Streaming media files by using Manager.createPlayer)

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  I am developing a lot of web project, and I'm using localhost.

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  Agree with the statement of what Murray...

  However, you have explained on an error...

  I realize this problem when sending to the real server and received the error

  Do you remember the exact error message?

  Check the settings of your site server. It is same as defined by you at the first time when the definition of the site.

  Try the Site cache recreate: select your site > Site Menu > advanced > recreate Site Cache.

  In addition, you can also try re-creating the preferences of DW. Backup you old preferences on the desktop before recreating them.
  http://kb2.Adobe.com/CPS/839/cpsid_83912.html

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  Hi stephanie,.

  Thanks for joining us out on Microsoft Community Forums.

  Looks like the Windows firewall prevents the discovery network, files and printers, sharing, public sharing of files and streaming media. We will analyze and identify the cause of the problem.

  You have a third-party antivirus installed on the computer program?

  Method 1:

  To turn on network discovery
  
  1. Open advanced sharing settings by clicking the Start button, then Control Panel. In the search box, type network, click Network and sharing Center, and then, in the left pane, click on change settings for sharing advanced.
  2. click on the chevron to expand the current network profile.
  3. click turn on network discovery and then click on save changes. If you are prompted for an administrator password or a confirmation, type the password or provide
  confirmation.

  The article below explains all about the network discovery:
  http://Windows.Microsoft.com/en-us/Windows7/enable-or-disable-network-discovery

  If any of these responses not solve the issue, let us then run the sfc scan and check if any file system is corrupt. I also recommend to perform a clean boot in order to find the root cause of the problem.

  Method 2:

  Use the (SFC.exe) System File Checker tool to determine which file is causing the problem and then replace the file. To do this, follow these steps:

  a. open an elevated command prompt. To do this, click Start, click programs, accessories principally made, right-click Guest, and then click Run as administrator. If you are prompted for an administrator password or a confirmation, type the password, or click on allow.

  b. type the following command and press ENTER:
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  More information on SFC scan found in this document:
  http://support.Microsoft.com/kb/929833

  See also:

  Open a port in Windows Firewall

  http://Windows.Microsoft.com/en-in/Windows7/open-a-port-in-Windows-Firewall

  Allow a program to communicate through Windows Firewall

  http://Windows.Microsoft.com/en-in/Windows7/allow-a-program-to-communicate-through-Windows-Firewall

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• Problems with Manager.createPlayer)

  Hello

  I'm new in the world of development of BB... I'm doing a simple application that retrieves a file from a URL .wav and it plays, but the process is stuck on Manager.createPlayer (URL).

  I ran the application using the debugger and when it comes to this line he says 'source not found', here's a snippet of what I'm trying to do:

  public class MyPlayer implements PlayerListener, passable
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  Player;

  (I call this my main application thread and start it)

  {} public void start()
  Thread t = new Thread (this);
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  void run() {}
  try {}
                     
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  make the player
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  }

  The funny thing is that I tried the same code with a MIDlet and it works well in Nokia and Sony Ericsson simulators, but Blackberry is locked. I'm missing something here?

  I use Eclipse IDE, BlackBerry JDE component Pack Version: 4.5.0.16 and the Simulator Curve BlackBerry 8300 that come with the JDE.

  I also tried the application in a BlackBerry Pearl Simulator, with the same results

  Any advice will be highly appreciated = (...)

  I found the solution, the problem was that my emulator had no access to the internet, when he tried to connect to the URL and get the .wav file it so never found the source.

  I downloaded Blackberry email and MDS services Simulator package, which allows the internet connection for the simulators, and it worked!

  I could connect to the URL and play the .wav

• simple code help with streaming 1 file

  I created the Flash Media Server 2.0 on Windows (test box) under the dl35.tamu.edu of the host (behind a firewall, so I don't mind giving it)
  Under the application directory, I create a directory named test
  In this directory I place a flash called motion.flv film
  In this same directory, I copy the main.asc that comes with Flash 8 software
  I load the application of 'test' and use _definst_ as instance name
  
  In Flash Professional 8, I create a new fla called test.fla
  I incorporate a movie and use the ClearOverAll.swf as the skin for the film.
  On the settings tab I have change the path of advanced content to rtmp:"//dl35.tamu.edu/test/_definst_/motion.flv
  I have test produces the HTML and indeed the server indicates a connection even if nothing is playing.
  
