With CVI SQL Toolkit, how to add the new variable param column in a table.

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  I think the best way is to add the column at the end of the table and create a new view with the order of the columns...

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  SELECT * FROM password);

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  first name

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• How to add the new column in the tabular layout editor in Oracle Forms

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  See http://www.youtube.com/watch?v=7emNa7THMLg

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  Workspace - WS_SUNITI

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  82863 application ID.

  Name of the tab - PSVANS3

  Page no 5

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• How to set the value of a column in a table according to another column?

  Hello world!
  
  I use Apex 4.1.
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  and when I insert the value in the column content, I want to change this value in the note column with the note, which is generated with pl/sql function (function of string returned if the typed value is in the range).

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• How to add the new column to a specific position

  Hello

  My table looks like Fallows.

  Select * from company

  PRODUCT_ID	COMPANY_ID	COMPANY_SHORT_NAME	COMPANY_LONG_NAME
  1	1001	An Inc.	Long name A Inc.
  1	1002	B Inc.	Long name B Inc.
  1	1003	C Inc.	Long name C Inc.
  2	1004	D Inc.	Long name D Inc.
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  I tried like Fallows alter company table add company_location varchar2 (100) after company_short_name;

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  If the query I've tried is correct?

  Give me your suggestions.

  Thanks in advance.

  As long as you're on 11 GR 2 or lower, it will not work.

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  You have the chance to use dbms_redefinition (when no interruption of service is possible) or manually create a new table with the columns in the order you need and then migrate the data and then drop the original and rename a new.

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  Kind regards

  Carsten

• How to add the new currency?

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  Adobe Acrobat X pro

  Thanks in advance,

  Follow the instructions in the previous section: http://forums.adobe.com/message/4439659

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  function bs_Keystroke() {}

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  Custom Format script

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  Custom keystroke script

  bs_Keystroke();

• How to add the new line?

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  I wrote a select statement, the data is displayed, and I want to add a new line, how do?

  There is no icon "more (add)" the above data.

  Then, you insert first a table, then in the other.

  If you choose multiple tables so you are most likely to join them in some way, and when joins between in the field (or even worse grouping functions) you're sure source of data you see actually (this is the reason why by default you cannot insert data from a select query), as it is perfectly possible to select only a single column in a single table , but if this table has multiple columns and one of them is defined as NOT NULL, and you're not selecting then you are out of luck and you cannot insert of your select query.

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• How to add the new hard drive RAID 5 on

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• How to create the partition on a column in a table on a daily basis

  Hi all
  I wrote a query that does not, I have a column of varchar type, and I want to create the partition of the table on that column based daily interval. but ist is in error...
  
  my query is...
  
  create the table user_detail
  (username varchar2 (50))
  The user ID number,
  country varchar2 (25).
  accupation varchar2 (100),
  company varchar2 (100),
  joindate varchar2 (14))
  partition by range (joindate)
  INTERVAL (NUMTOYMINTERVAL (1, 'DAY'))
  (PARTITION newone VALUES LESS THAN (to_date (April 13, 19 ', 'aa-mm-dd')));
  
  
  error is:
  
  Error from the 1 in the command line:
  create the table user_detail
  (username varchar2 (50))
  The user ID number,
  country varchar2 (25).
  accupation varchar2 (100),
  company varchar2 (100),
  joindate varchar2 (14))
  partition by range (joindate)
  INTERVAL (NUMTOYMINTERVAL (1, 'DAY'))
  (PARTITION newone VALUES LESS THAN (to_date (April 13, 19 ', 'aa-mm-dd')))
  Error in the command line: 1 column: 0
  Error report:
  SQL error: ORA-14751: type of invalid data for the partitioning column of a partitioned table interval
  
  
  Can I create partition on the varchar data type?

  On ORA11gR1 it works:

  --virtual column
  CREATE TABLE TEST(joindate VARCHAR2(14), part_joindate AS (to_date(joindate,'dd.mm.yyyy'))) partition by range (part_joindate)
  INTERVAL(NUMTOYMINTERVAL(1, 'YEAR'))
  (PARTITION newone VALUES LESS THAN (to_date('2013-04-19', 'yyyy-mm-dd')))
  ;
  
  INSERT INTO TEST(joindate) VALUES('19.04.2013');
  SELECT * FROM TEST;
  
  DROP TABLE TEST;
  --aux column
  CREATE TABLE TEST(joindate VARCHAR2(14), part_joindate AS (to_date(joindate,'dd.mm.yyyy'))) partition by range (part_joindate)
  INTERVAL(NUMTOYMINTERVAL(1, 'YEAR'))
  (PARTITION newone VALUES LESS THAN (to_date('2013-04-19', 'yyyy-mm-dd')))
  ;
  
  INSERT INTO TEST(joindate) VALUES('19.04.2013');
  SELECT * FROM TEST;
  
  DROP TABLE TEST;
  

  Published by: spajdy on April 19, 2013 14:58