The left join - no data in the table don't want to display the data from the table one

Similar Questions

• What is the best strategy to migrate data from Windows to one Mac to another? I use Parallels Desktop to run Windows on my current Mac but want to use Bootcamp on my new.

  What is the best strategy to migrate data from Windows to one Mac to another? I use Parallels Desktop to run Windows on my current Mac but want to use Bootcamp on my new.

  If it is only the data (not apps) I use Dropbox. It turned out to be the best way to move things between the side Mac and the bootcamped Windows of my iMac side. I don't see why it would not work to move data from a virtual machine installation of Win to a BootCamp installation.

• How can get rid you of the bookmarks I don't want everything at once without having to delete one by one. Step by step please.

  How can delete multiple bookmarks that I don't want everything at once without having to delete one by one in the menu dropdown. Step by step please.

  Click the Favorites button in your menu and then "show all bookmarks" (or Ctrl + Shift + O). On the left side, you can click on toolbar or Bookmarks menu or Unsorted Bookmarks bookmarks (depending on where you have saved the). Now you can mark multiple bookmarks by pressing the Ctrl or the SHIFT key and clicking on it and pressing then on delete.

• I installed Photoshop elements 12 from a CD on my laptop. I think to buy a Tablet, so I was wondering if (a) can be installed on a 2nd unit (b) can use the serial number online because I don't want to beable to install from a CD, and (c) I will beabl

  I installed Photoshop elements 12 from a CD on my laptop. I think to buy a Tablet, so I was wondering if (a) can be installed on a 2nd camera (b) can use the serial number online because I don't want to beable to install from a CD and (c) I will beable to choose a mac, after the initial report was on a PC? Thanks Martin

  A single user license for activating facilities on both machines. A license of elements allows for each platform in many cases (recently not the case from what I've seen).  If you have the disc, see if it contains the Mac installation files... If not then you should be able to install them via download as well.  I can't answer with any certainty to the last question because it depends on the previous question.  Personally, I wouldn't let an inexpensive piece of software not dictate a decision to purchase expensive equipment.

• I have a panel of serch the history on the left side of my page, and I don't want and can't get rid of it!

  I got this Panel of historical research on the left side of my pages on Mozilla Firefox after downloading updates today. I can't click it, drag it or otherwise do anything... Help!

  You can enable or disable the Panel aside historical/off tension with "Ctrl + H".
  The sidebar story works for me, if you change the view in the sidebar "by last visit."

  The side bars can be viewed or deleted through the display (menu) > toolbars by clicking on a sidebar to use/replace/remove what one toolbar can be shown at once.
  If you don't see the view menu, press 'Alt' (or 'F10')

  You can make Firefox 6.0.2 resemble Firefox 3.6.21, see numbered items 1-10 of the next topic difficulty Firefox 4.0 UI toolbar, problems (make Firefox 4.0 to 8.0, resemble 3.6). If you make changes, you must be aware of what has changed and what it takes to use changed or missing features.

  • http://dmcritchie.MVPs.org/Firefox/Firefox-problems.htm#fx4interface

• Left join of the two tables and multiple values into a single value separated by commas

  Hello

  I have following tables with their structures and their data as below.

  CREATE TABLE 'BETODI '. "" BETINFO ".

  (

  VARCHAR2 (8 BYTE) "CURRENTPRESS."

  ENABLE 'TYPEIDCONTAINER' VARCHAR2 (30 BYTE) NOT NULL

  )

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24D', 'Pensky-MARTENS');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A25D", "CMP");

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A25G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26D', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A32G", "V-BFC3");

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A32D', "V-BFC2");

  CREATE TABLE 'BETODI '. "" BETMASTER ".

  (

  ACTIVATE THE "CUREPRESS" TANK (5 BYTES) NOT NULL,

  ACTIVATE THE "TYPE" VARCHAR2 (5 BYTE) NOT NULL,

  NUMBER (5.0) "LASTPCIRIM".

  )

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A24', '45 M 8', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A25', 42 16', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A26", 16' 45, 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A27", '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A28', '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A29', '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A30', '45MCH', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A31", "45MCH", 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A32', '45MCH', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A33', '45MCH', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A34", "45MCH", 16);

  These two tables have left join as

  BETMASTER. CUREPRESS = substr (BETINFO. CURRENTPRESS, 1, 3)

  now I want to have the data in the two tables with fields Curepress, Lastpcirim, typeidcontainer.

