regular expression to remove the zeros on the right

Similar Questions

• Regular expression to remove the space in the HTML tag

  Hi all

  My HTML string is as below.

  Select ' < CityName > RICHMOND < / Nom_ville >

  < StateCd > ABCD CDE

  < StateCd / >

  < CtryCd > CAN < / CtryCd >

  < CtrySubDivCd > BC < / CtrySubDivCd > ' double Str

  Output desired is

  < CityName > RICHMOND < / Nom_ville > < StateCd > ABCD CDE

  < StateCd / > < CtryCd > CAN < / CtryCd > < CtrySubDivCd > BC < / CtrySubDivCd >

  I want to remove these spaces of the tag value box with only spaces otherwise leave it as what. Please help to implement the same using regular expressions.

  Hello

  We don't know what you want.  This site seems to be formatting your message in a weird way.

  As the statement

  SELECT «...» "THE DOUBLE;

  without formatting, to show your entry and after the exact output desired friom as, with as little in shape as possible.  It might be useful if you use some character like ~ instead of spaces (just for viewing; we will find a solution that works for spaces).

  To remove the text which consists of spaces and nothing else between the tags, you can say

  REGEXP_REPLACE (str

  , '> +<>

  , '><>

  )

  How is this string generated?  Maybe there is an easier and more effective way to keep the bad wrtings sub off the chain in the first place.

• Using regular expressions to store the first 3 letters of a string

  Can anyone help with regular expressions?

  The problem:

  I have a contact field which is holder of a value of campaign here is an example of how we look at:

  EMC | TEACHER | HRSUB | June2012-may-01

  I need to store the first three letters of the code in another field of contact, the first three letters are not a defined value and may change in different codes.

  
  

  I have next to no experience with regular expressions, so I am struggling to set up cloud connector Eloqua - here's a screenshot:

  A few tips on how to set up?

  

  This should do the trick, although I would recommend that make you a few tests more using http://regexpal.com/

  ^|\| (.*)$

  Chris
  

• Regular expression TO validate the name of column

  Hi all
  
  I want to write a regular expression to validate the name of column names.i.e enterted must follow the convention of valid column name
  contain only A - Z, a-z, 0-9, _, $, and #.
  
  Please someone help me to do this.
  Padma

  Hey padma.

  Regular expression TO validate the name of column

  to set jaspx for example in the Validation number:

  **

  If your use na na... chain mention you model as etc. from A to z...

  otherwise if the two method nt answer using java Scrpit na... it's better ground for you.

  If however hepatitis is any querys na msg me... If possible I try best,.

  Thnks,
  Suresh V

  Published by: V Suresh on April 2, 2012 16:55

• How can I use a regular expression to validate the email address

  How can I use a regular expression to validate the e-mail address.

  var emailExp:RegExp = /([a-z0-9._-]+?) @([a-z0-9.-] +). ([a - z] {2,4});

• Regular expression to remove a single carriage return character

  Hi all
  
  What is the regular expression to remove only one character to return to a text string. I have something like this:
  
  1
  
  (two returns)
  
  2
  
  and I want to delete only one of the characters turn it over so I'll go
  
  1
  2 (one after the other
  
  I know / r but ot deletes all of the text string.
  
  Thanks a lot for any help
  

  Try something like:
  (in my message window):
  s = "a" & RETURN & RETURN & "two".
  placed s
  l = [s]
  put re_replace (l, "(?)")<=\r)\r", "g",="">
  Place the [1]
  (exit):
  -"a".

  two ".
  -1
  -"a".
  two ".

  I don't know how effective the situation described above could be for research, but
  You can also try:
  put re_replace (l, "\r\r", "g", RETURN)
  or:
  put re_replace (l, "\r{2"}, "g", RETURN)
  However, these last 2 only work in the situation where there
  exactly 2 returns you want to replace with a single DECLARATION - the first
  replaces any number of multiple returns with one RETURN

  It is possibly more effective than the first - it will replace again
  all multiple with a single; but it will unnecessarily replace one
  RETURN character with one character in RETURN - but I'm not a regular expression
  Expert:
  put re_replace (l, "\r+", "g", RETURN)

• PC DM files: my hard drive is currently filled by PC DM files in my folder/Public user folder. How can I safely remove the right files in this folder?

  My hard drive is currently filled by PC DM files in my folder/Public user folder.  How can I safely remove the right files in this folder?  Vista Home Premium 64 bit is my os.

  Hi templar_39,

  DM (Message Delivery) file types are not Windows files, they can be generated by a third-party program.

