What is cumulative hierarchy?

Similar Questions

• What is the hierarchy for running reports?

  Hello world
  
  Can someone tell me what is the hierarchy for running reports as fact when the query data model is executed, when groups (Group of columns, the place holders etc. within a group of data model is executed), form setting etc is executed.
  
  Thank you
  Gerard

  If there are two absolutely independent querries, then I can just tell.
  If two querries are related, then, that the other is linked is executed first.
  But before any two querry run the beforereport, the beforeparameterform and after triggers parameterform.
  So, the best way to ensure that something is executed first is putting in the afterpform trigger.
  Do not count the trigger on afterreport.

• Hierarchy and symbols

  What is the hierarchy, or rather, the functions of some symbols in the ACA?
  
  For example, unlike a sign with two + ++?
  It is necessary to create a layer, and then set a point with the pen tool, since by clicking directly on the figure, shape the value, it automatically creates a layer?
  
  Is there a difference between the layers in the form of their construction?
  
  Point of origin sometimes causes distortions in the shape of head, for example. There is a fundamental error committed for that to happen and how to fix it?
  
  There is a detailed list of codes of symbols with their appropriate explanations and functions for the work done on the PS?
  
  (Note: usually only work with Photoshop to build my characters).
  
  Thank you

  A lot of this stuff is to be large in the next release Preview 4 this summer. We realize how painful it is to fake things in Photoshop or Illustrator - animator of the character is much better suited for such things.

  + Is just a way to call something 'independent chain' - meaning it can move its own.  ++ is the equivalent of adding + to each child of the parent group, but we encourage that most (I know that we need to update some of our examples to reflect this).

  Yes, your method of pen tool works very well, but in PV4, you won't need to do more - you see and be able to move the origin of all the groups inside CH.

  The unwanted distortion is usually a matter of hierarchy or mesh - CH thinks a mesh is shaped differently than expected, or in a group or something that is pulling the wrong way. Again, it will be easier to diagnose and solve in PV4 with new attachment styles, in order to have more control how things connect through welding, rotate and without attaching styles-, but also a new tool discontinuous that tie together things much easier (this is my go - to tool for "difficulty this weird fix the problem").

  The help doc 'Prepare your work' has the complete diagram and info we currently recommend: work prepared in Adobe character animation

  Hope that helps!

• Identify the missing lines for the hierarchy

  Oracle 10.2.0.1
  Windows XP
  
  create table vill (identification number (5), area varchar2 (20), subarea1 varchar2 (20), subarea2 varchar2 (20), location varchar2 (20));
  Insert in the vill values(1,'AREA1','SUBAREA1','SUBAREA2','AREA1');
  Insert in the vill values(2,'AREA1','SUBAREA1','SUBAREA2','SUBAREA1');
  Insert in the vill values(3,'AREA1','SUBAREA1','SUBAREA2','SUBAREA2');
  Insert in the vill values(4,'AREA1','SUBAREA1','SUBAREA2','VILL1');
  Insert in the vill values(5,'AREA1','SUBAREA1','SUBAREA2','VILL2');
  Insert in the vill values(6,'AREA1','SUBAREA1','SUBAREA2','VILL3');
  Insert in the vill values(7,'AREA1','SUBAREA1','SUBAREA2','VILL4');
  -Before is a perfect set of lines because it has all the lines in the area, subarea1 and subarea2.
  Insert in the vill values(8,'AREA2','SUBAREA1','SUBAREA2','AREA2');
  Insert in the vill values(9,'AREA2','SUBAREA1','SUBAREA2','SUBAREA1');
  Insert in the vill values(10,'AREA2','SUBAREA1','SUBAREA2','VILL5');
  Insert in the vill values(11,'AREA2','SUBAREA1','SUBAREA2','VILL6');
  Insert in the vill values(12,'AREA2','SUBAREA1','SUBAREA2','VILL7');
  Insert in the vill values(13,'AREA2','SUBAREA1','SUBAREA2','VILL8');
  
  Insert in the vill values(14,'AREA3','SUBAREA1','SUBAREA2','AREA3');
  Insert in the vill values(15,'AREA3','SUBAREA1','SUBAREA2','SUBAREA2');
  Insert in the vill values(16,'AREA3','SUBAREA1','SUBAREA2','VILL9');
  Insert in the vill values(17,'AREA3','SUBAREA1','SUBAREA2','VILL10');
  Insert in the vill values(18,'AREA3','SUBAREA1','SUBAREA2','VILL11');
  Insert in the vill values(19,'AREA3','SUBAREA1','SUBAREA2','VILL12');
  
