Remove duplicates from the oracle table using 2 columns

Similar Questions

• XML from the Oracle Table data

  Hi all
  
  I'm new to this network. I'm also new to oracle XML package. I want a help with the query below.
  
  CREATE TABLE EMP (ID NUMBER PRIMARY KEY, NAME VARCHAR2 (10), TELEPHONE NUMBER);
  
  INSERT INTO EMP (ID, NAME, PHONE) VALUES (11, 'Joy', 1234);
  INSERT INTO EMP (ID, NAME, PHONE) VALUES (22, 'Mike', 5678).
  INSERT INTO EMP (ID, NAME, PHONE) VALUES (33, "Jason", NULL);
  COMMIT;
  
  I want to export data from the EMP table in an XML file with the format below.
  
  Power required:
  
  <? XML version = "1.0" encoding = "UTF-8"? > < Joy STATICDATA > < EMP > < ID > 11 < /ID > < NAME > < / NAME > < / EMP > < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? > < Mike STATICDATA > < EMP > < ID > 22 < /ID > < NAME > < / NAME > < / EMP > < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? > < Jason STATICDATA > < EMP > < ID > 33 < /ID > < NAME > < / NAME > < / EMP > < / STATICDATA >
  
  I used some XML functions and you wrote the following query.
  
  Select XMLROOT (XMLELEMENT (staticdata, XMLELEMENT (EMP, XMLELEMENT(ID,ID), XMLELEMENT(NAME,NAME))), version "1.0" encoding = "UTF - 8') xml EMP;
  
  my query output:
  
  <? XML version = "1.0" encoding = "UTF-8"? >
  < STATICDATA >
  < EMP >
  < ID > 11 / < ID >
  Joy of < NAME > < / NAME >
  < / EMP >
  < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? >
  < STATICDATA >
  < EMP >
  < ID > 22 / < ID >
  < NAME > Mike < / NAME >
  < / EMP >
  < / STATICDATA >
  <? XML version = "1.0" encoding = "UTF-8"? >
  < STATICDATA >
  < EMP >
  < ID > 33 / < ID >
  Jason < NAME > < / NAME >
  < / EMP >
  < / STATICDATA >
  
  
  But I want the out as the power required above. all records in a single line. can someone help me achieve the desired output. also can I export all columns of the table with something like select * from the table in the XML file?
  
  Thank you
  Delobelle

  Don't know why you need it on a single line, but you could:

  Select XMLTYPE (REGEXP_REPLACE (XMLROOT (XMLELEMENT (staticdata, XMLELEMENT (EMP, XMLELEMENT(ID,ID), XMLELEMENT(NAME,NAME))), version "1.0" encoding = "UTF - 8'), CHR (10) |)) ' *<><'))>
  FROM EMP;

  SY.

• Remove duplicates in an oracle table

  Hello
  
  I want to remove duplicates from a table of account
  
  Contains 2 column Account_id and Account_type
  
  counts the values in the table are
  
  Account_id Account_type
  1 GPR
  1 GPR
  1 GPR
  
  
  I want only one entry and delete the other entry with Account_Id = 1
  
  Thank you
  Petri

  One of the ways is...

  delete accounts
  where rowid not in (select max (rowid) of the Group of accounts by account_id, account_type)

  Concerning

• Remove duplicates from the result set

  Here's a challenge question that I was playing with a my free time during the work.
  
  I assume you have the basic HR example somewhere around (I hope is not in production).
  
  Let's say you want to get employees from the employees table whose name is similar to another employee last name.
  The easiest way is to join the two tables with a join condition that checks for the name and employee id. Here's what I came with.
  
  *************
  
  Select e1.last_name, e1.first_name b, e2.last_name c, e2.first_name d
  employees employees join e1 e2
  on (e1.last_name = e2.employee_id <>e2.last_name and e1.employee_id)
  order by one;
  
  ************
  
  The above query returns 10 rows. The first and the second are essentially the same. It is similarly, 3 & 4, 5 & 6, 7 and 8 and 9 and 10. The question is: is there a way that allows me to get rid of using only sql duplicate rows from the result set of this query. I sat on it for 15 minutes and I couldn't know. I'll try to watch my completed work once again.

