Expand all the layers using JS

Similar Questions

• I use Illustrator CC and sent a file to a colleague who uses CS6 where all the layers become a great layer.  How can I send it and preserve the layers?

  I use Illustrator CC and sent a file to a colleague who uses CS6 where all the layers become a great layer.  How can I send it and preserve the layers?

  coledang,

  Save a copy, and in the following options choose CS6.

  In this way, it should open correctly in CS6, and the original document is unscathed.

  You may find that some (new CC) features will not survive the downsaving.

  Edit: Hi SRiegel.

• Is it possible to copy all the layers in the layers panel and paste them in a new document?

  The content of each layer will be different on each document so I don't want to copy. I have 12 documents to be used in a calendar and I want all the layers as well as their names and colors to be the same in each document. I already have all the pages designed and built, but personal information is to be added, and I want each of them to match all the others.

  Basically, all I want to do is to copy the contents of the layers panel and past in each of the other documents.

  I just create a page at the end of the document w / layers and on this page, add an item by layer. Also, if you have 15 layers, drag the small fifteen frames on the page and the layer icon to assign each image to another layer.

  Then in the Pages panel menu, choose move Pages. Choose this 'page of layers' to move to your receiving document (another of your calendar documents), Destination: end of the Document.

  The receiving document will get all the layers. Remove all items (15 views) on the extra page and the layers remain.

  Next time you make a schedule, you should check the add-on for InDesign Calendar Wizard. You will cry all the time you wasted it making manually ;-(

  Home Calendar Wizard

  Anne-Marie

  InDesignSecrets.com

• Get all the layers and apply to other documents

  Hello everyone,

  I'm copying all layers from one document to the other. But just copy paste is not enough for several reasons (root document may already be closed, copy at a time when the new document is not open yet,...).

  This means that I have to remember all the layers and use them later.

  At the moment I am sth. Like this:

  ---------------------------------------------------------------------------------------

  public static std::vector < PIActionDescriptor > layeractions;

  Sub testGet()

  {

  Result PIActionDescriptor = NULL;

  numLayers Int32;

  SPErr error = kSPNoError;

  DescriptorTypeID typeID = 0;

  Int32 docCounter = 1;

  error = PIUGetInfoByIndex (docCounter,

  classDocument,

  keyNumberOfLayers,

  & numLayers,

  (NULL);

  If (numLayers > 0)

  for (int32 layCounter = 1;

  layCounter < = numLayers & & error == kSPNoError;

  layCounter ++)

  {

  error = PIUGetInfoByIndexIndex (layCounter,

  docCounter,

  classLayer,

  classDocument,

  0,

  and result,

  (NULL);

  layeractions.push_back (result);

  }

  }

  Sub testSet()

  {

  SPErr error = kSPNoError;

  Result PIActionDescriptor = NULL;

  for (auto & it: layeractions)

  {

  error = sPSActionControl-> Play (& result, eventMake, he, NULL);

  }

  }

  ---------------------------------------------------------------------------------------

  So what I'm doing, open a doc with some layers. Then testGet(), open new document then testSet().

  But bench always puts "the command 'Make' is not currently available." and error = - 128.

  Hope you get what I'm trying.

  Thanks for any thoughts!

  Who's going to be a difficult path to travel to this topic. Even if you can get all the properties of the active document and the layers within the document, you have not dealt with pixels on a normal layer data. You will need to save this broad as well. And for dynamic objects and linked smart objects... you have a job to do. Any topic of a document is not capable 'get '.

  Trying to cope with this: "document might already be narrow" would be almost impossible IMO.

  Remember, the source document, which is now closed I now want to copy. Then you can do:

  1. open closed source document. (Or make it more if it is already open)

  2. for each layer in the source document

  a. Select the layer

  b. copy of the document target

  3. close source document.

  The Get accessor routines are not for 'read' directly. You must get the interesting bits of information on and then use the game code that you found using listener.

• Merge all the layers?