  Also something like

  Make a group of typeidcontainer if this value is greater than 1 by press separated the values of semicolon (;)

  So, for example above, we should be given as

  A24 PMC 15; PENSKY-MARTENS

  A25 15 PMC

  A26 15 PMC

  A27 16 (NULL)

  A28 16 (NULL)

  A30 15 (NULL)

  A31 16 (NULL)

  A32 16 BFC2-V; V BFC3

  A33 16 (NULL)

  A34 16 (NULL)

  How could do?

  My current request is as

  Select distinct Curepress, lastpcirim, typeidcontainer

  BETMASTER STD left join INF BETINFO

  on the trim (STD. CUREPRESS) = substr (trim (INF. CURRENTPRESS), 1, 3)

  but I am unable to get the values separated by commas.

  Any help would be appreciated.

  Thank you

  Mahesh.

  Hi, Mahesh,

  If you want to only 1 row of output for each distinct combination of currentpress and lastpcirim?  This sounds like a job for GROUP BY.

  And you want the row to contain a list of all different typidcontainers-delimited?  This sounds like a job for the aggregate LISTAGG function.

  WITH joined_data AS

  (

  SELECT DISTINCT

  MST.curepress, mst.lastpcirim, inf.typeidcontainer

  OF betmaster STD

  LEFT JOIN betinfo ON TRIM (mst.curepress) inf = SUBSTR (TRIM (inf.currentpress)

  1

  3

  )

  )

  SELECT curepress, lastpcirim

  LISTAGG (typeidcontainer, ',')

  THE Group (ORDER BY typeidcontainer) AS container_list

  OF joined_data

  Curepress GROUP, lastpcirim

  ;

  Unfortunately, you can't say LISTAGG (DISTINCT ...), so you should always get the separate containers how you already are.  (Note that the subquery is just what you posted).

  Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.  Don't forget to tell what version of Oracle you are using.  LISTAGG was new in Oracle 11.2.

  Why not add CHECK constraints (and perhaps triggers) to your tables, so that curepress and currentpress are not stored with the head or trailing spaces?  Then you wouldn't need to use the PAD in queries like this, and your code would be simpler and more effective.

• How to join two tables to retrieve the data from the columns in table two. Tables have primary and foreign key relationships

  Hello

  I want to join the two tables to retrieve the data from the columns of the two table passing parameters to the join query. Tables have primary and foreign key relationships

  Details of the table

  Alert-1 - AlertCode (FK), AlerID (PK)

  2 AlertCode-AlertDefinition-(PK)

  Help, please

  
  

  ----------
  

  Hi Vincent,.

  I think that you have not worked on adf 12.1.3.  In adf 12.1.3 you don't have to explicitly create the association. When you create the EO to your table, Association xxxxFkAssoc, will be created by ADF12.1.3 for you automatically. Please try this and do not answer anything... You can also follow the links below. I solved the problem by using the following link

  Oracle ADF Guide step by step - Oracle ADF tutorial: creating a relationship of the master / detail using Oracle ADF

  ---

• Seen the lock of brain on Left Join

  Always on Oracle 11.2.0.1.0
  
  Examples of data
  

  CREATE TABLE theEmails (
  RID NUMBER(10) PRIMARY KEY,
  employee NUMBER(6),
  emailType VARCHAR2(4),
  emailAddress VARCHAR2(50),
  emailActive number(1)
  )
  ;
  INSERT INTO theEmails VALUES(778437,231509,'OTHR','[email protected]',0);
  INSERT INTO theEmails VALUES(847168,231509,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(784690,231509,'OTHR','[email protected]',1);
  INSERT INTO theEmails VALUES(1459884,239868,'OTHR','[email protected]',0);
  INSERT INTO theEmails VALUES(1485781,239868,'OTHR','[email protected]',1);
  INSERT INTO theEmails VALUES(1485782,239868,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(1501028,231509,'WRK1','[email protected]',1);
  INSERT INTO theEmails VALUES(1492288,239868,'WRK1','[email protected]',1);
  INSERT INTO theEmails VALUES(1456785,239865,'OTHR','[email protected]',0);
  INSERT INTO theEmails VALUES(1489166,239865,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(1482668,239865,'WRK1','[email protected]',0);
  INSERT INTO theEmails VALUES(1482667,239865,'OTHR','[email protected]',1);
  