  This particular file type is often associated with audio data and can be hosted on some cell phones to be used as ringtones or multimedia clips. To my knowledge, these files can be generated by your mobile phone.

  Note: you can go ahead and remove these files only if you notice that the files do not contain any important information.

  If this happens without connect you all devices (like mobile PHONES), this may be a virus or malware activity. You can run a virus scan to get rid of them

  Step 1: A scanner online for any threat and try to correct

  http://OneCare.live.com/site/en-us/Center/cleanup.htm

  Thank you, and in what concerns:

  Ajay K

  Microsoft Answers Support Engineer

  Visit our Microsoft answers feedback Forum and let us know what you think.

• How can I remove the right in DC (LOCKED) reader pane

  How can I remove the right pane (export pdf, create pdf, edit pdf, etc.) on the CD player?  It occupies a quarter of my screen and I never use that kind of thing!

  Thanks for your help!

  July 2015 Acrobat & DC update introduces a change in the user interface for the right pane. Now, when you launch Acrobat/Reader DC, it will retain the last State (collapsu or open) tools in the right pane. You can find more details on this page

  Acrobat help. Summary of new features.

  Edit: Just to clarify in the CD player, it's a preference located under Edit > Preferences > Documents 'tool open for each document pane.

• Regular expression to remove space after the tag &lt; a... &gt;?

  Hello

  I'm relatively new to using regular Expressions, but am in need who will help me find all the tags < a... > with space immediately after this tag and replace it with the exact same tag, but not space after the tag < a... >.

  Thus, for example, a regular expression that there is:

  < a href = "somelink.html" > Somelink < /a >

  as well as:

  "< a href =" # "MM_swapImgRestore" onmouseover = "MM_swapImage (' sub-nav_button_professional_portal',", ' images/sub-nav_button_ professional_portal_f2.png', 1 ') "> Somelink < /a >

  And just remove the space in the hyperlink.  Does anyone know how to do this?

  Find-

  \ (.*)\

  Replace-

  $2

  Post edited by: Murray * CPA *.

• Regular expression to extract the date

  Hi all
  
  Please show me how can I extract date of statement, that date has four forms such as
  2008-08-08 or 08/08/2008 or 2008-agu-8 or 8.8.2008
  
  the follwing query can extarct in this form 08/08/2008.
  
  SELECT REGEXP_SUBSTR ("the Conference will be on 08/08/2008 ',' [0-9] {1,} / [0-9] {1,} / [0-9] {2,}'") FROM dual;
  
  concerning
  Isabelle
  
  Published by: Isabelle on 29 July 2012 10:17

  Specifically, he writes that

  the date has four following forms: 2008-08-08 or 08/08/2008 or 2008-agu-8 or 8.8.2008

  then why you will keep nagging on 10/11/12?

  @OP: here is a starting point, as I understand it:

  with dirtydates as (
  select 1 myrow, 'The date is 8.8.2012' mydate from dual union all
  select 2 myrow,  'The date is 19.Aug.2012' mydate from dual union all
  select 3 myrow,  'The date is 20-08-2012' mydate from dual union all
  select 4 myrow,  'The date is 21-8-2012' mydate from dual union all
  select 5 myrow,  'The date is 22/8/2012' mydate from dual)
  
  select myrow, mydate,  regexp_substr (mydate , '[0-9]{1,2}[[:punct:]]([0-9]{1,2}|[[:alpha:]]{3})[[:punct:]][0-9]{4}' ) datesubstr
  from dirtydates
  order by 1
  ;
  
       MYROW MYDATE                  DATESUBSTR
  ---------- ----------------------- -----------------------
           1 The date is 8.8.2012    8.8.2012
           2 The date is 19.Aug.2012 19.Aug.2012
           3 The date is 20-08-2012  20-08-2012
           4 The date is 21-8-2012   21-8-2012
           5 The date is 22/8/2012   22/8/2012              
  
  5 rows selected.
  

  It's a regular expression simple-thing. You can use: punct: or the list of the ones you want, like [.-/]

• Remove the right frame

  On the right side of the screen, there is a box that occupies a quarter of the screen. There details of file, convert into options etc. to this.

  It restricts the display for the document space.

  Could someone tell me how to get rid of it please?

  Click on tools.

• GREP expression to remove the zeros on the right?

  Hello

  I have to find and edit multiple entries of zeros. Please find the example below to understand the type entered must change.

  1.00-> 1

  0.01200-> 0.12

  4.50 - > 4.5

  -> 0.004 0.0040

  Please help me how can I use grep to find and change in CS6

  Thanks in advance.

