Type of the interval of MC: Derivation of value

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• dbms_scheduler.create_window fails with ORA-27418: syntax error in the interval of recurrence or calendar

  I tried to create a window to test the activation of plans of RM. But I get this error.

  SQL > EXECUTE dbms_scheduler.create_window.

  > (-)

  > window_name = > 'day ', -.

  > resource_plan = > 'my_plan ', -.

  > start_date = > systimestamp + 1 /(24*60).

  > repeat_interval = > ' freq = > daily '.

  > time = > ' 0 01:00:00 '.

  > Comments = > ' C know if it works without a job "-"

  >);

  BEGIN dbms_scheduler.create_window (window_name = > 'day', resource_p)

  LAN = > 'my_plan', start_date = > systimestamp + 1 /(24*60), repeat_interv

  Al = > ' freq = > daily ', duration = > ' 0 01:00:00 ', comments = > ' C so she

  works without employment '); END;

  *

  ERROR on line 1:

  ORA-27481: 'SYS '. "' DAY ' has an invalid schedule

  ORA-27418: syntax error in the interval of recurrence or calendar

  ORA-06512: at "SYS." DBMS_ISCHED", line 486

  ORA-06512: at "SYS." DBMS_SCHEDULER', line 1295

  ORA-06512: at line 1

  I have tried many tips found on the web, nothing works.

  Any help would be greatly appreciated.

  Also, can you pls tell me if this command run once automatically activates the my_plan after 1 minute, 1 minute, after which, it will disable the my_plan? So, you do not need to create a JOB for this. If you create a window, that is, as a job creation to enable an RM plan?

  2734369 wrote:

  Wow, discovered the issue: the repeat interval is broken (I use a database of 12.1 in Windows 7). It must be uppercase. Very surprising in the windows to be case-sensitive.

  SQL >

  SQL > EXECUTE dbms_scheduler.create_window.

  >  (-

  > window_name-online 'day ', -.

  > resource_plan-online 'my_plan ', -.

  > start_date-online systimestamp + 1 /(24*60).

  > repeat_interval-online ' FREQ = DAILY; BYHOUR = 10; BYMINUTE = 30', -.

  > time-online ' 0 01:00:00 '.

  > Comments => ' C know if it works without a job "-"

  >  );

  PL/SQL procedure successfully completed.

  Problem is, after 1 minute, always that the plan is not activated?

  SQL > SEE THE RESOURCE_MANAGER_PLAN PARAMETER

  VALUE OF TYPE NAME

  ------------------------------------ ----------- ----------------------

  resource_manager_plan chain

  Why the Plan is not activated after 1 minute. Have we not create a job (I don't think).

  I think you misunderstand the meaning of "start_date".  Please see the documentation on what this means exactly.

  This attribute specifies the first date and time where it is scheduled to open in this window. If the value start_date specified is in the past or is not specified, the window opens, from its inception.

  To repeat windows using an expression of the calendar to specify the repetition interval, the value of start_date is a reference date. The first time the window opens depends on the specified repeat interval and the value of start_date .

  (From Types and Oracle® packages of PL/SQL Database 11g Release 2 (11.2) reference E40758-03); dbms_scheduler, create_window.  DBMS_SCHEDULER

  Once you have done this, you will see that it is pretty useless to specify that you have.

  Your repeat_interval said "every day at 10:30.

• Query for the partitions of the interval, system and reference

  Hi, I want to ask some of range partitions, system and reference information.

  In the partition of the interval, the script looks like this

  CREATE TABLE interval_sales

  (prod_id NUMBER (6))

  cust_id NUMBER

  time_id DATE

  )

  PARTITION OF RANGE (time_id)

  INTERVAL (NUMTOYMINTERVAL (1, 'MONTH'))

  (PARTITION p0 VALUES LESS THAN (TO_DATE (' 01/01/2005 ',' DD-MM-YYYY "")));

  I would like to write a query to find the expression of the interval "MONTHS" but could not find what he makes.

  In the reference partition, the script looks like this

  CREATE TABLE child_tab)

  ID NUMBER NOT NULL,

  parent_tab_id NUMBER NOT NULL,

  code VARCHAR2 (10),

  Description VARCHAR2 (50).

  CREATED_DATE DATE,

  CONSTRAINT child_tab_pk PRIMARY KEY (id),

  CONSTRAINT child_parent_tab_fk FOREIGN KEY (parent_tab_id)

  REFERENCES parent_tab (id)

  )

  PARTITION BY REFERENCE (child_parent_tab_fk);

  I want to write a query to find the foreign key name 'child_parent_tab_fk' after the PARTITION BY REFERENCE to the last line, but have no luck so far.