  Insert in the vill values(20,'AREA4','SUBAREA1','SUBAREA2','SUBAREA1');
  Insert in the vill values(21,'AREA4','SUBAREA1','SUBAREA2','SUBAREA2');
  Insert in the vill values(22,'AREA4','SUBAREA1','SUBAREA2','VILL13');
  Insert in the vill values(23,'AREA4','SUBAREA1','SUBAREA2','VILL14');
  Insert in the vill values(24,'AREA4','SUBAREA1','SUBAREA2','VILL15');
  Insert in the vill values(25,'AREA4','SUBAREA1','SUBAREA2','VILL16');
  commit;
  Select * from city;

          ID AREA                 SUBAREA1             SUBAREA2             LOCATION
  ---------- -------------------- -------------------- -------------------- --------------------
           1 AREA1                SUBAREA1             SUBAREA2             AREA1
           2 AREA1                SUBAREA1             SUBAREA2             SUBAREA1
           3 AREA1                SUBAREA1             SUBAREA2             SUBAREA2
           4 AREA1                SUBAREA1             SUBAREA2             VILL1
           5 AREA1                SUBAREA1             SUBAREA2             VILL2
           6 AREA1                SUBAREA1             SUBAREA2             VILL3
           7 AREA1                SUBAREA1             SUBAREA2             VILL4
           8 AREA2                SUBAREA1             SUBAREA2             AREA2
           9 AREA2                SUBAREA1             SUBAREA2             SUBAREA1
          10 AREA2                SUBAREA1             SUBAREA2             VILL5
          11 AREA2                SUBAREA1             SUBAREA2             VILL6
          12 AREA2                SUBAREA1             SUBAREA2             VILL7
          13 AREA2                SUBAREA1             SUBAREA2             VILL8
          14 AREA3                SUBAREA1             SUBAREA2             AREA3
          15 AREA3                SUBAREA1             SUBAREA2             SUBAREA2
          16 AREA3                SUBAREA1             SUBAREA2             VILL9
          17 AREA3                SUBAREA1             SUBAREA2             VILL10
          18 AREA3                SUBAREA1             SUBAREA2             VILL11
          19 AREA3                SUBAREA1             SUBAREA2             VILL12
          20 AREA4                SUBAREA1             SUBAREA2             SUBAREA1
          21 AREA4                SUBAREA1             SUBAREA2             SUBAREA2
          22 AREA4                SUBAREA1             SUBAREA2             VILL13
          23 AREA4                SUBAREA1             SUBAREA2             VILL14
          24 AREA4                SUBAREA1             SUBAREA2             VILL15
          25 AREA4                SUBAREA1             SUBAREA2             VILL16
  
  25 rows selected.

  Power required:

          ID AREA                 SUBAREA1             SUBAREA2             LOCATION
  ---------- -------------------- -------------------- -------------------- --------------------
          26 AREA2                SUBAREA1             SUBAREA2             SUBAREA2
          27 AREA3                SUBAREA1             SUBAREA2             SUBAREA1
          28 AREA4                SUBAREA1             SUBAREA2             AREA4

  Why?
  
  Because as I said above that rowset for the euro1 area is perfect because in the location column there are lines for the euro1, SUBAREA1 and SUBAREA2 area. is exists, whereas if we see that there are no lines for AREA2 with the value SUBAREA2 in the place, even regarding the Domain3, there is no line that has the value of the SUBAREA1 location and even for AREA4, there is no line as location = AREA4. It is a table which is having all the names of place with nested values; for example, we can see that vill7 is exist in zone2 including SUBAREA1 (COLUMN NAME) = "SUBAREA1" AND SUBAREA2 (COLUMN NAME) = "SUBAREA2", but I would like to know location = SUBAREA2 then it will say no line, I want to generate all the lines that is to have no value in the column location for said AREA/SUBAREA1/SUBAREA2 column. Table is sorted by ID. Total column lines are 45800.
  

