Why the node formula Eval gives only outputs 9?

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  The formula is AI0 = AI0 - AI6; AI1 = AI1 - AI6; AI2 = AI2 - AI6; AI3 = AI3 - AI6; AI4 = AI4 - AI6; AI5 = AI5 - AI6;

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  I thought about it!

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• Problems of bit shift left in the node of the formula

  Hello

  Sorry, but my English is not good.

  I am trying to run a bit left SHIFT in the node of the formula, but the left SHIFT does not work as I expected.

  uInt32 parametro[5];
  float32 valorAmostra;
  int16 indiceAmostra;
  uInt8 indiceResposta;
  int16 controle;
  int32 valor;
  int8 i;
  
  for(i=0; i<5; i++)
      parametro[i]=param[i];
  
  valor = parametro[5]<<16 | parametro[4]<<8 | parametro[3];
  controle = parametro[1]<<8 | parametro[0];
  
  indiceAmostra = (controle & 0x3FF);
  indiceResposta = (controle >> 10);
  
  valorAmostra = valor & 0x7FFFFF;
  valorAmostra = valorAmostra*(2.4/8388607);
  
     if((valor & 0x800000) == 0x800000)
        valorAmostra = valorAmostra*(-1);
  

  the input param array is uInt8 type, because I saw in other topics that does not move with uInt8,

  I copy the values in the array param to parameter , which is of type uInt32, but still does not work.

  Test the input parameter with the following values:

  [] param = {10,14,10,0,16}

  the returned valorAmostra is 0,00117188 then it should be 0,300003.

  Can someone help me please?

  Portuguese:

  OLA,

  Is um no bug no LabVIEW para esta operacao. Este bug devera ser corrigido em paid futuras. UMA Solução para esta down e use int32 ao investment of um ulnt32 um.

  Any doubt please between let em.

  Obrigado.

  English:

   

  I studied the problem you are having, and it turns out that this is a bug that has already been reported and documented. The work around is to use int32 instead of uInt32.

  Thank you.

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