  Looking for a method in one quick step, to merge all the layers.

  I usually select the first layer, then shift + click on the layer below (select all layers between), then right click and hit "merge layers".

  Pretty - simple, but I'm working on an 'action' and recording of the above method is limited because it is based on the names of specific layers in a file.  I want to be able to use this action as a generic action for any project with several layers.

  Is there a better way to do it or file > merge all miss me?

  You could try Shift + Ctrl + Alt + E (Shift-Cmd-Option-E) (Merge visible layers into a new layer)

  Or just flatten out would be to merge all layers

  If you just want to select specific merge layers, you can use keyboard shortcuts that don't record names layers:

  http://help.Adobe.com/en_US/Photoshop/CS/using/WSD578BD7D-07BC-46f6-AAC2-6E491E8AD818a.htm l #WS7D245964 - 27B 4 - 403 - 82D 5-DDD1CB19A82Ba

• Photoshop script to copy all the layers of close PSD to open the current document

  Hi, I have very limited capacity script so this task is above my pay grade

  I'm looking for a script to read and copy all the layers in a PSD saved file and copy them into the current active document. The two documents have the same size and I need to be able to change text layers after copying. Anyone has any advice or examples of how I might be able to do this?

  Thank you in advance for any help you can offer.

  Kind regards

  Marcus

  Try the script in entry below. You must open the destination file, and you must put in the path and name where your source file. It will not choose a layer from background from the source file.

  #target photoshop
  var sFile = new File('~/desktop/template.psd');//change path to template file
  var doc = activeDocument;
  var sDoc = open(sFile);
  
  var idselectAllLayers = stringIDToTypeID( "selectAllLayers" );
      var desc2 = new ActionDescriptor();
      var idnull = charIDToTypeID( "null" );
          var ref1 = new ActionReference();
          var idLyr = charIDToTypeID( "Lyr " );
          var idOrdn = charIDToTypeID( "Ordn" );
          var idTrgt = charIDToTypeID( "Trgt" );
          ref1.putEnumerated( idLyr, idOrdn, idTrgt );
      desc2.putReference( idnull, ref1 );
  executeAction( idselectAllLayers, desc2, DialogModes.NO );
  
  var idDplc = charIDToTypeID( "Dplc" );
      var desc5 = new ActionDescriptor();
      var idnull = charIDToTypeID( "null" );
          var ref2 = new ActionReference();
          var idLyr = charIDToTypeID( "Lyr " );
          var idOrdn = charIDToTypeID( "Ordn" );
          var idTrgt = charIDToTypeID( "Trgt" );
          ref2.putEnumerated( idLyr, idOrdn, idTrgt );
      desc5.putReference( idnull, ref2 );
      var idT = charIDToTypeID( "T  " );
          var ref3 = new ActionReference();
          var idDcmn = charIDToTypeID( "Dcmn" );
          ref3.putName( idDcmn, doc.name );
      desc5.putReference( idT, ref3 );
      var idVrsn = charIDToTypeID( "Vrsn" );
      desc5.putInteger( idVrsn, 5 );
      var idIdnt = charIDToTypeID( "Idnt" );
          var list1 = new ActionList();
          list1.putInteger( 3 );
          list1.putInteger( 4 );
      desc5.putList( idIdnt, list1 );
  executeAction( idDplc, desc5, DialogModes.NO );
  

• How to get through all the layers?

  I would like to write a script to rename all the layers, but I don't know how to do, who can help me?

  function traverse( layerSet, callback )
  {
    for ( var i = 0; i < layerSet.layers.length; i++ ) {
         var l = layerSet.layers[ i ];
         app.activeDocument.activeLayer = l;
         if ( l.typename == "LayerSet" )
         {
              traverse( l, callback );
         }
         callback( l );
    }
  }
  
  function toUpp( l )
  {
      l.name = l.name.toUpperCase();
  }
  
  traverse( app.activeDocument, toUpp );
  

  In this case, the callback is defining the name of the layer in upper case. The app.activeDocument is a layerSet too. For some reason you need to select a layer before running this script.

