Today's date in the month and year

Similar Questions

• get the month and year of date type

  Hi all
  I need to get the month and year of type date.
  
  For example

  select to_date('2011-01-17', 'yyyy-mm-dd') from dual;

  Required result:

  01-2011

  Any ideas?
  
  Thanks in advance,
  Bahchevanov.

  select to_char(to_date('2011-01-17', 'yyyy-mm-dd'),'mm-yyyy') from dual;
  

  HTH

• Get the number of days in a month based on the month and year of fields

  I have a column in my form which lists the days in a month. I want to configure a hidden field that calculates the total number of days in a month, based on the month and year of the field inputs. The number of days will determine what appears on the column. For example, if I put 4 months, and 2016 in the field of the year, I get 30 in the hidden field. Thus, on the column 'Day', I'll have numbers 1-30. Or if I put 2 months and 2016 in the field of the year, I get the 29 in the hidden field. If the numbers 1-29 appears in the column 'day '.

  Found this on some forum javascript code:

  //Month is 1 based
function daysInMonth(month,year) {
   return new Date(year, month, 0).getDate();
}

//July
daysInMonth(7,2009); //31
//February
daysInMonth(2,2009); //28
daysInMonth(2,2008); //29

  I do not know how to convert this code in JavaScript to adobe and don't really know how to use it. All I know how to do is to configure the field values for the field month and year as variables. I am a novice programmer and would appreciate it really all the help I can get. Thank you in advance!

  The code seems to be JavaScript and runs as needed by using the JavaScript console.

  I would like to consider making more general code, so if you have a date string that includes at least the month and year we could just call the function and get the number of days for that month.

  The following script will calculate the number of days in a month, by using at least the month and year values can display the result on the JavaScript console and all of the value field for the field that has this code as the custom calculation Script.

  function daysInMonth (oDate) {}
  return new Date (oDate.getFullYear (), oDate.getMonth () + 1, 0) .getDate ();
  }

  nMonth var = this.getField("Month").valueAsString; get the value of month;
  nYear var = this.getField("Year").valueAsString; get the value of the year;

  Event.Value = "";

  If (nMonth! = "" & nYear!) = "") {}
  var MyDate = util.scand ("' / mm/yyyy ', nMonth +" / "+ nYear); convert to date object;
  var nDaysInMonth = daysInMonth (MyDate); get the number of days;

  Console.Open (); Open the JavaScript console;

  Console.clear(); clear the console;

  Console.println ("Days in" + nMonth + ":" + nDaysInMonth); show days in month;

  Event.Value = nDaysInMonth; Set the value of the field;

  }

• to get the month and year separated

  Hello
  
  I have the entry_date_fin of column (type of data-varchar2 (8))
  
  with values like Apr.-2008
  Feb-2009 etc.
  
  can I get the distinct month and year separated

  i tried select to_date(entry_date_fin,'MM') FROM  xyz  doesnt wrk

  kindly guide me

  Although you are (wrongly, IMO) storage of dates as strings, just use string manipulation...

  SQL> with t as (select 'FEB-2008' as txt from dual)
    2  --
    3  select substr(txt,1,3) as mnth
    4        ,substr(txt,5) as yr
    5  from t
    6  /
  
  MNT YR
  --- ----
  FEB 2008
  
  SQL>
  

• Hide the 0 before the month and year

  I m using this query to generate the sequence

       SELECT     TO_CHAR (SYSDATE, 'MM')
                           || TO_CHAR (SEQ.NEXTVAL)
            || TO_CHAR (SYSDATE, 'YY')
            
        FROM   DUAL;

  The result is
  

  0612109

  06 is the month
  121 is the sequence
  09 is the year
  
  I want to hide 0 before the month and the year also.
  
  Looks like this
  
  * 61219 *.

  if here Month is 10 and year is 2010
  
  then It will display
  1021110
  

  Try this

  SQL> SELECT     ltrim(TO_CHAR(to_date('12-10-2010','dd-mm-yyyy'), 'MM'),'0')
    2       || TO_CHAR (SEQ.NEXTVAL)
    3            || ltrim(TO_CHAR (to_date('12-10-2010','dd-mm-yyyy'), 'YY'),'0') format_date
    4           FROM   DUAL;
  
  FORMAT_DATE
  --------------------------------------------
  1026010
  

• How to find the sum of the month and year of a date

  Hi all
  
  I want to find the sum of the date
  for example, 10 November 2010 I need to find (11-2010).
  
  Please help me

  You can use the extract function...

  SQL> select extract(month from systimestamp)+extract(year from systimestamp) from dual;
              EXTRACT(MONTHFROMSYSTIMESTAMP)+EXTRACT(YEARFROMSYSTIMESTAMP)
                                      ------------------------------------------------------------
                                                          2021
  

  Concerning
  Renjith Malet

• Error definition day LOV based on the month and year

  Select ' 1 ', ' 01' day_aff union double val
  ...
  Select '29', ' 29 "double where '29' < = to_char (last_day (to_date ('01.' |)))" '02'. '.' || (((', 'dd.mm.yyyy')), 'jj') union
  Select '30', ' 30 "double where '30' < = to_char (last_day (to_date ('01.' |)))" '02'. '.' || (((', 'dd.mm.yyyy')), 'jj') union
  Select '31', '31' from dual where '31' < = to_char (last_day (to_date ('01.' |))) '02'. '.' || (((', 'dd.mm.yyyy')), 'jj')
  order by 2
  
  That works well.
  
