search model error string

Hello

I encountered a problem using the model string search in labview.

I use xbee modules pro digi to establish a network with 8 + knots (mode API). Each node has a microcontroller behind her who, when asked by the lv program, sends a package in the form of 01-08-07-04-00-00-00-00-00-00-40-64;

This I would like to extract the received frame.

This works for all units except one. When configuring the copy and placing another module (another address), the problem goes away, but I will not experience this problem when you are working in the field of risk

There are 2 api has received the first one is a status of transmission and the 2nd is the received frame containing the data I want.

To do this I put together the identifier of the received frame (0 x 90) the address of the module (8 bytes long), and network address (2 bytes), frame number for correspondence.

I've included the vi, you can see and choose between working and not working data by using the command.

Also I have included this screenshot of the xbee datasheet for information on the format of the received image.

Can you see the mistake I do or has similar experiences?

Kind regards

Rob

Hi kokodiem

The problem you are experiencing is actually linked to the used regular expression. If you see the model match function help, you will see that there is a list for the "special characters". In this list, you will see that a + is interpreted as a regular expression rather than the sign '+' itself. In hexagonal presentation, the + sign is represented by the value 0x2B. As this value is used in the address of the string is not formatted, this means that your channel you actually have the sign '+', which means the function pattern he will perform as a regular expression.

If you do not want Labview to find the special character itself, rather than interpretting it as a regular expression, you need to escape with one-(or hexagonal 0x5C). In the case of the unformatted string, so the original regex used was:

\90\00\13\A2\00@V+\E5\FF\FE\01 or hex: 9000 13A 2 0040 and 562 b E5FF FE01

Given that the + sign must be "escaped", the regular expression to use should be in this case:

\90\00\13\A2\00@V\\+\E5\FF\FE\01 or hex: 13A 2 9000 0040 565 2BE5 DATA 01

If you try the last of them, you will see that the string will be formatted correctly.

You can find more information in the following forum post. It might be quite interesting to have a look because it contains an example of VI to escape special characters automatically.

http://forums.NI.com/NI/board/message?board.ID=170&message.ID=51850&requireLogin=false

Tags: NI Software

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