Using the regular Expression of PL/SQL.

Similar Questions

• I know by logic box to get the output using the regular expression?

  Hello
  
  I am now only study the notion of Regexp. I had seen the best of Mr. Blus. Can I know how it works. I need this logic of the functionality of wildcards in sting matching Regexp (wildcard string Matching).
  

  SQL> ed
  Wrote file afiedt.buf
   
    1  WITH test_data AS (
    2  SELECT 'c:\temp\folderA\fileA.txt' t FROM DUAL UNION ALL
    3  SELECT 'c:\temp\fileA.txt' t FROM DUAL UNION ALL
    4  SELECT '\\mymachine\A\fileB.txt' t FROM DUAL UNION ALL
    5  SELECT '\\mymachine\A\B\fileB.txt' t FROM DUAL UNION ALL
    6  SELECT '\\mymachine\A\B\C\image.jpg' t FROM DUAL UNION ALL
    7  SELECT '\\mymachine\A\B\C\D\music.mpg' t FROM DUAL UNION ALL
    8  SELECT 'c:\myfolder\folderD\folderE\4969-A.txt' t FROM DUAL
    9  )
   10  select regexp_replace(t, '^.*[\]([^\]*)[\][^\]*$','\1')
   11* from test_data
  SQL> / 
   
  REGEXP_REPLACE(T,'^.*[\]([^\]*)[\][^\]*$','\1')
  ------------------------------------------------------------------
  folderA
  temp
  A
  B
  C
  D
  folderE
   
  7 rows selected.
   
  SQL>

  Please help me in this matter.
  
  Iqbal

  Sabrina wrote:
  One last question what is the average of

  The final "\1" in

   select regexp_replace(t, '^.*[\]([^\]*)[\][^\]*$','\1') 
  

  Iqbal

  It is a reference.

  See here:
  http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14251/adfns_regexp.htm#CHDHCIGH

  and in the middle of the table here:
  http://download.Oracle.com/docs/CD/B19306_01/AppDev.102/b14251/adfns_regexp.htm#CHDIEGEI

  Matches the nth previous subexpression, in other words, either grouped in parentheses, where n is an integer between 1 and 9. The parentheses cause > an expression be remembered; a backreference refers to him. A backreference account subexpressions from left to right, starting with the opening > bracket of each subexpression preceding. The expression is not valid if the source string contains less than n subexpressions preceding the \n.

  Oracle supports the expression of backreference in the regular expression pattern and the replacement of the REGEXP_REPLACE function string.
  The expression (abc: def) matches the strings abcxyabc and defxydef xy\1, but does not abcxydef or abcxy.

  A backreference allows you to search for a string repeated without knowing the actual string advance. For example, the expression ^(.*) \1$ > matches a line consisting of two adjacent instances of the same string.

  As explained in table 4-2, backreferences store sub-expressions matched in a temporary buffer, which allows to reposition the characters. You access the pads with the notation \n, where \n is a number between 1 and 9. Each subexpression brackets and is numbered from left to right.

• Using the regular expression!

  Hi all!
  
  
  I tried to get the right regular expression to parse the database link in scripts.
  For example
  
  Select 'X' from the double where REGEXP_LIKE (' select * from [email protected] myalias; ',' ([[: alnum:]\:._]+)(@)([[:alnum:]\:._]+]])', 'i')
  
  
  works fine but I don't want to return only DatabaseLinks which would include the lowercase characters... If I use this one:
  
  Select 'X' from the double where REGEXP_LIKE (' select * from [email protected] myalias; ',' ([[: alnum:]------:. _] +) (@) (. * [[: lower:]]. *) ([[: white:] |])) [[: space:]] | ; | /){1}' , 'i')
  It always returns true, because there are a few tiny characters after my DBLINK. Anyone know how to make in a way that I return true if the dblink itself contains lowercase characters?
  
  Thank you
  DOM
  
  Published by: user11846374 on 2009-08-31 12:22

  If all characters are uppercase, then return false. If there is at least 1 character lowercase, return true.