  Example:

  SQL> column a format a10
  SQL> column b format a10
  SQL> column c format a10
  SQL> column d format a10
  SQL>
  SQL>
  SQL> select e1.last_name a , e1.first_name b, e2.last_name c, e2.first_name d
    2  from employees e1 join employees e2
    3  on ( e1.last_name = e2.last_name and e1.employee_id != e2.employee_id)
    4  where e1.employee_id < e2.employee_id
    5  order by a;
  
  A          B          C          D
  ---------- ---------- ---------- ----------
  Cambrault  Gerald     Cambrault  Nanette
  Grant      Kimberely  Grant      Douglas
  King       Steven     King       Janette
  Smith      Lindsey    Smith      William
  Taylor     Jonathon   Taylor     Winston
  
  SQL>
  

• How to remove duplicates from the PL - SQL table?

  Hi gurus,
  
  I have a PL - SQL table with the following structure
  Authors (SR_NO, Auth_Code, Change_Date, cost)
  
  This table is filled using a slider. However, this table can have a few lines in double (for column (Auth_Code)
  for example

  SR_NO      Auth_Code       Change_Date                       Cost
  1               A1             14-FEB-09 08.18.47 AM          11.00
  2               A2             14-FEB-09 08.18.56 AM       2839.00
  3               A1             15-FEB-09 08.00.02 AM      1299.00
  4               A1             15-FEB-09 07.00.00 AM        789.00
  5               A3             14-FEB-09 08.18.56 AM        312.00
  6               A4             14-FEB-09 08.19.02 AM        233.00

  I need to get the above result set select the separate lines of Auth_Code including the Change_Date is maximum (and store in another PL - SQL table for treatment later or even the removal of this table will be also!)
  
  of the data A1 is duplicated and a maximum Change_Date above = 15 February 09 08.00.02 AM.
  Where my PL - SQL Table that results must have given below
  

  SR_NO      Auth_Code       Change_Date                       Cost
  2               A2             14-FEB-09 08.18.56 AM       2839.00
  3               A1             15-FEB-09 08.00.02 AM      1299.00
  5               A3             14-FEB-09 08.18.56 AM        312.00
  6               A4             14-FEB-09 08.19.02 AM        233.00

  I'm not very aware of the PL - SQL tables and there is no chance to change the existing cursor that fills the data in this table PL - SQL.
  I guess that I need to compare each record of PL - SQL table with others, but do not know how to do this.
  
  Could you please help?

  Hello

  Like this?:

  Connected to Oracle Database 10g Express Edition Release 10.2.0.1.0
  Connected as hr
  
  SQL>
  SQL> with data as(
    2  select 1 as SR_NO, 'A1' as Auth_Code, to_date('14-FEB-09 08.18.47', 'dd-mon-yy hh24:mi:ss') as change_date,    11.00 as cost from dual union all
    3  select 2 as SR_NO, 'A2' as Auth_Code, to_date('14-FEB-09 08.18.56', 'dd-mon-yy hh24:mi:ss') as change_date,  2839.00 as cost from dual union all
    4  select 3 as SR_NO, 'A1' as Auth_Code, to_date('15-FEB-09 08.00.02', 'dd-mon-yy hh24:mi:ss') as change_date,  1299.00 as cost from dual union all
    5  select 4 as SR_NO, 'A1' as Auth_Code, to_date('15-FEB-09 07.00.00', 'dd-mon-yy hh24:mi:ss') as change_date,   789.00 as cost from dual union all
    6  select 5 as SR_NO, 'A3' as Auth_Code, to_date('14-FEB-09 08.18.56', 'dd-mon-yy hh24:mi:ss') as change_date,   312.00 as cost from dual union all
    7  select 6 as SR_NO, 'A4' as Auth_Code, to_date('14-FEB-09 08.19.02', 'dd-mon-yy hh24:mi:ss') as change_date,   233.00 as cost from dual)
    8  select * from data d where change_date = (select max(change_date) from data d2 where d.auth_code = d2.auth_code);
  
       SR_NO AUTH_CODE CHANGE_DATE       COST
  ---------- --------- ----------- ----------
           2 A2        14/02/2009        2839
           3 A1        15/02/2009        1299
           5 A3        14/02/2009         312
           6 A4        14/02/2009         233
  
  SQL>
  

  Kind regards

• Generation of the XML from the Oracle tables

  I'm using Oracle 11 g R1.
  
