Selection of the records of several dates but specific time
Hello:I have to select records of several dates, but time should be 00:00:00 to 06:00:00 (i.e. 12 AM - 06:00)
For the part of date, this can be done:
WHERE
START_TIME BETWEEN TO_DATE (APRIL 1, 2012 ',' DD-MM-YYYY ') AND TO_DATE (5 APRIL 2012 ',' DD-MM-YYYY ')
But how can I fix the time above mentioed.
Please let me know.
Thank you/Tequila
you mean something like this?
If you are using timestamp you can use extract (time deposit)
with t1 as
(select sysdate - 3 / level as dt from dual connect by level < 101)
select dt, to_char(dt, 'HH24') from t1 where to_number(to_char(dt, 'HH24')) < 7
Tags: Database
Similar Questions
-
How to select all the records that have the difference of two dates of greater than a value
Hi all
I have a table as below:
ID creation_date Modify_date
-- ------------- -----------
1 10:11:07.243000000 JANUARY 7, 14 H 10:16:16.865000000 7 JANUARY 14 H
2 13 JANUARY 14 12:07:27.603000000'M 12:08:09.955000000 13 JANUARY 14: 00
I want to select all the IDs that is difference of Modify_date and creation_date is greater than 5 minutes.
Please suggest how to achieve this goal, oracle database.
TIA,
Bob
Select *.
from table_name
where (Modify_date - creation_date) * 1440 > = 5
for timestamp:
Select *.
from table_name
where extract (minute (Modify_date - creation_date)) > = 5
-----
Ramin Hashimzade
-
How to calculate the difference between 2 dates, but with interruptions and stops between
Hello
How can I calculate the difference in minutes between 2 dates but taking into account the existence of a table in the Appendix, so if between start_date and end_date arguments, there is no 'work time' then this part of the time will not be included in the total difference.
Records of the time table example:
Time_configuration start_hour end_day end_hour 2 19:00 3 07:00 3 19:00 4 07:00 so for example first record said that on Monday you start at 19:00 and leave the next day at 7:00 and then save the same sort of thing.
There is an event that I want to track how many minutes lasted. for example, this event began the day 2 at 19:00 and ended the day 3 at 21:00
Theoretically, this event really lasted: 840 minutes. This 840 minutes are within the limits of the annex.
Thanks in advance.
The storage of the dates not as data type DATE in most cases is bad design. In addition, how do you know what day of the date is 2 at 19:00? East - Monday 2 November 2015 or Monday, March 7, 2016? It is the same for the event. In any case, assuming that both calendar and events don't extend over several weeks:
According to schedule)
Select time_configuration 2, 19:00 ' start_hour, end_day 3,' 07:00 ' end_hour of all the double union
Select 3, 19:00 ', 4,' 07:00 ' double
),
event like)
Select event_id 1, time_configuration 2, 19:00 ' start_hour, end_day 3: 21:00 ' end_hour of the double
)
Select e.event_id,
Sum)
less (e.end_day + to_date (e.end_hour, 'HH24'), s.end_day + to_date (s.end_hour, 'hh24:mi')).
greater (e.start_day + to_date (e.start_hour, 'HH24'), s.start_day + to_date (s.start_hour,'hh24:mi'))))
) * 24 * 60 minutes
Appendix s,
e event
where e.start_day + to_date(e.start_hour,'hh24:mi')< s.end_day="" +="">
and e.end_day + to_date(e.end_hour,'hh24:mi') > s.start_day + to_date(s.start_hour,'hh24:mi')
E.event_id group
/EVENT_ID MINUTES
---------- ----------
1 840SQL >
SY.
-
Synchronization of photos for the records of several PC iPAD
Hello
I have pictures in several files in my PC.
I would like to synchronize all at once to my iPAD.
When I opened "Synchronize the Photos" - page in iTunes, it is possible to select only a single folder.
Is it possible to select several folders?
