Set the start and end of a graph
Hello
I already searched the topic but have not found an answer. I'm a newbie to LabWindows.
I write an application. For the application, there is a graph that shows a signal, axis is-> voltage and x-> time axis. By default the signal starts with the value 0 in the time axis. But my signal does not begin with 0. I would change the start value and the value of the end of the shaft manually. Does anyone know how it works (between AutoScaling)?
I have also two x-axis in my chart. I put them with the offset (10 v and the other to-10V), but I would like to have two x axis starting with the 0 value in different heights. Is it possible to implement who?
Best regards
Tags: NI Software
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Hi guys,.
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OK, here is therefore an update.
The problem is not at all with Photoshop or Cintiq, with Windows 10 parameters of the stylus.
Fortunately, there is a small piece of free software that you can download called "Fix my pen" (by Smith Reddy) which defines the features of Windows Tablet PC in the registry for you (essentially by disabling everything related to it):
viziblr - News - difficulty my pen makes your Wacom tablet JUST WORK on Windows 7
It works fine on Win10 too.
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Fix My Pen sets a lot of things in the registry, but you cannot individually control which setting is disabled. So I guess that one of them is the cause.
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I did a search on the forum for calculating start and end time and found the code depending on which I am using as a formcalc on the duration field.
==============================================================
Form1. Page1.duration::calculate - (FormCalc, client)
If (HasValue (StartTime) and HasValue (EndTime)) then
industrial var = Time2Num (StartTime.formattedValue, "h: mm A")
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on the other
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=============================================================
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To view the results in a regular time format, you can use:
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/ * Formatted 05/20/2013 09:53 (PS5 v5.115.810.9015) * /.
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Hello, can you please help me or guide me in the calculation of the dates of beginning and end to the underside of logic
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Results Required A100 A100,M100,M101,M102,M103,M104 1/1/2010 5/18/2013 A100 A100,M100,M107,M102,M103,M104 5/20/2013 12/31/9999 A101 A101,M105,M106 1/1/2010 12/31/9999
WITH the CLAUSE will make it readable
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REGEXP_REPLACE remove the start and end quotes.
Hello guys,.
I have a problem with my regular expression and I hope someone can help me with this?
Imagine the following sample_data:
{code}
WITH sample_data AS
(
SELECT "'[email protected] "' double UNION ALL e
SELECT "'[email protected] ' double UNION ALL e
SELECT ' [email protected] "' double UNION ALL e
SELECT "'[email protected] "' double UNION ALL e
SELECT ' [email protected] "' double UNION ALL e
SELECT "'[email protected] ' like e dual FROM
)
SELECT e, REGEXP_REPLACE (e, '(^'')? (. *) (''$)', '\2')
OF sample_data;
{code}
I would like to remove all the quotes of beginning and end of the email. I made previous regexp, but she does not return the correct result. I know not why, but for some reason, when my email ends with a quote, the main quotation is not deleted.
Can someone help me with this?
Thank you
Another solution...
WITH sample_data AS (SELECT '''[email protected]''' AS e FROM DUAL UNION ALL SELECT '''[email protected]' AS e FROM DUAL UNION ALL SELECT '[email protected]''' AS e FROM DUAL UNION ALL SELECT '''[email protected]''''' AS e FROM DUAL UNION ALL SELECT '[email protected]''' AS e FROM DUAL UNION ALL SELECT '''''[email protected]' AS e FROM DUAL) SELECT e, REGEXP_REPLACE (e, '(^''+)|(''+$)') FROM sample_data
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How can I get the following result
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09:30 1 100
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can someone help me?It should work
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Test case with the smaller date range
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Thanks to Solomon Yakobson to its solution on thread:
I found the solution from there.
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How does the index start and end in the reference Word text VI to a word document?
How a correlation between the index values start and end to a position or coordinate in a Word document?
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The start and end of the Text.vi in Format Word values are the positions of the characters in the document. The values start at 0 on the first (or ASCII character such as a space, tab, or carriage return) and for each character (or the ASCII character). So for example if I wanted to "BOLD" the word "carrots" in the list below, where the values start at 0 on the word 'grocery store '.
