random number in table

Similar Questions

• AS3 getting a random multiple number of table

  Hello:

  I have a hard time finding ways to manage the division with random numbers of tables using AS3.

  On my stage, I have two dynamic boxes; Box1 and box2 and a button, btn.

  in the Assembly, I have the following berries:

  var myDivisor:Array = [3,6,9,12,15,18,21,24,27,30];

  var myDivider:Array = [1,3,6];

  The idea is to divide 1 box per box of 2, so myDivisor should be a random number greater than a random number between myDivider

  WITH THE HELP OF BTN, HOW CAN I GET A RANDOM OF EACH TABLE, SO THIS DIVISOR NUMBER IS HIGHER THAN THE DIVISOR?

  In the timeline for button, here is the code:

  btn.addEventListerner (MouseEvent, CLICK, rNum);

  function rNum (MouseEvent): void

  {

  Box1. Math.Floor (Math.random) * myDivisor.length) / box2. Math.Floor (Math.random) * myDivider.leng th);

  }

  Please suggest ways to make this work.

  German

  var myDivisor:Array = new Array (3,6,9,12,15,18,21,24,27,30,23,89,90,1,34,56,78,99,345,456);
  var myDivider:Array = new Array (1,3,6);
  var divisor: int;
  var divisor: int;

  getNumbers();
  function getNumbers() {}
  divisor = getRandom (myDivisor);
  divisor = getRandom (myDivider);
  checkValues();
  }
  function getRandom(array:Array):int {}

  var NombrAl = Math.floor (Math.random () * array.length);
  return table [NombrAl];

  }
  function checkValues() {}
  If (getRandom (myDivisor) > getRandom (myDivider)) {}
  trace (getRandom (myDivisor));
  trace (getRandom (myDivider));

  } else {}
  getNumbers();
  }
  }

• Generating unique random number with a Boolean signal on an RT target

  Hello, this is my first time asking your question. I apologize if I post this question in the wrong Council.

  [What I'm trying to do]

  I am stable heating and cooling in an experimental space that I (with cRio9024).

  And I'm putting a different experimental condition in space based on the function 'random number '.

  'Different experimental conditions' sense different combinations of Tind, Twat_s and mdot (refer to the attached VI).

  For example, if I get the Boolean TRUE signal.

  I should have a set of [Tind, Twat_s, mdot] = [21,14,0.05], and IS this set of numbers until this Boolean signal goes to FALSE.

  And when the signal passes to the TRUE once again.

  I should have a different set of [Tind, Twat_s, mdot] = [24,16,0.15] for example.

  [I]

  Problem I am with my code is that,

  When the VI is running, the random number remains the same as the Boolean signal is set to TRUE.

  From what I tried so far for the last couple days, using 'the event structure' was the message more concerned that I found,

  However, LabView help tells me that "structure of the event" on the objectives of the RT do not support the events associated with the user interface such as the façade of VI or controls panels.

  I would therefore ask a quick help, since my knowledge of LabView is exhausted at this point.

  

  This is so the part where I want to generate random numbers, WHEN this structure case is TRUE.

  convert whole numbers, random numbers

  Use them as a table index,

  while I can choose conditions from radom to the given set of conditions.

  Once more, I want to do is,

  generate a SINGLE random number series when the structure above is TRUE.

  Hope I have developed quite clear.

  I'm appreciated for any kind of advice.

  Thank you!

  You just need to store the Boolean from the previous run. Then the logic would be (I'll call her Boolean previous B_prevand current boolean B):

  If B AND B_prev > don't generate new values

  otherwise if B > generate new values

  Edit: to store your Boolean value, you can use a feedback node, or a loop with N = 1 and a registry change.

• Unique random number

  Hello

  Oracle 11.2.0.1

  Windows

  I have a table something like this:

  create table (ID, number of rnd) rnd;

  I need a process something like this:

  exec genrnd (200,300);

  After executing the procedure, there will be 100 lines in the table of rnd and there will be unique random numbers in the column of rnd.  OK, suppose if I run once again something like this:

  exec genrnd (173,514);

  therefore table will be truncated and (514-173) + 1 = 342 lines will be rnd table and new unique random numbers will be in the column of rnd.

  Column ID is just at the end of the order of.  There will be 1,2,3... 100 or 1,2,3,4... numbers 342.

  I get random number in this way:

  Select trunc (dbms_random.value (200,300)) rnd twice;

  Select trunc (dbms_random.value (173,514)) rnd twice;

  but number must be unique within the given range, so I don't get how this is possible, please help me.

  Thank you.

  Insert into rnd

  Select rownum, one of

  (

  Select * from

  (

  Select rownum + start_value - 1A

  Double connect rownum<= end_value="" -="" start_value="" +="">

  )

  order of dbms_random.value

  );

  This query has 4 parts

  (1) generation X Y numbers in order

  (2) randomized data generated

  (3) assign a rownum for each row of data

  (4) Insert the result in the table

  So he adapts to the requirements of the opus and don't know how

  > Order by on the insert does nothing

  available in photo with this code.