  Sanjay

  I think this will work:

  Find (?.)<=[\.\d])0+(?=\s) and="" replace="" with="">

• Regular expression to remove a part of the URL

  I need do the following:
  
  "" Search for all URLS that contain" http://www.mycompany.com/dept/catalogs/ ' and remove whatever happened... / catalogs / '.
  
  Basically I have 3000 + links that start with " http://www.mycompany.com/dept/catalogs/" and I need to strip it of everything what they have after the part of the URL .../catalogs/.
  
  Anyone know of an automatic way to achieve this?
  
  Thanks in advance!

  In what programming environment you doing this?

  In find/replace DW?

  If so, then try this carefully on a test page, because I have not tested:

  To find:

  http:///\/www\.mycompany\.com\/dept\/catalogs\/[^\"]*\".

  Replace with:

  http://www.mycompany.com/Dept/catalogs/ ".

  If you need it in another environment, let us know.

  --

  E. Michael Brandt

  www.divaHTML.com
  www.divahtml.com/Products/scripts_dreamweaver_extensions.php
  According to the standard scripts and the Dreamweaver Extensions

  www.valleywebdesigns.com/vwd_Vdw.asp
  JustSo PictureWindow
  JustSo PhotoAlbum, and alia

  --

• Model maching class of regular Expression to validate the alphanumeric string

  Hello
  MY version of DB is Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Production 64-bit
  
  I wanted to use the model maching given by oracle classes to check whether a given input string is alphanumeric.
  
  Documentation Oracle 10 g said about classes like [: digit:], [: alnum:] and many others.
  
  http://www.DBA-Oracle.com/t_regular_expressions.htm
  
  However these classes seems not work with my version of DB.
  
  Can someone tell me the DB version in which these classes work?
  
  Here is the code I use to validate an input string.
  

  SQL> CREATE OR REPLACE FUNCTION fn_is_alphanumeric
    2  (
    3     pi_value             IN       VARCHAR2
    4  )
    5  RETURN VARCHAR2
    6  IS
    7     lv_length   NUMBER;
    8  BEGIN
    9     lv_length := length(pi_value);
   10     IF ( REGEXP_LIKE(pi_value,'[:alnum:]{'||lv_length||'}')) THEN
   11        RETURN 'TRUE';
   12     ELSE
   13        RETURN 'FALSE';
   14     END IF;
   15  END fn_is_alphanumeric;
   16  /
  
  Function created.
  
  SQL> 
  SQL> 
  SQL> SELECT fn_is_alphanumeric('abc123') alpha FROM DUAL;
  
  ALPHA
  --------------------------------------------------------------------------------
  FALSE
  
  SQL> 
  SQL> 
  SQL> CREATE OR REPLACE FUNCTION fn_is_alphanumeric
    2  (
    3     pi_value             IN       VARCHAR2
    4  )
    5  RETURN VARCHAR2
    6  IS
    7     lv_length   NUMBER;
    8  BEGIN
    9     lv_length := length(pi_value);
   10     IF ( REGEXP_LIKE(pi_value,'[A-z0-9]{'||lv_length||'}')) THEN
   11        RETURN 'TRUE';
   12     ELSE
   13        RETURN 'FALSE';
   14     END IF;
   15  END fn_is_alphanumeric;
   16  /
  
  Function created.
  
  SQL> SELECT fn_is_alphanumeric('abc123') alpha FROM DUAL;
  
  ALPHA
  --------------------------------------------------------------------------------
  TRUE

  Arun Kr Gupta says:
  Hi knani
  I need to check whether the input string is alphanumeric.

  That's why "ABC" all entries as '1234', '123ABc', must return true.

  Also can the alphanumeric string contains characters that are available on the keyboard which can be seized of it.

  Concerning
  Arun

  Published by: Arun Gupta of Kr on October 18, 2010 11:46

  I just read your requirement "all printable characters.

  Try:

  select regexp_like('string','^[[:print:]]$') from dual
  

  to get only the records that have only printable characters.

• How can I remove the right of the Home's smiling face?

  I suddenly noticed last day right of home button there is an annoying smiley face button. How can I remove it?

  You use the option customize and drag it in the palette of unused icons.

  • For the complete instructions with screenshots, see controls to customize Firefox, buttons and toolbars

  Please post to say how you're going. The icon should remove easily.

  If you do not already know the icon, Hello is an experimental free of Firefox similar to Skype.

  Additional information for any reader of this tread who wants to learn more about Hello

  • Hello Firefox - video and voice chat conversations
  • Where's the Firefox Hello button?
  • Start with Firefox – an overview of the main features