Two tables with different values of basic on an analysis filter

Hi guys,.

Let assume that I have an analysis with columns: group_id and sales.
On this basis I would like to create two tables: table1 where group_id = 1 and table2 where group_id = 2.

OBIEE is able to do?

Kind regards
Slavi

Hi Slavi,

You can do it in a single analysis, but you have to have the column with group_id twice.

Bring, group_id_1, group_id_2 (same column), sale

Now in table 1.

bring group_id_1, sales

Then in the selection steps for group_id_1-> select members-> Action choose keep only-> choose the value of the filter 1

This will filter the table 1 with group_id 1

In table2 group_id_2 porter, sales

Then do the same step for group_id_2 with the value 2.

You now have two reports with different filter in the same report.

If you want you can keep the same name column for the two columns group_id, I just kept group_id_1, group_id_2 for easy reference.

Tags: Business Intelligence

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I wouldn't lines with the same id and have values of E and F 10258932.

I would like the following data:

A        B  C      D     E N
-------- -- ------ ----- - -
10258927 1  103,35 0
10258929 3  284,85 89,52 E N
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But I have the following lines:

SQL> with my_table as
  2  (
  3  select '10258927' a, '1'  b, '103,35'  c, '0'      d,   NULL  e from dual union all    
  4  select '10258928' a, '2'  b, '0'       c, '15,19'  d,  'E'    e from dual union all
  5  select '10258929' a, '3'  b, '284,85'  c, '89,52'  d,  'E'    e from dual union all
  6  select '10258929' a, '4'  b, '323,85'  c, '89,52'  d,  'E'    e from dual union all
  7  select '10258930' a, '5'  b, '478,80'  c, '91,53'  d,  'E'    e from dual union all
  8  select '10258931' a, '6'  b, '436,67'  c, '78,09'  d,  'E'    e from dual union all
  9  select '10258932' a, '7'  b, '784,88'  c, '23,19'  d,  'E'    e from dual union all
 10  select '10258932' a, '8'  b, '100,88'  c, '11,11'  d,  'E'    e from dual union all
 11  select '10258932' a, '9'  b, '300,88'  c, '22,22'  d,  'F'    e from dual union all
 12  select '10258932' a, '10' b, '468,25'  c, '78,33'  d,  'F'    e from dual)
 13  select a, b, c, d, e, no_ds from
 14  (
 15    select a, b, c, d, e,
 16           case when c > 0 and e != 'F'
 17                then 'N'
 18           end no_ds
 19    from my_table)
 20  where no_ds = 'N' or e is null
 21  order by 1
 22  /

A        B  C      D     E N
-------- -- ------ ----- - -
10258927 1  103,35 0
10258929 3  284,85 89,52 E N
10258929 4  323,85 89,52 E N
10258930 5  478,80 91,53 E N
10258931 6  436,67 78,09 E N
10258932 7  784,88 23,19 E N
10258932 8  100,88 11,11 E N

7 Zeilen ausgewählt.

SQL>

Does anyone have an idea?

Oh, I read the title again once: 'remove double lines with different values.
If it means that he is not specifically E and F values, but only if there is more than one distinct value, then you can do the following:

with my_table as
(
select '10258927' a, '1'  b, '103,35'  c, '0'      d,   NULL  e from dual union all
select '10258928' a, '2'  b, '0'       c, '15,19'  d,  'E'    e from dual union all
select '10258929' a, '3'  b, '284,85'  c, '89,52'  d,  'E'    e from dual union all
select '10258929' a, '4'  b, '323,85'  c, '89,52'  d,  'E'    e from dual union all
select '10258930' a, '5'  b, '478,80'  c, '91,53'  d,  'E'    e from dual union all
select '10258931' a, '6'  b, '436,67'  c, '78,09'  d,  'E'    e from dual union all
select '10258932' a, '7'  b, '784,88'  c, '23,19'  d,  'E'    e from dual union all
select '10258932' a, '8'  b, '100,88'  c, '11,11'  d,  'E'    e from dual union all
select '10258932' a, '9'  b, '300,88'  c, '22,22'  d,  'F'    e from dual union all
select '10258932' a, '10' b, '468,25'  c, '78,33'  d,  'F'    e from dual
)
--
-- end-of-test-data
--
select a, b, c, d, e,
       num_distinct_values
from
(
  select a, b, c, d, e,
         count(distinct e) over (partition by a) num_distinct_values
  from my_table)
where num_distinct_values <= 1
order by 1
/

The county notes how the distinct non-null values in column e for each one.
Where clause then selects those with count = 0 (this is where e = null) and count = 1.
If the number is greater than 1, different values exist for this id.

Choose what fits your condition ;-)

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If you want to only 1 row of output for each distinct combination of currentpress and lastpcirim? This sounds like a job for GROUP BY.

And you want the row to contain a list of all different typidcontainers-delimited? This sounds like a job for the aggregate LISTAGG function.

WITH joined_data AS

(

SELECT DISTINCT

MST.curepress, mst.lastpcirim, inf.typeidcontainer

OF betmaster STD

LEFT JOIN betinfo ON TRIM (mst.curepress) inf = SUBSTR (TRIM (inf.currentpress)

1

3

)

)

SELECT curepress, lastpcirim

LISTAGG (typeidcontainer, ',')

THE Group (ORDER BY typeidcontainer) AS container_list

OF joined_data

Curepress GROUP, lastpcirim

;

Unfortunately, you can't say LISTAGG (DISTINCT ...), so you should always get the separate containers how you already are. (Note that the subquery is just what you posted).

Thanks for posting the CREATE TABLE and INSERT statements; It is very useful. Don't forget to tell what version of Oracle you are using. LISTAGG was new in Oracle 11.2.

Why not add CHECK constraints (and perhaps triggers) to your tables, so that curepress and currentpress are not stored with the head or trailing spaces? Then you wouldn't need to use the PAD in queries like this, and your code would be simpler and more effective.

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