  If I replace '02' by: P10_MONTH & P10_MONTH. or v ('P10_MONTH') and 2008 by: P10_YEAR & P10_YEAR. or v ('P10_YEAR'), I get the following error on the creation of LOV (in shared components or LOV section of the element):
  
  LOV query is not valid, a display and a return value is needed, the column names must be different. If your query contains a query online, the first CLAUSE in the SQL statement must not belong to the query online.
  
  No work around?
  
  Igor

  Hi Igor,.

  I think it's the | in the SQL that is causing the problem. You can get around this by the presence of a hidden page element which is calculated at the point of process before header which calculates the first day of the selected month.

  I did it on this page: [http://apex.oracle.com/pls/otn/f?p=35917:16]

  In addition, you can simplify your SQL statement to something like:

  SELECT LEVEL d, LEVEL r
  FROM DUAL
  CONNECT BY LEVEL <= TO_NUMBER(TO_CHAR(LAST_DAY(TO_DATE(v('P16_FIRSTDATE'),'DD/MM/YYYY')),'DD'))
  

  (P16_FIRSTDATE is the element that contains the calculated date)

  Andy

• problem to insert only month and year instead of the full date

  select b.penjara_id, p.penj_lokasi, a.no_daftar, b.episod, b.nama1,to_char(a.trkh_mula_prl,'dd/mm/yyyy') as trkh_mula_prl, to_char(bulan_proses,'mm/yyyy') as bulan_proses,
          b.epd, b.lpd
  from prl_daftar_proses a, senarai_pesalah b, penjara p
  
  where a.no_daftar=b.no_daftar
  and a.episod=b.episod
  and b.penjara_id = p.penjara_id
  and a.setuju_jplp is null
  and a.bulan_proses between to_date(:FROM,'dd/mm/yyyy') and to_date(:TO,'dd/mm/yyyy')
  
  
  order by b.penjara_id, a.bulan_proses,a.no_daftar

  Hi, can someone help me how I can register only the month and year of the value which have full day in the database?
  
  for example, the date is 18/09/2012, but I want to just insert 09/2012 as a parameter. If I want to insert only one setting, I can do... But I have problem when I want to insert two parameters...

  Lina saleh wrote:
  I already try before that and he invites me error like this...
  "name of the invalid host/identification variable.

  Change the name of the connection variable to: from_date and: to_date

  Is a reserved keyword.

• How to set the filter criteria for the month and the year to aid in the timestamp input field?

  Hello

  I use jdev 11.1.2.3.

  I have a problem with the generation of reports, I have a report table that is in the form of VO (query based) and I want to search this table in the month and year of the basic

  but in this table (query) This timestamp field of having value based on... How to do a search with the name of the month and year only... Here I totally use vo base query to generate a

  reports... Anyone can guide me.

  Thank you.

  I want to create a drop-down list for month + year as an executable parameters with bind variable no matter what idea this subject, my attribute here is TimestampFormat.

  Then add to your sql query something like:

  WHERE extract (your_timestamp_column MONTHS) =: monthBindVar

  OR an extract (YEAR your_timestamp_column) =: yearBindVar

  and add monthBindVar and yearBindVar as a bind variable to your view object.

  Then you can use it as a ExecuteWithParams operation (or manually set these bind variables and execute the query)

  Dario

• Set the calendar to display day, month and year

  In addition to the time of day, my computer began giving the day of the week (Monday) only instead of day, month and year as it did before. Tried to go back to 29/12/2014 or something similar without success.  Any suggestions?

  Hello

  Sorry for the late reply and I appreciate your patience.

  User profile corruption might have caused the problem. As a solution, I suggest to create a new user profile and check if the date format displays the same thing.

  To do this, see the link below.

  http://Windows.Microsoft.com/en-us/Windows/fix-corrupted-user-profile#1TC=Windows-7.

  It will be useful. Just answer us with the State, and we will be happy to help you.

• How can I order a list first for the year and sort the months each year?

  Hello

  I created a report that lists a number of items grouped by month, although elements it since 2012 so together and you spend your order is strange because the groups to report on 2 months.

  example:

  2013 - 01-50

  01/2012 - 56

  02/2013 - 45

  02/2012 - 54

  .

  .

  .

  How do I ordernar first a year and and sort the months each year?

  Sort by DATE... not VARCHAR2

  It is a thing of database, not an APEX.

  In your select statement to the report, the column for DATE information must be one data type DATE or another...

  MK

  PS - TRUNC (a_date_column, 'MONTH')

• Get the number of days, months and year

  Hi all
  
  I'm using OBIEE 11 g. I have a line of dash for year (2010, 2011, etc.) and months (Jan, Feb,..., Dec). How can I get the number of days in a given month and year in my report?
  