  I have two tables header and the line:
  
  CREATE THE TABLE HEADER
  (
  EXPENSE_INFO VARCHAR2 (2000).
  NUMBER OF ERROR_CODE,
  REASON_OF_FAILURE VARCHAR2 (4000)
  )
  /
  
  
  CREATE THE ROW IN THE TABLE
  (
  EXPENSE_INFO VARCHAR2 (2000).
  DATE OF EXPENSE_DATE,
  EXPENSE_CODE VARCHAR2 (10),
  EXPENSE_REF VARCHAR2 (2000).
  GROSS_AMOUNT NUMBER,
  NUMBER OF TAX_AMOUNT,
  NUMBER OF ERROR_CODE,
  REASON_OF_FAILURE VARCHAR2 (4000)
  )
  /
  
  These tables are linked by the EXPENSE_INFO column.
  
  Complete the tables with the following data:
  
  Insert in the header (ErrorCode, EXPENSE_INFO, REASON_OF_FAILURE)
  values ('A', 0, 'SUCCESS');
  
  Insert (EXPENSE_INFO, EXPENSE_DATE, EXPENSE_CODE, EXPENSE_REF, GROSS_AMOUNT, TAX_AMOUNT, ERROR_CODE, REASON_OF_FAILURE) online
  values ('A', to_date (December 14, 2012 ', 'dd-mm-yyyy'), 'ABC', 'HOTEL', 100, 500, 0, 'SUCCESS');
  
  Insert (EXPENSE_INFO, EXPENSE_DATE, EXPENSE_CODE, EXPENSE_REF, GROSS_AMOUNT, TAX_AMOUNT, ERROR_CODE, REASON_OF_FAILURE) online
  values ('A', to_date (December 14, 2012 ', 'dd-mm-yyyy'), 'DEF', 'MOVIE', 10, 50, 1, "Cost Code does not exist.");
  
  Insert in the header (ErrorCode, EXPENSE_INFO, REASON_OF_FAILURE)
  values ('B', 1, "Emp Id does not exist.");
  
  Insert (EXPENSE_INFO, EXPENSE_DATE, EXPENSE_CODE, EXPENSE_REF, GROSS_AMOUNT, TAX_AMOUNT, ERROR_CODE, REASON_OF_FAILURE) online
  values ('B', to_date (December 14, 2012 ', 'dd-mm-yyyy'), "XYZ", "MILEAGE", 200, 300, 0, 'SUCCESS');
  
  
  
  I want to generate the XML following these tables:
  
  
  COSTS of <>
  < EXPENSE_DETAILS >
  < EXPENSE_INFO > is < / EXPENSE_INFO >
  < ERROR_CODE > 0 < / ERROR_CODE >
  SUCCESS of < REASON_OF_FAILURE > < / REASON_OF_FAILURE >
  < EXPENSE_LINES >
  < EXPENSE_LINE_REC >
  < EXPENSE_INFO > is < / EXPENSE_INFO >
  < EXPENSE_DATE > 14/12/2012 00:00:00 < / EXPENSE_DATE >
  ABC of < EXPENSE_CODE > < / EXPENSE_CODE >
  HOTEL < EXPENSE_REF > < / EXPENSE_REF >
  < GROSS_AMOUNT > 100 < / GROSS_AMOUNT >
  < > 500 TAX_AMOUNT < / TAX_AMOUNT >
  < ERROR_CODE > 0 < / ERROR_CODE >
  SUCCESS of < REASON_OF_FAILURE > < / REASON_OF_FAILURE >
  < / EXPENSE_LINE_REC >
  < EXPENSE_LINE_REC >
  < EXPENSE_INFO > is < / EXPENSE_INFO >
  < EXPENSE_DATE > 14/12/2012 00:00:00 < / EXPENSE_DATE >
  DEF < EXPENSE_CODE > < / EXPENSE_CODE >
  FILM of < EXPENSE_REF > < / EXPENSE_REF >
  < GROSS_AMOUNT > 10 < / GROSS_AMOUNT >
  < TAX_AMOUNT > 50 < / TAX_AMOUNT >
  < ERROR_CODE > 1 < / ERROR_CODE >
  < REASON_OF_FAILURE > fresh Code does not exist. < / REASON_OF_FAILURE >
  < / EXPENSE_LINE_REC >
  < / EXPENSE_LINES >
  < / EXPENSE_DETAILS >
  < EXPENSE_DETAILS >
  B < EXPENSE_INFO > < / EXPENSE_INFO >
  < ERROR_CODE > 1 < / ERROR_CODE >
  < REASON_OF_FAILURE > Employee Id does not exist. < / REASON_OF_FAILURE >
  < EXPENSE_LINES >
  < EXPENSE_LINE_REC >
  B < EXPENSE_INFO > < / EXPENSE_INFO >
  < EXPENSE_DATE > 14/12/2012 00:00:00 < / EXPENSE_DATE >
  XYZ < EXPENSE_CODE > < / EXPENSE_CODE >
  POINT MILE < EXPENSE_REF > < / EXPENSE_REF >
  < > 200 GROSS_AMOUNT < / GROSS_AMOUNT >
  < > 300 TAX_AMOUNT < / TAX_AMOUNT >
  < ERROR_CODE > 0 < / ERROR_CODE >
  SUCCESS of < REASON_OF_FAILURE > < / REASON_OF_FAILURE >
  < / EXPENSE_LINE_REC >
  < / EXPENSE_LINES >
  < / EXPENSE_DETAILS >
  < / SPENDING >
  
