query to find concurrent programs defined in each queue of concurrent Manager

Similar Questions

• Query to find data conneting that intersect each other.

  Hello

  I have a table like road_point_ids (script is below). Basically, this table have road_id with its start and its end point.

  I'm looking for a query that actually will connect each ID path beginning or end points.

  create the table road_point_ids

  (

  road_id number (10),

  start_point number (10),

  Number of end_point (10)

  );

  insert into road_point_ids

  values (1001, 10, 20);

  insert into road_point_ids

  values (1002, 20, 30);

  insert into road_point_ids

  values (1003, 30, 40);

  insert into road_point_ids

  values (1004, 40, 50);

  insert into road_point_ids

  values (1005, 50, 10);

  insert into road_point_ids

  values (1006, 70, 75);

  insert into road_point_ids

  values (1007, 30, 50);

  insert into road_point_ids

  values (1008, 10, 40);

  insert into road_point_ids

  values (1009, 80, 70);

  insert into road_point_ids

  values (1010, 90, 95);

  insert into road_point_ids

  values (1011, 50, 60);

  
  

  commit;

  SQL > select * from road_point_ids by 2;

  ROAD_ID START_POINT END_POINT

  -----------           -----------           -----------

  1001               10                    20

  1008               10                    40

  1002               20                    30

  1007               30                    50

  1003               30                    40

  1004               40                    50

  1011               50                    60

  1005               50                    10

  1006               70                    75

  1009               80                    70

  1010               90                    95

  11 selected lines

  In the example above only seven road_ids intersect at TWO points corresponding to start or end point.

  Output desired must be as...

  	ROAD_ID	START_POINT	END_POINT
  	1001	10	20
  	1002	20	30
  	1003	30	40
  	1004	40	50
  	1005	50	10
  	1007	30	50
  	1008	10	40

  7 selected lines

  I tried to use a lot of operator AND with the OR operator but sent to an incorrect result. Could someone provide me please help.

  Thanks in advance

  Saaz

  Hi, Saaz,

  How is this problem differs from your original problem?

  If it's just that the data is now contained in 2 tables (a few lines in a table, a few lines in the other) instead of a table, you can change my original solution by using a UNION to combine the two tables into one:

  WITH road_point_ids AS

  (

  SELECT road_id, start_point, end_point OF road_point_ids_1 UNION ALL

  SELECT road_id, start_point, end_point FROM road_point_ids_2

  )

  SELECT DISTINCT road_id, start_point, end_point

  OF road_point_ids

  WHERE CONNECT_BY_ISCYCLE = 1

  CONNECT BY NOCYCLE start_point = PRIOR end_point

  ;

  The WITH clause is new; the main request is that I posted earlier.

• SQL query to assign several concurrent programs to the concurrent Manager.

  Hello

  You have any script to assign a list of program contributing to separate concurrent managers. Currently, there are more than 100 programs need to be assigned to the manager.ut

  We do front end, but it will take quite a long time to complete this task.

  Could you please help me on this.

  Thank you and best regards,

  Simone.

  Hi Simone,.

  First of all I need a sql query to find out what custom programs are assigned to which Manager.

  Please see:

  How can I tell which concurrent Manager handled a simultaneous [ID 344011.1] application/program

  Find all programs assigned to the specialization Manager rules? [271283.1 ID]

  Second, I have to give these programs customized to different custom managers.

  See if this helps:

  https://forums.Oracle.com/thread/2343489

  Thank you &

  Best regards

• Find concurrent program name / name of the given package. PLS files

  * Hi all,.
  
  I want to know is possible to find a simultaneous program name / name of data packages. PLS files in Oracle E-Business Suite 11i.
  
  Is not do we have any other way to match this two things (.) PLS and Package/name of the concomitant program). *
  
  Kind regards
  REDA
  
  Published by: Raj on April 8, 2013 18:14

  Another question:

  How can I program simultaneously on the whole name?

  Under the responsibility of the system administrator, go to (simultaneous > program > executable) and queries 'Execution filename', using the name of the package and get the 'short name '. Next, go to (simultaneous > program > define) and question the "short name" for simultaneous program name.

  Thank you
  Hussein

• Query to find data of each month

  Hello
  
  I have 2 tables.
  
  (1) Order_tb
  
  Name Null? Type
  ----------------------------------------- -------- ----------------------------
  
  ORDERID NOT NULL NUMBER
  NUMBER OF CUSTOMERID
  ORDERDATE DATE
  
  (2) Order_d
  
  Name Null? Type
  ----------------------------------------- -------- ----------------------------
  
  ORDERID NUMBER
  PRODUCTID NOT NULL NUMBER
  PRODUCTNAME VARCHAR2 (20)
  NUMBER OF SELLINGPRICE
  
  I need to find the total find the selling price for each month of the year 2012 (orderdate) total.
  
  I tried to use join, but I couldn't take the 2012 in particular data. Please help me on this issue.
  
  Thank you
  
  Published by: RSD on February 28, 2013 09:18

  Hello

  RSD wrote:
  I tried to use join, but I couldn't take the 2012 in particular data. Please help me on this issue.

  The WHERE clause below, is what limits the results for 2012.