  SQL> select * from vill where area='AREA1' and location='SUBAREA1';
  
          ID AREA                 SUBAREA1             SUBAREA2             LOCATION
  ---------- -------------------- -------------------- -------------------- --------------------
           2 AREA1                SUBAREA1             SUBAREA2             SUBAREA1

  Ok

  SQL> select * from vill where area='AREA2' and location='SUBAREA1';
  
          ID AREA                 SUBAREA1             SUBAREA2             LOCATION
  ---------- -------------------- -------------------- -------------------- --------------------
           9 AREA2                SUBAREA1             SUBAREA2             SUBAREA1

  It is also ok, but if said

  SQL> select * from vill where area='AREA2' and location='SUBAREA2';
  
  no rows selected 

  < <-Yes, this line I want to generate, because there should be a line whose location = "SBUAREA2" but why? Because otherwise how do I know what is the hierarchy of the SUBAREA2; While vill 5,6,7 and 8 were SUBAREA2 as "SUBAREA2".
  
  I'm not sure how I am clear in my question, please let me know if I need to provide more details.
  
  Thank you.

  user12050217 wrote:
  ... query should return:

  ID AREA                 SUBAREA1             SUBAREA2             LOCATION
  ---------- -------------------- -------------------- -------------------- --------------------
  131 my state             my city              my city              street 2
  

  Sorry, I don't understand that one line. Was it a mistake? I think I understand all the other lines that you want to, but I do not understand why you want the one above. Did you mean

  ID AREA                 SUBAREA1             SUBAREA2             LOCATION
  ---------- -------------------- -------------------- -------------------- --------------------
  131 my state             my city              street 2             street 2
  

  ?

  If this is not the case, why you don't want the row immediately above? Why don't you also:

  `       ID AREA                 SUBAREA1             SUBAREA2             LOCATION
  ---------- -------------------- -------------------- -------------------- --------------------
         131 my state             new city             new city             street 2
  

  ?

  Assuming it was just a mistake, the following Gets the results you want

  WITH     rows_needed     AS
  (
       SELECT     area
       ,     area          AS subarea1
       ,     area          AS subarea2
       ,     area          AS location
       FROM     vill
       WHERE     area           != subarea1
       OR     area          != subarea2
       OR     area          != location
      UNION
       SELECT     area
       ,     subarea1
       ,     subarea1     AS subarea2
       ,     subarea1     AS location
       FROM     vill
       WHERE     subarea1     != subarea2
       OR     subarea1     != location
      UNION
       SELECT     area
       ,     subarea1
       ,     subarea2
       ,     subarea2     AS location
       FROM     vill
  )
  SELECT     (
            SELECT     MAX (id)
            FROM     vill
       ) + ROWNUM          AS id
  ,     area, subarea1, subarea2, location
  FROM     rows_needed
  WHERE     (area, subarea1, subarea2, location)
             NOT IN (
                     SELECT  area, subarea1, subarea2, location
                     FROM    vill
                   )
  ;
  

  except that it is for an indefinite period including the ID will assign to what line. I guess that doesn't matter, as long as 130 to 137 numbers are used (or 131 to 138, if that is what you really want).

  When I run your code on the table he returned me the desired output, but when I run it on my actual table that is having 45800 lines, then he messed up some results, because I think that in your code, I should mention the clause ORDER BY ID somewhere... Therefore, in this example I mention different IDS while inserting the lines. Your code worked very well because it is having only 25 rows with ID Ordered, while my actual table is to have 45800 lines in the table, there is no guarantee of ID ordered... so I think that its a problem with the order by clause, ID... but I don't know where I should put this clause

  What is the significance of id? Is this just a unique key? That's, I guess that each line must have an id and two rows can have the same id, but, aside from that, it doesn't matter what line has which id.
  The query I posted yesterday assumes that subarea1 and subarea2 were functionally dependent on the area. as in the example of data you posted yesterday. I see your last post that's not true, and which explains erroneous results.

  As I said yesterday, if you are actually setting up new lines in the table, you must use a sequence to generate identifiers.

• terminology of field layout?

  Open the message on BOARD:

  I find it quite difficult to understand all the terminology field layout. There is a good reference for this?

  As I read through the API reference for a field, I see the following similar terms:

  • Border
  • Content
  • To what extent
  • FocusPhantom
  • The margin of
  • Padding

  They all seem to be a sort of rectangular area relevant for the field, but the API documentation is poor enough to explain what each region is and how they differ. A photo would go a long way to explain what are these different regions, how they relate to each other, and what is their hierarchy.

  Thank you

  Came across a photo illustrating these terms. It's in the section of the API 6.0.0 HorizontalFieldManager.

  http://www.BlackBerry.com/developers/docs/6.0.0api/index.html

• Code/script to extract all the text in the Illustrator document?

