Weighted average end days: how the sum in different currencies?

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• How the SUM cells including the text and the number?

  Hello world

  Someone can tell me how the SUM cells include the text and the number?

  1 Bob 20

  2 30 Jane

  3 50 Jame

  Total 100

  Thank you

  Hi Jordan,.

  If the numbers are not always two digits, FIND the position of the space between the number and name:

  

  Formula in B2 (fill down)

  = FIND("",A2)

  Then use the LEFT function to get the number in the column C:

  

  Formula in C2 (fill down)

  = LEFT (A2, B2)

  This will give a text string (Tip: left-aligned).

  Convert to a numeric value in the D column with the VALUE function:

  

  Formula in D2 (fill down)

  VALUE = (C2)

  (Tip: propped right)

  Table 1 has a header row and footer of the line, and the SUM is easy. Formula to the D8 footer line:

  = SUM (D)

  Kind regards

  Ian.

  Edit: You can hide columns B and C

  

  Ian.

• How graphic how the sum of several metrics of in a dashboard.

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  An example would be showing collective management s VM in balloning of CPU and memory of the pool on line on a chart.

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  If you want the chart to reflect everything that you can do the stacking graphics option which will be sleeping all values.

• How the sum of a series of if Athens?

  Given:

  

  I need adding the cost of reception (PM01) breakfast (Cost01), reception cost (Cost02) and lunch cost of reception (Cost03).

  If the cost of each receipt exceeds each meal allowance, use value meal in sum compensation.

  If the cost of each reception is less than or equal to each value of the meal allowance, then use the cost of reception in all.

  You can use a calculation script customized to the field which displays the sum, something like:

  Custom calculation script

  (function () {}

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  var v1 = + getField("Cost01").value;

  var v2 = + getField("Cost02").value;

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• Columns of the sum of different record count of joined tables

  I have a problem with a query, please help.
  
  I have two tables:

  create table rec_a (key_code varchar(20),
                  TOT_AMT varchar(20),
                  INV_AMT varchar(20))
  / 
   
  create table rec_B (key_code varchar(20),
                  INVOICE_AMT varchar(20),
                 PAID_AMT varchar(20))
  / 
   
  insert into REC_A values (123123,  1168182.16, 1168182.16);
  
  insert into REC_B values (123123, 205699.04,205699.04);
  insert into REC_B values (123123,130912.78,130912.78);
  insert into REC_B values (123123, 81622.87,81622.87);
  insert into REC_B values (123123, 438032.43,438032.43);
  insert into REC_B values (123123, 159936.17,159936.17);
  insert into REC_B values (123123, 151978.87,151978.87);
   

  Table 1
  KEY_CODE TOT_AMT INV_AMT
  123123 1168182.16 1168182.16
  
  
  Table 2
  KEY_CODE INVOICE_AMT PAID_AMT
  123123 205699,04 205699.04
  123123 130912,78 130912.78
  123123 81622,87 81622.87
  123123 438032,43 438032.43
  123123 159936,17 159936.17
  123123 151978,87 151978.87
  
  
  I wrote a query to sum up all the areas (tot_amt, inv_amt, invoice_Amt, paid_amt)

  SELECT B.key_code,sum(A.invoice_amt),sum(a.paid_amt),SUM(b.tot_Amt),SUM(b.inv_amt) FROM rec_a B, rec_b A WHERE A.KEY_CODE=B.KEY_CODE AND B.KEY_CODE in ('123123')
  group by B.key_code

  I got this:
  
  KEY_CODE SUM (A.INVOICE_AMT) SUM (A.PAID_AMT) SUM (B.TOT_AMT) SUM (B.INV_AMT)
  123123 1168182.16 1168182.16 7009092.96 7009092.96
  
  But I expected this
  
  KEY_CODE SUM (A.INVOICE_AMT) SUM (A.PAID_AMT) SUM (B.TOT_AMT) SUM (B.INV_AMT)
  123123 1168182.16 1168182.16 1168182.16 1168182.16
  
  
  Can someone help me out here?
  
  Thank you
  
  Published by: 1003064 on April 29, 2013 03:19

  Hello

  1003064 wrote:
  I have a problem with a query, please help.