  
  
  CREATE TABLE thePeople (
  employee NUMBER(6),
  recordNum NUMBER(2),
  lastName VARCHAR2(20),
  firstName VARCHAR2(20)
  )
  ;
  
  INSERT INTO thePeople VALUES(231509,0,'P','Michelle');
  INSERT INTO thePeople VALUES(239868,0,'K','Dan');
  INSERT INTO thePeople VALUES(239865,0,'T','Mary');

  So, here is my SQL that does not work well:
  

  SELECT p.employee, p.recordNum, p.lastName, p.firstName, e.emailaddress, e.emailactive, e.emailtype
  FROM thePeople p LEFT JOIN theemails e ON p.employee = e.employee
  WHERE (e.emailactive = 1)
        AND
        (e.emailtype = 'WRK1')
        AND
        (e.emailaddress LIKE '%school.edu')
  ;

  AND this:
  

  SELECT p.employee, p.recordNum, p.lastName, p.firstName, e.emailaddress, e.emailactive, e.emailtype
  FROM thePeople p LEFT JOIN theemails e ON p.employee = e.employee
  WHERE (e.emailactive = 1 OR e.emailactive IS NULL)
        AND
        (e.emailtype = 'WRK1' OR e.emailtype IS NULL)
        AND
        (e.emailaddress LIKE '%school.edu' OR e.emailaddress IS NULL)

  Both give me this:
  
  employee | record | lastName. firstName. emailAddress. emailActive | emailType
  231509 | 0 | P     | Michelle | [email protected] | 1. WRK1
  
  
  But what I need is the following:
  employee | record | lastName. firstName. emailAddress. emailActive | emailType
  239868 | 0 | K     | Dan |      |     |
  231509 | 0 | P     | Michelle | [email protected] | 1. WRK1
  239865 | 0 | T     | Mary |          |
  
  
  Email from Dan is not included, because his "wrk1" email does not stop it school.edu
  E-mail Mary is not included, because his 'wrk1' email is not active.
  However, I need to come back with their numbers of name registration and employee.
  
  
  Once it works, I'll add employee = number in the WHERE clause, because I only need to find a person both for the actual production.
  
  What I am doing wrong?
  
  Thank you!
  
  Michelle

  Hello

  WHERE is the filtering actually record the selection.

  In your case, you might want to include in your LEFT OUTER JOIN ON conditions:

  SELECT p.employee, p.recordnum, p.lastname, p.firstname
       , e.emailaddress, e.emailactive, e.emailtype
    FROM    thepeople p
         LEFT JOIN
            theemails e
         ON     p.employee = e.employee
            AND e.emailactive = 1
            AND e.emailtype = 'WRK1'
            AND e.emailaddress LIKE '%school.edu';
  

  If you put them in your JOIN conditions actually join Chronogram of table theemails that adapt to the conditions of membership.
  As you use LEFT [OUTER] JOIN unmatched chronogram thepeople table will be displayed even when the theemail table column appears with a NULL value in the output files

  I hope that I was able to unlock your brain. :-)

  Kind regards.
  Al

  Published by: Alberto Faenza on 25 October 2012 16:58
  Additional note added

• Left outer join without data in a table

  I have two tables defined (see below). Emp table has given, and there is still no data in the table of Emp_Type! Now it is empty.
  
  I want to write a query that returns the data from the tables, even if there is no data in the Emp_type table. I use a left outer join but it return nothing. Can anyone help?
  

  create table EMP
  (
    EMPID   NUMBER(10,2),
    EMPNAME VARCHAR2(100)
  );
  
  INSERT INTO emp (empid,empname) values (1, 'Mark');
  INSERT INTO emp (empid,empname) values (2, 'Jason');
  INSERT INTO emp (empid,empname) values (3, 'Kevin');
  INSERT INTO emp (empid,empname) values (4, 'Drew');
  INSERT INTO emp (empid,empname) values (5, 'Jessica');
  INSERT INTO emp (empid,empname) values (6, 'Pena');
  INSERT INTO emp (empid,empname) values (7, 'Roxanne');
  
  create table EMP_Type
  (
    ID          NUMBER(10,2),
    EMPID       NUMBER(10,2),
    TYPE_ID     NUMBER(10,2),
    END_DATE    DATE
  );
  
  No data
  
  select *
    from emp e
    left outer join emp_Type t
      on e.empid = t.empid
   WHERE t.type_id = 1
     and t.end_date is null;

  WHERE t.type_id = 1

  will be ever true when table has no rows (or t.type_id is NULL?)