  Any who have code/script for this, or how to create the code to extract all the text on an active document in Illustrator. Extract the text as the text for any and all text elements in the document (TextFrameItem, TextRange, TextPath, etc.). We can just empty the text with alerts().

  I'm not sure of is what order or hierarchy to retrieve the text. Where do we start from activeDocument.textFrameItems/TextRanges/etc. How are text in Illustrator? I'm new to Illustrator scripting.

  Something as simple as that can do the trick.

  It will act on all open documents.

  you could then create a file and write to this alert, rather then just

  for(var i = 0; i < app.documents.length; i++){
      for(var j = 0; j < app.documents[i].textFrames.length; j++){
          var str = app.documents[i].textFrames[j].contents;
          alert(str);
          }
      }
  

• Oracle 10g Client 32 bit to 64 bit Win7

  Hi all
  
  I'm confused with the pairing of the 32-bit and 64 bit OS/Oracle.
  
  I install a 10g Client 32 bit for my laptop Win7 64-bit. Is it supported?
  
  I hope it's not because I can't run, so I wouldn't be crazy troubleshooting my mistake.
  
  
  Thank you

  What is incremental? I understand not reach newspapers are added by default. If you do not delete the archive logs, you can recover to any point in time right? What is the use of differentials?

  Best manual to understand what is cumulative and incremental backups

  http://docs.Oracle.com/CD/B19306_01/backup.102/b14192/bkup004.htm

  Are there any other links or docs or white paper tips/tricks/to those who passed a VLDB?

  Check this box below note for VLDB backup
  Merged incremental backup strategies [ID 745798.1]

• removeInstance with button Delete

  I created a form with a button to remove the current action item via the script. Although I looked at this script several times and used the Action to add the button can't always the button to remove the current instance. The button always removes the first instance. Someone at - it answers to this problem? What's my hierarchy hurt for this action?

  

  

  What code is now on the delete button?

  It is not clear what you're trying to remove, the CorrAction subform?

  If the subform "CorrAction", you would need:

  _CorrAction.removeInstance (this.parent.parent.index);

  As CorrAction is on 2 levels (parents) over the delete key.

  If it's 'The Action' you try to delete, you must:

  _Action.removeInstance (this.parent.parent.parent.index);

• Can we have two controllers in a page of the OPS?

  If so, then what would the hierarchy in which they would be called?
  It would be much appreciated if anyone can discuss a case where we would have to use two controllers in a single page.

  The OAF page can have any number of controllers, but a particular bean UIX cannot have more than 1 controller. The controllers are called hirarachy of how UIX bean tree is created on your page, for example if root is region pagelayout, then first controller called the controller at the level of the pagelayout regions and then all his children bean controllers.
  Mukul-

• What is the formula to bring the current date of the last of the hierarchy of the time

  Hello
  
  IAM working on Hyperion financial Reporting.i have created a grid with 2 dimensions (entity and period). My requirement is know last date of the period of hierarchy should appear automatically in the header when the report is run.what formula should I write in the textbox control make aware of the date of the last. Besides, I don't want to create a prompt for the period dimension.
  
  Kindly help me on this.
  
  Thanks in advance.

  Hello
  I guess you have after time hierarchy
  Period
  -2008
  -Jan
  February-
  -Mar
  ----------
  ----------
  -Sep
  -Week1
  -Semaine2
  -08-sep-2008
  -09-sep-2008
  -------------------------------
  -12-sep-2008

  Now if I'm not mistaken, your requirement is to display 12-Sep-2008 in the header...
  There is a function called relative Member, who will provied you the required result. Use level 0 in the list of members.
  Hope this is what you want.
  Kind regards
  Rahul

• I can't insert working links in my emails. Should what procedure I use?

  Every effort to include a link to Web site fail. I use the link function, type the address of the Web site and paste it into the email.
  However, recipients cannot use the link to open the site Web connected.
  What I am doing wrong?

  Thank you

  If what you link is a Web page that is accessible to anyone, I would NOT select the checkbox "bind the source."

  When you save a Web page in your browser, usually an HTML document is created, as well as a file in which are written the graphic elements and possibly other related documents. You can see if any of the elements themselves contain links, there is a theoretical possibility of a complex hierarchy and at several levels, documents and records being generated.

  Now, if we choose "attach" option, then it seems to me that Thunderbird needs to do something similar to what the browser only when you save a page, and frankly, I don't think that Thunderbird is - this smart.