• What is the possibility of obtaining the same repeated random number?

  I would like to generate a random number of 5 digits;
  
  Select round (dbms_random.value (10, 999990)) twice;
  
  The query above seems pretty good, but what is the possibility of obtaining the same repeated random number? I'm fine with repetition until it spreads not less than a second. Is there such a guarantee?
  
  Thank you
  VINET

  983902 wrote:
  I would like to generate a random number of 5 digits;

  Select round (dbms_random.value (10, 999990)) twice;

  On my laptop, I can call trunc (dbms_random.value (0,100000))-which allows a random number to range form 0 to 99 000 - 100 000 times per second. The probability of repetition in a second depends on the number of calls per second, but in my case that the worst cases are a value that appeared 8 times and 18 445 values appeared twice.

  From what you have said so far, I'd probably use a column of date and a sequence in a column number (10) - possibly with a separate strain by table - for a high volume system.

  Concerning
  Jonathan Lewis

• How to generate a single random number in a MySQL database

  I create a volunteer and also a separate request form from the seller for an air show. The volunteer and seller info is stored in separate tables in MySQL db, a line by volunteer or the seller. There will be about 100 volunteers and 50 sellers. When the request should immediately be printed by the applicant signed and mailed in. This year we had problems with some people who do not immediately print asked, so I would still give them the possibility to print immediately, but also to send them an email with a link to their specific line in the MySQL database. I have an AutoIncrement primary key for each table field, but I think to send this key to the applicant in an email would be too easy for them to guess a different id and access the information of others.

  I think I should add a column for each table containing a unique random number and then I would send this key in the e-mail to the applicant. So, can anyone suggest a simple way to do this or suggest a better way to give the applicant a way to access their own request and nobody elses not after submitting their form?

  Thank you all.

  Tony Babb

  In your code, you should:

   VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s, $s)",
  

  Change the $s to %s and that should solve the problem for you.

  Let me know.  Thank you!

  Chad

• How to sort a random number without using the command by

  Hello
  
  How must be sorted, 5 random number without the use of order by in PLSQL
  for example.
  amount of ID
  1 2
  2 9
  3 3
  4 5
  5 7
  
  Edited by: sake1 1-dec-2010 08:16

  I used Altavista and found an example, how is it?

  DECLARE
  
    /* there is no built array in oracle, you must declare
    your own */
    TYPE Numarray IS TABLE OF NUMBER INDEX BY BINARY_INTEGER;
  
    /* the array of numbers - using assoc array because I can start
    with zero like traditional arrays */
    Nums Numarray;
  
    n NUMBER := 0;
  
    Temp NUMBER;
  
  BEGIN
  
    /* load up the array, put 20 random values in the array,
    in array indicies 0 to 19 */
    FOR i IN 0 .. 19
  
     LOOP
      Nums(i) :=  Round(Dbms_Random.Value(1, 1000));
    END LOOP;
  
    /* get the array size */
    n :=  Nums.Count();
  
    /* display the unsorted values - loop through the whole array and
    print out the values */
    Dbms_Output.Put_Line('unsorted:');
    FOR i IN Nums.First .. Nums.Last LOOP
      Dbms_Output.Put_Line(Nums(i));
    END LOOP;
  
    /* bubble sort - using two loops, compare each value with the one
    after it
    if the one after the current one is smaller , then
  
    switch their locations in the array, this is just like standard
    bubble sorts
    in other languages. The only real diff is the syntax.
    */
  
    FOR i IN 0 .. n - 1 LOOP
      FOR j IN 0 .. n - (i + 1) - 1 LOOP
  
        IF (Nums(j) > Nums(j + 1)) THEN
          Temp := Nums(j);
          Nums(j) :=  Nums(j + 1);
          Nums(j + 1) :=  Temp;
        END IF;
  
      END LOOP;
    END LOOP;
  
    /* display the values sorted */
    Dbms_Output.Put_Line('sorted');
    FOR i IN Nums.First .. Nums.Last LOOP
      Dbms_Output.Put_Line(Chr(9) || Nums(i));
    END LOOP;
  END;
  /*
  unsorted:
  155
  909
  795
  977
  942
  214
  105
  269
  283
  820
  108
  594
  784
  921
  856
  736
  802
  457
  951
  411
  sorted
       105
       108
       155
       214
       269
       283
       411
       457
       594
       736
       784
       795
       802
       820
       856
       909
       921
       942
       951
       977
  
  */
  

  In the code the first comment is wrong in fact, I think, this one:
  "There is no table built in oracle, you must declare your own."
  I remember there are some types of collection of the system, if I not mix with something, I remember there was a sort of like they were undocumented, so we can say legally that the comment in the code has always been right.