• move all the layers into a single layer

  Hello

  I am new to the script and I need to make a script that the passage of all the layers into one layer (in Illustrator I press CTRL + A and then CTRL + G in layers and works) but I need in the script

  Please could someone help me?

  Thank you!

  I found the solution

  main() {} function

  If (app.documents.length == 0) {return ;}

  app.userInteractionLevel = UserInteractionLevel.DONTDISPLAYALERTS;

  var doc = app.activeDocument;

  var mast = doc.layers.add ();

  Mast.Name = "original";

  var group = mast.groupItems.add ();

  var pageIt = mast.pageItems.add ();

  While (doc.layers.length > 1)

  {

  While (doc.layers [doc.layers.length - 1].pageItems.length)

  doc. Layers [doc.layers.Length - 1] .pageItems [doc.layers [doc.layers.length - 1].pageItems.length - 1] .move (grup, ElementPlacement.PLACEATBEGINNING);

  doc. Layers [doc.layers.Length - 1] .remove ();

  }

  }

• Method to select all the layers 'invisible '?

  Hello

  Does anyone know if there is a plugin or a way to select all the invisible layers in a photoshop file automatically with a single click?
  It would be really handy when it comes to huge photoshop with lots of files files and layers...

  

  Kind regards

  Ben

  Not sure on the hiden targeting all the layers in a single click, but you can filter so that no visible layers only show, then it is easy to target all.  (On the tab of the layer panel, choose attribute, then no Visible)

  Might be possible to write a script or an action recording to do the same thing?

• List of all the fonts used in a document?

  If I understand correctly, TextFonts is a collection of all the fonts that are available on Illustraot.  There is a collection of all the fonts used in the document currently open?  Or should I scroll each textFrame a create this list myself?

  I don't know why and how you write the error log, so I only add a single alert after all. "xmpString" and "XMP library" are two different methods, you only need one, then.

  #target illustrator
  
  var inputFolder = Folder.selectDialog("Select a folder contains '*.eps' files ");
  
  if (inputFolder) {
      var fileList = inputFolder.getFiles('*.eps'),
          fontsInfo = [];
      loadXMPLibrary();
      for (var i = 0; i < fileList.length; i++) {
          if (fileList[i] instanceof File && fileList[i].hidden == false) {
              fontsInfo.push(getFontsInfo(fileList[i]));
          }
      }
      unloadXMPLibrary();
  }
  
  var Loginfo = new File(inputFolder + '/Font.info.txt');
  Loginfo.open('w', 'TEXT', '????');
  var info = fontsInfo.join('\n\n');
  Loginfo.write(info);
  Loginfo.close();
  
  if (/(Open Type|TrueType)/.test(info)) {
      alert('Open Type / TrueType font found, see log file for details!')
  }
  
  function getFontsInfo(file) {
      var arr = ['File: ' + decodeURI (file.name)],
          xmpFile, oXmp, fontNumber, i, path, fontname, fonttype, ns = 'http://ns.adobe.com/xap/1.0/t/pg/';
      xmpFile = new XMPFile(file.fsName, XMPConst.UNKNOWN, XMPConst.OPEN_FOR_READ);
      oXmp = xmpFile.getXMP(); //Returns an XMPMeta object
      fontNumber = oXmp.countArrayItems(ns, 'xmpTPg:Fonts');
      xmpFile.closeFile(XMPConst.CLOSE_UPDATE_SAFELY);
      if (fontNumber) { // if there's at least 1 font, proceed
          for (i = 1; i <= fontNumber; i++) {
              path = XMPUtils.composeArrayItemPath(ns, 'xmpTPg:Fonts', i);
              fontname = oXmp.getStructField(ns, path, XMPConst.TYPE_FONT, 'fontName');
              fonttype = oXmp.getStructField(ns, path, XMPConst.TYPE_FONT, 'fontType');
              arr.push([i, '. ', fontname, '-', fonttype].join(''));
          }
      }
      return arr.join('\n');
  }
  
