Transform the data in the column marked in lines

I've already implemented Tom Kytes solution for dynamic / variant in the list that is found here and on his own works very well when passing a variable.  I'm trying to use it to decode several rows in a table.  Each row has a column of delimited data and I want to turn these data delimited by lines.

Here is the configuration.

create table data_source

(upload_id number not null,

data_source_id integer not null,

sources varchar2 (50).

ERROR_MESSAGE varchar2 (100)

);

insert into data_source (upload_id, data_source_id, sources) values (1, 1, 'a');

insert into data_source (upload_id, data_source_id, sources) values (1,2, 'A:B:C:X');

insert into data_source (upload_id, data_source_id, sources) values (1, 3, 'c');

insert into data_source (upload_id, data_source_id, sources) values (1, 4, 'B');

insert into data_source (upload_id, data_source_id, sources) values (1.5, 'Y');

create the table data_source_lookup

(varchar2 (10) sources non-null)

;

insert into data_source_lookup (sources) values('A');

insert into data_source_lookup (sources) values('B');

insert into data_source_lookup (sources) values('C');

My goal is to update the table data_source for lines where there is an invalid data source, in the example above that would be 2 and 5 lines.  I can do this individually using the in_list solution:

Select * from table (in_list ('A:B:C:X',' :'))))

If column_value not in (select data_source_lookup sources)

Returns 'X' as expected.

What I am struggling with is a method to make it through all the lines for a given loading ID:

Update data_source

ERROR_MESSAGE = "Source of data" is not a valid value

where upload_id = 1 and...

I tried to create a join cross- like this:

Select ds.data_source_id, ds.sources, x.column_value

DS data_source cross join (select column_value in the table (in_list (ds.sources,' :'))) x)))

but as you can imagine passing in the function ds.sources has failed, returning "ORA-00904:"DS".» "SOURCES": invalid identifier.

I'm sure I can solve this problem in a loop, but that seems inefficient.  Anyone know of a method by which I can pass the content of the column to the table function (in_list ()) for each line?

For someone else it may call a function table in several lines, here's what I came with.  First of all, I changed my data to test a bit to add some very incorrect values.

setting a day from sources set data_source = 'A:B:C:X:Y' where data_source_id = 1;

This query will not return a list of lines that contain invalid values, including their wrong value:

Select the rowid, sources, column_value

de)

Select the rowid, data_source sources)

x cross table junction (utils.in_list (x.sources,' :'))))

where column_value is not null

and not exists (select null from data_source_lookup l where l.sources = column_value)

AABk3MAAjAAAKd8AAA A:B:C:X:Y X

AABk3MAAjAAAKd8AAA A:B:C:X:Y Y

AABk3MAAjAAAKd8AAB A:B:C:X X

AABk3MAAjAAAKd8AAE Y Y

With this work, I can then modify cela a little bit to turn it back in a delimited list bad values that I can put in the error column.

Update data_source x 2

ERROR_MESSAGE = value

(by selecting bad_value in)

Select RID, "Invalid Data Source - ' |" listagg(column_value,':') within the Group (column_value control) bad_value

de)

Select the rowid RID, data_source sources)

x cross table junction (utils.in_list (x.sources,' :'))))

where column_value is not null

and not exists (select null from data_source_lookup l where l.sources = column_value)

(Group of RID) where rid = x 2 .rowid)

where x 2 .upload_id = 1

and x2.rowid in (select RID)

de)

Select the rowid RID, data_source sources)

x cross table junction (utils.in_list (x.sources,' :'))))

where column_value is not null

and not exists (select null from data_source_lookup l where l.sources = column_value))

;

It works well, and I find myself with:

Error sources

Source of invalid data in A:B:C:X:Y - x: y

Invalid Data Source - X A:B:C:X

C

B

Valid source of data Y - Y

Tags: Database

Similar Questions

  • Some of the columns to pivot lines

    Hello

    I need some columns to pivot lines and have the remaining columns in the result.

    At this point, I have already made a subquery to gather data and to keep the running time down I prefer not to do it again as a UNION would require.

    A row
    CUST TEST_DATE TEST_TYPE1 TEST_TYPE2 TEST_TYPE3
    1 20 MARCH 09 AA BB CC

    Result rows
    CUST TEST_DATE TEST_TYPE
    1 AA 20 MARCH 09
    1 BB 20 MARCH 09
    1 BB 20 MARCH 09

    Suggestions please?