Peter
If the records are directly under the same parent folder then you should be able to select this parent folder at the top of this screen of Photos and records of the child must be indicated below (if you select "Selected folders") for the selection and timing of the iPad for example
If files are located on your computer, then no, you will not be able to select and synchronize them with your iPad - I created a folder separated (with specific subfolders for holidays/events) for the photos that I have synced my iPad
-
Period of time must be selected among the "window period" and "Date".
Hello
Creates reports. In my report, I have a requirement where in measures are calculated for the selected date range. The two parameters for the "selection of"(Date Range) period of time are: to select the 'window period' and 'Date' "»
•Position window period is 5 days.
•Position date should be the date of the day
The report will display data for the last 5 days up to the current date by default.
and the user should be able to choose the length of the latency period.
For example, user should be able to select * 10-day window period * and then see the data from a past date 14/09/2009. The system should then display data from 05/09/2009 to 14/09/2009.
Please let me know how this can be achieved. Any help would be appreciated
Thank you
LeelaDepends on your date format of calendar quick dashboard.
Try this:
FILECONTROLDATA. FIDA_RECEIVEDDATE
between
EVALUATE ('TO_DATE(%1, %2)-%3 'as date', @{date} ', 'yyyy-mm-dd hh24:mi:ss', @{WindowLength})
and
* EVALUATE ('TO_DATE (%1, %2)' as date, ' @{date} ', "yyyy-mm-dd hh24:mi:ss") *.And to see Understanding whose code is gererated in NQQuery.log, I assume you are using the Oracle database.
Concerning
Goran
http://108obiee.blogspot.com -
Fill in the blanks on several words at a time issue
Hello
I know there are other discussions on this topic, but I couldn't find what I want.
I need a slides simple quiz FIB and more than one word (with a drop down menu of each) on this subject.
a. I find extremely difficult to access the menu where you can type ('white') response options. I try to click on the word or the dotted line, but nothing helped. What Miss me?
How can b. I add additional words with a drop-down list to a FIB slide?
As:
"A _ made _ with a _____."
I Don t need to partial credit and I Don t want to use TEB or widgets as I Don t have much time to program something like this.
Is there an easy way?Thank you very much.
You can mark a word or a sequence of words such as 'White' by selecting the word by clicking on "Mark Blank" in the Panel properties of Quiz (CP8 CP9).
The Word Gets a dotted underline. Click on the word and the HUD is displayed with the word typed as the first entry. Use the sign to access more opportunities for input from the user (all correct) or select from the drop-down list and check in this case the possible correct answers, +. I think it is wise to have mixed responses as well for this second scenario.
Click outside the HUD to close. Select the next word and repeat the whole process. Take a look at this screenshot (for a second scenario with drop-down list):
-
find data between specific times in a date range
HII all,.
I'm pretty new in PL/SQL so any help will be greatly appreciated. I'm trying to retrieve data from a set of tables. one of these tables has a field that is a timestamp in the format «dd/mm/yyyy hh24:mi:ss» field asked me to produce data for records that were created between 16:00 and 20:00 between 01/01/2010 and 31/08/2010. I can eat the date of issue, but the question of time is that I'm stuck.
your help would be appreciatedSELECT * FROM my_table WHERE col_date BETWEEN DATE '2010-01-01' AND DATE '2010-09-01' AND TO_NUMBER ( TO_CHAR ( col_date, 'HH24MI' )) BETWEEN 1600 AND 2000;
Now something difficult:
A DATE data type represents a specific time. It's something abstract. There's no format. It is in some cases stored internally, but we know not how (in fact, we know a little). Cannot directly display a DATE value - it is not a text, it is a point in time, it can be established on a calendar and a clock, but not on the screen. DATE FORMAT allows us to tell Oracle how we want it to be converted into a string and displayed. Do we want to day/month/year or year/day/month? Do we want a 24 hour clock 12-hour am/pm or? The same value, the same point in time can be displayed using different channels, produced using different DATE FORMATS. "Friday, September 17, 2010 13:15" is exactly the same point in time as "2010-09-17 13:15" - the only difference is the FORMAT. This allows us to perform several clever tricks with DATE data. Ok?
