Find people with their date of birth? find trenches of age to find people?

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No, Skype does not offer of this nature of the directory search filters.

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    HI :)

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    I've heard this can be done with USER_TABLES... but I have no idea how: (...)

    Edited by: user8865125 the 17.05.2011 12:22

    Hello

    USER_TAB_COLUMNS data dictionary view has a row for each column of each table in your schema. The columns TABLE_NAME, COLUMN_NAME and DATA_TYPE contains all the information you need.
    Another view of data, USER_TABLES dictionary, can be useful, too. He has a line of table pre.

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    Hi there-

    I am working on a form where the user will enter both their date of birth and date of beginning of employment. I need to create two fields that will calculate their age based on their date of birth and their total number of years of service, based on their start date.

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    Thank you

    Erin

    If you use fields to date, tap the calculate text fields, you can put something like

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    will be calc, the age, while something similar for startdate

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  • to join two columns with different data types

    Hello experts,

    I have two tables...
         create table1
       (
         col1 varchar2(20)
        );
        
      create table2
        (
          col1 number(10)
        );  
    
      
    with their data as below
              with table1 as
      (  select 'xx' col1 from dual union all 
         select 'yy' col1  from dual union all
         select '01' col1  from dual union all
         select '02' col1  from dual union all
         select '03' col1  from dual union all
         select '04' col1  from dual 
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         select '02' col1 from dual union all
         select '03' col1 from dual union all
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    How to join table1.col1 table2.col1? since they are different data types... .i tried to use To_char but then I got 0 zero,.
    is there is all the functions I can use?


    Thank you!!

    user642297 wrote:
    Hello experts,

    I have two tables...

    create table1
    (
    col1 varchar2(20)
    );
    
    create table2
    (
    col1 number(10)
    );  
    

    with their data as below

    Above, you said that table2.col1 was a NUMBER.
    Below, is a VARCHAR2:

    with table1 as
    (  select 'xx' col1 from dual union all
    select 'yy' col1  from dual union all
    select '01' col1  from dual union all
    select '02' col1  from dual union all
    select '03' col1  from dual union all
    select '04' col1  from dual
    ),table2 as
    (
    select '01' col1 from dual union all
    select '02' col1 from dual union all
    select '03' col1 from dual union all
    select '04' col1 from dual
    )
    

    Woudn't be a better approximation of your real tables:

       ),table2 as
        (
          select 1 col1 from dual union all
          select 2 col1 from dual union all
          select 3 col1 from dual union all
          select 4 col1 from dual
         )
    

    ?

    My question
    How to join table1.col1 table2.col1? since they are different data types... .i tried to use To_char but then I got 0 zero,.
    is there is all the functions I can use?

    Your postal code. I think the best way is to use TO_CHAR, but maybe you were using it differently.

    SELECT     *
    FROM     table1
    JOIN     table2     ON     NVL ( LTRIM (table1.col1, '0')
                       , '0'
                       )     = TO_CHAR (table2.col1)
    ;
    

    This assumes that table1.col1 never contains decimal points, unary + signs, exhibitors, or other things like that.
    He will be responsible for negative numbers, but if table1.col1 contains 0 in front after the sign less (for example '-0012' "), then the solution is a bit more complicated.

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    I would like to calculate age based on DOB.  I get a syntax error.  Not familiar with the proper syntax of PL/SQL for nesting of IF/THEN statements.  Any help would be fantastic:

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    Hello

    I managed to find a date column with some null on my test platform (SA406).

    The formula I posted without the NULL case already return 0 when date is NULL (was not really planned).

    If you want to use a CASE IFNULL WHEN ("personal attributes used". "" Employee Date of birth»(, 0) <> 0 THEN you'll get an error: "

    [nQSError: 59021] CASE conditional expressions have correspond to data types.

    So 2 options:

    CASE WHEN IFNULL ("personal attributes used". "" Date of birth of the employee»(, CURRENT_DATE) <> CURRENT_DATE THEN "

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    ELSE 0 END

    or

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