  What is

  SQL>  with t as (
   select '[email protected]' txt from dual union all
   select 'dual@DBLINK' txt from dual union all
   select 'dual@DBLInK' txt from dual union all
   select '[email protected]' from dual union all
   select '[email protected]' from dual union all
   select 'select * from [email protected] alias' from dual union all
   select 'select * from [email protected] alias' from dual union all
   select 'select * from [email protected] alias' from dual
  )
  --
  --
  select t.*,
         case
          when regexp_like (txt,
                            '@(\w*[[:lower:]]|\w*\.\w*[[:lower:]])')
          then
           'TRUE'
          else
           'FALSE'
         end
          c
  from t
  /
  TXT                                C
  ---------------------------------- -----
  [email protected]                     FALSE
  dual@DBLINK                        FALSE
  dual@DBLInK                        TRUE
  [email protected]                     TRUE
  [email protected]                     TRUE
  select * from [email protected] alias TRUE
  select * from [email protected] alias TRUE
  select * from [email protected] alias FALSE
  
  8 rows selected.
  

• in the regular expression non-pl/sql variable

  Hello again people.
  
  Wondering just if possible to pass a value of variable column in the regexp_substr model? Given: column_value = 123
  RegExp (string, pattern), where the model includes column_value? column_value can change at any time according to the value of the column in the table.
  
  Thank you!
  
  Published by: user11922215 on August 16, 2010 20:20
  
  Published by: user11922215 on August 16, 2010 20:21

  Hello

  Of course, you can use variables like this.
  By example, to see if x precedes y in one ',' - list delimited:

  REGEXP_LIKE ( string
           , ','      ||
             x          ||
             ',.*,'     ||
             y          ||
             ','
           )
  

  x and there can be any kind of expression that reutrns one string, including the columns, function calls and expressions BOX.

• Form validation helps with the regular Expression [a-zA-Z]

  I'm trying to use the regular expression [a-zA-Z] to allow only upper or lowercase WITHOUT SPACES. With the help of [a-zA-Z] allows space and numbers.

  Could someone give me a point in the right direction?

  Thank you!

  RGNelson wrote:

  I'm trying to use the regular expression [a-zA-Z] to allow only upper or lowercase WITHOUT SPACES. With the help of [a-zA-Z] allows space and numbers.

  Could someone give me a point in the right direction?

  Please try with the following regular expression, which should work for text entry fields 'a line' well standard.

  ^ [A-Za-z] + $

  See you soon,.

  Günter

• How can I use a regular expression to validate the email address

  How can I use a regular expression to validate the e-mail address.

  var emailExp:RegExp = /([a-z0-9._-]+?) @([a-z0-9.-] +). ([a - z] {2,4});

• The regular expression Dilimit

  How can I delimit the regular expression with the number sign (#) and then use an apostrophe in the expression.
  Can someone give some explamples.
  
  As regular expressions are placed in quotation marks, and I have an apostrophe in a string also how would I be able to specify the regular expression with a sign by dilimiting #.
  
  
  Thank you
  
  Published by: LostWorld Sep 15, 2010 05:40

  Hello

  Not sure I understand the question you are faced with, but I think using q citing might help:

  SQL> with t as (
    2  select 'abcd ''1234''' str from dual)
    3  -- end of sample data
    4  select str, regexp_substr(str, q'#'1234'#') str from t;
  
  STR         STR
  ----------- -----------
  abcd '1234' '1234'
  

  The symbol # now includes the string in the example above.

  You can view the documentation for more information in the link below:
  http://download.Oracle.com/docs/CD/E11882_01/server.112/e17118/sql_elements003.htm

• Is the function of the regular Expression

  Hi guys, using this model, I got this error:

  -4600 error has occurred during the regular expression match.

  I have attached the VI.

  can you help me? Thank you

  inuyasha84 wrote:

  Hi well I want to save (create) a file and do a check to see if the new file that I want to create already exists or not. If the idea was to see if the path of the new file is equal to the old path

  Why not just use 'check if the file or folder exists? (E/s files-> Adv file functions)

  Cameron

• Analyze the Mac address with the regular expression matching

  Hello world

  I have a problem with the function of regular expression matching,

  I try to analyse the response both a query arp - a 192.168.0.15 to retrieve the MAC address of the remote IP address, I used the following regular expression: ^ ([0-9a-fA-F]{2}[:-]){5}([0-9a-fA-F]{2})$

  I wonder why should I do a subset of the first string to extract only the part of the MAC address. The regular Expression function is not able to recognize the regular expression directly in the middle of a string?

  I only works when I extracted the subset of tring right as in the picture below.