(If you do not specify a DATE format, and then there are the values by default for your session and for the database. But the principle remains the same: a point-in-time value is converted to a string using the DATE FORMAT). -
Find the slot during several dates
I am unable to find a way to write a statement where clause to pull all the studies 16:00 - 17:00 on a range of dates from 01/09/12-19/09/12
I know that this is possible in a MYSQL and MSSQL database by separating the time out the timestamp and the creation of another filter... one for the date and one for the moment, but in Oracle, I'm not having any luck.
If anyone has any suggestions that would be great!Hello
960108 wrote:
I'm looking to see how many studies have been made in a range of dates from 9/1 to 9/16, but I also need a statement that will allow me not to receive that studies not only these days, but only between 16:00 and 17:00 time.Some examples of code: back would be your base timestamp field
SELECT
patient,
back,
birthday,
raceOf
SA.patientdemo
where
(dos) > = to_date ('2012-06-06 07:30 ', "YYYY-MM-DD HH24")
and (back)<= to_date="" ('2012-06-08="" 16:30',="" 'yyyy-mm-dd="">=>If you want the 1 September 16, then remember to change the conditions above.
To see if the back is between 16:00 (inclusive) and 17:00 (exclusive), regardless of the day, then add this to your WHERE clause:
AND TO_CHAR (dos, 'HH24') = '16'
Who chooses the back in a window that's exctly long 1 hour.
If you want to include to 17:00, so that the window is 1 minute and 1 second, more than an hour, you can do something like this:AND TO_CHAR (dos, 'HH24:MI') BETWEEN '16:00' AND '17:00'
-
Selection of the records that have no referencing records at a small price
I try to get records that has no records of references. Here's the script and test the query I wrote to get the result.
I can get result, but my problem is to lower the cost. This table has more than 50,000 rows. Hope someone can guide me to write a better query.
create table ot_req (rh_sysid rh_txn_type VARCHAR2 (NO.4), rh_ref_sys_id (5), (4), rh_ref_txn_cod VARCHAR2 (5));
INSERT INTO ot_req VALUES (800, 'MR SS', NULL, NULL);
INSERT INTO ot_req VALUES(801,'SSPR',800,'SSMR');
INSERT INTO ot_req VALUES(810,'SSMR',,);
INSERT INTO ot_req VALUES(811,'SSMR',,);
INSERT INTO ot_req VALUES(812,'SSMR',,);
INSERT INTO ot_req VALUES(813,'SSPR',812,'SSMR');
INSERT INTO ot_req VALUES(814,'SSMR',,);
INSERT INTO ot_req VALUES(815,'SSPR',814,'SSMR');
SELECT
rh_sysid
Of
ot_req
WHERE
rh_sysid
PO NO
(SELECT
rh_ref_sys_id
Of
ot_req
WHERE
rh_ref_sys_id IS NOT NULL)
AND
rh_txn_type! = "SŠPR";
Result
RH_SYSID
810
811
Looking forward to your support.
