A parsing sql problem?
Hi allI'm on the OracleXE 11 GR 2 and have the following conditions for the release of the select statement:
Tables:
GARAGE
======
ID GARAGE_NAME
--- -----------
1 GARAGE_1
2 GARAGE_2
PERSONS
=======
ID GARAGE_ID NAME
--- --------- -----
1 1 NAME1_1
2 1 NAME1_2
3 1 NAME1_3
4 1 NAME1_4
5 1 NAME1_5
6 1 NAME1_6
7 2 NAME2_1
8 2 NAME2_2
9 2 NAME2_3
10 2 NAME2_4
CARS
====
ID GARAGE_ID CAR
--- --------- -----
1 1 CAR1_1
2 1 CAR1_2
3 1 CAR1_3
4 1 CAR1_4
5 2 CAR2_1
6 1 CAR2_2
7 1 CAR2_3
8 1 CAR2_4
9 1 CAR2_5
10 1 CAR2_6GARAGE_ID GARAGE_NAME CAR PERSON
--------- ----------- ------ -------
1 GARAGE_1 CAR1_1 NAME1_1
1 GARAGE_1 CAR1_2 NAME1_2
1 GARAGE_1 CAR1_3 NAME1_3
1 GARAGE_1 CAR1_4 NAME1_4
1 GARAGE_1 NAME1_5
1 GARAGE_1 NAME1_6
2 GARAGE_2 CAR2_1 NAME2_1
2 GARAGE_2 CAR2_2 NAME2_2
2 GARAGE_2 CAR2_3 NAME2_3
2 GARAGE_2 CAR2_4 NAME2_4
2 GARAGE_2 CAR2_5
2 GARAGE_2 CAR2_6 What is a parsing SQL problem?
Dear community, I need your help!
Kind regards
Looks like than just an outer join...
But how are you going to jining cars and people - from the name?
Or something like that?
with c as
(
select c.garage_id,c.car,g.garage_name g_name,
row_number() over(partition by c.garage_id order by c.id) rn
from cars c,garage g
where c.garage_id = g.id
),
p as
(
select p.garage_id,p.name p_name,g.garage_name g_name,
row_number() over(partition by p.garage_id order by p.id) rn
from persons p,garage g
where p.garage_id = g.id
)
select nvl(p.garage_id,c.garage_id) garage_id,
nvl(p.g_name,c.g_name) garage_name,
car,p_name person
from c
full outer join p on
(c.garage_id = p.garage_id and c.rn = p.rn);
GARAGE_ID GARAGE_NAME CAR PERSON
--------- ----------- ------ -------
1 GARAGE_1 CAR1_1 NAME1_1
1 GARAGE_1 CAR1_2 NAME1_2
1 GARAGE_1 CAR1_3 NAME1_3
1 GARAGE_1 CAR1_4 NAME1_4
1 GARAGE_1 NAME1_5
1 GARAGE_1 NAME1_6
2 GARAGE_2 CAR2_1 NAME2_1
2 GARAGE_2 CAR2_2 NAME2_2
2 GARAGE_2 CAR2_3 NAME2_3
2 GARAGE_2 CAR2_4 NAME2_4
2 GARAGE_2 CAR2_5
2 GARAGE_2 CAR2_6
12 rows selected
If this isn't what you want, please explain the logic to get to your exit.
Published by: JAC on November 17, 2012 15:15
Tags: Database
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SUP: SQL +-PROBLEM OF QUERY IN MULTI TABLE
SQL + QUERY DATA:
-----------
SELECT PATIENT_NUM, PATIENT_NAME, HMTLY_TEST_NAME, HMTLY_RBC_VALUE,
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-------------
-------------
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4.6 - 6.0 HMTLY_RBC_NORMAL
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DLC_TEST_NAME LEUKOCYTE COUNT PREMIUM
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DLC_POLYMORPHS_NORMAL_VALUE 40-65
---------------
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PATIENT_NUM 3
PATIENT_NAME KKKK
HMTLY_TEST_NAME HEMATOLOGY
HMTLY_RBC_VALUE 4
4.6 - 6.0 HMTLY_RBC_NORMAL
DLC_TEST_NAME LEUKOCYTE COUNT PREMIUM
DLC_POLYMORPHS_VALUE 60
DLC_POLYMORPHS_NORMAL_VALUE 40-65
----------------------------
4 TABLES OF LABORATORY CLINIC FOR DATA ENTRY AND GET REPORT ONLY FOR THE TESTS CARRIED OUT FOR PARTICULAR
PATIENT.