  Thanks for your replies.

  Get rid of the "^" at the beginning of your regular expression. You are ordering him to find the model at the beginning of the string.

• The regular expression problem

  Dear friends,

  In my script I have some sections that test the contents of an edit field before it is processed further.

  Perfectly things like the following:

  var re_Def = /#[A-Za-z][A-Za-z0-9_]+/;          // valid variable name ?
  items = ["#correct", "notcorrect", "#This_is4", "#thisIs", "@something", "#ALLOK", "", ];
  // search    0            -1          -1!!        -1!!          -1        -1!!     -1      <--- incorrect method
  // test    true         false         true        true        false       true    false    <--- correct method
  for (var j = 0; j < items.length; j++) {
    var item = items[j];
    alert ("'" + item + "' ==> " +  item.search(re_Def) + "\n" + re_Def.test(item));
  }
  var re_Def = /(\[ROW +\d+\]|\[COL +\d+\]|\[CELL +\d+, +\d+\]|Left *\(\d*\)|Right *\(\d*\)|Above *\(\d*\)|Below *\(\d*\))/;
  items = ["[ROW 17]", "[Row n]", "[ROW n]", "[CELL 3, 9]", "[CELL 3 9]", "Abbove()", "Right(3)"];
  // result  true        false      false         true         false        false         true    
  for (var j = 0; j < items.length; j++) {
    alert ("'" + items[j] + "' ==> " +  re_Def.test(items[j]));
  }
  

  But what follows always returns false, independly of the content of the string element:

  var re_Def = /{[EFJ]\d*}|{I}/;    // valid format def?
  var item = "{E27}";
  var result = re_Def.test(item);
  alert (result);                   // false !!
  

  RegEx buddy told me, that
  -l' REGULAR expression is correct
  -the result must be true, not false

  -The verbose definition of the RegEx is:
  Match is the following regular expression (attempting the next alternative only if this one fails) "{\d* [EYF]}."
  Match the character "{" literally "{}".
  Match a single character present in the list "J" "[EYF]."
  Match a single digit 0. 9 paper"\d*»
  Between zero and unlimited times, as many times as possible, giving as needed (greedy) «*»
  Match the character "}" literally "}".
  Or match number 2 below (the entire match attempt fails if it cannot match) regular expression "{i}".
  Match the characters "{i}" literally "{i}".

  Typo unrecognized? Test the faulty method?

  Results are fake, as soon as I use the list of characters []] - but look at the first block of code: there are also lists of character they are treated properly.

  The braces in the regular expression must be escaped to be taken literally:

  var re_Def = /\{[EFJ]\d*\}/;
  

  Kind regards

  JoH

• How get us a word in the regular expression

  Hi all

  I am new to regular expressions, I did some tests in Google, but not clearly how to reach the scenario below

  SELECT *
  FROM Icehead tih, head fh
  WHERE  tih.head_id = fh.head_id         
  AND    UPPER (tih.head) LIKE UPPER ('%WANT%') 
  

  The query above, we check a keyword like "WANT."

  -Along with the 'FAULT', we must move to another keyword like 'SHELL '.

  -Have you used or condition operator to above query as shown below

  SELECT *
  FROM Icehead tih, head fh
  WHERE  tih.head_id = fh.head_id 
  and UPPER (tih.head) LIKE UPPER ('%WANTS%') or UPPER (tih.head) LIKE UPPER ('%SHELL%')
  

  -Instead of use 'or' want to use the regular operator, in the future if any other keyword want to use, then we can send this word using dynamically in the process, could help me on this.

  Kind regards

  Sruthitamiri

  Sruthi Tamiri wrote:

  Thanks for your suggestion, I have % in a regular expression, sorry for the same.

  One last point after patten 'i' used what I indicate here, can you explain even.

  It is a match parameter to specify the corresponding case. Please see the documentation for the basic questions like this.

• The Regular Expressions and GUID.

  Hello gurus, I hope you can help me!
  I need to select GUID from a table and to do this, I need the regular Expression. My
  Perl is not good and not good Regular Expression. My database is Oralce 11.2.0.2.0 and
  Linux (Oracle Version 6) is the operating system of the Machine. If you need further information,
  I'll look closely. Thank you. Jehangir.

  >

  Hi Jehangir and welcome to the forums.

