Groups get duplicate

Similar Questions

• Get duplicates in the case and Count clause in the generation of reports

  Hi all
  
  Let me explain first Base (just the Section that is in the scope of the present code) then evil go to code and my problem.i have a Set of pre-defined tasks in * 'TASK' * Table.i have a system that puts the user's request by assigning the task to their request to Request.Each will be mapped to the Instance of the task (predefined) , it will remain in a separate table * "TASK_INSTANCE" * against the user of the application id. Each task has a predefined duration.and, that their maturity date is stored in the Time Stamp data type column.
  
  My scenario is I need to generate report based the date.report requirement is complete, I need get the number of tasks that have the date of completion as today, tomorrow and the next day they grouped based on task names.
  
  My problem is, im getting duplicates if I used separate. It is not possible to duplicate using the join because im using Group by task nameevery record in the Task_instance table has direct relationship with the task ID. For example: im getting a line with the County satisfying the Condition and the next row with empty set.i he cannot understand why happening.need your help to understand this.
  
  Let me add the query below,
  
  SELECT task.task_name,
  * (CASE *)
  WHEN ((TRUNC (SYSDATE) - TRUNC (task_instance.ptd_pdd_date)) =
  (- 1).
  THEN
  * (COUNT (task_instance.ptd_pdd_date)) *.
  END)
  AS "1_day_behind."
  * (CASE *)
  WHEN ((TRUNC (SYSDATE) - TRUNC (task_instance.ptd_pdd_date)) =
  (- 2).
  THEN
  COUNT (task_instance.ptd_pdd_date)
  END)
  AS "2_day_behind."
  * (CASE *)
  WHEN ((TRUNC (SYSDATE) - TRUNC (task_instance.ptd_pdd_date)) =
  (- 3).
  THEN
  COUNT (task_instance.ptd_pdd_date)
  END)
  AS "3_day_behind".
  The TASK task_instance
  WHERE task.task_id = task_instance.task_id
  AND task_instance.status_id = 1
  AND task_instance.ptd_pdd_date IS NOT NULL
  GROUP BY (TRUNC (SYSDATE) - TRUNC (task_instance.ptd_pdd_date)),
  Task.Task_Name;
  
  
  task_instance.status_id = 1 refers to the task located in "in progress".
  
  
  It's overall results (example) I get. In this area, the UI_Contact_Customer task is repeated three times. features of different in separate lines and null in the line separate .i need to avoid these duplicates.please Advisor.
  
  __________________________________________________________________________________
  TASKNAME | "1_DAY_BEHIND" | "2_DAY_BEHIND" | "3_DAY_BEHIND" |
  ______________________________|________________|_________________|_________________|
  UI_Conduct_Fiber_Plant_Survey___ | ___ | ___ | ___ |
  UI_Conduct_Site_Survey___ | ___ | ___ | ___ |
  UI_ConductFiberSurvey_C___ | ___ | ___ | ___ |
  UI_ConductSiteSurvey_C _ | ___ | ___ | ___ |
  UI_Contact_Customer_____________|________________|_________________|_________________|
  _ UI_Contact_Customer | ___10___ | ___ | ___ |
  UI_Contact_Customer___ | ___ | ___ 12___ | ___ |
  UI_Create_Account_Equip_C___ | ___ | ___ | ___ |
  UI_Create_Account_Equipment___ | ___ | ___ | ___ |
  UI_Create_CM_Ticket |     | | |
  ______________________________|________________|_________________|_________________|
  
  In the above result set, in particular UI_Contact_Customer task, ten of their instance with completion date tomorrow and 12 instance having the next day as the date of completion. I need to get all those as single line without duplicate.
  