  
  I'm not able to generate the XML file. Kindly help me.
  
  Kind regards
  Sudhanshu

  I love working at the deepest level and then "wrap" with external level tags.

  You want to list all columns of each LINE by line. XMLFOREST is good for this:

  select xmlforest(
    expense_info, expense_date, expense_code, expense_ref,
    gross_amount, tax_amount, error_code, reason_of_failure
  )
  from line;
  
  A
  2012-12-14
  ABC
  HOTEL
  100
  500
  0
  SUCCESS
  ...
  

  Now you want to wrap this up in EXPENSE_LINE_REC

  select xmlelement("EXPENSE_LINE_REC",
    xmlforest(
      expense_info, expense_date, expense_code, expense_ref,
      gross_amount, tax_amount, error_code, reason_of_failure
    )
  )
  from line;
  
  
    A
    2012-12-14
    ABC
    HOTEL
    100
    500
    0
    SUCCESS
  
  

  So far, you have a XML fragment by line in the table of the LINE. You can use XMLAGG to put those together in a single fragment - or rather, a fragment by EXPENSE_INFO.

  Then you use XMLELEMENT again to give the name "EXPENSE_LINES" in this fragment.

  Then you gather the header values and the 'EXPENSE_LINES' fragment in "EXPENSE_DETAILS". This gives you all the information for each row header and associated lines of the LINE.

  Then, you gather all the information into one with XMLAGG header, and give everything a name with XMLELEMENT

  select xmlelement("EXPENSES",
    xmlagg(
      xmlelement("EXPENSE_DETAILS",
        xmlforest(expense_info, a.error_code, a.reason_of_failure),
        xmlelement("EXPENSE_LINES",
          xmlagg(
            xmlelement("EXPENSE_LINE_REC",
              xmlforest(
                b.expense_date, b.expense_code, b.expense_ref,
                b.gross_amount, b.tax_amount, b.error_code, b.reason_of_failure
              )
            )
          )
        )
      )
    )
  )
  from header a join line b using(expense_info)
  group by expense_info, a.error_code, a.reason_of_failure;
  

  _Note: _ with the GROUP BY clause, you can 'total' twice, once at the expense_info level and then overall. That's what I do with the two XMLAGGs: the second he puts just all the different stuff EXPENSE_DETAILS together in one package that I wrap "CHARGES" tag autour.

  Also, I omit EXPENSE_INFO of each LINE as it is already in the header information.

  Published by: stew Ashton on December 17, 2012 14:03

• Best practices for retrieving a single value from the Oracle Table

  I'm using Oracle Database 11 g Release 11.2.0.3.0.

  I would like to know the best practice to do something like that in a PL/SQL block:

  DECLARE
    v_student_id    student.student_id%TYPE;
BEGIN
    SELECT  student_id
    INTO    v_student_id
    FROM    student
    WHERE   last_name = 'Smith'
    AND     ROWNUM = 1;
END;

  Of course, the problem here is that when there is no success, the NO_DATA_FOUND exception is thrown, which interrupts the execution.  So, what happens if I want to continue despite the exception?

  Yes, I could create a block nested with EXCEPTION section, etc, but it seems awkward for what seems to be a very simple task.