  For example, if I choose to Jan & 2011, I'd get 31 and 356. And if I choose Feb & 2011, I would get 28 and 356.
  
  Thank you!

  I have something more good option here... Try to use this

  DAYOFMONTH (TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH (CURRENT_DATE) *-1, TIMESTAMPADD (SQL_TSI_MONTH, 1, CURRENT_DATE)))

  This will give you the days for the month in progress (Oct 2011) after calculating the last day of each month... Similary dynamically pass the value Date or month... You will need to modify this function but shud be simple. Hope this helps :)

• I want to collect rain for the day, month and year; Can what formula I use?

  I want to collect rain for the day, month and year; What formula or expression that I can use.

  I use a Rain Wise product that converts impulses to an analog value.  The rain wise device can be

  "the value measure up to 1", 5", or 10".  I will be setting the unit at 10 inches in increments of 0.01 inch.

  What I would do is at each time increments of signal I would consider it as 0.01 then after reaching

  a period of time a day or a month, back to zero.

  Need some advice on this problem.

  How about you, using a counter to count the number of times where the signal is less than 0.01?

  For example,.

  Counter.Count = signal<=>

  The total number of rain is

  Counter * 10 + signal

  Use TimeOfDay or TimeOfWeek to reset the counter.

• To find the months and days between 2 dates

  Hello

  I want to find the months and days between 2 dates.

  For example.

  1 - Date: August 25, 2013

  2 - Date: October 23, 2013

  If we consider each month 30 days, it should give

  August 25, 2013 to August 30, 2013 = 6 days

  01-Sep-2013-30-Sep-2013 = 1 month

  October 23, 2013 to October 30, 2013 = 8 days

  Total = 1 month and 14 days.

  Kindly help as soon as possible.

  Thanks and greetings

  Suresh

  Assuming that d2 > d1,.

  where d)

  Select sysdate d1, sysdate + 56 double d2

  Union all select to_date (March 1, 2013 ',' dd-mon-yyyy "") d1, to_date (March 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (5 February 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy "") d1, to_date (March 23, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 25, 2013 ',' dd-mon-yyyy ') d1, to_date (March 31, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (August 2, 2013 ',' dd-mon-yyyy "") d1, to_date (29 October 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (February 1, 2013 ',' dd-mon-yyyy "") d1, to_date (May 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (25 August 2013 ',' dd-mon-yyyy "") d1, to_date ('03-Sep-2013', 'Mon-dd-yyyy') d2 double

  Union all select to_date (July 30, 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (August 30, 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (July 31, 2013 ',' dd-mon-yyyy ') d1, to_date (3 August 2013 ',' dd-mon-yyyy "") double d2

  Union all select to_date (3 July 2013 ',' dd-mon-yyyy "") d1, to_date (August 31, 2013 ',' dd-mon-yyyy ') d2 double

  Union all select to_date ('31-08-2013', ' dd-mm-yyyy'), to_date('05-10-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('31-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-03-2013','dd-mm-yyyy') of the double

  Union all select to_date ('05-02-2013', ' dd-mm-yyyy'), to_date('05-02-2013','dd-mm-yyyy') of the double

  )

  Select d1, d2,

  1 + 30 * trunc (months_between (d2, d1)) + LESS (extract (day of d2), 30)-LESS (excerpt (d1 day), 30)

  + CASE when extracted (d2 day)< extract(day="" from="" d1)="" then="" 30="" else="" 0="" end ="">

  d

  D1 D2 DAYSBETWEEN

  ----------- ----------- -----------

  October 10, 2013 5 December 2013 56

  March 1, 2013 30 March 31, 2013

  5 February 2013 March 31, 2013 56

  February 25, 2013 March 23, 2013 29

  February 25, 2013 March 31, 2013 36

  August 2, 2013 29 October 2013 88

  February 1, 2013 may 31, 2013 120

  August 25, 2013 03 - Sep-2013 9

  July 30, 2013 31 August 31, 2013

  July 31, 2013 August 30, 2013 31

  July 31, 2013 3 August 2013 4

  July 3, 2013 August 31, 2013 58

  31 August 2013 5 October 2013 36

  5 February 2013 March 31, 2013 56

  5 February 2013 March 5, 2013 31

  February 5, 2013 February 5, 2013 1

  In my view, which corresponds to your rules.

• How to fill a field of date with today's date when the signature field is signed?

  How to fill a field of date with today's date when the signature field is signed? In the LCD, I insert a signature field and a date field, what parameters in these two fields are necessary to make this work? Is the date field, the value calculated? I tried different JS suggestions I found, but none work. In the form, I named the signature ClaimSignature field and the date in the ClaimSigDate field.

  The thought of her with a little help. In the script editor window, I selected the postSign event and added the following JS:

  Form1.Page1.ClaimSignature::postSign - (JavaScript, client)

  var date = new Date();

  var day = date.getDate ();

  var month = date.getMonth () + 1;

  var monthstring = (month, 10?) ('0' + month: month)

  year var = date.getFullYear ();

  var = year DateString + '-' + monthString + '-' + (day< 10="" "0"="" +="" day="" :="">

  ClsimSigDate.rawValue = dateString;

  I hope this helps someone else save time.