  
  
  
  Thank you
  Jeevanand.K

  Jeevanand K wrote:

  I need to generate the report for the following scenarios

  So what's the problem:

  SELECT  task.task_name,
          COUNT(
                CASE
                  WHEN TRUNC(SYSDATE) - TRUNC(task_instance.ptd_pdd_date) = -1 THEN 1
                END
               ) AS "1_day_ago",
          COUNT(
                CASE
                  WHEN TRUNC(SYSDATE) - TRUNC(task_instance.ptd_pdd_date) = -2 THEN 1
                END
               ) AS "2_day_ago",
          COUNT(
                CASE
                  WHEN TRUNC(SYSDATE) - TRUNC(task_instance.ptd_pdd_date) = -3 THEN 1
                END
               ) AS "3_day_ago",
          COUNT(
                CASE
                  WHEN TRUNC(SYSDATE) - TRUNC(task_instance.ptd_pdd_date) = -14 THEN 1
                END
               ) AS "2_weeks_ago",
          COUNT(
                CASE
                  WHEN TRUNC(SYSDATE) - TRUNC(task_instance.ptd_pdd_date) < -3 THEN 1
                END
               ) AS "more_than_4_days_ago"
    FROM  task,
          task_instance
    WHERE task.task_id = task_instance.task_id
      AND task_instance.status_id = 1
    GROUP BY task.task_name;
  

  Keep in mind "more_than_4_days_ago" includes tasks as filled with "2_weeks_ago".

  SY.

• How to stop emails double in my Inbox in? I get duplicates of all emails.

  I use OUTLOOK EXPRESS for my e-mail. For months I get duplicates of 90% of the e-mails received. I can't figure out how to stop the duplicates. Can anyone help?

  First of all, check tools | Accounts and make sure that the account is not listed twice.
   
  Second, make sure that your security program is not set to scan e-mail.
   
   
  If the above does not help, create a new file Pop3uidl.dbx.
   
  Tools | Accounts | Mail | Properties | Advanced. Uncheck: Leave a copy of messages on the server. Then, remove the Pop3uidl.dbx file. You will get the messages once more, but it should be.
   
  Tools | Options | Maintenance | Store folder will reveal the location of your Outlook Express files. Note the location and navigate on it in Explorer Windows or, copy and paste in start | Run.
   
  In Windows XP, the files of user OE (DBX and WAB) are by default marked as hidden. To view these files in Windows Explorer, you must enable Show hidden files and folders under start | Control Panel | Folder Options icon | Opinion, or in Windows Explorer. Tools | Folder options | View.
   
  With OE closed, find the Pop3uidl.dbx file and delete it.  Another will be created automatically when you open OE.
   
  
   

• Why did I GET DUPLICATE COLUMNS on THE SIDE LEFT, INBOX SENT JUNK ETC etc.

  The left column of choices, ie.local folders Inbox, together, drafts, archives and onI so have all duplicated below, how can I get rid of the second batch... your Richard

  Can you provide a screenshot?

  https://support.Mozilla.org/en-us/KB/how-do-i-create-screenshot-my-problem

  You could describe unified folders view. Or maybe you used Outlook Express before and had not planned the way Thunderbird presents each account separately with its own collection of records.

• Get duplicates of files when generating deployment

  I just upgraded from Dev Suite 2009 to 2010. I use the same .tsd file to create a deployment. However, I now get the following error at the start of construction:

  Turns out that my addiction got paths watered by the update.

• Application of color in Group arts groups gets randomized

  Hey guys I'm fought with this problem for a little more here.

  I have a collection of color groups, I am applying for group objects.

  but whenever I have change the color group, it makes random order which

  the colors are applied.

  In the kind of work in bulk I sound really do turn into a burner hours.

  The specific process that I use (I tried several different ways with the same result)

  (1) to draw my art

  (2) the art group

  (3) create a new color with my selected art group.

  4) double-click the color group and redefine colors.

  (5) save the color chart

  -good

  6) double-click on a group of different color (or select from the Panel of Recolor)

  -here applied the other group of color (color chart), but every time I do, the order of which color is applied to

  It is a standing feature lon request to associate a color with an object so that you can more easily Recolor art.