  In the end, I want to achieve this goal:

  If (interval_partitioning_type)

  Assign the interval expression to a string variable

  Another yew (reference_partitioning_type)

  Set the foreign key to a variable of type of foreign key

  Is there a way to get the type of partitioning? (interval and reference here)

  Please advise,

  Jack

  You can query ALL_PART_TABLES

  REF_PTN_CONSTRAINT_NAME	VARCHAR2(30)		Name of the referential partitioning constraint for partitioned tables reference
  INTERVAL	VARCHAR2(1000)		The value of the interval chain

• assign the interval

  BANNER
  Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
  PL/SQL Release 11.2.0.3.0 - Production
  CORE     11.2.0.3.0     Production
  TNS for HPUX: Version 11.2.0.3.0 - Production
  NLSRTL Version 11.2.0.3.0 - Production

  is it possible to assign a data type of a table variable interval?
  

  CREATE TABLE mytable
  AS
     (SELECT '4' num_of_days FROM DUAL);
  
  DECLARE
     myinteverval   INTERVAL DAY TO SECOND;
  BEGIN
     myinterval := INTERVAL '4' DAY;  --happy
  
     SELECT num_of_days INTO myinteverval FROM mytable;
  
     myinteverval := interval myinteverval day; -- not happy
  end;

  Hello

  Pollywog wrote:

  BANNER
  Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
  PL/SQL Release 11.2.0.3.0 - Production
  CORE     11.2.0.3.0     Production
  TNS for HPUX: Version 11.2.0.3.0 - Production
  NLSRTL Version 11.2.0.3.0 - Production
  

  is it possible to assign a data type of a table variable interval?

  CREATE TABLE mytable
  AS
  (SELECT '4' num_of_days FROM DUAL);
  
  DECLARE
  myinteverval   INTERVAL DAY TO SECOND;
  BEGIN
  myinterval := INTERVAL '4' DAY;  --happy
  

  What is the reason why he is happy

  INTERVAL '4' DAY
  

  a perfectly formed INTERVAL is literal. By itself

  '4'
  

  would be a VARCHAR2 interval, but is not in itself. immediately before the first quotation mark is the INTERVAL keyword, which means that the expression is a literal INTERVAL, and a literal INTERVAL must contain a certain number in single quotes; No matter what kind of expression.

  SELECT num_of_days INTO myinteverval FROM mytable;
  
  myinteverval := interval myinteverval day; -- not happy
  end;
  

  Use the NUMTODSINTERVAL function:

  myinterval := NUMTODSINTERVAL (4, 'DAY');
  

• Average data with columns of type of data INTERVAL DAY (99) second (99)

  Hi all
  I'm trying to get an average of the run_duration column in the view of oracle JOB_RUN_DETAILS SCHEDULER(11 g R2). The data type for the run_duration column is INTERVAL DAY (3) to SECOND (0).
  How we can perform mathematical functions (sum, avg, diff) on the columns with data types (INTERVAL DAY) (3) OF SECOND (0) or TIMESTAMP WITH TIMEZONE?
  
  Thanks in advance
  VB

  user5526066 wrote:
  How we can perform mathematical functions (sum, avg, diff) on the columns with data types (INTERVAL DAY) (3) OF SECOND (0) or TIMESTAMP WITH TIMEZONE?

  For some reason any Oracle allow to add/subtract intervals but does not aggregate the. If you don't care about fractions of a second:

  select  owner,
          job_name,
          numtodsinterval(avg((sysdate + run_duration) - sysdate),'day') average_run_duration
    from dba_scheduler_job_run_details
    group by owner,
             job_name
  /
  
  OWNER                          JOB_NAME                                                          AVERAGE_RUN_DURATION
  ------------------------------ ----------------------------------------------------------------- -------------------------------
  EXFSYS                         RLM$SCHDNEGACTION                                                 +000000000 00:00:00.015873015
  ORACLE_OCM                     MGMT_STATS_CONFIG_JOB_1                                           +000000000 00:00:00.000000000
  SYS                            PURGE_LOG                                                         +000000000 00:00:00.290322580
  ORACLE_OCM                     MGMT_CONFIG_JOB                                                   +000000000 00:00:00.479999999
  ORACLE_OCM                     MGMT_CONFIG_JOB_1                                                 +000000000 00:00:01.439999999
  SYS                            AUTO_SPACE_ADVISOR_JOB                                            +000000000 00:00:19.680000000
  EXFSYS                         RLM$EVTCLEANUP                                                    +000000000 00:00:00.000000000
  ORACLE_OCM                     MGMT_STATS_CONFIG_JOB                                             +000000000 00:00:01.000000000
  SYS                            GATHER_STATS_JOB                                                  +000000000 00:01:52.400000000
  
  9 rows selected.
  