  function loadXMPLibrary() {
      if (!ExternalObject.AdobeXMPScript) {
          try {
              ExternalObject.AdobeXMPScript = new ExternalObject('lib:AdobeXMPScript');
          } catch (e) {
              alert('Unable to load the AdobeXMPScript library!');
              return false;
          }
      }
      return true;
  }
  
  function unloadXMPLibrary() {
      if (ExternalObject.AdobeXMPScript) {
          try {
              ExternalObject.AdobeXMPScript.unload();
              ExternalObject.AdobeXMPScript = undefined;
          } catch (e) {
              alert('Unable to unload the AdobeXMPScript library!');
          }
      }
  }
  

• Show or hide all the layers?

  What is the way to show or hide all the layers in the layers panel at the same time?

  Thank you.

  Close.  Quickly, you can show or hide all the layers, but on what you are.  Hold down the ALT key and click on the visibility icon (eyeball).

  -Christmas

• Expand all the nodes in a tree table

  Hello

  I have a tree table in my JSPX, which needs to expand all its nodes when the page is loaded. Also mis the data control is a POJO data contrl where I have a collection (ArrayList), which serves to make this table from the tree. Tree table is displayed as expected with it of the child nodes.

  
  

  I was referring rare item such as these... https://blogs.oracle.com/jdevotnharvest/entry/how_to_programmatically_disclose_a to expand all nodes. But I get an exception of cast of class on the piece of code following

  Code:

  CollectionModel model = (CollectionModel) your_af_tree_reference.getValue();
  

  Exception:

  javax.faces.el.EvaluationException: java.lang.ClassCastException: oracle.adfinternal.view.faces.model.binding.FacesCtrlHierBinding$FacesModel cannot be cast to oracle.adf.view.rich.model.CollectionModel
  at org.apache.myfaces.trinidad.component.MethodExpressionMethodBinding.invoke(MethodExpressionMethodBinding.java:51)
  

  ......................

  I use Jdev 11.1.1.4

  Let me know if you need more details to achieve this please.

  Refer to this:

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/78-man-expanding-trees-treetables-354775.PDF

  You can download the sample code from:

  http://www.Oracle.com/technetwork/developer-tools/ADF/learnmore/index-101235.html

  Search for number 078.

• Export all the layers in png in Photoshop, including those outside the canvas area

  I use the script, but if some of my layers are outside the canvas, it removes those the only visible part.

  But we need everything in the layer in png, so is visible in the Web or it is outside.

  Best,

  Gunjan

  Use activeDocument.revealAll (); then export all your layers.

• Expand all the Table-to-Table

  I currently have a table-to-table of work. I have an obligation to create a function to expand - all so that all retail lines can be extended with a single click. I've scoured the forums looking for a dev-guide and approach, but I have not found anything. Is this possible?

  In this case, you can use the following code in the controller associated with your table processRequest():

  Assuming that the table is an object of advancedTable,
  This will allow for the "view details | Hide all details"links on your outer table
  Import oracle.apps.fnd.framework.webui.beans.table.OAAdvancedTableBean;

  OAAdvancedTableBean outerTbl = (OAAdvancedTableBean) oawebbean.findChildRecursive ("IdOfMyOuterTable");
  If (outerTbl! = null)
  {
  outerTbl .setAllDetailsEnabled (true);
  }

  I hope this helps.

• expand all the nodes in an af:tree component

  Hello
  
  We use the ADF 11 g. In a one of our pages, we use an af:tree control and we want to show all nodes developed by default. How to get there? "Expand all" in the menu contextual works only for the current node.
  
  Thank you.
  
  Published by: Deniz Gulmez on 16.Ara.2009 06:27

  Hi Deniz,

  Have you tried setting the property initiallyExpanded to true for the tree?

  Something like

  Arun-

  Edit: Also, take a look at Frank blog