  But that would never happen even if it is a great feature.

• How to get distinct records by using the ListAgg OBIEE report function?

  Hi all

  I get a correct result as mentioned below. But I don't see duplicates in my result here, in my example, I get duplicate for the name of the employee 'Pat '. So how to get Distinct values by using the LISTAGG function?

  Data set of sample with the Department and its employees

  Service employee

  ----------      ----------

  Marketing Michael

  Pat of marketing

  Pat of marketing

  Pat of marketing

  Purchase of Den

  Purchase of Alexander

  Purchase of Shelli

  Purchase of Sigal

  Guy of purchase

  Purchase of Karen

  Using the ListAgg function, we can convert it to:

  Employees of the Department

  -----------     -------------------------------------

  Marketing of Pat, Pat, Pat, Michael

  Purchase of Sigal, Shelli, Karen, Guy, Den, Alexander

  I tried a lot of things, but I'm not able to understand how exactly this can be achieved, if anyone has any idea or suggestions please do share, thanks in advance.

  After much research, I found the solution & I want to share what he finds very useful, we can create SQL logic in the Advanced tab, as below and after you click Rescan, and then you will get your desired results.

  SELECT saw_0, Evaluate_Aggr T1.dept ("ListAgg(%1,'' & '') intra group (about 1%)") ("as long as VarChar (1000), T1.emp) saw_1 FROM)

  SELECT 'emp_dept '. "the Department dept,

  'emp_dept '. "' employee ' emp

  IN THE "DOMAIN".

  GROUP BY dept, emp

  ) T1 GROUP FROM T1.dept ORDER BY saw_0

  Also note here that we have good anti-aliasing for columns parent (ex: saw_0, saw_1), another by mistake oracle bi server.

• Need help with the use of GROUP BY in a select statement UNION

  I am writing a query that allows to combine a legacy system that interfaces it is trial balance in the Oracle of R12 GL.  It was only meant to continue for a month or two, but it is likely to continue for 6 months. Please Auditors Auditors, to provide proof that the system is in balance with Oracle GL.  By my verification requirements, I need to make a full reconciliation from the month of conversion (life in the amount of date), then PTD for each month. 

  The legacy account is placed in attribute1 on the lines of the journals. Uses of the old system balancing segments that are also used on the platform in Oracle for this division, i.e., Procure-to-Pay has been cut over Oracle, but not everything yet.  So, I can't count on the GL_BALANCES table for the info, I get from the JE_LINES.

  My problem is not the only request for the month.  But when I try to combine the queries with a Union, to aggregation of each measurement period in its own column, the group is necessary after each selected instruction rather than allowing me to put at the end of the UNION.  (When I put the group by at the end of the UNION, I have the 'not one group' function)

  So I get duplicate for each month of discrete measure accounts. When I duplicate in my Oracle database accounts, I can't count on the VLOOKUP function in excel to exactly match an account of inheritance.  I know there are more sophisticated ways to provide this output, but I'm hoping to get this info in a simple query.

  Thank you in advance for any advice you can provide

  Example of data output (the goal for me is to get the two rows to appear as one based on common points on the LEGACY_ACCOUNT and the ORACLE ACCOUNT

  The LEGACY ACCOUNT	ORACLE ACCOUNT	JUN_15	JUL_15	AUG_15	SEP_15	OCT_15	NOV_15	DEC_15
  010000001109000003584	190-600552-1001-100231-000-0000-0000-0000	0	0	-242961.04	0	0	0	0
  010000001109000003584	190-600552-1001-100231-000-0000-0000-0000	0	192588.02	0	0	0	0	0

  Here is a simplified version of my code that returns both records.  In my research, I had found a number of conversations where it has been shown that the group could be put at the end of the select statement.  However, when I remove the group from the first select statement I get SQL error: ORA-00937: not a function of simple-group

  Select

  l.attribute1 LEGACY_ACCOUNT,

  C.SEGMENT1: '-' | C.SEGMENT2: '-' | C.SEGMENT3: '-' | C.SEGMENT4: '-' | C.SEGMENT5: '-' | C.SEGMENT6: '-' | C.SEGMENT7: '-' | COMBINATION OF C.SEGMENT8,

  JUN_15 TO_NUMBER('0').