  I have two tables:
  Table 1
  KEY_CODE TOT_AMT INV_AMT
  123123 1168182.16 1168182.16

  Table 2
  KEY_CODE INVOICE_AMT PAID_AMT
  123123 205699,04 205699.04
  123123 130912,78 130912.78...
  123123 81622,87 81622.87
  123123 438032,43 438032.43
  123123 159936,17 159936.17
  123123 151978,87 151978.87

  I wrote a query to sum up all the areas (tot_amt, inv_amt, invoice_Amt, paid_amt)

  SELECT B.key_code, sum (a.invoice_amt), sum (a.paid_amt), SUM (b.tot_Amt), SUM (b.inv_amt) FROM rec_a A, rec_b B WHERE A.KEY_CODE = B.KEY_CODE AND B.KEY_CODE in ('123123')
  B.key_code group

  I got this:
  KEY_CODE SUM (A.INVOICE_AMT) SUM (A.PAID_AMT) SUM (B.TOT_AMT) SUM (B.INV_AMT)
  123123 1168182.16 1168182.16 7009092.96 7009092.96

  But I expected this

  KEY_CODE SUM (A.INVOICE_AMT) SUM (A.PAID_AMT) SUM (B.TOT_AMT) SUM (B.INV_AMT)
  123123 1168182.16 1168182.16 1168182.16 1168182.16

  Thus, the last 2 columns must be exactly what is stored in table1? Then either
  b include these columns in the GROUP BY clause and not to use the SUM,
  (b) the GROUP BY on rec_a alone, separately, can't join the results to the rec_b, or
  (c) using MIN or MAX, instead of SUM. (Anyone. Since there is only one value, MIN will be the same as MAX.)

  Here is an example of (a):

  SELECT    B.key_code
  ,       sum (a.invoice_amt)     AS sum_invlice_amt
  ,       sum (a.paid_amt),     AS sum_paid_amt
  ,       b.tot_Amt
  ,       b.inv_amt
  FROM        rec_a          A
  ,        rec_b          B
  WHERE        A.KEY_CODE     = B.KEY_CODE
  AND        B.KEY_CODE      in ('123123')
  group by  B.key_code
  ,            b,tot_amt
  ,       b.inv_amt
  ;
  

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
  Point where the above query is to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in these places.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• Capture the salary of the employee in different currencies in a single enterprise group

  Hello
  
  Scenario: According to group unique buiness, information of the employees of several countries are counted (as there may be very few employees in each of these countries).
  
  Status of pay is NOT implemented, how we capture information on country-specific employee wages to say, capture of an employee's salary in different currencies under unique business group.
  
  Thank you

  You can use Add'l salary admin. Details FDF to capture the currency and converted value. Salary of the hand will be in a base currency.

  Thank you

• SQL - how the sum on specific lines

  Hello

  Forever, the line, I want to show MySQL for previous lines, only when the previous values are equal = 1,.

  and only for successive lines.

  for example, the result expected on the column 'result '.

  Result of ID value

  100 1-

  130 1 2-> (current 1 + pre 1)

  3 500-

  1 600-

  2-1-700-> (current 1 + pre 1)

  1000-1-3-> (current 1 + precedent1 + 1 previous pre)

  4 1 1200

  How can do us it easily?

  I thank everyone in advance.

  Here's a way...

  with t (id, value) :)

  Select 100.1 in union double all the

  Select 130.1 Union double all the

  Select 500,3 Union double all the

  Select 600,1 Union double all the

  Select 700,1 Union double all the

  Select 1000,1 Union double all the

  Select double 1200,1

  )

  Select

  ID

  value

  case

  When start_of_group = 0 and = 1 value

  then MySQL over (partition by group_num by id order)

  Another null

  end result

  de)

  Select sum (start_of_group) (any order by id) as group_num

  start_of_group

  id

  value of)

  Select

  case

  When lag(value,1,0) (any order by id)! = 1 then 1

  0 otherwise

  end as start_of_group

  id

  value

  t

  )

  )

  order by id

  ;

  Kind regards

  Bob

• calculation of ratios and rounding - how the sum of last record to give 1

  I'm putting in a single query to calculate the reports for an unknown number of records. I want to turn the ratios to 5 decimal places and I want the total reports of equal to 1.
  
  for example
  
  If I have 3 folders with Qty total overal 4,5,6 is 15
  I note 3 lines
  Round (4/15.5),
  Round (5/15.5),
  Round (6/15.5)
  
  but I want to ensure total = 1
  so I will try to do something like
  
  Round (4/15.5),
  Round (5/15.5),
  1 - round(4/15,5) - round(5/15,5)
  
  can someone help show me the sql construction? I've been trying and failing using where clause
  
  of course this example would add to 1 but other unknown ratios may not match up to 1.
  
