Problem to get the startup-config under the privilege level

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• Unable to switch to the privilege level using password set using ACS enable

  Hi all

  I am not able to not be able to visit the privilege level to help enable password set using ACS 1121 (5.4.0.46).

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  ASA5580-20
  version of the software - 9.1

  LAB - FW / see the law # run | I have aaa
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  I created the Shell profile so & given privilege 15 it.please find wink 1 similarly in word doc attached

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  Hello Dominic,.

  For authorization privileges to take effect, you must add the following command to your configuration on the ASA:

  AAA authorization exec-authentication server

  After adding it, the ASA will take into account the level of privilege that are sent by the ACS.

  Associated with the error you are getting on the graphical interface of the ACS, please make sure that you are using a browser supported for ACS 5.4 version based on the release notes:

  http://www.Cisco.com/c/en/us/TD/docs/net_mgmt/cisco_secure_access_contro...

  Note: Please mark it as answered as appropriate.

• Username with the privilege level 15 bypass activation

  Hi experts,

  I guess I never really understand the process of authentication on Cisco routers and devices lol. In any case I want users privilege level 15 in order to be implemented in enable mode immediately after the connection, without having to type in the 'enable' command and activate the password. Users with other levels of privilege will still put in EXEC mode.

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  !

  username admin privilege 15 secret 5 $1$ $2bdl VIp53G4/zpo4f9aHh.t5v0
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  line vty 0 5
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  entry ssh transport

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  Thank you!

  On the issue of the cisco device the below listed order

  AAA authorization exec default local radius group

  On the radius if server the ACS or IAS

  The attribute of type of service like this

  service-type = administrative

  In doing so, the user will be beginning of landing in mode exec privileges #.

  Kind regards

  Jousset

  The rate of useful messages-

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  I want to say individual personnel in support of HP thin is always very friendly and helpful. It's just a phone, it costs and often listen to music for a long time, its very difficult to get hold of the same person again, if you spend hours to repeat the details of your problem, and despite vehement promises they call you rarely back - probably because they are too busy. His support system which is very poor, not the support staff.

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  Good luck

  BobA

• Problem to get the background color

  Mr President, in my code, I wasn't able to use fully all the width of the screen,

  This is my code

  public class HorizontalField extends VerticalFieldManager
  {
     HorizontalFieldManager sd=new HorizontalFieldManager(HorizontalFieldManager.USE_ALL_WIDTH);
     HorizontalFieldManager r1=new HorizontalFieldManager(HorizontalFieldManager.USE_ALL_WIDTH);
     MySeparatorField ds=new MySeparatorField();
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         fntv = this.getFont().derive(FontFamily.SCALABLE_FONT, 11);
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         /*---------------------Heading-----------------------------------*/
         DateField dd=new DateField("Date");
  
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         sd.add(dd);
        /*------------------*/
         MyLine s=new MyLine();
         sd.add(s);
         Desp d1=new Desp("Description");
         d1.setFont(fnt);
         sd.add(d1);      
  
         /*_________________*/
         MyLine s1=new MyLine();
         sd.add(s1);
  
         Amt d2=new Amt("Amount");
         d2.setFont(fnt);
         sd.add(d2);
         add(new SeparatorField());
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         add(new SeparatorField());
  
             DateField dfr=new DateField("13.08.09")
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                 public void paint(Graphics g)
                 {
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                      g.clear();
                      super.paint(g);
                 }
             };
             r1.add(dfr);
             MyLine sr=new MyLine();
             r1.add(sr);
             Desp dr=new Desp("Reent")
             {
                 public void paint(Graphics g)
                 {
                      g.setBackgroundColor(Color.RED);
                      g.clear();
                      super.paint(g);
                 }
             };
             r1.add(dr);
             MyLine sra=new MyLine();
             r1.add(sra);
             Amt amtr=new Amt("5000")
               {
                 public void paint(Graphics g)
                 {
                      g.setBackgroundColor(Color.RED);
                      g.clear();
                      super.paint(g);
                 }
             };
             r1.add(amtr);
             add(r1);
             add(new SeparatorField());
  
         }
  
      }
  
   class DateField extends LabelField
  {
       DateField(String s)
      {
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       }
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      {
          return Display.getWidth()*2/10;
      }
  
  }
  
    class Desp extends LabelField
  {
       Desp(String s)
      {
          super(s,LabelField.RIGHT);
       }
      public  int getPreferredWidth()
      {
          return Display.getWidth()*5/10;
      }
  
  }
  
    class Amt extends LabelField
  {
      Amt(String s)
      {
          super(s,LabelField.RIGHT);
       }
      public  int getPreferredWidth()
      {
          return Display.getWidth()*4/10;
      }
  
  }
  

  MyLine code is

  public class MyLine extends LabelField
  {
      int width,height;
  
      ButtonField dd;
      MyLine()
      {
          width=1;
          //height=200;
      }
       MyLine(int w)
      {
          width=w;
          //height=200;
      }
  
       public int getPreferredWidth()
          {
              return width;
           }
  
       public void paint(Graphics g)
              {
                     // g.setBackgroundColor(Color.BLUE);
  
                   g.drawLine(0,0,0,70);
              }
  }
  

  When I call this HorizontalField I get the result, but in the amount column (i.e. red) background color I get half of this label, I don't know what problem I did

  Thank you

  The problem is in your calculation of width.

  Your should calculate your width in such a way that (approximate):

  Display.getWidth () = DateField width, width PED, Amt width + 2 * MyLine width;

  Furthermore, a solution may be simply change your constructor Amt class as below:

          Amt(String s)        {                   super(s,LabelField.RIGHT | Field.USE_ALL_WIDTH);        }
  

  Concerning

  Bika

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  =====================================================

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  Hello

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  import java.util.Enumeration;
  
  import com.saiservices.ui.Logger;
  
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  Hello

  Try again with

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  Hello
  
  I created a user "ionm. in PL/SQL, how can I get all the privileges, this user's roles? I'm with dba role, I may grant him certain privileges and so on, now, how do I access all and all the tables there?
  
  
  Edit: another question: How can I grant all privileges and user roles "ionm" to any other user, 'john', without having to write many statements like

  grant .... on .... to ....

  Thank you!
  
  Edited by: Roger22 the 07.06.2009 11:26

  Hello

  Roger22 wrote:
  Hello

  I created a user "ionm. in PL/SQL, how can I get all the privileges, this user's roles? I'm with dba role, I may grant him certain privileges and so on, now, how do I access all and all the tables there?

  Hello

  You can query the data dictionary views
  DBA_TAB_PRIVS for direct privileges on tables and views.
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  DBA_SYS_PRIVS for access privileges, and
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  ,       table_name
  ,       privilege
  ,       grantable
  FROM    dba_tab_privs
  WHERE   grantee  = 'IONM'        -- Strings inside quotes are case-sensitive
  ;
  

  Edit: another question: How can I grant all privileges and user roles "ionm" to any other user, 'john', without having to write many statements like

  grant .... on .... to ....
  

  I don't know how to do it without run of many statements like that.
  You don't have to write them manually; You can have an entry of query them all to a coil of the file, and then run the hold file.
  In PL/SQL, you can use EXECUTE IMMEDIATE in a loop that reads all the privileges.