  JUL_15, sum (NVL(l.accounted_dr,0.00)-NVL(l.accounted_cr,0.00)),

  TO_NUMBER('0') AUG_15.

  TO_NUMBER('0') SEP_15.

  TO_NUMBER('0') OCT_15.

  TO_NUMBER('0') NOV_15.

  DEC_15 TO_NUMBER('0')

  Of

  b GL.gl_je_batches,

  GL.gl_je_headers h,

  GL.gl_je_lines l,

  GL.gl_code_combinations c,

  GL.gl_je_sources_tl j

  where b.je_batch_id = h.je_batch_id

  and h.je_header_id = l.je_header_id

  and l.code_combination_id = c.code_combination_id

  and h.je_source = j.je_source_name

  and c.segment1 ('190 ', '191', '192', '193', '194', ' 195 ', ' 196',' 197', ' 198 ', ' 199',)

  ('200 ', '203', ' 205', '206 ', '330', '331', '332',' 333 ', ' 334',' 335', ' 336 ', ' 337')

  and j.language = 'en '.

  and h.PERIOD_NAME ("JUL-15'")

  Group

  l.attribute1,

  C.SEGMENT1: '-' | C.SEGMENT2: '-' | C.SEGMENT3: '-' | C.SEGMENT4: '-' | C.SEGMENT5: '-' | C.SEGMENT6: '-' | C.SEGMENT7: '-' | C.SEGMENT8

  UNION

  Select

  l.attribute1 LEGACY_ACCOUNT,

  C.SEGMENT1: '-' | C.SEGMENT2: '-' | C.SEGMENT3: '-' | C.SEGMENT4: '-' | C.SEGMENT5: '-' | C.SEGMENT6: '-' | C.SEGMENT7: '-' | COMBINATION OF C.SEGMENT8,

  JUN_15 TO_NUMBER('0').

  TO_NUMBER('0') JUL_15.

  AUG_15, sum (NVL(l.accounted_dr,0.00)-NVL(l.accounted_cr,0.00)),

  TO_NUMBER('0') SEP_15.

  TO_NUMBER('0') OCT_15.

  TO_NUMBER('0') NOV_15.

  DEC_15 TO_NUMBER('0')

  Of

  b GL.gl_je_batches,

  GL.gl_je_headers h,

  GL.gl_je_lines l,

  GL.gl_code_combinations c,

  GL.gl_je_sources_tl j

  where b.je_batch_id = h.je_batch_id

  and h.je_header_id = l.je_header_id

  and l.code_combination_id = c.code_combination_id

  and h.je_source = j.je_source_name

  and c.segment1 ('190 ', '191', '192', '193', '194', ' 195 ', ' 196',' 197', ' 198 ', ' 199',)

  ('200 ', '203', ' 205', '206 ', '330', '331', '332',' 333 ', ' 334',' 335', ' 336 ', ' 337')

  and j.language = 'en '.

  and h.PERIOD_NAME ("AUG-15'")

  Group

  l.attribute1,

  C.SEGMENT1: '-' | C.SEGMENT2: '-' | C.SEGMENT3: '-' | C.SEGMENT4: '-' | C.SEGMENT5: '-' | C.SEGMENT6: '-' | C.SEGMENT7: '-' | C.SEGMENT8

  order by 1

  Is there a good reason to make this period both as a series of trade unions?  This looks like a classic pivot for me query.  This will make a way through the tables and should get the desired results.