  SQL> 
  

  SY.

• I've just updated to the latest version and now I can not manually type in the URL. I can't get to a new page if I click on a link.

  I've just updated to the latest version of Firefox 32.0.3 today and now I can not manually type in the URL. I can't get to a new page if I click on a link. I had to use - gasp - Chrome just to get to this help page!

  I tried to restart Firefox.
  I can type (not a keyboard problem), but the browser never tries to go to URL, when I hit enter

  Any ideas?

  Thanks - kept looking around and found a rec to make a reset of Firefox. This seems to have worked.

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  In the end, we tried all those - they didn't work, but this thread and recommended prog worked.

  http://www.techsupportall.com/how-to-remove-doSearch-com-from-Internet-Explorer-chrome-Firefox/

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  So it has now been resolved.

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  No, I just realized that I was holding Command-Shift-N rather than command-N

• What did you do for Firefox? I don't have the left arrow key or arrow - I can't type in the url box - Firefox has suddenly become USELESS!

  I clicked on 'Customize' as you suggest, am the arrows and the area url, you click on ok, and everything is back to what I had already. I know, except for a really quick fix, I have to go back to IE.

  Hello

  I'm a bit confused. Your title says
  

  What did you do for Firefox? I don't have the left arrow key or arrow - I can't type in the url box - Firefox has suddenly become USELESS!

  Yet your said OP
  

  Click on 'Customize' as you suggest, am the arrows and the area url, you click on ok, and everything is back to what I had already. I know, except for a really quick fix, I have to go back to IE.

  Your problem is resolved or not?

  Right-click on an empty space in the toolbar, then click Customize, then click restore default value

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  Work on Firefox for windows 19.0.2. I imported the firefox profile everything from the old computer to a new one – after importation, a thing is broken:

  -When I open a new tab (topic: setting newtab) it opens a new tab with the tiles of sites previously used well, but I need to click on the address bar of browser-> first while on the machine to another, in my opinion, the default setting is that I can type in the Url bar immediately after the opening of the new tab to any address manually in the browser to the URL (without the need of) (click on the additional url bar)-j' I hope you understand you what I mean). A way to restore this feature?

  Thanks in advance

  Start Firefox in Safe Mode to check if one of the extensions (Firefox/tools > Modules > Extensions) or if hardware acceleration is the cause of the problem (switch to the DEFAULT theme: Firefox/tools > Modules > appearance).

  • Do NOT click on the reset button on the start safe mode window or make changes.
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  • https://support.Mozilla.org/KB/troubleshooting+extensions+and+themes

• How can I restore google search when you type in the address bar? or xfinity ate my search engine

  When the xfinity installed our internet guy it changed all my settings, great. now, when I type in the bar to find something I get xfinity instead of google. and their search engine is not very useful. I looked on the site of firefox so it is said, is that if you type in the address bar google is the default value. How to restore the default? Thank you all!

  Try this extension:

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  See also:

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  • https://support.Mozilla.org/KB/resetting+preferences
  • https://support.Mozilla.com/kb/location+bar+search

• whenever I type in the google box to search for each letter i firefox type which application I would like to use to open this file, this is so embarrassing, how to stop this?

  whenever I type in the google box to search for each letter i firefox type which application I would like to use to open this file, this is so embarrassing, how to stop this?

  You are welcome

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• Key on the keyboard does not work in firefox box when you type in the web site, but it works everywhere else?

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  A way of solving problems, which disables most of the modules.
  
  (If you use it, switch to the default theme).

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  Do not choose anything at the moment, just use 'continue in safe mode.

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  Can be caused by an add-on to the AVG.

  When find you what is causing that, please let us know. It might help others who have this problem.

• The address bar where I can type in the Web addresses does not appear on my Mozilla, please help me with this... How to activate it?

  The address bar where I can type in the Web addresses does not appear on my Mozilla, please help me with this... How to activate it?

  Hi kdwis,

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