  This is probably where I'm more confused, but I could have done something wrong with the above as well. I'm not a Flash programmer, I'm a network guy. All I want to do is the bare minimum in the simplest form of streaming. I couldn't find examples of code that worked including the tutorial on the Adobe site (which seems to be fairly widespread). Search in other examples I "think" I found what I wanted, but apparently I don't implemented it correctly or not what I need after all and I would like someone to check. Here it is the action script that I found that I placed in the test.fla. Is it bad to do?
  
  NC = new NetConnection();
  NC. Connect ("rtmp://dl35.tamu.edu/test/_definst _");
  
  NS = new NetStream (nc);
  my_video.attachVideo (NS);
  ns.setBufferTime (0);
  NS. Play ("test");
  
  Is the above correct? Given names, again, what needs to be changed. Also should this same go here? Is it supposed to be in a file by itself action script? In any case when this product in html format, there are several errors:
  
  * Error * scene = scene 1, layer = Layer 1, frame = 1:Line 16: statement must appear in the onClipEvent/Manager
  NC = new NetConnection();
  
  * Error * scene = scene 1, layer = Layer 1, frame = 1:Line 17: statement must appear in the onClipEvent/Manager
  NC. Connect ("rtmp://dl35.tamu.edu/test/_definst _");
  
  * Error * scene = scene 1, layer = Layer 1, frame = 1:Line 19: statement must appear in the onClipEvent/Manager
  NS = new NetStream (nc);
  
  * Error * scene = scene 1, layer = Layer 1, frame = 1:Line 20: statement must appear in the onClipEvent/Manager
  my_video.attachVideo (NS);
  
  * Error * scene = scene 1, layer = Layer 1, frame = 1:Line 21: statement must appear in the onClipEvent/Manager
  ns.setBufferTime (0);
  
  * Error * scene = scene 1, layer = Layer 1, frame = 1:Line 22: statement must appear in the onClipEvent/Manager
  NS. Play ("test");
  
  Total ActionScript errors: 6 reported errors: 6
  
  Goal: All I want to do is stream 1 file... only 1. I have no way of knowing if this server works before taking this simple step. It would be nice is Adobe delivered out of the box streaming samples like all other servers continuously, we support do. But I digress. Any help is appreciated beyond all means I can transmit properly including a working example of code package that I can change just a few lines then I can understand what is happening.

  Imstamu, I'm relatively new to myself, but I noticed a few things in your message that I wanted to comment. First, you come up with the error messages can be the result of putting the actionscript code in the video object itself, rather than in the scenario for the main SWF movie. What I think that you can do is put the actionscript code in a layer called 'Actions' in the main timeline, select the keyframe for that layer 1 frame and put the ActionScript in this key frame. If you put in the video object (or another object such as a button, etc.), you can get errors of the type you declare (at least it happened to me). However, as shown below, you may not need as actionscript at all.

  Second, you can try placing a directory under the 'test' directory called 'streams', another directory called "_definst_" under the "streams" directory and put the FLV file in the _definst_ directory. This is where FMS is looking for the files to stream, if I understand correctly. (It appears from your description that you have placed the FLV file directly below 'test'). To test level * is * the right place for main.asc, like you did. IMPORTANT: Regarding the path that you use in the variable contentPath in the video player object, the path for the directory in fact holding the FLV file must * always * be rtmp://dl35.tamu.edu/test/_definst_/motion.flv, as you have done - that is to say, "broadcasts" should not be included in the contentPath variable. Don't ask me why, but it worked for me. The reason why the server is showing a connection is that you put a directory 'test' in the right place and so entered the application from the point of view of the FMS, but you don't have the FLV file in the right place, and SGF therefore cannot find the FLV file in the path that you specified.