  Select l.attribute1 legacy_account,

  c.Segment1: '-' | c.Segment2: '-' | c.segment3: '-' | c.segment4: '-' |

  c.segment5: '-' | c.segment6: '-' | c.segment7: '-' | combination of c.segment8,

  sum (case when h.period_name = 'JUN-15'

  then nvl(l.accounted_dr,0.00)-nvl(l.accounted_cr,0.00)

  otherwise 0 end) jun_15,.

  sum (case when h.period_name = 'JUL-15'

  then nvl(l.accounted_dr,0.00)-nvl(l.accounted_cr,0.00)

  otherwise 0 end) jul_15,.

  - and similar to DEC - 15

  GL.gl_je_batches b, gl.gl_je_headers h, gl.gl_je_lines l.

  GL.gl_code_combinations c, gl.gl_je_sources_tl j

  where b.je_batch_id = h.je_batch_id

  and h.je_header_id = l.je_header_id

  and l.code_combination_id = c.code_combination_id

  and h.je_source = j.je_source_name

  and c.segment1 ('190', '191', '192', '193', '194', '195',' 196', ' 197',

  '198 ', '199', '200', '203', '205' ', 206',' 330 ', ' 331',

  "332 ', '333', '334', '335',' 336 ', ' 337')

  and j.language = 'en '.

  and h.period_name (' Jun-15', ' 15 JUL', ' AUG-15'... "" ")

  L.attribute1 group,

  c.Segment1: '-' | c.Segment2: '-' | c.segment3: '-' |

  c.segment4: '-' | c.segment5: '-' | c.segment6: '-' |

  c.segment7: '-' | c.segment8

  If you're on the 11G version of the database, you might want to look at the PIVOT keyword that will do the same thing in a more concise expression.

  John

• Group of subquery

  Hello

  I need help in the following

  DB version: 11 GR 2

  several times that I need to find the duplicate rows exist in a table.where I do it in two parts

  1 write group and get duplicates

  select customer_id , count(order_id) from customers c , orders o where c.customer_id=o.customer_id group by customer_id having count(order_id ) >1;
  
  
  

  2. more than lines returned in the second request for information

  {code}

  Select c., s.*

  customers c, order_status s

  where c.customer_id = s.customer_id

  and c.customer_id (values from the query above);

  {code}

  instead of plugging the details, I can complete the foregoing in a stmt

  Please notify

  Thank you for your time

  Hello mydba

  Try this:

  SELECT *.

  FROM (SELECT c., s.*)

  , COUNT (c.customer_id) OVER (PARTITION BY c.customer_id) AS CNT_ID

  CUSTOMERS c

  s order_status

  where c.customer_id = s.customer_id

  )

  WHERE cnt_id > 1

  ;

  In this case, you should get all the visitors that they arrested more than 1.

  I hope it helps.

• Alert to be fired only for the first record, when there are duplicate entries

  Hello
  
  This is related to the fact of Oracle 10 g.
  I have a block record multi in which I entered and save some codes, something like below
  
  Code Description
  =====================
  AAAAAAAAAAAA ABCD
  BBBBBBBBBBBBB PQRS
  GENEVIEVE DAVIS
  ABCD DHGFKSDHKSHG
  PQRS DFJHHGS
  EEEE SDT85604ET
  =====================
  
  Now I need to post a warning/msg to go when-validate-the field Code. So now if I'm on the first record, the alert/msg will appear for code ABCD which is Ok. Now, on the next album, I get a different code PQRS as indicated above, the new alert appears which is Ok. If I enter a code that has been previously entered into the record block multi and alert/msg had been exposed to the only first alert/msg need is not displayed now know if I enter ABCD again the fourth record, the alert should not be displayed.
  Note that this must be done at the time of data entry itself. I guess that maybe it can be done by using groups Records / table plsql.
  
  Help with a way to solve this matter will be highly appreciated...
  
  Thank you and best regards...

