problem of regular expression with brackets

Hello

I have a Zebra printer string that contains tokens that I want to search.

^ BY2, 3, 55 ^ FT50, 219 ^ BCN, Y, N... ^ FD >: [[number 1]] ^ FS
^ BY2, 3, 55 ^ FT525, 221 ^ BCN, Y, N... ^ FD >: [[serial number 2]] ^ FS
^ FT170, 192 ^ XG000. GRF, 1, 1 ^ FS
^ FT220, 430 ^ A0N, 27, 27 ^ FH\ ^ ea FD2. #00931 drum kit / ^ FS
↑ FT350, 460 ^ A0N, 27, 27 ^ FH\ ^ FD #00602 ^ FS
^ FO10, 32 ^ GB780, 480, 8 B, 1 ^ FS
^ FT720, 500 ^ A0N, 10, 10 ^ FH\ ^ FD [[Date Code]] ^ FS

I want to find any instance of double hooks regardless of the bracketed text. I find [[SerialNumber 1]] for example, but I also want to analyze the entire string and ensure that there no case [[text]] left in the string. I was not able to build a regular expression that will find them.

Hi elrathia,.

Please find below screenshot

Kind regards

SrikrishnaNF

Tags: NI Software

Similar Questions

  • Problem on regular expressions

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    Hi all

    I am little confused with expression with logical operator evaluation. I'm trying to understand the in expression.

    -----
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    >

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    Published by: LostWorld Sep 15, 2010 05:40

    Hello

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  • Need help with a simple regular expression replacement

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    He comes to the table that I have to work with.
    CREATE TABLE "TBL_ACCOMMODATION" ("ACCOMMODATION_ID" NUMBER, "HOTEL_NAME" VARCHAR2(100), "ADDRESS" VARCHAR2(200), "LOCATION" VARCHAR2(100), "PHONE" VARCHAR2(50), "EMAIL_ADDRESS" VARCHAR2(60), "CONTACT_PERSON" VARCHAR2(60), "STATUS" CHAR(1), "CREATED_BY" VARCHAR2(10), "CREATED_DATE" DATE, "MODIFIED_BY" VARCHAR2(10), "MODIFIED_DATE" DATE, "MOBILE" VARCHAR2(50))
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    Insert into TBL_ACCOMMODATION (ACCOMMODATION_ID,HOTEL_NAME,ADDRESS,LOCATION,PHONE,EMAIL_ADDRESS,CONTACT_PERSON,STATUS,CREATED_BY,CREATED_DATE,MODIFIED_BY,MODIFIED_DATE,MOBILE) values (147,'Testt','Auckalnd','Henderson','565756776','[email protected]','Jasmine','A',null,null,'JEEJJ',to_date('23/10/12','DD/MM/RR'),null);
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    Wellington','Wellington','04 918 8513','[email protected]','Deahdoow Maharg','A',null,null,'LEAN',to_date('14/02/13','DD/MM/RR'),'027 356 4333');
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     Auckland','Auckland','9555555','[email protected]','Quentin QQ','A',null,null,'LEAN',to_date('04/03/13','DD/MM/RR'),null);
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    SELECT acc.hotel_name || '(' || replace(replace(acc.address,chr(13),', '),',,',',') || ')'
    FROM TBL_ACCOMMODATION acc
      inner join ijs_seminar s ON acc.accommodation_id = s.accommodation_id 
    where s.seminar_id = :P27_SEMINAR_ID
    I have to use the function replace twice. One is to replace the Chr (13) a comma is second band a comma where there are two commas.

    I don't know much about regular expressions.
    If someone can show me a better way to handle this using the regular expression rather than a heavy means above.

    Thanks in advance
    Ann

    Hi, Ann.

    Ann586341 wrote:
    Hello everyone,

    He comes to the table that I have to work with.

    CREATE TABLE "TBL_ACCOMMODATION" ("ACCOMMODATION_ID" NUMBER, "HOTEL_NAME" VARCHAR2(100), "ADDRESS" VARCHAR2(200), "LOCATION" VARCHAR2(100), "PHONE" VARCHAR2(50), "EMAIL_ADDRESS" VARCHAR2(60), "CONTACT_PERSON" VARCHAR2(60), "STATUS" CHAR(1), "CREATED_BY" VARCHAR2(10), "CREATED_DATE" DATE, "MODIFIED_BY" VARCHAR2(10), "MODIFIED_DATE" DATE, "MOBILE" VARCHAR2(50))
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    ...
    

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    Is this really the best set of sample data for this question? This problem involves Chr (13) and repeated commas, but I don't see any s CHR (13) or repeated commas in the sample data. In addition, it seems that there are a lot of columns that play no role in this issue and just to make things difficult to read.

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    SELECT acc.hotel_name || '(' || replace(replace(acc.address,chr(13),', '),',,',',') || ')'
    FROM TBL_ACCOMMODATION acc
    inner join ijs_seminar s ON acc.accommodation_id = s.accommodation_id
    where s.seminar_id = :P27_SEMINAR_ID
    

    I have to use the function replace twice. We need to replace the Chr (13) by a comma,.

    As posted, inside REPLACE replaces Chr (13) with a comma and a space which could be important if you then pick up consecutive commas.

    second is the band a comma where there are two commas.

    I don't know much about regular expressions.
    If someone can show me a better way to handle this using the regular expression rather than a heavy means above.

    Assuming you want to replace Chr (13) with just a comma, then an equivalent would be:

    SELECT    acc.hotel_name || '('
                      || REGEXP_REPLACE ( acc.address
                                          , '[,' || CHR (13) || ']{1,2}'
                                , ','
                                )
                    || ')'            AS h
    FROM        tbl_accommodation acc
    INNER JOIN  ijs_seminar       s   ON   acc.accommodation_id = s.accommodation_id
    WHERE s.seminar_id = :P27_SEMINAR_ID
    ;
    

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    [xy]{1,2}
    

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  • the simple regular expression problem

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    INSERT INTO tst VALUES('13/12'); 
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    Agree with the above,

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    RE
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  • Regular expressions - problem

    Hi @ all,

    I need a regular expression more difficult, I don't know Don t.

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    You want to replace the random text with anything?

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    I need your help, because I have no ideas more...

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    File1_v03.doc     File1_v1000.doc
    File1_v1.doc     File1_v1000.doc
    File1_v1.txt     File1_v3.txt
    File1_v115.doc     File1_v1000.doc
    File1_v2.txt     File1_v3.txt
    File1_v999.doc     File1_v1000.doc
    File2.doc     File2.doc
    File2_v01.doc     File2_v116.doc
    File2_v02.doc     File2_v116.doc
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    File2_v115.doc     File2_v116.doc
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