Thanks in advance :)Unus wrote:
My problem is to lower the cost.rh_ref_sys_id will never be sšpr. Only sšpr will reference number
SQL> exec dbms_stats.gather_table_stats(user,'ot_req') PL/SQL-procedure is geslaagd. SQL> set autotrace on SQL> select rh_sysid 2 from ot_req 3 where rh_sysid not in 4 ( select rh_ref_sys_id 5 from ot_req 6 where rh_ref_sys_id is not null 7 ) 8 and rh_txn_type!='SSPR' 9 / RH_SYSID ---------- 810 811 2 rijen zijn geselecteerd. Uitvoeringspan ---------------------------------------------------------- Plan hash value: 2746377339 ----------------------------------------------------------------------------- | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ----------------------------------------------------------------------------- | 0 | SELECT STATEMENT | | 5 | 60 | 7 (15)| 00:00:01 | |* 1 | HASH JOIN ANTI SNA| | 5 | 60 | 7 (15)| 00:00:01 | |* 2 | TABLE ACCESS FULL| OT_REQ | 5 | 50 | 3 (0)| 00:00:01 | |* 3 | TABLE ACCESS FULL| OT_REQ | 3 | 6 | 3 (0)| 00:00:01 | ----------------------------------------------------------------------------- Predicate Information (identified by operation id): --------------------------------------------------- 1 - access("RH_SYSID"="RH_REF_SYS_ID") 2 - filter("RH_TXN_TYPE"<>'SSPR') 3 - filter("RH_REF_SYS_ID" IS NOT NULL) Statistics ---------------------------------------------------------- 1 recursive calls 0 db block gets 14 consistent gets 0 physical reads 0 redo size 469 bytes sent via SQL*Net to client 416 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 2 rows processed SQL> select nvl(rh_ref_sys_id,rh_sysid) rh_sysid 2 from ot_req 3 group by nvl(rh_ref_sys_id,rh_sysid) 4 having count(*) = 1 5 / RH_SYSID ---------- 810 811 2 rijen zijn geselecteerd. Uitvoeringspan ---------------------------------------------------------- Plan hash value: 2435394825 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 1 | 6 | 4 (25)| 00:00:01 | |* 1 | FILTER | | | | | | | 2 | HASH GROUP BY | | 1 | 6 | 4 (25)| 00:00:01 | | 3 | TABLE ACCESS FULL| OT_REQ | 8 | 48 | 3 (0)| 00:00:01 | ------------------------------------------------------------------------------ Predicate Information (identified by operation id): --------------------------------------------------- 1 - filter(COUNT(*)=1) Statistics ---------------------------------------------------------- 1 recursive calls 0 db block gets 7 consistent gets 0 physical reads 0 redo size 469 bytes sent via SQL*Net to client 416 bytes received via SQL*Net from client 2 SQL*Net roundtrips to/from client 0 sorts (memory) 0 sorts (disk) 2 rows processed
Kind regards
Rob. -
Hi Cimmunaute
as you often work and as you say you have a lot of emails: how to remove the masses as delete block? on my old blackberry (except z10 newstes) I had the option "remove all front of (...)". Date"in the context menu, and could remove 1500 emails with a tap. do you know how to do this now? There is not such a function, we have to type and mark each email, even if there are 2000! crazy!
Thank you very much!!
BB: Please urgently add functionality...! I have an imap account with approximately 200 emails a day that are just a copy of the mail of the company and need to delete hundreds every day. I can not press on and select all mails only one and then delete.
Go in the hub, select e-mail account, just under the blue email account, click and hold the date below it, cursor appears on the right, click Recycle Bin (before deletion).
-
How can I select only the records that have more than 1 attached userID?
gurus of the afternoon...
As queries title, I can't find examples by searching the forum then...
Basically, I need to find all the web_user_ids who have more than 1 attribute_code of 'ICX_HR_PERSON_ID' in the table... I tried this but its is not as much as I think it should...
SELECT web_user_id, attribute_code, number_value, COUNT (web_user_id)
AS "Num of administrators."
OF AK_WEB_USER_SEC_ATTR_VALUES
-WHERE attribute_code = 'ICX_HR_PERSON_ID '.