• LEFT JOIN increases the number of lines

  Hi guys,.

  I had a problem, my left join retrieves multiple values. I know he has only 252 in there that correspond to the place where

  condition. If I use the table in a left join with the same condition where my row count increases.

  -1176 lines

  Select count (erg_ID) of

  MySchema. T_STA_ERG sta_erg

  INNER JOIN T_MEN hoechst

  ON sta_erg. PARAMETER = hoechst. PARAMETER

  AND sta_erg. JAHR = 2014

  where sta_erg. MESSERG_KNG = 'A' AND sta_erg. MESSERG_ALPHA IN ('03 ") and sta_erg. NORM_MESS is null

  -252 lines

  Select distinct erg_ID myschema. T_STA_ERG sta_erg where sta_erg. MESSERG_KNG = 'A' AND sta_erg. MESSERG_ALPHA IN ('03 ") and sta_erg. NORM_MESS is null

  any clue´s how I can build in conditions in my join which would not increase the results of the line?

  Why not just an inner join then?

• How to avoid the union and use a left join

  Hello

  I have the following tables

  {code}

  create the table mainTable

  (col1 varchar2 (2) varchar2 (2) col2, col3 varchar2 (2), col4 varchar2 (2));

  create table secTable

  (col1 varchar2 (2));

  create the table secTable1

  (col2 varchar2 (2));

  create the table secTable2

  (col3 varchar2 (2));

  Insert in maintable

  values ('a', 'b', 'this,' would be ');

  Insert in maintable

  values (', 'o', 'n', 'p');

  insert into secTable

  values ('a');

  insert into secTable1

  values ('b');

  insert into secTable2

  values ('c');

  commit;

  {code}

  I made a request, drank, I would use join without clause union how can I change to receive the same result as the following query?

  {code}

  	Select t1.*, 'bad value' | T1.Col1
  	from maintable t1
  	T1.Col1 left join t2 = t2.col1 sectable
  	where t2.col1 is null
  	Union of all the
  	Select t1.*, 'bad value' | T1.col2
  	from maintable t1
  	Join t2 left on t1.col1 = t2.col2 sectable1
  	where t2.col2 is null
  	Union of all the
  	Select t1.*, 'bad value' | T1. COL3
  	from maintable t1
  	Join t2 left on t1.col1 = t2.col3 sectable2
  	where t2.col3 is null

  {code}

  Thank you

  Coco

  Like this?:

  SQL > SELECT col1, col2, col3, col4, xvalue

  2 from (SELECT m0.*

  3, NVL (t0.col1, 'bad value t0' | m0.col1) t0_col1

  4, NVL (t1.col2, 'bad value t1' | m0.col2) t0_col2

  5, NVL (t2.col3, 'bad value t2' | m0.col3) t0_col3

  Maintable m0 6

  LEFT OUTER JOIN sectable t0 7

  8. WE (m0.col1 = t0.col1

  9 AND t0.col1 IS NULL)

  10 LEFT OUTER JOIN sectable1 t1

  11. WE (m0.col1 t1.col2 =

  12 AND t1.col2 IS NULL)

  13 LEFT OUTER JOIN t2 sectable2

  14. WE (m0.col1 = t2.col3

  15 t2.col3 AND IS NULL))

  16 UNPIVOT INCLUDES NULL values (xvalue wrongly IN (t0_col1, t0_col2, t0_col3))

  17 ORDER BY xvalue

  18.

  COL1 COL2 COL3 COL4 XVALUE

  ------ ------ ------ ------ ---------------------------------------------------

  a b c d bad value t0 a

  m o n p bad value m t0

  a b c d bad value t1 b

  m o n p o t1 value of evil

  a b c d bad value t2 c

  m o n p value t2 n bad

  6 selected lines.