    Thanks in advance for your help,

    Lou
    with t as (
               select 1 cust,to_date('20-MAR-09','dd-mon-yy') test_date,'AA' test_type1,'BB' test_type2,'CC' test_type3 from dual
              )
    select  cust,
            test_date,
            case lvl
              when 1 then test_type1
              when 3 then test_type2
              else test_type3
            end test_type
      from  t,
            (select level lvl from dual connect by level <= 3)
      order by cust,
               test_date,
               test_type
    /
    
          CUST TEST_DATE TE
    ---------- --------- --
             1 20-MAR-09 AA
             1 20-MAR-09 BB
             1 20-MAR-09 CC
    
    SQL> 
    

    SY.

  • Sort sort the columns number of lines n columns in the RTF PivotTable but hide them.

    Hello

    I'm trying to sort on the columns number of sort for lines n columns in the PivotTable but hide them. Any help appreciated.

    Attached model RTF, XML and output required. Thank you

    Please check your email that I have forwarded to update the model.

    by default, it performs a sort on the column, we used to pivot rows and columns. If we need custom sort, we must specify that column in the logic that was present in the C form field.

    by default, you are as below

    Custom sort

    {INDUSTRY_sort, o = a, t = n} « ; » MONTHS {Month_sort, o = a, t = n} '; SALES '; "' sum '? >

  • How to control the columns of various lines

    Dear members,

    I have a few lines displayed in the region of table edge on a Page of the OFA.

    The page has 3 columns, i.e., Col1, Col2 and Col3

    I also add a line on this chart button.

    When I opened the page, by default, it displays 4 rows. Now I don't want users to update these 4 rows. But users can insert new lines by clicking on the button Add a line.

    When users click on the button to add a line, I am able to create a new line, but how do I prevent users from updating the already displayed 4 lines.

    Please help me.

    Thanks in advance.

    Kind regards

    Hello

    Define a transitional attribute and name it freezes and set the default value for Y and when the query is executed in the query process, set the value as Y and make fields read-only if the value is there.

    Add which line touches, get the value of the current line and the value of gel on the current line as N. This way only the new lines added will be editable. On save, make the value of gel to Y for all records.

    I did the same thing, and it would solve your problem.

    Kind regards
    P.D. Moorthy

  • view the column and gutter lines in a document

    CS3, I was displayed and lost due to the mistroke key lines? now I can't find them

    You probably pressed Cmd (or Ctrl on Windows) +; which is the shortcut to activate the guides on or off, or you can have changed in preview mode (with no text cursor active, press W). You can also access them from the view menu, and there is a button (or two buttons if your toolboz is two columns wide) at the bottom of the tool box to control the display.

  • can I create an index on the column of duplicate lines?

    Hello

    I tried to create a unique index on an existing table, containing the duplicate lines.

    I want to create an index of type everything on this column of duplicate rows.

    If possible pls suggest me.


    Kind regards
    Vincent.

    Yes.

  • SQL help - Need help to rotate the columns to rows

    I have a HughesNet to divide the columns into multiple lines. For example:

    EMP_DEPT

    ROWID empid1 ename1 empid2 ename2 empid2 ename2 empid4 ename4 dept4 dep3 dep2 dept1
    100001 1 'SCOTT' 10 2 'DAVE' 20 3 10 4 20 SMITH "MILLER"
    100002 1 'SCOTT' 10 2 'DAVE' 20 3 'MILLER' 20

    Note: EMP_DEPT do not always have information about the 4 employees settled for example in info only 3 employees rank 2 are there

    I need to convert and insert it into the EMPLOYEE table as follows:

    EMPLOYEE

    EmpID ename dept
    1 SCOTT 10
    2 20 DAVE
    3 MILLER 10
    4 SMITH 20

    1 SCOTT 10
    2 20 DAVE
    3 MILLER 20

    Thank you
    KeV

    Hey Kevin,

    Here's one way:

    WITH t AS (
      SELECT level i FROM dual CONNECT BY level <= 4
    )
    SELECT enty_type, enty_name, enty_id
    FROM (
      SELECT case when mod(t.i,2) = 0 then 'DEPARTMENT'
                  else 'EMPLOYEE'
             end as enty_type
           , case t.i
               when 1 then emp_name1
               when 2 then dept_name1
               when 3 then emp_name2
               when 4 then dept_name2
             end as enty_name
           , case t.i
               when 1 then emp_id1
               when 2 then dept_id1
               when 3 then emp_id2
               when 4 then dept_id2
             end as enty_id
      FROM emp
           CROSS JOIN t
    )
    WHERE enty_id IS NOT NULL
    ;
    