- AND web_user_id = '4123'
Web_user_id GROUP, attribute_code, number_value
SEEN (COUNT (web_user_id) > 1)
ORDER BY web_user_id ASC;
Val
JTry:
SELECT web_user_id, attribute_code, COUNT(web_user_id) AS "Num Of Administrators" FROM AK_WEB_USER_SEC_ATTR_VALUES WHERE attribute_code = 'ICX_HR_PERSON_ID' GROUP BY web_user_id, attribute_code HAVING (COUNT(web_user_id) > 1 ) ORDER BY web_user_id ASC;
Or, better, there is no need to extract the attribute_code:
SELECT web_user_id, COUNT(web_user_id) AS "Num Of Administrators" FROM AK_WEB_USER_SEC_ATTR_VALUES WHERE attribute_code = 'ICX_HR_PERSON_ID' GROUP BY web_user_id HAVING (COUNT(web_user_id) > 1 );
Max
Published by: Massimo Ruocchio, November 12, 2009 16:28
-
How to read/select only the records from a table with non-English characters
Hello
I need to find all records in a table with non-English (mainly Chinese) characters in at least one of the varchar2 columns. Let me kow if someone knows a way by which it can be done using SQL/PLSQL.
Best regards
Imranselect * from your table where your_column != convert(your_column, 'UTF8', 'US7ASCII)
Replace UTF8 with your database character set
Published by: thtsang on October 15, 2009 03:53 - unequal sign change of! =
-
This is what appears whenever I open it. I would be very grateful if someone could help me solve this problem.
Hi FioMio,
See the error you posted in screenshot when Lightroom can't access the Adobe folder in ~/Library and / library
Please make sure that you have added all the users by clicking on the bottom right "+" in permissions in my previous post.
> Go to/Library/Application Support / Adobe / Lightroom and manually create all folders that he said that he could not create
> Other repair permissions using the disk utility
Choose go > utilities.
Double-click disk utility.
Select the volume in the left pane for which you want to repair the permissions.
Click the first aid tab.
Select the volume that you want to install the Adobe application and then click on repair disk permissions.
Hope that helps
Assani
-
How can I configure the computers to stop at a specific time
Hello good people, I work as a computer technician and my manager asked me to find a way to activate the computers in our offices off at 12:00 for example automatically. How can I do this and it is possibel to define computers to start automatically at the precise moment
Say you Manager is probably not a good idea (according to tricky300).
Of course - you can make it work and you can force it to work (at least the part of the judgment), but someday someone will lose their data or it stops while they are in the middle of something (assuming that people could work at 12:00) and they are going to be angry with the one that came with and implemented this idea (which would probably be you - not your manager).
You can make your computer wake up at a certain time, if the system supports such an option (not all systems are supported this option to wake up at a certain time). Or, as tricky300 said, you can use WOL (Wake On Lan), but not all systems support this option either and someone in your IT Department will have to get there.
I would like to ask the manager what is the particular problem, trying to solve and to get a good understanding of the problems, explain the pitfalls of the demi-cuite idea and come up with some other ideas that do not threaten for the work that employees could work on and something that will work for all your systems.
-
selection of the missing records between 2 duplicity without worrying about tables of records
Hi all
I have received_bills and send_bills of 2 tables.
The SEND_BILLS table is the source table displaying all records in it.
I need to compare two tables together and insert all the missing elements in received_items including duplicate records.
There may be duplicate in 2 tables records.
I wrote a query, but it does not select the duplicate records if it's all the 2 tables. When the same duplicate records are send_bills and received_bill without worrying because send_bills has 4 of them and received_bill 2, it does not select the other 2 duplicate records. And it's just what I need.