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Then I would enter a start 33 and the end of the 40s, making sure to count the ramasseherbe returns and spaces.
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I have to add the start and end dates to my flex belt and make it visible on the plus edition + inspect mode. For the Fund, it is STANDARD, but I have an obligation to do so for other assets that is not active promotion.
Is there any doc/blog I can do? Help, please.
Hi Avi.
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CS.sitepreview = ContentManagement
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Hello:
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How to seek early and dates of activity in the secondary database or tertiary reference end? There are areas of activities and methods provided in planning extraction and primary base line project (active class getBaseline1StartDate(), getBaseline1FinishDate) but can't find any secondary data or tertiary basis even if we show them in details the activity in the Primavera. I use Primavera integration API version 8.2.
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Hi all
Need your help to solve a SQL query
My data like this look
year of CID rid
52 1000 2001 1
52 1000 2002 1
52 1000 2003 6
52 1000 2004 6
52 1000 2005 6
52 1000 2007 1
52 1001 2003 1
52 1001 2004 1
52 1001 2005 1
52 1001 2006 3
52 1001 2007 3
I need to produce the output is
CID RID TITLE START AND END
52 1000 2001 - 2002 1
52 1000 2003 - 2005 6
52 1000 2007 - 2007 1
52 1001 2003 - 2005 1
52 1001 2006 - 2007 3
-----------
Here's the script for the table and data
create table T)
CID NUMBER,
rid the NUMBER,
start_year NUMBER,
title NUMBER
);
Insert into t (cid, RID, start_year, title) values (52, 1000, 2001, 1).
Insert into t (cid, RID, start_year, title) values (52, 1000, 2002, 1).
Insert into t (cid, RID, start_year, title) values (52, 1001, 2003, 1);
Insert into t (cid, RID, start_year, title) values (52, 1000, 2003, 6);
Insert into t (cid, RID, start_year, title) values (52, 1001, 2004, 1);
Insert into t (cid, RID, start_year, title) values (52, 1000, 2004, 6);
Insert into t (cid, RID, start_year, title) values (52, 1001, 2005, 1).
Insert into t (cid, RID, start_year, title) values (52, 1000, 2005, 6);
Insert into t (cid, RID, start_year, title) values (52, 1001, 2006, 3);
Insert into t (cid, RID, start_year, title) values (52, 1001, 2007, 3);
Insert into t (cid, RID, start_year, title) values (52, 1000, 2007, 1);
commit;
I managed to go as far (some as close to what I need but not exactly what I need)
Select the title, max (year1), min (year2), cid, RID
de)
Select tc.cid, tc.rid, tc.title, tc.start_year year1, year2, tp.start_year, decode (tc.title, tp.title, 'n', 'Y') gap
t tc,.
t tp
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and tc.cid = tp.cid
and tc.rid = tp.rid
)
Cid group, RID, title, gap
Thank you for thinking
Ngoyi,
Houston-TexasHi, Ngoyi,
Here's one way:
WITH got_grp_id AS ( SELECT cid, rid, start_year, title , ROW_NUMBER () OVER ( PARTITION BY cid, rid ORDER BY start_year ) - ROW_NUMBER () OVER ( PARTITION BY cid, rid, title ORDER BY start_year ) AS grp_id FROM t ) SELECT cid , rid , MIN (start_year) || '-' || MAX (start_year) AS start_end , title FROM got_grp_id GROUP BY cid, rid, title, grp_id ORDER BY cid, rid, start_end ;
Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.
Still, it would be more useful if the sample data and the results don't always have the same value in a column. I'm just guessing at what cid and get rid of play in this problem.
Also, thanks for posting your request. It helps to understand the problem.For an explanation of the technique of Difference sets used in the above query, see {message: id = 9953384} and/or {message: id = 9956917}
Published by: Frank Kulash, March 23, 2012 13:34
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I need to be able to use the coordinates xy of the pano_mc captured by the delivery, to set the starting point of the interpolation which then tweens the movie at a predefined point... create an interpolation of seemless...
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