    Another using the MODEL clause:

    SELECT *
    FROM (
      SELECT enty_id, enty_name, enty_type
      FROM emp
      MODEL
      RETURN UPDATED ROWS
      PARTITION BY (pk)
      DIMENSION BY (0 i)
      MEASURES(
         emp_id1, emp_name1
       , emp_id2, emp_name2
       , dept_id1, dept_name1
       , dept_id2, dept_name2
       , cast(null as number(10)) enty_id
       , cast(null as varchar2(200)) enty_name
       , cast(null as varchar2(30)) enty_type
      )
      RULES (
         enty_type[1] = 'EMPLOYEE' , enty_id[1] = emp_id1[0], enty_name[1] = emp_name1[0]
       , enty_type[2] = 'EMPLOYEE' , enty_id[2] = emp_id2[0], enty_name[2] = emp_name2[0]
       , enty_type[3] = 'DEPARTMENT' , enty_id[3] = dept_id1[0], enty_name[3] = dept_name1[0]
       , enty_type[4] = 'DEPARTMENT' , enty_id[4] = dept_id2[0], enty_name[4] = dept_name2[0]
      )
    )
    WHERE enty_id IS NOT NULL
    ;
    

    Published by: odie_63 on 8 Dec. 2010 21:00

  • Dates are not appearing in the column start and Finsh of MS Project 2010. They become W31/4, W31/5, etc. Instead of 7/31/20113. How can I fix it?

    Dates are not appearing in the column start and Finsh of MS Project 2010. They appear rather like W31/4, W31/5, etc. When it should be like this: 7/31/20113. How can I fix it? Note: Dates listed do appear correctly.

    Hello Charlie,.

    You are welcome. It is what we are trying to do... help people! Thanks for letting me know that the problem is solved. Don't forget to mark it as your response so that we can spread the knowledge more far.

    Kind regards

    BearPup

  • Display the name of the tag as the column name and the value in the tag as a row of data from the input string.

    Hi Forum members,

    I am looking for a query display the name of the tag as the column name and the value in the tag as a row of data.

    I have to print the values within the tag to a file by choosing the value of the flags. the sequence of the tags will vary each time, as the tag name will change dynamically.

    So here is the example of input data and the expected output. The string in the text column must be separated as the column names and values.

    Input data
    Select 1 as seqno,' < > 0210A 50 4f < / 4f > < 5f20 > TEST CARD 16 < / 5f20 > < 5f2a > < / 5f2a > < 82 > 1 c 00 < / 82 > ' double text


    Output:

    Seqno 4f 5f20 5f2a 82
    0210A 50 16 1 00 TEST CARD 1

    Please help me by providing your entries on this.

    We use the version of Oracle 11.2.

    Note: This is not the XML string

    Thank you

    Shree

    with

    data in the form of

    (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

    Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

    Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

    Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

    )

    Select d.seqno, x.*

    d the data,

    XMLTable ('/ root')

    by the way xmltransform (xmltype ('': replace (replace (text,'<><>'),)))

    XmlType (q'~http://www.w3.org/1999/XSL/Transform "version ="1.0"> ")

                                                     

                                                       

                                                         

                                                       

                                                     

                                                     

                                                       

                                                         

                                                       

                                                     

    ~'

    )

    )

    path of columns '4f' varchar2 (10) "tag4f."

    path of "5f20' varchar2 (30)"tag5f20. "

    path of '5f2a' varchar2 (10) "tag5f2a."

    path of varchar2 (10) "82" "tag82.