  As you have already guessed, you must be able to keep track of how many times a value has been entered. If you know what all the possible values of 'CODE' at design time, you can create a counter for each value variable, but it would be a total pain. A better solution would be to permanently keep a total dynamics you can quickly check against. For this I recommend you use a group of registration of forms. Take a look at the demo of Forms - record group treatment (duplicate values check) I wrote. Using the packet of forms Rec_Group condition in this demo, you can easily change the process listed in the working document in your scenario. Follow all the steps in the demo. For your situation, you must change the when-validate-Item trigger so that instead of checking the dupicates and omitting the form if a duplicate is found, you check the number of entries to a value in the record group and display a message if the number is 0 or not to display a message if the number is greater than 0. Your modified WVI trigger might look like this:

  DECLARE
     ignore     NUMBER := 0;
     bignore   BOOLEAN := FALSE;
  BEGIN
     IF ( :YOUR_BLOCK.CODE IS NOT NULL ) THEN
        ignore := Rec_Group.Get_Number(Rec_Group.rg_name, :YOUR_BLOCK.CODE);
        IF ( ignore = 0 ) THEN
            -- Display your message
        ELSE
            -- Don't display any message
        END IF;
        /* add the code to the record group */
        bIgnore := Rec_Group.Add_Value(rec_group.rg_name, :YOUR_BLOCK.CODE, :system.trigger_record);
     END IF;
  END;
  

  Hope this helps,
  Craig B-)

  If someone useful or appropriate, please mark accordingly.

  Published by: Silvere March 30, 2011 15:07

• Output and group records into several column format problem

  Hi all

  I'm banging my head on the wall with this one. I have a query that displays the result in the form of two columns, it works fine.

  I have a problem when I try to use "group"for the field DSC1 doesn't show duplicates."  He transforms the output in column 2, column 3 and column 4 spots white all along.

  Someone knows how can I get it to display 2 columns of output and does not show in double DSC1 fields? The following are examples of what is happening:

  
  

  1 example of what he does without group (note to Apple is twice, which is not):

  Apples apples

  Orange peaches

  banannas grapes

  What I need to do (only show each DSC1 once and continue with the format of two columns) :

  oranges apples

  Fisheries banannas

  grapes

  Here is the code I use:

  < cfquery name = "getProduct" datasource = "mydb" >
  SELECT * from ecitm
  WHERE DSC1 <>' '
  order by DSC1

  < / cfquery >

  <! - start the 2-column output table - >

  < table border = "0" width = "90%" border = "0" align = "center" cellpadding = "5" cellspacing = "5" >
  
  < cfset newrow = false

  < b >
  < cfoutput query = "getProduct" group = "DSC1" >
  
  < cfif newrow EQ "true" >
  < b >
  < / cfif >
  < td >
  #DSC1 #.
  < cfif DSC2 NEQ "" > "".
  < br >
  #DSC2 #.
  < / cfif >

  < br >
  < a href = "DetailsList.cfm? ID = #getProduct.ID # & litm = #getProduct.LITM #" > VIEW < /a > DETAILS
  < table >
  
  < cfif getProduct.currentRow MOD 2 EQ 0 >
  < /tr >
  < cfset newrow = true >
  < cfelse >
  < cfset newrow = false >
  < / cfif >

  
  < / cfoutput >
  < /tr >
  < /table >

  The currentRow always property will count the number or records in the record setting loop, if you their output or not.

  Since you are not the output values for each record in the Recordset, you must count the itterations yourself.

  Put a meter of itteration before the loop.

  Update the counter at the top of the loop.

  OR on newer versions of CF

  Reset the counter in the true clause of the block, where you also define new line. >

  Then use the variable in the iit instead the currentRow property to determine the number of items have been posted.

  **** OR ****

  You could do a simple SQL command does not get duplicates first and then use a loop of simple without any of the grouping and additional logic that you do.

