access a type of user to another schema (collection)

Similar Questions

• Restoration to a corrupt user or copy corrupted to a newly created user. I am not allowed access to corrupt the user of another administrative user.

  When I try to copy the files from the user to a new user, the corrupt user is inaccesable when I click it.  I'm another user of the admin access.  I restarted the computer.  Does anyone have any suggestions?

  I encountered this problem immediately after removing an accessory program Apple ITunes that I have not used.  I did it to clear up disk space.  This has happened also when I got a low disk space to open the user.  I could open another admin user account and free up enough disk space to open the user.  When I try to connect to the corrupt user, it connects me to another user called (name.value of initial user followed a string of alpha-numberic characters)

  Thank you

  Hello Cscoler,

  Corruption of the profiles can be caused by malware, by repeated interruptions due to file system corruption and bad hardware issues. Did you run any malware removal software?

  When you created a new user account, have you configured it as an administrator? Do you receive error messages when you try to open a session in the corrupted profile, such as "the system has recovered from a serious error or user profile is corrupted"? When you log in the corrupted profile, are you able to view your data?

  Thank you

  James

• With the help of the TYPE operator % on objects in another schema

  Suppose I have the following architecture:
  * A schema called APP_SCHEMA (for example), which contains all applications level PL/SQL packages that contain a business application logic
  * A data schema, called DATA_SCHEMA (for example), that contains the schema objects that are referenced by the PL/SQL in APP_SCHEMA
  Suppose I create a simple procedure like this in the APP_SCHEMA:

  CREATE OR REPLACE PROCEDURE test_proc(pVar IN DATA_SCHEMA.TABLENAME.TABLECOLUMN%TYPE)
  AS
  BEGIN
       DBMS_OUTPUT.PUT_LINE(pVar);
  END;
  /{code}
  For this simplified procedure I get the following error:
  {code:java}1/25     PLS-00201: identifier 'DATA_SCHEMA.TABLENAME' must be declared{code}So, my basic question is how do I use the %TYPE operator to reference objects in another schema?
  
  Other Pertinent info:
  * Windows Server 2003
  * Oracle Database 10gR2 (10.2.0.3)
  Thanks!                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

  Its almost certainly a problem of privileges.

  I can create a test procedure based on the same script that compiles successfully.

  Verify that your user can access the table. Might need to have to grant access directly, rather than in a role.

  Published by: Keith Jamieson on August 25, 2008 17:51
  typo fixed

• Access to the content of the tables of a schema into another schema

  Hello
  
  I have my doubts... Suppose I have a user called DEMO and it has tables. now I have another user called DEMO1
  
  my doubt is. How can I get the DEMO user tables in DEMO1. If updating the table DEMO1 which should reflect
  
  DEMO user. Help me...

  Dear friend,

  You can consult the tables of a schema in another schema using the following steps.

  (1) you must grant privileges on table demo Demo1, here's the statement to do so.

  Grant Select, update on the table table_name to Demo1

  (2) Create in Demo1 for the table_name demo, the suite is about education to do.

  SYNONYM to CREATE or REPLACE table_name for Demo.table_name;

  (3) do the Update statement on the table table_name in Demo1. Updated these results reflected in demo when you post the update statement in Demo1.

  Hope that gives you an idea.

  Kind regards
  Ravi Kumar Ankarapu.

• transfer tables belonged to a user to another user schema

  Hello
  in 10 G R2
  in DB control how to transfer the tables belonged to a user to another user scheme?
  
  Thank you.

  It isn't a way that I know of.

  You can study using EXPDP/IMPDP or EXP/IMP.

• Grant execute on a package in another schema of users

  I need the ability to grant enforcement on a package in another schema of users...
  
  i.e. User_1 a Package pkg_package1
  
  User_2 should be able to grant execute on user_1.pkg_package1 to other users.
  
  I know you can give any procedure (I think) to user_2 and - it must be able to do.
  
  The problem is - I don't want user_2 can grant execute on any procedure in the database - just a diagram of user_1.
  
  Is there a way to do this?

  Hello

  FOT individual packages, you can tell

  GRANT   EXECUTE  ON pkg_package1
  TO      user2
  WITH GRANT OPTION;
  

  Alternatively, you can write a procedure in the schema of user_1 which grants privileges and give privileges to EXECUTE user_2 on the procedure.