  I need to select the GUID of a table and to do this,

  Well, the first thing we do is read the forum FAQ and also the post by BluShadow
  at the top of the messages on the home page of the forum. You should have provided code (DDL
  and DML) showing your particular problem, but since it's your first time, I'll be gentle ;)

  We have it done - clients have sometimes GUID as PKs, and we need to send data to
  their systems, but it is not as simple as it may first appear.

  GUID may arise in three formats.

  The Oracle one - SELECT Sys_GUID() from DUAL which is just a string of 32 hexadecimal characters.
  Then the chain with the hyphen, then the string with dashes and {} at the beginning and end (see
  examples of data).

  with datax as
  (
    SELECT '79A864CCD8E44CD8B0A2765DF9EF337B' as guid  FROM DUAL  UNION ALL
    SELECT '79A864CFD8E44CD7B0A2765DF9EF337B' FROM DUAL UNION ALL
    SELECT '8gdfsgsgfdg' FROM DUAL UNION ALL  -- dummy for testing
    SELECT '21EC2020-3AEA-1069-A2DD-08002B30309D' FROM DUAL UNION ALL
    SELECT '21EC5550-3AEA-1069-A2FF-08002B30309D' FROM DUAL UNION All
    SELECT '{21CC2020-3AFA-1A69-A2DD-08002B30309D}' FROM DUAL
  )
  
  -- first one is the Oracle format
  select * from datax where regexp_like(guid, '[0-9a-fA-F]{32}'); -- Oracle select sys_guid();
  
  -- second one is with hyphens
  
  select * from datax where regexp_like(guid, '[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}');
  
  -- third one is with hyphens and curly brackets.
  
  select * from datax where regexp_like(guid, '^\{[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}\}$');
  
  -- This converts both of the last two formats back into Oracle format, which is what
  -- we use. Notice, that I haven't used regualar expressions to do this. Regexes are
  -- computationally expensive, and you should use Oracle's string furnctions if possible
  
  SELECT REPLACE(REPLACE(REPLACE(GUID, '{', ''), '}', ''), '-', '')  FROM Datax;
  

  HTH,

  Paul...

  Jehangir.

• Sense of the regular expression in detail

  Hi all
  
  I don't know if this question is to type correct forum but my question is
  
  What is retail mean more regex? Please help me understand this character by character.
  
  Expression is ^ [(\\w\\-]([\\.\\w])+[\\w]+@([\\w\\-]+\\.) + [A - Z] {2,4} $]
  
  Thank you

  sabre150 wrote:
  In general terms, that the regular expression is a poor attempt to check email address syntax. Very bad because it does not cover the complete specification.

  Yes. And after that: If your application looks at the e-mail address (valid) of someone and told them that this is not an email address valid, they will think you are a fool. And if your application is used for commercial purposes, which would be a black mark against your company. You're better not to validate e-mail addresses to all that the implementation of a solution with false negatives.

• Is it possible to use the AirPort Express to AirPlay only? (Wireless)

  Hello

  I have a speaker and I would empower AirPlay for it. I have an old airport express here in my house and I wanted to plug my express from the airport to my wireless network and allow the airplay.

  The only thing I don't want to not remove is the possibility to extend the wireless network, because I'm pretty sure it will do more bad then good, since I was a big of AC very close to the speaker wireless router. (http://www.asus.com/us/Networking/RT-AC5300)

  Is it possible to use the Airport express only airplay? Without trying to extend my network?

  Thanks in advance!

  Kind regards

  Tiago

  Yes, if you have the main router near the speakers... then simply plug the Express into the enclosure of the ethernet... Run it in Bridge mode and turn off wireless... Then check if you can find it in iTunes etc to send the stream of airtime.

  Or you can configure it to join a wireless network... it will not extend... Apple call it client mode.

  AirPort Express: How to join an existing client mode - Apple Support Wi - Fi network

• I can animate individual characters in a block of text using the Wiggle Expression?

  I'm new to after Express and just diving in expressions. I was trying to understand if there was a simple way to use the wiggle expression so that he would wiggle of the individual characters in a text block independently of each other.

  Certainly appreciate any help.

  Have you tried the earthquake selector? Alternatively, you could add a selector expressions and add and raise the expression as follows:

  seedRandom (textIndex, true);

  Wiggle (1,100)

  Dan