TABLE1:PATIENTS_MASTER1
COLUMNS: PATIENT_NUM, PATIENT_NAME,
VALUES:
PATIENT_NUM
1
2
3
4
PATIENT_NAME
BENAMER
GIROT
KKKK
PPPP
---------------
TABLE2:TESTS_MASTER1
COLUMNS: TEST_NUM, TEST_NAME
VALUES:
TEST_NUM
1
2
TEST_NAME
HEMATOLOGY
DIFFERENTIAL LEUKOCYTE COUNT
-------------
TABLE3:HAEMATOLOGY1
COLUMNS:
HMTLY_NUM, HMTLY_PATIENT_NUM, HMTLY_TEST_NAME, HMTLY_RBC_VALUE, HMTLY_RBC_NORMAL_VALUE
VALUES:
HMTLY_NUM
1
2
HMTLY_PATIENT_NUM
1
3
MTLY_TEST_NAME
HEMATOLOGY
HEMATOLOGY
HMTLY_RBC_VALUE
5
4
HMTLY_RBC_NORMAL_VALUE
4.6 - 6.0
4.6 - 6.0
------------
TABLE4:DIFFERENTIAL_LEUCOCYTE_COUNT1
COLUMNS: DLC_NUM, DLC_PATIENT_NUM, DLC_TEST_NAME, DLC_POLYMORPHS_VALUE, DLC_POLYMORPHS_
NORMAL_VALUE,
VALUES:
DLC_NUM
1
2
DLC_PATIENT_NUM
2
3
DLC_TEST_NAME
DIFFERENTIAL LEUKOCYTE COUNT
DIFFERENTIAL LEUKOCYTE COUNT
DLC_POLYMORPHS_VALUE
42
60
DLC_POLYMORPHS_NORMAL_VALUE
40-65
40-65
-----------------
Thank you
RCS
E-mail:[email protected]
--------I think you want an OUTER JOIN
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Set serveroutput on;
declare
client cursor is
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order of order_date, customer_id, order_id item_id, ship_date
update the order_id, item_id;neworder_id ph2_item.order_id%type;
multicust multi_site_cust.cust%type;
newitem_id ph2_item.item_id%type;Start
/ * Initialization neworder_id * /.
Select
Max (order_id) + 1
in
neworder_id
Of
sales_order;newitem_id: = 1;
for c_rec looping cust
/ * initilising multicust * /.
Select
customer
in
multicust
Of
multi_ships_cust
order by
customer;Update
ph2_item p
set
p.order_id =
(
case
When
c_rec.customer_id = multicust
then
neworder_id
on the other
neworder_id + 1
end
),
p.item_id =
(
case
When
c_rec.customer_id = multicust
then
newitem_id + 1
-other
-newitem_id
end
)
the location being the customer.
end loop;
end;
/Published by: cdkumar on October 6, 2008 14:55
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That's what I get when I run this sql:
and I table having partition named PART100730, when I make this selection, I get this partition name:SQL> select '''%'|| to_char(sysdate,'mmdd') ||'%''' from dual; '''%'||T -------- '%0730%'
but, when I do this sql, I get no lines, and I don't understand why.SQL> SELECT partition_name 2 FROM dba_tab_partitions 3 WHERE table_name = 'PART' 4 AND partition_name LIKE '%0730%' 5 ; PARTITION_NAME ------------------------------ PART100730 SQL>
: (SQL> SELECT partition_name 2 FROM dba_tab_partitions 3 WHERE table_name = 'PART' 4 AND partition_name LIKE '''%'|| (select to_char(sysdate,'mmdd') from dual) ||'%''' ; no rows selectedThis can give you some tip!
SQL> select * from emp where ename like '''%'||(select ename from emp where empno=7902)||'%''' ; no rows selected SQL> ed Wrote file afiedt.buf 1* select * from emp where ename like '''%||(select ename from emp where empno=7902)||%''' SQL> / no rows selected SQL> select * from emp where ename like '%'||(select ename from emp where empno=7902)||'%'; EMPNO ENAME JOB MGR HIREDATE ---------- ----------------------------------- --------- ---------- --------- SAL COMM DEPTNO ---------- ---------- ---------- 7902 FORD ANALYST 7566 03-DEC-81 3000 20 -
I use the following SQL and it works very well for retrun me 5 random recordings of the entire database.