• Assigning images to the grid according to their value random number cells?

  Hi all!

  I need a good point (or push) in a good way.

  Background

  (With previous assistance from this forum), I created a random number of 12 x 9 grid that scrolls the numbers 1 to 9, a total of twelve times each. Then I created a button that mixes the current grid cells whenever it locks. I now want to use 9 images that I imported as individual symbols in the library (I gave them each their own class called "skin1," 'skin 2',...) "skin9") as the cell labels or equivalent. I also created images as individual video clips (using the.) The class Sprite as extended but base class keeping the real image of class names in line with the name of the object, i.e. the "skin1" image is the class "skin1.as").

  Question

  How can I assign these images for the cells in the grid according to their respective values (from 1 to 9) and ask them to fill the grid, whenever I click on the button 'shuffle'? Thus, for example, in my grid numbers 1 to 9 randomly appear 12 times each. Whenever the number 4 appears in a cell, I want it to be assigned to the picture "4 GB" (which is just a chart that looks like a button and has a fancy number '4' printed top). Here's a piece of code that I use to draw the grid cells with:

  // Creates a grid cell when called by generateGrid().
  private funciton drawCell(_numeral:int):Sprite
  {
       /*
            This is the code I am currently implementing to populate the grids with (although I
            don't want to use text labels as I want to fill each grid with an image according 
            to its numerical value (1 to 9).
       */
       var _label:TextField = new TextField();
       _label.multiline = _label.wordWrap = false;
       _label.autoSize = "center";
       _label.text = String(_numeral);
       // Add numerical label to cell array.
       cellLabels.push(_label);
       var _s:Sprite = new Sprite();
       _s.graphics.lineStyle(2, 0x019000);
       _s.graphics.drawRect(30, 0, cellW, CellH);
       _s.addChild(_label);
       return _s;
  }
  

  
  While what follows is not the labour code, it will show if all goes well I want to reach inside this function so I can't use the code snippet above to the text labels:

  This will create "if all goes well" a table of 9 images by calling their classes.      var _imageArray:Array = [skin1, skin2, skin3, 4 GB, skin5, skin6, skin7, skin8, skin9];      That's what I want to get for each cell using the matrix in the image above: for (i = 0; I < cells; i ++) {if (_numeral == 1) {/ / Insert image skin1 for each instance of #1 in the grid.}}           } If (_numeral == 2) {/ / Insert image skin 2 for each instance of #2 in the grid.}           }... If (_numeral == 9) {/ / Insert image skin9 for each instance of #9 in the grid.}           }      }

  Again, I want not to use text labels. I have a skin graph custom that I want to go over each number on the grid, based on its value (from 1 to 9). Help with this is greatly appreciated!

  :

  // Creates a grid cell when called by generateGrid().
  private funciton drawCell(_numeral:int):Sprite
  {
       /*
            This is the code I am currently implementing to populate the grids with (although I
            don't want to use text labels as I want to fill each grid with an image according
            to its numerical value (1 to 9).
       */
       var _label:TextField = new TextField();
       _label.multiline = _label.wordWrap = false;
       _label.autoSize = "center";
       _label.text = String(_numeral);
       // Add numerical label to cell array.
       cellLabels.push(_label);
       var _s:Sprite = new Sprite();
       _s.graphics.lineStyle(2, 0x019000);
       _s.graphics.drawRect(30, 0, cellW, CellH);
       _s.addChild(_label);
  
  var classRef:Class=Class(getDefinitionByName("skin"+numeral));var image:*=new classRef();_s.addChild(image);      return _s;
  }
  
  

• A random number in the range generator please help!

  Hey hope someone can help out me, im sure its a easy:

  var tstArray:Array = new Array (1,2,3);

  for (var a: uint = 0; has < tstArray.length; a ++)

  {

  var x: Number = Math.floor ((Math.random () * tstArray [a]));

  trace (x);

  tstArray.splice (a, 1);

  }

  I have this code but it does not exectply what I want it to do. Im trying to generate a random number of signle click between 1 and 3, and when all numbers have been used upwards, remove this click listener.

