sql forum

  SQL and PL/SQL

• ARE regex does not recognize umlauts, etc...

  Friends of regular expressions!

  I want to check (Special) valid variable names and

  \w 
  

  for alphabetic characters. This is no characters such as ä - or any character of no ASCI.

  My test script is:

  var toTest = [], j, n;
      toTest.push("#Apple");                            // true
      toTest.push("#Apfel, #apple, #Gurkensalateska");  // true
      toTest.push("#t_27Apples");                       // true
      toTest.push("#côté");                             // false
      toTest.push("#Grüne_5Äpfel");                     // false
      toTest.push("#Äpfel");                            // false
  
  n = toTest.length;
  for (j=0; j < n; j++) {
    $.writeln(ContainsVariable (toTest[j]), " ", toTest[j]);
  }
  
  function ContainsVariable (text) {
  var re_variable= /(^#[\w][\d_\w]*)(, +)?/,
      indexOfChar, character, lSkip, kText;
  
    for(indexOfChar = 0; character = text[indexOfChar]; indexOfChar++) {
      kText = text.substring(indexOfChar); // rest of the statement
      sFound = kText.match(re_variable);
      if (sFound != null) {
        lSkip = sFound[0].length;
        indexOfChar = indexOfChar + lSkip -1;
        continue;
      }
      return false;
    }
    return true;
  }
  

  Any ideas how to get valid results for non-English variable names?

  There is also other gaps: indesign-scripts-forum-roundup-7 #hd4sb3.

  I have not found any documation the regex flavor to YOU. Is there anything?

  Klaus

  Well, friends, this page gave me a clue:

  var re_variable= /(^#[A-Za-z\u00C0-\u017E][\d_A-Za-z\u00C0-\u017E]*)(, +)?/,
  

  works as expected.

  Thanks for listening

  Klaus