  I've also seen this handled like this:

  DECLARE
    v_student_id    student.student_id%TYPE;
    CURSOR c_student_id IS
        SELECT  student_id
        FROM    student
        WHERE   last_name = 'Smith'
        AND     ROWNUM = 1;
BEGIN
    OPEN c_student_id;
    FETCH c_student_id INTO v_student_id;
    IF c_student_id%NOTFOUND THEN
        DBMS_OUTPUT.PUT_LINE('not found');
    ELSE
        (do stuff)
    END IF;
    CLOSE c_student_id;   
END;

  But it still seems to kill an Ant with a hammer.

  What is the best way?

  Thanks for any help you can give.

  Wayne

  201cbc0d-57b2-483a-89f5-cd8043d0c04b wrote:

  What happens if I want to continue despite the exception?

  It depends on what you want to do.

  You expect only 0 or 1 rank. SELECT INTO waiting for exactly 1 row. In this case, SELECT INTO may not be the best solution.

  What exactly do you do if you return 0 rows?

  If you want to set a variable with a NULL value and continue the treatment, Frank's response looks good, or else use the modular Billy approach.

  If you want to "do things" when you get a line and 'status quo' when you don't get a line, then you can consider a loop FOR:

  declare
    l_empno scott.emp.empno%type := 7789;
    l_ename scott.emp.ename%type;
  begin
    for rec in (
      select ename from scott.emp
      where empno = l_empno
      and rownum = 1
    ) loop
  l_ename := rec.ename;
      dbms_output.put_line('<' || l_ename || '>');
    end loop;
  end;
  /
  

  Note that when no line is found, there is no output at all.

  Post edited by: StewAshton - Oops! I forgot to put the result in l_ename...

• Create the flat file data from the oracle table

  d_adp_num char (10)
  d_schd_date tank (8)
  d_sched_code tank (25)
  d_pay_code char (50)
  d_mil_start char (4)
  d_mil_end char (4)
  d_duration char (5)
  d_site_code char (4)
  d_dept_id tank (6)
  
  Select payroll_id,
  schedule_date,
  reason_code, (sched_code)
  reason_code, (pay_code)
  start_time,
  end_time,
  total_hours,
  site_code,
  department_id
  of dept_staff
  where schedule_date between (sysdate + 1) and (sysdate + 90)
  
  
  loading data for the date range instead.
  sched_code - if 'Unavailable' reason_code = 'OD' and 'THE '.
  
  pay_code - "Berevevement BD" If reason_code = "BD".
  "UP PTO without reasonable excuse" If reason_code = 'UP '.
  "RG" If reason_code = "SH".
  "PTO" If reason_code = "GO".
  Here are some...
  
  start_time and end_time - convert military time
  based on start_ampm and end_ampm
  
  On this basis, I need help to create a flat file. Sewing of the flat and data file in dept_staff sample
  
  If site_code is there so no need to get department_id (see the sample flat file)
  ------------------------------------
  
  examples of data to flat file
  
  ZZW002324006072012 PTO
  0800160008.00
  ZZW002428106072012 RG
  1015174507.50HM34
  ZZW002391606072012 RG
  1100193008.50
  ZZW002430406072012 RG
  1100193008.50 130000
  ----------------------------
  
  dept_staff table data
  
  REASON_CODE_1 PAYROLL_ID SCHEDULE_DATE REASON_CODE START_TIME, END_TIME START_AMPM END_AMPM TOTAL_HOURS SITE_CODE DEPARTMENT_ID
  ZZW0024468 08/06/2012 HS HS 730 HAS 400 850 12 P
  ZZW0000199 08/06/2012 HS HS 730 HAS 400 850 14 P
  ZZW0023551 08/06/2012 SH SH 1145 A 930 975 GH08 95 P
  ZZW0024460 08/06/2012 SH SH 515 HAS 330 P 1025 GH08 95
  ZZW0023787 08/06/2012 SH SH 630 HAS 300 850 24 P
  ZZW0024595 08/06/2012 TR TR 730 HAS 400 850 90 P
  ZZW0023516 08/06/2012 OD OD 800 HAS 400 800 95 P
  ZZW0023784 08/06/2012 OD OD 800 HAS 400 800 5 P
  ZZW0024445 08/06/2012 SH SH 1145 A GH08 930 975 5 P
  ZZW0024525 08/06/2012 OD OD 800 HAS 400 800 23 P
  ZZW0024592 08/06/2012 TR TR 730 HAS 400 850 5 P
  ZZW0024509 08/06/2012 SH SH 95 MK21 830 HAS 330 P 700
  
