Why is there the oscillations during sampling a signal by steps?

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    It is a question about a tip found in the explanations on the acquisition of data error-200279. This explanation it is said: '... ". reading a fixed number of samples instead of all available samples can fix this... »

    AFAIK the DAQ system buffer is a ring buffer, so we can consider having a writing position and a position of reading "in motion" along the ring. While the playback position is the position of writing, everything is brilliant. But if writing catch up reading, samples will be overwritten and therefore-> error-200279.

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    I do not understand why a fixed amount of reading samples would help me with this error. I don't understand why other Councils (increase in the size of the buffer or the frequency of reading) would help me because they reduce the probability of the playback position being outrunned by the position of the writing.

    But if I read everything which is available, whenever I read the only way for the buffer fills would be that the time between two readings take more time than necessary fill the entire buffer.

    Or in other words to each reading I will read at least as many elements that it has been filled by writing since the last read, so the only way to fill the buffer would fill completely at once since the last reading.

    This should be a lot safer than reading a fixed amount, because in this case, I'd get a problem if I read it that fewer items than writing complete at the same time, regardless of the number of items that would be and no matter what the size of the size of the buffer that would be.

    What I understand here?

    Thanks and regards,


    SBach wrote: this VI is a State Machine in queue, the reading part is made in the case of timeout and cases are used as initialization orders, stop and change the outside DAQ hardware.

    That I can't tell when these commands will trigger the time between two readings could not be set. If a strictly fixed amount of data could lead to a buffer to fill.

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    The way I see it, the other commands must stop the task anyway.  If you can leave the timeout do its job and do not do a lot of extra stuff.

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    1. use a shift register to keep track of how long your wait time should be.  In the case of reading, make the deadline to be whatever it is that you are using.  In all other cases, only the 0 so that a read timeout must be performed immediately (once the queue is empty).

    2. When you do your check to 1.5 times the timeout, if there is too much data, queue a reading at the front of the queue so that playback will happen.  The idea is that you really want to keep the same stack sizes to keep the memory to be allocated.  So just to be read more often.

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