  You don't need to send the contents of the page; the correspondent from your browser or email client can get to them.

  I think the appropriate time to use this option is when the link points to an element that is not visible via the Internet, such as a document or a file on your own local computer or network, and ideally, it would be a simple, self-contained, stand-alone document with no links to external resources. If a Word document which pulled in images or Excel spreadsheets would be inappropriate. But make it a PDF, and it is more likely to succeed. But in this situation, I would be sent as an attachment, in any case.

• 'Photos' and 'pictures' do not contain the same number of photos.  What is going on?

  My library 'photos' unless photos my album 'pictures' in it (11 308) (11 863).  -What happened?  I thought they were supposed to be 2 ways to display a single library.  I try, in vain, to organize the photos in a way that makes sense for my family (I frequently experience problems with apple products are not designed with multiple users in the same family spirit), and need to start with the entire collection of photos.  Clearly, "all photos" contains more photos, but according to the hierarchy, "all photos" should not be the top category.  I thought 'photos' and 'pictures' saw the same library in two ways (photo taken compared to what photo added to the library).  Thank you for your help.

  Several possibilities

  hidden photos show in pictures but no pictures - you have pictures in your hidden folder?

  a damaged library can cause this - you can repair the library (save the library and then press and hold the option and command launching photos - what causes a comparison of the library to rebuild to iCloud library is you use it)

  LN

• What's in a .vin file?

  I noticed when you work with AWR project that there is a *.emp and *.vin files that have the same name as my project.  What is the .vin file?

  Hello

  When you close a project, a .vin with the same name of stem from the record that the project file is created. The .vin file contains information that windows are open, including their size and their location. It also contains information about the State has collapsed and expanded the project tree. When a project that has an accompanying .vin file is opened, the interface of the project when the project was closed is restored. If a .vin file does not exist, when a project is loaded without windows are open and the hierarchy of the entire design in project browser is expanded.

  Also, in the case where you wondered why it's a separate file, not only stored in the project file (*.) EMP), it is because if you were to open a project and display data in charts, changing the State of the window, then this would require the project to be saved again.  With the file separate wine then you can open the project, search data, and then close without being prompted to save the project to close.

  Thank you

  Shane

• Organization chart... .to leave Vi hierarchy?

  I know that I went on this point the wrong way... probably the point #1 in the top ten things not to do when programming, not but...  (I'm not a software engineer, you guessed?)

  I have a state machine relatively complex vi developed and deployed and I don't have a chart for it. As I was only working on this, I know it all and how it works, but I need to have an overview for non-geeks out there, who will use the standalone version.

  Is it possible to generate a diagram of the VI hierarchy?

  or what is the best way to develop the organizational chart (not from the beginning..)

  Kind regards

  Leeser

  There is nothing automatic.

  Condition is not based on a construction of QSM (this design model can enable transitions that are impossible to document completely...), it can be done by hand with your favorite flowchart software (don't wince but I use paint and PP for this for so long I know all shortcuts and can do it quickly).

  I received the code developed by other groups and drwaing place the diagram of the State was the first step in the estimate of what would be needed to begin to support it.

  This thread is for some years on a similar topic and can be useful.

  I'm safely assuming that you have learned your leason for ' first, second document ", or do you want a conference?

  Ben

• Show only the screws used to VI hierarchy instead of all polymorphic Versions of a VI

  Hello!

  When you pull the top of the hierarchy of VI for a program, you get a diagram showing all polymorphic versions of a VI used in your program (at least I do).  Is a checkbox hide somewhere that I did not find that put the screws in the hierarchy I call in my program?  For example, if I use the polymorphic VI 'DAQmx create Virtual Channel' in my program, and the "AI Input" version is used, I always get every version, which is several, figure in the hierarchy of VI.  This clutters the schema a bit.  Instead of an icon that appears in the hierarchy, it is instead of 20 or 30.

  Everyone there knows what can be done?  Thanks for any help you can give me.

  Thank you, Jeff, to confirm this as I was afraid of.  I was wondering where they were hiding this darn box!

  I guess that the code that creates the diagram hierarchy VI must have been written before polymorphic VIs and he travels find as all loaded screws to add them to the diagram.  When any one version of a polymorphic VI is called, all versions are loaded and found the code that creates the schema.  If only the specific version of a polymorphic VI takes over, then this theory does not work.

  If I helped you and I get this feature implemented, I am glad that I could be useful.

  I appreciate your response.