• Re: "insufficient privileges" error when you run the Java stored procedure in another schema

  I get an "insufficient privileges" error when you run the Java stored procedure in another schema, see details below.  I don't know what are missing privileges (I already granted the EXECUTE privilege), suggestions?  -Thank you.

  Define a simple java class and deploy it as a Java stored procedure to test:

  
  

  Schema: User1

  test of the package;

  public class HelloWorld {}

  public HelloWorld() {

  Super();

  }

  public static String Hello () {}

  Return "HELLO";

  }

  }

  CREATE or REPLACE FUNCTION HELLO RETURN VARCHAR2 AUTHID CURRENT_USER AS LANGUAGE JAVA NAME ' test. HelloWorld.hello () return java.lang.String';

  Grant execute on USER2 HELLO

  Test the Java stored procedure through the PL/SQL function call (in the same schema):

  
  

  Schema: User1

  SET SERVEROUTPUT ON

  DECLARE

  v_Return VARCHAR2 (200);

  BEGIN

  v_Return: = User1. HELLO;

  DBMS_OUTPUT. Put_line ('v_Return =' | v_Return);

  END;

  anonymous block filled

  v_Return = HELLO

  Test the Java stored procedure through the PL/SQL function call in a different pattern:

  
  

  Schema: USER2

  SET SERVEROUTPUT ON

  DECLARE

  v_Return VARCHAR2 (200);

  BEGIN

  v_Return: = User1. HELLO;

  DBMS_OUTPUT. Put_line ('v_Return =' | v_Return);

  END;

  Error report-

  ORA-01031: insufficient privileges

  ORA-06512: at "User1." HELLO', line 1

  ORA-06512: at line 4 level

  01031 00000 - "insufficient privileges".

  * Cause: An attempt was made to change the user name or password

  without the privilege appropriate. This error also occurs if

  trying to install a database without the need for employment

  access privileges.

  When Trusted Oracle is configure in DBMS MAC, this error may occur

  If the user has been granted the privilege necessary for a higher label

  that the connection is active.

  * Action: Ask the database to perform the operation or grant administrator

  the required privileges.

  For users Trusted Oracle get this error, well that granted the

  the privilege that is suitable for the top label, ask the database

  administrator to grant the privilege to the appropriate label.

  You have created the function with AUTHID CURRENT_USER, which means that the function is executed with the rights of the applicant (but not with the rights of the author). This means that the applicant must have grants (directly or through roles) on all used/accessible objects in the service. In your case the user USER2 has not granted with EXECUTE on the class/source Java test. Class HelloWorld, causing the ORA-01031 exception. You create service without AUTHID CURRENT_USER (i.e. with AUTHID DEFINE, which is by default, if you do not have a specific reason to use AUTHID CURRENT_USER) or grant EXECUTE on JAVA test SOURCE. Class HelloWorld to User2.

  Dimitar

• How to share data in the tables ' User_ * ' with another schema

  I want to share the data in the table WHERE USER_SEGMENTS with another schema. If I create a view and grant select on the view, when the other schema queries the view data are identical to themselves querying the SYS.user_segments table directly.
  

  create view sys_user_segments as select * from sys.user_segments;
  grant select on sys_user_segments to A;

  My guess is that the SYS.user_segments table is a view based on the current user.
  
  Is there a way to share such data without creating a copy of the table?
  
  Oracle: 10g
  
  Thank you

  If the ADMINISTRATOR is concerned about B access to DBA_SEGMENTS (or by creating DBA_SEGMENTS views that belongs to a user who has access on top and then grant access to this view of B), it seems pretty crazy allow that kind of database connection.

  If you create a database link belonged to B that connects to A, B is, in substance, given any privilege that has exercises. But it is done in a very, very dark which will no doubt be neglected in the future when someone gets a check. He'll be sitting here to wait that someone (accidentally or intentionally) Decides to exploit the security hole and do something that is causing a problem (by removing all data from a table, grabbing all the sensitive data in a table, etc.). Risks of this almost certainly far, far* far * outweigh the risks of even leaving B to obtain direct access to DBA_SEGMENTS.

