SQL case in where clause

I have the following table.

I need to create a query that returns:

(a) if the table contains 1 and 0 on pass that only values with 1

(b) otherwise, if the table contains only 1 on collar that only values 1

(c) otherwise, if the table contains only 0 on pass that only values to 0.

I tried with the following query, but if the table contains only 0 returns nothing

{code}

create table test

(col1 number);

Insert in the test

values (1);

Insert in the test

values (1);

Insert in the test

values (1);

Insert in the test

values (0);

Insert in the test

values (0);

Insert in the test

values (0);

commit;

Select *.

of the test

where

col1 case

When 1 then 1

0 otherwise

end = nvl2 (col1, 1, 0);

{code}

Thank you

Hello

If you want to find which is the highest value of col1 in the table and view only the lines where col1 has this value.

Here's a way to do it:

WITH got_max_col1 AS

(

SELECT col1

MAX (col1) ON (AS max_col1)

OF the test

WHERE col1 IN (0, 1) - if necessary

)

SELECT col1

OF got_max_col1

WHERE col1 = max_col1

;

With the sample data you posted, you do not have the condition: WHERE col1 IN (0, 1)

If you add lines where col1 can be anything other than 0 or 1, then this condition will ignore them.

Tags: Database

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SUCCESS_IND                             VARCHAR2(2)
ENTRY_CREATEDDATE                       DATE       
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PLAN_TABLE_OUTPUT
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Plan hash value: 2224314832

----------------------------------------------------------------------------------------------------------
| Id  | Operation            | Name              | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
----------------------------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT     |                   |   590 | 33040 |  2501K  (1)| 08:20:15 |       |       |
|   1 |  HASH GROUP BY       |                   |   590 | 33040 |  2501K  (1)| 08:20:15 |       |       |
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