• Must use the nested left join syntax?

  I am currently an editing view. The view has one with a followed left join to an inner join such as this:
  
  Select
  T1.a,
  T2.b,
  T3.c
  Of
  (select 1 as a Union double all the)
  Select 2 as double
  ) t1
  left join
  (select 1A, 11 b of all the double union)
  Select 2A, 12 b of the double
  ) t2
  on t1.a = t2.a
  Join
  T3 (select 11 b, 14-c double)
  on t2.b = t3.b;
  / * - Try out: -.
  A, B AND C
  ------- ------- -------
  1-11-14
  */
  
  The inner join converts left join in an inner join "de facto"? should I use nested join syntax in order to get the other ranks:
  
  Select
  T1.a,
  T2.b,
  T3.c
  Of
  (select 1 as a Union double all the)
  Select 2 as double
  ) t1
  left join
  (select 1A, 11 b of all the double union)
  Select 2A, 12 b of the double
  ) t2
  on t1.a = t2.a
  Join
  T3 (select 11 b, 14-c double)
  on t2.b = t3.b;
  / * - Try out: -.
  A, B AND C
  ------- ------- -------
  1-11-14
  */

  Sorry, just saw your last join condition now:

  on t2.b = t3.b;
  

  This results in a JOIN INTERNAL to the EXTERNAL table JOINED to, will certainly lead to a result of diminshed set - not quite the same that forced an INNER JOIN, but the result is the same, Yes. So there are indeed of equivalence.

  This, however, would not have resulted a reduced resultset:

  on t1.a = t3.a;
  

  But of course it is not possible, since the t3 has a column "a".

• Using data from the control table

  Hello

  I would like to use the data entered in a table to automate volume/sequence of airflow for a test Chamber. As shown in the screenshot of control table, the first column indicates the number of iterations by elements of array in a series of tests and the second data column specifies the length of each line sequence. Entries in the other columns are specific to different valves and specify values set required in the flow meter.

  

  I guess my question is how can I index/assign each column of the table such that the data to exploit the respective valves are obtained in subsequent iterations all acquire simultaneously with data from other components in the order? While I recognize that the solution may be very simple, I searched on through various examples and messages on the tables and the tables without knocking on a solution. The attached .vi allows me to be a part of the series of tests.

  Best regards

  Callisto

  Hi Callisto,

  If I understand your question then the solution is actually quite simple. The important point to keep in min is the fact that the Table control can actually be treated as an array of string. You can then use all the traditional table manipulation tools and techniques to manipulate your data as you wish. For example, use the Array Index function to retrieve specific columns and then if you want to spend the individual elements in a column in a loop, wire the table until the loop and ensure that indexing is enabled. If you then want to use these data elements to control your test application, you can convert a portion of the resulting string in more useful to digital.

  All these concepts are illustrated in the attached VI. I hope this helps, but let me know if you have any other questions.

  Best regards

  Christian Hartshorne

  NIUK

• How to copy the data from the indicator table 1 d to the Clipboard

  Is it possible to copy data from table 1 d indicator to the Clipboard as a text and for more than one cell?

  I use LV8.6.

  Leszek

  Sorry, I wasn't sure if it was available in 8.6, apparently not.

  You could create an indicator of fine print and use 'picture to a worksheet string' to complete. Now, you can just cut & paste the text instead.

• Using the calendar function to select and read data from MS access tables?

  Hello

  I woke up in the learning of database in no time. I'm using Labview 9 to create a table based on DDMMYY hhmmss format. I can write data to the table in access. The picture will be 24 hours before a new table will be created. However, I find that this concept is not very gd as time goes by, I'll have a lot of paintings for example after 6 months.

  1.I would like to create a calendar (similar to the system clock) in labview, through which the user can click and select, which will then open and retrieve the data. Inorder to do I think I need to create queries and the relationship in MS Access? can any1 advice? Please give as much detail as possible.

  2.i can access data and display in labview. However, I want to display the data and plot in the chart. For instance, coloum b, c and trace on the graph in a proceeding for the analyst.

  3. how to generate a report to an email in a file to document the daily data inserted. I can do it in labview?

  Any help would be much appreciated.  If you have examples of code and don't mind not to share, I would be very grateful.

  Thanks 1million