  ZZW0023916 06/14/2012 SH SH 1100 A 850 27 730 P

  How to ask questions
  SQL and PL/SQL FAQ

  UTL_FILE allows to write the OS file

• How to count the number of columns in an oracle table using sql

  How to count the number of columns in an oracle table using sql

  You must put the name of the table in capital letters

  As

  SELECT COUNT(1)
    FROM user_tab_columns
  WHERE table_name = 'EMP';
  
  or
  
  SELECT COUNT(1)
    FROM user_tab_columns
  WHERE table_name = UPPER('Emp');
  

  Concerning
  Arun

• ORA-22992: cannot use LOB Locators selected from the remote tables...

  Oracle 10.2.1.0.4
  Solaris 10
  
  We try to access a table in another database via a db_link.
  
  The table we are trying to access has a LOB.
  
  We get the following error: ora-22992: cannot use LOB Locators selected from the remote tables.
  
  Is there a way to get around this? We need the data in the BLOB field.
  
  Thank you.

  See on metalink:

  ORA-22992 has a workaround solution in 10 gr 2
  DOC - ID: 436707.1

  Werner

• I use Homeshare to watch downloaded movies on my computer and then visible on my TV via Apple TV, but I how remove items from the library of movies on Apple TV when I looked at the

  I use Homeshare to watch movies downloaded on my computer and made visible on my TV via Apple TV. How to remove items from the show announced on television through homeshare /AppleTV when I looked at them?

  You must delete the contents of iTunes on the computer to remove it from the list of content on Apple TV.

• How to remove the logo from the Oracle of tableFirstTemplate?

  How to remove the logo from the Oracle of tableFirstTemplate?

  Dear aJohny!

  My worm jdeveloper is 12.1.3.0.0.

  For Jdeveloper code would be

  and the screen would be like this

  

  I think it's the correct process and the best answer to my question

  Concerning

• How to import the XML file into an oracle table using a BPEL process

  Hi friends
  
  How can I import XML file in the db oracle table using a BPEL process
  
  (1) I have generated an XML file in my local system with a field
  (2) I created a temporary table in my oracledb with the same field in the XML file
  (3) that I want to import these XML files which is the local host to my db oracle using a BPEL process
  (4) for that what steps should I me fallow please suggest me if there is no document for this?
  
  Thanks in advance
  AT

  Hi to

  Here you go...

  http://blogs.Oracle.com/ajaysharma/2011/03/using_file_adapter_database_adapter_and_mediator_component_in_soa_11g.html

  I hope that helps!

  Thank you
  AJ

• How to remove the user from the IOM by using Trusted Recon

  We trust Sun to IOM LDAP Recon. We delete usually old Sun LDAP users periodically. According to the requirement, these users should also be eliminated from IOM as well as all its databases that are put into service.
  
  Looks like that, the behavior by default of 'iPlanet Trusted remove user Recon Task' is to set the user status to 'Deleted' and 'Revoked' about the users corresponding IOM and resources put into service. How can I remove users from the IOM as well as the database placed in service in the case of user removed from Sun's LDAP?
  
  Thank you!
  Kabi

  Once a user is created in the IOM, you cannot remove it. As you said, the default behavior for the removal of the recon user approved is that the user will be disabled in IOM and revoked from all target applications. Revoke the user will remove the user from the target applications.

  This is done for the purpose of audit so that later we can determine which users have been removed or terminated.

  But as a you can manually delete the records of user database directly which is not recommended.

• Windows Live Movie Maker 2011 - how to remove items from the recent projects list

  Windows Live Movie Maker 2011

  I have duplicates on my list of recent projects.

  How to remove items from the numbered list of recent projects?  What are the (thumb)

  bugs used for?  Thank you.

  Hello

  The question you have posted is related to Windows Live Movie Maker and would be better suited in the Windows Live Solution Center. Please visit the link below to find a community that will provide the best support.

  http://www.windowslivehelp.com/product.aspx?ProductID=5

  Amrita M

  Microsoft Answers Support Engineer