  SELECT       TRUNC (t.orderdate, 'MONTH')     AS month
  ,       SUM (d.sellingprice)          AS total_sellingprice
  FROM       order_tb  t
  JOIN       order_d   d  ON  d.orderid  = t.orderid
  WHERE       t.orderdate  >= DATE '2012-01-01'
  AND       t.orderdate  <  DATE '2013-01-01'
  GROUP BY  TRUNC (t.orderdate, 'MONTH')
  ORDER BY  TRUNC (t.orderdate, 'MONTH')
  ;
  

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
  Simplify the problem. For example, pretend you're only interested in the first 3 or 4 months of 2012; We will find a solution tht can easily be adapted for 12 (or any other number) of motnhs.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• Windows cannot find the program to open the exe file

  I did the windows repair option by restarting then pressed f8 to get to come repair options. I did it to try to remove a number of problems of virus on my laptop. It seems that it has solved the problem, but now when I try to access one of my desktop icon shortcuts it indicates that windows cannot find the program to open the exe file. She does it with every shortcut. I can access the location of the program and then select open with and it will be opened in this way, but there is not and I have to select each time. Another option that works is a right-click on the icon and selecting 'start' and who will run the program properly. Other than simply double-click the icons automatically no longer works since I did this repair.

  Windows Startup Repair fixed my problem, but now my desktop icons not properly opens with double-click

  Hello

  You can try to create a new user account and check. If it works in a new user account, then probably your user account have been damaged and would need a fix.

  Create a user profile.
  http://Windows.Microsoft.com/en-us/Windows-Vista/create-a-user-account
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  Follow the link provided below to fix the damaged user profile.
  http://Windows.Microsoft.com/en-us/Windows-Vista/fix-a-corrupted-user-profile

• Error message states that windows cannot find "C:\program files (x 86) \internet explorer\iexplore.exe"

  I get an error message when I try to open internet explore and I get in safe mode as well... He said windowns cannot find "C:\program files (x 86) \internet explorer\iexplore.exe someone help me please!"

  Hello

  x 86 is 32-bit operating system

  and the 64-bit vista 32-bit and 64-bit browsers explore included

  The Internet Explorer shortcut in the Quick Launch toolbar, and in the x 64 Vista Start menu will run the 32-bit version of Internet Explorer by default. Why run the 32-bit version if IE on the 64-bit version of Vista?

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  Run the sfc/scannow command.

  http://support.Microsoft.com/kb/929833

  Use the (SFC.exe) System File Checker tool to determine which file is causing the problem and then replace the file. To do this, follow these steps:

  1. Open an elevated command prompt. To do this, click Start, click principally madeprograms,Accessories, right-clickguest, and then clickrun as administrator. If you are prompted for an administrator password or a confirmation, type the password, or clickallow.
  2. Type the following command and press ENTER:
     sfc/scannow

     The sfc/scannow command analyzes all protected system files and replaces incorrect versions with appropriate Microsoft versions

  If SFC detects the main problems it can't fix you may need to borrow a Microsoft dvd vista not an acer, HP etc. recovery disk and do a repair installation

  read the below tutorial on how to perform a repair installation

  http://www.Vistax64.com/tutorials/88236-repair-install-Vista.html

• Could not open the dialog box of .msi files saying find a program to open the file type

  In time, I used msi files to install many programs. But I know longer really since then, msi files could not open. Now, I can't open the msi installer, which I had used to install programs. When I click on the msi file, it displays a dialog box saying find a program to open the file type.

  Hello

  1. Were there some recent changes to the computer before the show?

  Method 1: I suggest you unregister and re - register the windows setup program and check if that helps you. To do this, please follow the steps below:

  Unregister and register the Windows Setup program again

  (a) click Start, click run and then type cmd in the dialog box, and then click command prompt.

  (b) at the command prompt, type the following and press ENTER after each line:

  MSIExec /Unregister

  MSIExec/regserver

  Method 2: When you run an .exe on a Windows XP, Windows Vista or Windows 7 computer file, the file can start another program.

  http://support.Microsoft.com/kb/950505/

  Method 3: Change default programs using Set Program Access and computer defaults:
  http://Windows.Microsoft.com/en-us/Windows7/change-default-programs-using-set-program-access-and-computer-defaults

  Changing the programs Windows uses by default: http://windows.microsoft.com/en-US/windows7/Change-which-programs-Windows-uses-by-default

  Hope this information is useful.

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  Still having the problem? Were you able to run SFC in Mode safe?

  You could try a repair of Windows 7 installation or if not a clean install.

• How to avoid the report query needs a unique key to identify each line

  Hello

  How to avoid the error below

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  I have master-detail tables but without constraints, when I created a query as dept, emp table he gave me above the error.

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  Ashish

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  Work on interactive report?

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  Hi all

  Help me on the writing of SQL query to retrieve a single record for each employee of the following table? preferably a standard SQL.

  CREATE TABLE xxc_contact)

  empnum NUMBER,

  alternatecontact VARCHAR2 (100),

  relationship VARCHAR2 (10),

  phtype VARCHAR2 (10),

  Phone NUMBER

  );

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Work', 8888888888)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Work', 7777777777)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Home', 3333333333)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Home', 9999999999)

  expected result:

  EmpNum AlternateContact Relationship PhType Phone       

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Thanks in advance.

  994122 wrote:

  Thank you all, that I got a result

  http://www.orafaq.com/Forum/m/620305/#msg_620305

  By Lalit Kumar B...

  Specifically, the two simple solutions provided were:

  1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).

  SQL > column alternatecontact format A20;

  SQL >

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))

  3 FROM xxc_contact one)

  4. WHEN r = 1

  /

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)

  3 WHERE phone = rn

  4.

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Kind regards

  Lalit

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  Hi all
  
  I have a table like this in SQL Server
  
  Date of sale of product
  A date
  A date
  A date
  B date of
  B date of
  C date
  C date
  C date
  
  I would like to write a query to find the minimum date (i.e. the date
  the first sale) for each product
  
  Thus, the expected results would be
  
  Date of sale of product
  A date min
  B date of min
  C date of min
  
  How can I do this using SQL Server?
  
  any help is greatly appreciated!
  
  Thank you!
  
  

  Product SELECTION, MIN (sale_date)
  From your_table
  GROUP BY product

  Etienne

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