Using the MIN and MAX functions
HelloGuide to please the following:
I have a table with records like below:
Invoice ID RegistrationNo InvoiceDate
1 AB-1 JANUARY 1, 10
2 CB-4 MARCH 23, 10
3 AB-1 1ST JULY 10
4 FG-2 AUG 1, 10
AB - 5 1 7 FEBRUARY 11
CB - 6 4 FEBRUARY 8, 11
7 CB-4 12 AUG 11
I want to pass the result of the SQL query, as below
For RegistrationNo = AB-1
Reffacture RegistrationNo InvoiceDate
3 AB-1 1ST JULY 10
AB - 5 1 7 FEBRUARY 11
For RegistrationNo = CB-4
Reffacture RegistrationNo InvoiceDate
CB - 6 4 FEBRUARY 8, 11
7 CB-4 12 AUG 11
I want to get that two records by RegistrationNo with the previous date of min, whose date max more forward.
Kind regards
Something like that?
WITH A AS (SELECT 1 INV_ID, 'AB-1' REG_NO, TO_DATE ('01-JAN-10', 'dd-mon-rr') INV_DATE FROM DUAL
UNION
SELECT 2 INV_ID, 'CB-4' REG_NO, TO_DATE ('23-mrz-10', 'dd-mon-rr') INV_DATE FROM DUAL
UNION
SELECT 3 INV_ID, 'AB-1' REG_NO, TO_DATE ('01-JUL-10', 'dd-mon-rr') INV_DATE FROM DUAL
UNION
SELECT 4 INV_ID, 'FG-2' REG_NO, TO_DATE ('01-AUG-10', 'dd-mon-rr') INV_DATE FROM DUAL
UNION
SELECT 5 INV_ID, 'AB-1' REG_NO, TO_DATE ('07-FEB-11', 'dd-mon-rr') INV_DATE FROM DUAL
UNION
SELECT 6 INV_ID, 'CB-4' REG_NO, TO_DATE ('08-FEB-11', 'dd-mon-rr') INV_DATE FROM DUAL
UNION
SELECT 7 INV_ID, 'CB-4' REG_NO, TO_DATE ('12-AUG-11', 'dd-mon-rr') INV_DATE FROM DUAL)
SELECT INV_ID,
REG_NO,
INV_DATE
FROM (SELECT INV_ID,
REG_NO,
INV_DATE,
ROW_NUMBER() OVER (PARTITION BY REG_NO ORDER BY INV_DATE DESC) RN
FROM A
)
WHERE RN<3
ORDER BY REG_NO,
INV_DATE DESC
Tags: Oracle Development
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the min and MAX values maintain their good values tia sal22
Hi all
I have problems a little value to stay in their correct min and max values min and max.
Continue to change their values (up and down) trying to get the max value to only display the maximum value at a given time and the same for the min value. I looked at the examples max and min and it seems that it should be in a while loop
http://forums.NI.com/NI/board/message?board.ID=170&thread.ID=359822but I would add another while loop and if so put it in the loop for? or is there a better way to do it.
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Grouping and then find the min and max
DROP TABLE purge of y;
CREATE TABLE y
(
ID NUMBER (10),
START_DATE_TIME NUMBER (15),
END_DATE_TIME NUMBER (15)
);INSERT INTO y VALUES (1, 20140602164819, 20140606140851);
INSERT INTO y VALUES (1, 20140827141743, 20140827142131);
INSERT INTO y VALUES (1, 20140827141744, 20140827141835);
INSERT INTO y VALUES (1, 20140827141744, 20140827142131);
INSERT INTO y VALUES (1, 20140827141944, 20140827142131);
INSERT INTO y VALUES (1, 20140827141944, 20140924142131);
INSERT INTO y VALUES (1, 20140927141944, 20141027142131);
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INSERT INTO y VALUES (2, 20140827141743, 20140827142131);
INSERT INTO y VALUES (2, 20140827141744, 20140827141835);
INSERT INTO y VALUES (2, 20140827141744, 20140827142131);
INSERT INTO y VALUES (2, 20140827141944, 20140827142131);
INSERT INTO y VALUES (2, 20140827141944, 20140924142131);
INSERT INTO y VALUES (2, 20140927141944, 20141027142131);COMMIT;
Select
*
Of
There
order by 2, 3;out necessary: when the output of the table are sorted by start_date_time and end_date_time in ascending order.
and when the value of for a particular id start_date_time is located between the
another set of values start_date_time and end_date_time for the same id then min (start_date_time) and max (end_date_time) is the desired output.and if there is no overlap then (start_date_time) min and max (end_date_time) is the output desired.
and for each line of the output in ascending order of line number order addd;
Example output is in the output table named
drop table output is serving;
create an output table
(
ID NUMBER (10),
START_DATE_TIME NUMBER (15),
END_DATE_TIME NUMBER (15),
ROW_NUMBER NUMBER (10)
);
Values to INSERT OUTPUT (1, 20140602164819, 20140606140851, 1);
Values to INSERT OUTPUT (1, 20140827141743, 20140924142131, 2);
Values to INSERT OUTPUT (1, 20140927141944, 20141027142131, 3);
Values to INSERT OUTPUT (2, 20140602164819, 20140606140851, 1);
Values to INSERT OUTPUT (2, 20140827141743, 20140924142131, 2);
Values to INSERT OUTPUT (2, 20140927141944, 20141027142131, 3);COMMIT;
SELECT
*
Of
output
ORDER BY 1,2,3,4;Thank you
SQL_Novice
Hello
Your postal code. It is difficult to tell what you're doing wrong without knowing what you are doing.
user6166680 wrote:
Hi Frank:
Max works for ID 3 values only because there is only one group here, as all other values compared, they overlap with max (end_date_time);
but when I use MAX for ID 1 and 2, the result set is not the same thing as LAG works because there is a GAP...
Exactly, you have to find the gaps. If start_date_time is less than or equal to the MAXIMUM of all the end_date_times earlier, then it isn't a gap; Otherwise, there is a gap.
What is the problem with MAX?
WITH got_new_group AS
(
SELECT id, start_date_time and end_date_time
CASE
WHEN start_date_time <= >= > MAX (end_date_time) OVER (PARTITION BY id )
ORDER BY start_date_time
end_date_time
ROWS BETWEEN UNBOUNDED PRECEDING
AND 1 PRECEDING
)
THEN 0
1. OTHER
END AS new_group
OF y
)
got_group_number AS
(
SELECT id, start_date_time and end_date_time
SUM (new_group) OVER (PARTITION BY ID.
ORDER BY start_date_time
end_date_time
) AS group_number
OF got_new_group
)
SELECT id
MIN (start_date_time) AS group_start_date_time
MAX (end_date_time) AS group_end_date_time
group_number
OF got_group_number
GROUP BY id, group_number
ORDER BY id, group_number
;
You will notice that it is exactly what I posted earlier, in response #5, except that instead of using the OFFSET it uses MAX.
Output:
ID GROUP_START_DATE_TIME GROUP_END_DATE_TIME GROUP_NUMBER
--------------- --------------------- ------------------- ---------------
1 20140602164819 20140606140851 1
1 20140827141743 20140924142131 2
1 20140927141944 20141027142131 3
2 20140602164819 20140606140851 1
2 20140827141743 20140924142131 2
2 20140927141944 20141027142131 3
3 20140330041350 47121231000000 1
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