  
  
  SELECT DISTINCT *
       FROM ecitm
       WHERE DSC1 <> ' '
       ORDER BY DSC1
  
  
  
  
       #DSC1#
       
  
      
  
  
  

• How can I avoid duplicates with cfloop

  I use a bit of files Next-N code on a list of books which is obtained from a MS SQL database.
  The next-N registration code only works using a < CFLOOP QUERY = "" >, the way I have my SQL put in place I'm getting duplicates under CFLOOP but not under CFOUTPUT, this is because with CFOUTPUT can I use the group = "" param "
  
  Can you please look at my request and tell me how to structure my relationship so that this JOIN returns all the information on the same record rather than create two records (duplicate)?
  
  This is the basic layout of my tables
  
  Table of languages
  Language PK | Name of the language
  1 - English
  2 - French
  
  Table Books
  Book PK | Reserve name | Original language | Language of translation
  1 - book Test - 2-1
  
  Released on the site I want:
  Test book. O: French | T: English
  
  Released on the site I get:
  Test book. O: French | T: English
  Test book. O: French | T: English
  (the discharge reveals that a duplicate is produced due to the relationship between Orig and Trans with the table of languages)
  
  Here's my query:
  SELECT bookName, bookOrigLang, bookTransLang, langPK, bookPK, langLanguage
  (SELECT bookOrigLang FROM books WHERE Books.bookOrigLang = Languages.langPK) The original,
  (SELECT bookTransLang FROM books WHERE Books.bookTransLang = Languages.langPK) AS translation
  FROM dbo. Books, dbo. Translation
  
  -------------------
  I am grateful for any suggestions you might be able to

  Quote:
  Posted by: sjlsam2
  I get the following error if:
  Ambiguous column name 'cllangPK '.

  I can't be precise because most of the columns of the query is not a table name or an alias. So I'm not sure the columns that belong to tables. But the addition of a source table name, or an alias for all the columns should fix errors of "ambiguous column.

  Example:
  SELECT theSourceTable.clcoPK, theSourceTable.clcoCountry...

  Give each column a different name to refer to it in your cfoutput

  Example:
  SELECT
  ol.cllangLanguage AS OriginalLanguage,
  tl.cllangLanguage AS TranslatedLanguage,
  ....

  You will need to choose a single join syntax and use it consistently. So either do all your joins this way

  FROM TableA, TableB
  WHERE TableA.ID = TableB.ID

  ... or this way

  FROM TableA AS an INNER JOIN TableB b ON a.ID = b.ID

• How can I stop getting emails twice on the same subject being sent to me

  I get duplicate incoming emails.
  I need to know how I can stop this.
  I use Thunderbird on Bigpond. I did this experiment some time ago, but it seemed to stop and now it has recently started to reproduce.
  Is there a solution to this please?

  Best of British... If you can get anything useful to Bigpond support I'll be surprised. The last time I rang them all that they wanted to do was blame that was not yet installed outlook.

• How can I SAVE groups of tabs. They disappeared when I opened then Firefox

  I created 5 groups of tabs. It was awesome flick between them, but I closed my computer and when I open again once they had gone.

  How would you please save them or stop them endangered

  Thank you

  pingu70

  If you clear your recent history manually then there is no problem with App Tabs and tab groups get lost and you can delete all data you want... There is only a problem when you do this automatically whenever you close Firefox. Your first screenshot shows that you only clear the output cache, so it should be OK.

• application to remove duplicates?

  Hi all - two questions.  When I backed up my macbook Pro on an external hard drive, I accidentally duplicated my entire photo library (9 000 duplicate photos).  I wiped my mac, just reinstalled and went to export my photos.  Two things happened.  The library, many of them would not export.  Secondly, all duplicates of photos that have exported, also exported.  I want to get duplicates on my mac.  How can I do this?

  Thank you!

  These researchers duplicate are compatible with Photos:

  Photo Sweeper is safe, power Photos, Duplicate Annihilator.

  Photo Sweeper can find photos duplicate States changes or sizes.  It is very versatile.

  Photos of power is a great tool to have, if you use several libraries, because it can find duplicates in libraries, libraries of fusion, and we will navigate you in the libraries of pictures in mode list with added metadata.