the query is
SELECT SEND. POINT OF REFERENCE,
Send. PAYMENT,
Send. CODE
OF SEND_BILLS SEND
WHERE THERE IS NOT (SELECT REC. DATUM, PAYMENT, REC. REC. CODE
OF RECEIVED_BILLS REC
WHERE REC. REFERENCE = SEND. SCRATCH CARDS
AND REC. PAYMENT = SEND. PAYMENT
AND REC. CODE = SEND. CODE)
send_bills records
OCTOBER 10, 15 19 A1 OCTOBER 10, 15 19 A1 OCTOBER 10, 15 19 A1 OCTOBER 10, 15 29 A3 OCTOBER 10, 15 47 A4 9 OCTOBER 15 19 A8 OCTOBER 10, 15 20 A1 OCTOBER 10, 15 19 A1 OCTOBER 10, 15 25 A5 OCTOBER 10, 15 25 A5 received_bills records
OCTOBER 10, 15 19 A1 OCTOBER 10, 15 29 A3 OCTOBER 10, 15 47 A4 OCTOBER 10, 15 19 A1 the result of the query is:
OCTOBER 10, 15 25 A5 OCTOBER 10, 15 25 A5 OCTOBER 10, 15 20 A1 9 OCTOBER 15 19 A8 So he selects all the records
the result should be
OCTOBER 10, 15 25 A5 OCTOBER 10, 15 25 A5 OCTOBER 10, 15 20 A1 9 OCTOBER 15 19 A8 OCTOBER 10, 15 19 A1 OCTOBER 10, 15 19 A1 --------------------------------------------------------
-The DOF for Table SEND_BILLS
--------------------------------------------------------
CREATE TABLE SEND_BILLS
(DATE OF "DATUM",
NUMBER OF "PAYMENT."
'CODE' VARCHAR2 (5 BYTE)
) ;
--------------------------------------------------------
-The DOF for Table RECEIVED_BILLS
--------------------------------------------------------
CREATE TABLE 'RECEIVED_BILLS '.
(DATE OF "DATUM",
NUMBER OF "PAYMENT."
'CODE' VARCHAR2 (5 BYTE)
) ;
-Insert the script for send_bills
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 29, 'A3');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('09-OCT-15','DD-MON-RR'), 19, 'A8');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 20, 'A1');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5')
Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5')
-Insert invoices received from script
Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');
Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 29, 'A3');
Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');
Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');
Can someone please help me with the query so that I can also select all the missing records, including duplicates.
Thanks in advance.
Best regards
Caroline
If you should by all means use loop and then (send_bills and received_bills contain the same data as your original post):
Select the reference, payment, code
of (with
Duplicator (Datum, Payment, code, CNT) as
(select the reference, code, payment, cnt - 1).
from (select datum, payment, code, count (one) - cnt count (two)
(select date, payment, code, 1 one, to_number (null) two)
of send_bills
Union of all the
Select datum, payment, code, to_number (null), 2 two
of received_bills
)
Reference group, code
having count (one)! = count (two)
)
Union of all the
Select the reference code, payment, cnt - 1
The duplicator
where cnt > 0
)
Select the reference, payment, code
The duplicator
)
DATUM PAYMENT CODE 10/09/2015 19 A8 10/10/2015 19 A1 10/10/2015 25 A5 10/10/2015 20 A1 10/10/2015 19 A1 10/10/2015 25 A5 Concerning
Etbin
Maybe you are looking for
-
Having read all the info from the help and can't get out of a mode where it goes back to the last session with all the tabs in the condition that they stayed in except the page is not loaded until you go to the tab. I tried false session restore and
-
Some applications won't work in Safe Mode
Hello world I had a few problems with some applications for these past few weeks, they will start only when I'm in Mode safe. It's always the same applications, which include Spotify, Atom.io and website via Safari maps.google.com. I suppose that the
-
Upgraded Vista Business OEM for Vista Ultimate w/o a clean install?
Have Vista Business OEM on my Fujitsu tablet. As said Fujitsu Tablet does not Win 7, I bought a Ultimate Upgrade from Amazon. Everytime I try to upgrade, it tells me that I have to clean install because my version is too old for a upgrade path. To
-
How to view the mail server internal to the secondary address.
Peace, I have a wan with 3 addresses interface, and I have an internal e-mail server. When I send emails from the mail server it appears to the world as primary I address we will tell to x.y.z.67. I want it to appear in the secondary address x.y.z.68
-
When you open one link someone else apears to small to read email?
I get daily emails of a social network and it seems of normal size, but when I click on one of the links in the email, it will appear in very small print so small it cannot be read. This happens also in the links to ebay? Ralph W