    ) x


    SEQNO 4f 5f20 5f2a 82
    1 0210A 50 16 TEST CARD - 1 00
    2 0210A 50 16 TEST CARD - 1 00
    3 0210A 50 16 TEST CARD - 1 00
    4 0210A 50 16 TEST CARD - 1 00

    with

    data in the form of

    (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

    Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

    Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

    Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

    ),

    Chopper (seqno, Key, value, String) as

    (select seqno,

    regexp_substr (text,'<(.+?)>', 1, 1, null, 1),

    regexp_substr (Text,'>(.*?))

    regexp_substr (text,'<.+?>. *? ) (.*) $', 1, 1, null, 1). » <>'

    from the data

    Union of all the

    Select seqno,

    regexp_substr (String,'<(.+?)>', 1, 1, null, 1),

    regexp_substr (String,'>(.*?))

    regexp_substr (String,'<.+?>. *? ) (.*) $', 1, 1, null, 1)

    Chopper

    where regexp_substr (string,'<(.*?)>', 1, 1, null, 1) is not null

    )

    Select '4f', seqno, '5f2a', '82', '5f20.

    of (seqno, lower (key) select key, value)

    Chopper

    )

    Pivot (max (value) for key in ('4f' as '4f', '5f20' as '5f20', '5f2a' as '5f2a', "82" as "82"))

    Concerning

    Etbin

  • The checkbox in the column DB data record

    Hi all

    I created the article P1_checkbox (several checkboxes) using LOV(Select ename, empno from emp). Now when I checked the boxes, I want to INSERT these boxes given in the table in database 'emp_selected'.

    So when I log in again application, the boxes have pre-selected data of "emp_selected" boxes unchecked the 'emp' table and when I uncheck some preselected check boxes and check the new boxes, it should be updated accordingly in "emp_selected".

    My APEX oracle version is 4.2.

    Thank you

    Found the solution. Marking the link for others who may have doubts about the same subject.

    Oracle11g - box record data in a column DB - Stack Overflow

  • How transform the trailing spaces &amp; AREAS of data from sybase to oracle

    Helllo,

    We are the migration of data from sybase to Oracle using goldengate... Source Sybase with SPACES (single / Multiple) as data to CHAR/VARCHAR that will be migrated to the VARCHAR2 data type in Oracle. I'm having trouble trying to implement under two conditions to transform the data

    1) Remove SPACES during the IPL for CHAR/VARCHAR

    example: Data Source: "TRAILING SPACE.

    Given target expected - remove the spaces of trailinging: "TRAILING SPACE.

    2) If the data with SPACES like a value (single or Multiple) will be loaded as a single SPACE in Oracle.

    example : Source data                                                  :  "          "

    Expected data from target - unique space:

    Map: dbo. Target TEST_TABLE DEV01. Table_test, COLMAP (USEDEFAULTS, CRE_ID = @IF (@STRRTRIM (CRE_ID) = @NULL AND CRE_ID <>@NULL, ' ', @STRRTRIM (CRE_ID)));

    I tried above mapping in the settings file, but it returns error like below, guidance on the highest implementation requirement will be useful.

    ... RIM (CRE_ID) = @NULL AND CRE_ID...

    ^

    Error in the COLMAP clause. Invalid function or argument.

    Under column mapping is worked :-)

    Map: dbo. Target TEST_TABLE DEV01. TABLE_TEST, COLMAP (USEDEFAULTS, CRE_ID = @IF (@STRLEN (@STRTRIM (CRE_ID)) = 0, ' ', @STRRTRIM (CRE_ID)));

  • Change the Data Type of column on large partitioned Table Tablet

    Hello

    I was tasked to change a certain NUMBER of collar to a colonel VARCHAR2

    It is usually an easy task, but I ran into several challenges due to the size of the table, the second major problem is the compression of the table.

    To begin with, the Table and index are 4.4 to and hold around 11 lines billion. That the Table is compressed, not the index.

    The first option was to add a new collar of VCHAR, update from the Col de NUM, file and then drop the colonel NUM


    We ran this test in the Test environment and because discovered Compression Table that you can only mark the column is not used, and it can only be moved permanently from the Table if you unzip the whole Table and run «...» REMOVE the UNUSED COLUMNS'.

    The second way is to create a separate Table copy with the values of the source of neck, then write to null to the source of neck, change data Type when its empty and then update the source again with the copy Table values.

    The second option, that's what I'm testing, but I work with nearly 30 million lines by daily score, inserts take very long to fill.

    How can I make faster inserts between the Source and the copy Table?

    What other channels follow to accomplish the task above?

    Concerning

    Stephan

    Nowhere in your proposed solution was necessary for you to understand why the data source changes, its as simple that to take what is ons the table (all the facts in the original post) and offering the best way on the basis of previous experience or oracle skills acquired over time.