  If you can help it will be much appriciated

  THX pavel

  use:

  var fp1:farm_part1 = new farm_part1();

  and when you want to randomize a table use:

  var tstArray:Array = fp1.randomizeF ([1,2,3]);

  package

  {

  * / import flash.utils.Timer;

  import flash.display.Sprite;

  import flash.events.MouseEvent;

  import flash.display.MovieClip;

  import flash.events.Event;

  import flash.events. *;

  import flash.media.Sound;

  import flash.events.TimerEvent;

  import flash.media.SoundChannel;

  import flash.media.SoundTransform;*/

  public class farm_Part1

  {

  public void randomizeF(a:Array):Array

  {

  a.shuffle ();
  return a;
  }

  ///////////////////////////// change nothing below /////////////////////////////////////////

  function shuffle(a:Array)

  {

  var p:int;

  var t: *;

  var ivar:int;

  for (ivar =. Length-1; Ivar > = 0; Ivar-)

  {

  p = Math.Floor ((Ivar+1) * Math.Random ());

  t = a [ivar];

  a [ivar] = a [p];

  a [p] = t;

  }

  }

  } //randomAnimal

  } //class

  } //package

• generate a random number in a range of duplication no

  Good day people,

  I need help once again. I want to animate an image inside a movieclip with frame label animate1, animate2, animate3 and animate4.

  I managed to generate random numbers, but my concern is I want my animation not animate same image twice, here is my code.

  = main time line code =.

  function randRange(min:Number,_max:Number):Number {}
  Generate a number between and including min - max
  var randomNum:Number = Math.floor (Math.random () *(max-min)) + min;
  Return randomNum;
  }

  
  

  build table to hold the frame label names
  var frameArray:Array = new Array();
  frameArray [0] = "animate1";
  frameArray [1] = "animate2";
  frameArray [2] = "animate3";
  frameArray [3] = "animate4";
  
  Get created random number
  var n: Number = plageAleatoire (0, frameArray.length);

  
  

  trace ("n": + n);

  
  

  Stop Frame label name
  This.img_ani.gotoAndStop (frameArray [n]);

  
  

  trace ("frameArray:" + frameArray [n])

  = label code and frame inside a clip with 4 frames containing different pictures =.

  as layer: stop();

  image tag: animate1, animate2, animate3, animate4

  Any help is greatly appreciated. Thanks in advance.

  It is not a routine of brewing, integrated, but there is a pretty standard shuffle function that was happening around...

  var frameArray:Array = new Array();
  frameArray [0] = "animate1";
  frameArray [1] = "animate2";
  frameArray [2] = "animate3";
  frameArray [3] = "animate4";

  function shuffle (a) {}
  var p;
  var t;
  Ivar var;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

  trace (frameArray);  See the property before shuffle

  Use:
  Shuffle (frameArray);

  trace (frameArray);  Show after shuffle

• Virus on iPhone to clicking on a link. Compound random number several times. What should I do?

  I clicked on a link on Twitter, and then on this site, he asked to check my browser compatibility. When I click on this box he started numbering to a random number and several times. I got calls as fast I have could and also turned my phone works, but I'm afraid that my information may be compromised. What should I do? Thanks to help from there.

  Nothing to do.

  Do not click on those in the future.

  You can't catch a virus like this.

• How can I generate a single random number on a button for use in a VI?

  I'm creating a new VI and need a new random number every time that I hit a button... it will eventually be replaced by externally triggered en boolean, but for now, I would like to just press a button, get a new number, use this number, click the button, get a new number (previous deletion), etc etc.

  Thank you

  -Steve

  Just to add to what SAM has shown you can generate in a different ranges without limit it... It's just a very simple logic... Try this...

• How can I create a random number generator, protected by password and username?

  I have attached a VI that is a random number generator. I want to just be prompted for the name of user and password when I start this generator. There should be three names of users and passwords found in three different files. I would like to know how to link the code username/password for the code generator and how do the program to know that there are three txt files in my computer with usernames and passowrds.

  
  

• How to build a VI that generates a random number between 1 and 80... Help!

  Generate a VI that generates a random number between 1 and 80

  Divide the random number by a number specified in the front panel.

  If the number of seizures is zero, the VI program should light a LED in the face to indicate a divide by zero error.

  Hai edwardty2009,

  Welcome to the forum.

  Thanks for the congratulations.

  Your problem is solved? If so can you please mark as solution what post help better to solve your problem.

  Thank you

  Mathan

• How to generate a random number within a specified tolerance and control than tolerance.

  I am trying to simulate data without using a data acquisition device using a random number generator and I want to be able to control the "range" the random number generated well.  On the front panel, the user can enter a nominal number, and the random number generator would generate numbers more or less disponibles.003 this number nominal.  The data would be delayed on a chart.  Someone knows how to do this?  Or if it is still possible?

  Just for the sake of information, the random number is supposed to resemble thickness measures, that's why I want to simulate more and less disponibles.003 because the data might be thinner or thicker than the nominal value.

  Thanks in advance!

  Two ways of approaching the issue.  First of all, for even distribution, you can 'Roll the dice', which is the (0,1) random number function, multiply the result by 0.06 and then add Mean - 0.03 to center around average distribution.  If you simulate a real process, my initial guess would be that the results would follow a normal distribution.  In this case, you can use the VI of white noise Gaussian of the palette of generation of signals with a standard deviation of 0.015 if you wanted 0.03 to be the point of 2 sigma, then add average results.