  Published by: user12154024 on November 2, 2009 22:32

  Hello 12154024,

  Welcome to the forum. May not be a more elegant solution, but it shows how it works step by step

  WITH t AS (
  SELECT 4 n FROM dual
  UNION ALL
  SELECT  5 n FROM dual
  UNION ALL
  SELECT 6 n FROM dual
  )
  ,t1 AS (
  SELECT  n
         ,ROUND(RATIO_TO_REPORT(n) OVER (),5) AS rr
         ,COUNT(n) OVER () AS c
         ,ROW_NUMBER() OVER (ORDER BY n) AS rn
  FROM    t
  )
  ,t2 AS (
  SELECT  n
         ,rr
         ,SUM(rr) OVER (ORDER BY n) s
         ,c
         ,rn
  FROM t1
  )
  SELECT  n
         ,rr
         ,CASE WHEN c = rn THEN
              rr + (1 - s)
          ELSE
              rr
          END rr2
         ,s
  FROM    t2
  ORDER BY rn;
  
  N   RR        RR2       S
  --- --------- --------- --------
  4   0.26667   0.26667   0.26667
  5   0.33333   0.33333   0.6
  6   0.4       0.4       1        
  
  3 rows selected
  

  The part "WITH t AS" generates data
  T1 calculate the ratio, counts the number of records and signs a current issue
  T2 to calculate a cumulative ratio
  the last part takes these data and for the last record (number = count running) it allows to adjust the ratio.

  You can see if you are using other data

  WITH t AS (
  SELECT 4.78 n FROM dual
  UNION ALL
  SELECT  5 n FROM dual
  UNION ALL
  SELECT 6 n FROM dual
  )
  ...
  
  N    RR       RR2      S
  ---- -------- -------- --------
  4.78 0.30292  0.30292  0.30292
  5    0.31686  0.31686  0.61978
  6    0.38023  0.38022  1.00001  
  
  3 rows selected
  

  Concerning
  Marcus

• How the sum of these two tables?

  Hello

  I have two tables

  DESC ACTIVITE_EXCEP_FAITE

  NUMBER OF FICHE_ID

  NUMBER OF SERVICES_ID

  NUMBER OF ACTIVITES_EXCEPTIONNELLES_ID

  NUMBER OF TIME

  NUMBER OF ACTIVITE_EXCEP_FAITE_ID

  DESC ACTIVITE_FAITE

  NUMBER OF FICHE_ID

  NUMBER OF ACTIVITES_ID

  NUMBER OF SECTEURS_ID

  LENGTH NUMBER (8.2)

  NUMBER OF ACTIVITE_FAITE_ID

  NUMBER OF TYPE_ACTIVITE_ID

  I want to add the column to the DURATION of the two tables when they get the same FICHE_ID. FICHE_ID is not a join field.

  I've tried this application, but it gives result when two recordings of the two table share the same number FICHE_ID.

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  OF AF, ACTIVITE_EXCEP_FAITE AEF ACTIVITE_FAITE

  WHERE AF. FICHE_ID = AEF. FICHE_ID

  GROUP BY AF. FICHE_ID;

  Can you help me write this selection?

  Thank you very much for your help!

  Like this?

  select nvl(af.fiche_id, aef.fiche_id) fiche_id
       , sum(nvl(af.duree,0)) + sum(nvl(aef.duree,0)) duree
    from activite_faite af
    full join
         activite_excep_faite aef
      on af.fiche_id = aef.fiche_id
   group by nvl(af.fiche_id, aef.fiche_id);
  

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  Oops, my bad,
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• Need for a function defined by the user in order to obtain a weighted average

  Hello

  We have a table where we want to device the weighted average for a column of prices below using formula,

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  We have a few lines where part or all of the columns that is price or quantity can be NULL.

  We have tried to write the function as follows however, it fills even after 30 minutes, where as we have the addition of this feature request could was completed in 25 seconds.

  Please note that we are dealing with big data i.e. the table could have 50 million records. It has appropriate indexing and other components to improve performance required.

  We know that we did something wrong in the creation of feature below, but we are unable to resolve

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  IS

  TEMP NUMBER (26,13);

  BEGIN

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  RETURN TEMP;

  END WEIGHTEDAVGPRICE;

  
  

  Here, we send the parameter THAT PCOLNAME represents the name of the price column we want to do a weighted average.

  
  

  We know we could do this without adding a feature, but we need instructions BOX, and then in our SELECT clause. We use toplink to query the database, in this case, it will be difficult to covert.