    If you spent so much time and thought to help with a solution that you did on WHY complain, you could have provided some feasible solutions already.

    No thanks to your information irrelevant and unnecessary, I've implemented a solution already.

    1 export the Source Table

    2. create a 'replica Table' using the DDL source using a temporary table name

    3. import all Partitions in the Table new

    4. before the Cut-Over, synchronize the changes from the Source to the replica Table

    5 rename the Source

    5 rename the Table of replica for the Original Source Table name

    6. slide the original Source Table

  • How to remove tabs, several spaces, quotes from data in the column.

    Hello

    How can we remove legs, several spaces, quotes from data in the column.

    Entry:

    H ope you 'are' Ingo w ell

    Output:

    H ope do you everything - there is a tab in hope and double-spaced in the well. This should be replaced by space. (Tab and multi spaces)

    I found myself with below:

    REGEXP_REPLACE (REGEXP_REPLACE (Replace (col, Chr (9),' '), ' () {2,} ', ' '),'[' ""]', ")

    Can we do more efficiently, your contributions are appreciated.

    I tried

    REGEXP_REPLACE (col,'[^ [a - z, A - Z, 0-9, Chr (0) - Chr (127) [: Space:]]] *', ") but the tabs still exist and that my data have German characters I can't go along with this.

    Thank you

    GVK.

    Hello

    Karthik417 wrote:

    Hello

    Thanks for your suggestion. In the above expression, we still missed to replace the double quotes.

    So thought we must use another regular expression instead of REPLACE.

    Select REGEXP_REPLACE (REGEXP_REPLACE (' H ope you "are" d "Ingo ell w ',' [' |])) CHR (9) | + ',' '),'["" "]') twice;

    I suppose we must use at least 2 REGEXP to achieve and cannot get it with a single expression.

    Thank you

    Sorry, I removed single quotes, not double - quote.  (This shows one of the reasons why having a few lines of sample data is very useful).

    I think you don't need 2 separate functions.  I do not think that the two must be REGEXP_REPLACE; You can use TRANSLATE to remove both types of quotation marks in a single function call:

    TRANSLATE (REGEXP_REPLACE (col

    , '[ ' || CHR (9) | ']+'

    , ' '

    )

    , '?'''"',

    , '?'

    )

    Of course, you can use use REGEXP_REPLACE to remove the quotes, if you really want to.

    Powerful they are, regular expressions are basically only 1 thing, things not 2 or more different.  Sometimes, he can watch as they do several things, because they can operate on character classes, like the series containing the and the and a variable number of characters.  For example, the REGEXP_REPLACE function, I used above is simply changing expression expression x y, where x is 1 consecutive or more characters of a given set.  As we both demonstrated, we can have a separate function that changes from p to q, but I know not all built-in function which, in general, can change x to y at the time that it changes from p to q.  TRANSLATE comes close, but TRANSLATE only works if x, y, p and q are single (or NULL), characters not expressions.

  • Find the minimum date on multiple columns

    Hello

    I have two questions to find the minimum date on several columns:
    1. need a select query that should JOIN two tables and return any information (CASSEDTL) table with minimum date out of DATEISSUED, DATEPLACED, DATEENTERED and STATDATE.
    2. need of an update query that should update all cases in the CASEDTL table with the minimum date of DATEISSUED, DATEPLACED, DATEENTERED and STATDATE.

    The DDL:
    CREATE TABLE CASEMSTR 
    (   CASENBR     NUMBER,
        DATEISSUED  DATE,
        DATEPLACED  DATE,
        DATEENTERED DATE);
        
    CREATE TABLE CASEDTL 
    (   CASENBR     NUMBER,
        STATDATE    DATE,
        RCVDATE    DATE,
        MODDATE     DATE);
        
    INSERT INTO CASEMSTR VALUES (1, '1 JUL 2007', '1 JUL 2007', '12 JUL 2007');
    INSERT INTO CASEMSTR VALUES (2, '1 JAN 2008', '1 JAN 2008', '21 JAN 2008');
    INSERT INTO CASEMSTR VALUES (3, NULL, NULL, '3 DEC 2008');
    INSERT INTO CASEMSTR VALUES (4, '31 MAR 2009', NULL, '6 APR 2009');
    INSERT INTO CASEMSTR VALUES (5, NULL, '22 MAR 2009', '6 APR 2009');    
    INSERT INTO CASEMSTR VALUES (6, NULL, NULL, '16 JUL 2009');
    INSERT INTO CASEMSTR VALUES (7, '1 DEC 2008', '7 DEC 2008', '26 DEC 2008');
    INSERT INTO CASEMSTR VALUES (8, NULL, NULL, '17 MAY 2009');
    