  Third, using the FLVPlayback component in the swf file? (By the way that you use one of the Flash skins canned, looks like it is the case.) If so, and if you are just streaming a movie, you don't need to worry about the code to open a new NET connection, new netstream, etc - all this is integrated in the FLVPlayback object. So all you have to do is put in the RTMP path to the file - rtmp://dl35.tamu.edu/test/_definst_/motion.flv--dans the contentPath for the FLVPlayback object variable. you need not code opening the NetConnection and NetStream objects.

  I hope it's useful. As mentioned, I'm pretty new myself, but I was able to stream files successfully using FMS, FLV and Flash.

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  but when I create the player a ClassCastException is thrown.
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  I can't figure out how to solve this problem... someone has any advice?

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  Hey people,

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                  inputStream.close();
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          }
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  EDIT: I meant, the code works on os<>

  Hey,.

  Thank you much for the help. Impossible to get your solution work, maybe because I won't read SD card. My solution if it helps anyoneL

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      boolean keepPlaying = false;
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              }
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              m_Player = javax.microedition.media.Manager.createPlayer(is, "audio/mp3");
              m_Player.realize();
              m_Player.prefetch();
  
              VolumeControl vc = (VolumeControl) m_Player.getControl("VolumeControl");
  
              m_Player.setMediaTime(-1);
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              m_Player.addPlayerListener(new extendedPlayerListener(file, continuous, this));
  
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              ex.printStackTrace();
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      }
  
      public void stopSound()
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          if (m_Player == null)
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              try
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                      m_Player = null;
                  }
              } catch (Exception e)
              {
              }
  
          } catch (MediaException ex) {
              ex.printStackTrace();
          }
      }
  }
  
      class extendedPlayerListener implements PlayerListener
      {
          String file;
          boolean playContinuous;
          CDSoundPlayer player;
  
      public extendedPlayerListener(String file, boolean b, CDSoundPlayer player) {
          this.file = file;
          this.player = player;
          playContinuous = b;
      }
  
      public void playerUpdate(Player player, String event, Object eventData) {
          if (event.equals( PlayerListener.END_OF_MEDIA))
          {
              this.player.stopSound();
              if (playContinuous)
                  this.player.playSound(file, playContinuous);
          }
      }
  

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  My wmp streaming media has been disabled by me, since I want except or stream or play my media files with other users.

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  Hello!
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  When I try to install Media Streaming on Win 7 Home Premium 64 - bit, using Control Panel/Network Sharing Center/Media Streaming Options, I find the following strange problem.  The "show devices on:" drop-down list has no content and does not allow me to select anything.  On my Win 7 wife's computer, this dropdown allows of me selcet is "all networks" or "local networks".  I discovered this error when I bought an XBox 360 and setup of Windows media Center on it.  Windows Media center on the XBox can connect to my PC and play all the music in my library of music through Media Center, but the XBox can't find my pc on the network using the music library or picture library.  My PC does not list the XBox when I "see the network computers or devices", but nor does my wife's PC.

  I am confused as to how my XBox has been so easily connected to my PC and continues to work perfectly in the application of the XBox, Windows Media Center, and still fails to find my PC or browse its contents through its other music/photo/media applications.

  I have no problem connecting to XBox Live or on the internet.

  Any ideas?

  Hello

  Follow the steps described in the links below: reading your media to devices and computers using Windows Media Player: http://windows.microsoft.com/en-US/windows7/Stream-your-media-to-devices-and-computers-using-Windows-Media-Player

   

  Change settings for streaming media in Windows Media Player: http://Windows.Microsoft.com/en-us/Windows7/change-settings-for-streaming-media-in-Windows-Media-Player

  Also, you can try to temporarily disable anti-virus and check if you can get the opportunity to play and play on your Play Station 3.

  Share you must have under 'Network and Internet' a 'homegroup' set in place with share pictures etc. with controlled devices. You must also have under 'Network and Media Center' 'share with media devices' network Local set to "allow all". You can easily access these via WMP12, if you look under the drop down menu "share", it's the two base units, just select those to go to the relative Panel.

  All the media you want to share must be stored in the folder 'Libraries' relative to the topic. For some reason, videos are available to select the "folders" on the PS3, if you select 'All videos' only the recorded TV shows samples sample wtv file, which

  It will be useful.