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  Thank you

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  The reason for the decrease in performance when you use the function, you call the function from a query and which is originally a context switch between SQL and PL/SQL engines.  That is known to slow down performance.  If you can only do the task in SQL, you must do so, in order to avoid context switching.

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  Please read:

  Re: 2. How can I ask a question in the forums?

• How do rotate on a date and see the sum of the value of another column

  Hello
  
  I searched through the forum and cannot find a query similar to my question feels so post this new thread.
  
  First of all, it is probably useful indicating that I am using Oracle 10 g.
  
  I have a table that is used to store the details of the booking (essentially a booking system) and I would use this data to display the details of the customers stay on one line.
  
  The table has the following columns:

  BOOKING_ID
  CUSTOMER_ID
  DATE_OF_ARRIVAL
  NUMBER_OF_NIGHTS
  NUMBER_OF_PEOPLE

  Some example records could be:
  
  

  BOOKING_ID    CUSTOMER_ID     DATE_OF_ARRIVAL    NUMBER_OF_NIGHTS   NUMBER_OF_PEOPLE
  --------------------------------------------------------------------------------------------
  1                    201      13-JAN-2010        5                   1
  2                    202      13-JAN-2010        3                   2  
  3                    202      13-JAN-2010        4                   1
  4                    203      15-JAN-2010        2                   3

  On this basis I would like to display the output so that I can show a sum of the NUMBER_OF_PEOPLE reserved to per customer per day, as such:

  CUSTOMER_ID     13-JAN   14-JAN   15-JAN   16-JAN   17-JAN   18-JAN   19-JAN 
  -----------------------------------------------------------------------------------------
  201                   1       1        1        1        1        0        0
  202                   3       3        3        1        0        0        0
  203                   0       0        3        3        0        0        0

  I watched analytical functions in the documentation and several books of Oracle that I have, but have so far struggled to find how to make the performance desired. Even using the excellent response to the previous post on the forum, I got Re: how to count the occurrence of a date in a range I was not able to get a feasible request.
  
  Any help or advice would be much appreciated.
  
  Kind regards
  Stu
  
  Published by: macmanxie on January 10, 2011 21:16

  Hello

  macmanxie wrote:
  ... The suggested approach goes only to return a number if the DATE_OF_ARRIVAL corresponds to the date in the CASE statement, however I have the added complexity of wanting to show a count of all the days that the customer is booked, for, by making use of the NUMBER_OF_NIGHTS. I tried to use some of the examples provided on morganslibrary.org, for example:

  sum( CASE WHEN  TRUNC (arrival_date) between '01/13/2011' and TRUNC (arrival_date+no_of_nights) THEN nvl(no_of_people,0) ELSE 0 END) AS jan_13
  

  but this does not produce the desired result.

  You check if arrival_date is between January 13 and arrival_date + no_of_nights (as if the arrival date could all be posterior to the arrival_date + no_of_nights).
  Are not really interested in whether or not January 13 ib between arrival_date and arrival_date + no_of_nights?

  NVL ( SUM ( CASE
                  WHEN  TO_DATE ( '01/13/2011'
                         , 'MM/DD/YYYY'
                       )          BETWEEN  TRUNC (arrival_date)
                           AND       TRUNC (arrival_date) + no_of_nights
               THEN  no_of_people
           END
         )
      , 0
      )          AS jan_13
  

  Always format your code. It is important to format your code if you are the only who who will ever read but it is even more important if you are posting on a forum like this and ask other people to read.
  Not to compare the DATEs in the strings; explicitly use a conversion function, like TO_DATE, above, where necessary.
  Both
  SUM (NVL (x, 0)) and
  NVL (SUM (x), 0) get the same results, but the latter is more effective. If you have 1000 lines, the first way is calling NVL 1000 times, but the second way is calling only once.

  If your previous thread
  Re: How to count the occurrence of a date in a range
  Gets you the right data, but it has one row for each distinct combination of customer_id and date, then you can switch it to a form that contains a line by the customer and another column for each date.

  If you need help, post CREATE TABLE and INSERT statements for some examples of data and outcomes from these data. The post you are trying better to a request, including a subquery that gets no cross-the raw table dynamic results.
  There will be a fixed number of columns in the output swing? If this is not the case, how do you deal with that? Which of these options in the thread I posted above)
  Re: County report and the sum of the number of rows by multiple columns
  ) is best for your needs? Than others is acceptable?