    INSERT INTO CASEDTL VALUES (1, '25 JUN 2007', NULL, '2 AUG 2009');
    INSERT INTO CASEDTL VALUES (2, '1 JAN 2008', NULL, '2 AUG 2009');
    INSERT INTO CASEDTL VALUES (3, '11 NOV 2008', NULL, '2 AUG 2009');
    INSERT INTO CASEDTL VALUES (4, '31 MAR 2009', NULL, '2 AUG 2009');
    INSERT INTO CASEDTL VALUES (5, '19 JUL 2009', NULL, '2 AUG 2009');    
    INSERT INTO CASEDTL VALUES (6, '13 JUN 2009', NULL, '16 JUL 2009');
    INSERT INTO CASEDTL VALUES (7, '7 DEC 2008', NULL, '16 JUL 2009');
    INSERT INTO CASEDTL VALUES (8, '14 MAY 2009', NULL, '16 JUL 2009');
    COMMIT;
    The initial query I have is
    SELECT CD.CASENBR, CM.DATEISSUED, CM.DATEPLACED, CM.DATEENTERED, CD.STATDATE, CD.RCVDATE, NULL "NEW RCV DT" 
    FROM CASEDTL CD
        INNER JOIN CASEMSTR CM
            ON CD.CASENBR = CM.CASENBR;
    Need to know what is the best way to complete the new Date of RRS? Receive a new date should be the minimum date of DATEISSUED, DATEPLACED, DATEENTERED and STATDATE. And also how do I write an update statement unique to upade date of receipt in the detail table?

    Any help would be appreciated! Thanks in advance!

    Where is the function LESS? Refer to manual SQL.

    HTH - Mark D Powell.

    put1 > desc multdate
     Name                                      Null?    Type
     ----------------------------------------- -------- ----------------------------
     COL1                                               DATE
     COL2                                               DATE
     COL3                                               DATE
    
    put1 > select * from multdate;
    11-AUG-09 10-AUG-09 01-AUG-09
    
    put1 > select least(col1, col2, col3) from multdate;
    01-AUG-09
    

    Published by: MarkDPowell on August 11, 2009 15:53 added example

  • Display the date in a column

    Hi all

    I have a column that displays the date in the marker '2010-05-29 14:52:10 ', my requirement is I want to show only the month and year according to the results.

    Say '2010-05-29 14:52:10 ' should be displayed as "may 2010"...» I checked and found that we have MONTHNAME (expr), which returns only the month. We have one for the month and year in the format above. Please give your suggestions.

    Thank you
    Natraj

    Hi, to get the name of the month you can use MONTHNAME (date_expression). For the year, you can use YEAR (date_expression). I suppose that these two might meet your requirements.

    Alternatively, you can click on the properties of the columns, go to the "data format" tab, choose the custom date format and give the 'custom date format"yyyy MMMM for desired results

    -John CRMIT

Maybe you are looking for

  • Re: Qosmio x 770-136 - how to watch movies in 3D using VLC player

    Hello I just got a laptop X 770 - 136 Qosmio.How do 3d work? I have downloaded films to play through VLC.Do I have reason to think that the laptop replaces the 3D?Mine doesn't seem to work?

  • y at - it truly free streaming movie sites (or they are all scams)

    My question is this - I would like to find a site where I can stream movies that are truly free.  I mean there no registration, registration, or credit card information.  I just want to go to a Web site data feeds (or download) the movie and watch it

  • Audio CD import

    How do import you an audio CD compilation as a single album?  When I select Import, the program broken down into separate tracks and will bring together not as a folder under the name of the primary artist.

  • Binary indicator

    Hi all! I have a binary number, say 00000101. I would like to indicate that every bit of correspondent led on the front panel. So in this case, it'll be led0 and led2 on. How can I do?

  • Network Pro K8600 problems

    Hello We had a problem with the k8600. Theres no possible connection on the network. Indicates the configuration page: http://169.254.246.85 IP 169.254.246.85 .. Default gateway: 0.0.0.0 Configuration Suorce: Auto IP It is of course a random IP addre