SELECT penpals.*, Round (((acos (sin ((-74.1192 * pi () / 180)) * sin ((lon * pi () / 180)) + cos ((-74.1192 * pi () / 180)) * cos ((lon * pi () / 180)) * cos (((40.9353-lat)*pi()/180)))*180/pi())*60*1.1515)) distance)))))
CORRESPONDENTS
LEFT JOIN geozip ON penpals.zip = geozip.zip
WHERE geozip.zip IS NOT NULL
ORDER BY RAND() LIMIT 5
The round function is used to calculate the miles between 2 zip codes in the United States, based on longitide and latitude set as a named column distance.
This works very well and gives me what I need. However if I add the following
AND distance < 26 after WHERE geozip.zip IS NOT NULL
I get the error
Unknown column 'distance' in ' where clause'
But if I try to ORDER OF the distance, it works for sorting.
Anyone have any ideas? Thank you.oO (VernMan)
> I use following SQL and it works very well for retrun me 5 files randomly
> of the entire database.
>
> SELECT penpals.*, Round (((acos (sin ((-74.1192 * pi () / 180)) * sin ((lon * pi () / 180))))))
> + cos ((-74.1192 * pi () / 180)) * cos ((lon * pi () / 180)) * cos (((40.9353 -
((> lat)*pi()/180)))*180/pi())*60*1.1515)) distance
> CORRESPONDENTS
> Geozip LEFT JOIN ON penpals.zip = geozip.zip
> Geozip.zip WHERE IS NOT NULL
> ORDER BY RAND() LIMIT 5
>
> The rounding function is used to calculate the miles between 2 postcodes in
> in the United States, based on longitide and latitude, defined as a named column distance.
>
> This works very well and gives me what I need. However if I add the following
> AND distance< 26="" after="" where="" geozip.zip="" is="" not="">
> I get error
> Unknown column 'distance' in ' where clause'
>
> but if I try to ORDER OF distance he works to sort.
>
> Anyone have any ideas? Thank youTry
SELECT...
Of...
WHERE THE...
HAVING distance<>
ORDER IN...Micha
-
SQL problem - comprehensive selection
All,
I have the SQL below which returns me the correct data, how I would return another (assignment ID) column in the selected table without the group by? also as table date tracking, which means that the person_id and Max hours are not sufficient to identify a line of uniquly, I can't use it as a sub select.
Select
person_id,
Max (normal_hours)
Of
per_all_assignments_f
where
SYSDATE between effective_start_date and effective_end_date
and assignment_status_type_id = 1
Group
person_id
I worked around in a circle with this one so I can miss obvious somethig. I need basically ID assignment in the assignment of the person (identified by the ID of the person) work the most hours (normal hours). This baiscaly me givies a primary assignment for each person based on the Max Normal_Hours
Hope someone can point me in the right direction
Concerning
Published by: SolomonHill on November 24, 2009 15:09Hello
To find the associated assignment_id Max (normal_hours):
select person_id, MAX(normal_hours), MIN (assignment_id) KEEP (DENSE_RANK LAST ORDER BY normal_hours) AS top_assingment_id from per_all_assignments_f where sysdate between effective_start_date and effective_end_date and assignment_status_type_id = 1 group by person_idIn case of tie, the above query will choose the lowest assignment_id that goes with the MAX.
For example, if all the lines to person_id = 98765:ASSIGNMENT_ID NORMAL_HOURS ------------- ------------ 123 20 234 20 345 20 456 15 123 10then MAX (normal_hours) is 20, but what is the assignment_id that goes with 20? There are three different assignment_ids which have an equal right to the most hours. MIN in the above query is said that the lowest (123 in this example) one will be returned.
-
Hello
I'm trying to run the dynamic SQL string. It generates an error
ORA-00932: inconsistent data types: expected - was -.
Here is the code:
CREATE OR REPLACE PROCEDURE test_prc (d_output on sys_refcursor)
IS
l_sql VARCHAR2 (1000);
l_deptid NUMBER (10): = 30;
BEGIN
l_sql: = ' select empno, ename from emp where ename = "DISTRICT" and deptno =: l_deptid';
EXECUTE IMMEDIATE l_sql IN d_output USING l_deptid;
EXCEPTION
WHILE OTHERS THEN
dbms_output.put_line ('Err > ' |) SQLERRM);
END;
/
Set serveroutput on
declare
t sys_refcursor;
Start
test_prc (t);
end;
/
ERR > ORA-00932: inconsistent data types: expected - was -.
can you please tell me where I have to fix the code?
Thank you and best regards,
RSDHello
I think the output you get you want to switch to a ref cursor You can try this.
-not tested
EXECUTE IMMEDIATE l_sql IN d_output USING l_deptid;
BEGIN
Ref_cur OPEN FOR l_sql using l_deptid;-I hope this is your test program that you use no parameter for the SQL code.
Thank you
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