  Justin

• grant for dbms_metadata.get_ddl on objects in another schema

  In Oracle 11 g R2, I use dbms_metadata.get_ddl to get the DDL to another schema, but I got an error:
  
  ORA-31603: object not found 'IS_SNMP_DATA' of type TABLE in the schema "TXV.
  
  that grant is necessary for this package to get from another schema ddl?
  I tried with authid current_user (that I found on google), but no result...

  See the following example:

  SQL> create user us_one identified by us1;
  User created.
  
  SQL> grant connect, resource to us_one;
  Grant succeeded.
  
  SQL> create user us_two identified by us2;
  User created.
  
  SQL> grant connect, resource to us_two;
  Grant succeeded.
  
  SQL> conn us_one/us1
  Connected.
  SQL> create table t (id number);
  
  Table created.
  
  SQL> grant select on t to us_two;
  Grant succeeded.
  
  SQL> conn / as sysdba
  Connected.
  
  SQL> grant execute on dbms_metadata to us_two;
  
  Grant succeeded.
  
  SQL> conn us_two/us2
  Connected.
  
  SQL> select dbms_metadata.get_ddl('TABLE','T','US_ONE') from dual;
  ERROR:
  ORA-31603: object "T" of type TABLE not found in schema "US_ONE"
  ORA-06512: at "SYS.DBMS_SYS_ERROR", line 105
  ORA-06512: at "SYS.DBMS_METADATA", line 2806
  ORA-06512: at "SYS.DBMS_METADATA", line 4333
  ORA-06512: at line 1
  
  no rows selected
  
  SQL> conn / as sysdba
  Connected.
  SQL> grant select_catalog_role to us_two;
  
  Grant succeeded.
  
  SQL> conn us_two/us2
  Connected.
  SQL> select dbms_metadata.get_ddl('TABLE','T','US_ONE') from dual;
  
  DBMS_METADATA.GET_DDL('TABLE','T','US_ONE')
  --------------------------------------------------------------------------------
  
    CREATE TABLE "US_ONE"."T"
     (    "ID" NUMBER
     ) PCTFREE 10 PCTUSED 40 INITRA
  
  SQL> 
  

• reading of the objects in another schema schema

  My requirement is to create a schema and grant privileges to read all objects in another main schema, including the functions and procedures. creating a role and assigning it to the schema will read or select the tables, but she will not allow the user to see the description of a function, or a procedure. can you please tell me what are my options. Thank you.

  Hello

  Yes you can GRANT SELECT privilege to allow access to Tables / views, and GRANT EXECUTE privilege on the procedures in another schema.

  You can also CREATE SYNONYM of these Tables in order to hide their location. There is a way to ensure the transparency of the location, otherwise use views or procedures.

  These links can give you a few tracks on the transparency of the situation and manage privileges:

  http://download.Oracle.com/docs/CD/B28359_01/server.111/b28310/ds_admin006.htm

  http://download.Oracle.com/docs/CD/B28359_01/network.111/B28531/authorization.htm#DBSEG004

  Hope this helps.
  Best regards
  Jean Valentine

• Select a type of user account (for example, standard user, restricted user, and other types) on computer XP pro?

  Hello.

  I have a question about how to select the type of user account for each user account.

  I read that if I type 'control userpasswords2' term, it will bring up a window of hidden user accounts.  In this window, select a name of the user account and click property, click on membership group and it will show all the type of account you can purchase (including the standard user, restricted user, the other who has many other types)

  Here is the link I read

  http://www.exnol.com/globally-control-and-change-all-users-passwords-in-Windows

  Let's say my computer is XP pro and it is in the home (not domain joined ) working group. Am I able to set these types of accounts to my user account using 'control userpasswords2' just as I explained above?

  I was wondering because I read in the microsoft help article or somewhere that it indicates that the computer must be on the field to be able to choose the type of account by using this process, I explained, and one account type you can choose where your computer is located in the Working Group's account admin or limited using the control panel then click on accounts of users... but other said it should not be on the field... I got confused.

  I would like to try it myself, but I don't have XP pro computer with me right now, I'd appreciate it really if someone could help me with the answer.

  Hi greenyy,

  If you are the administrator of the machine Windows XP Professional, you can use the command 'control userpasswords2' and access the list of user accounts and change the type of account.

  You need not necessarily be on a domain, however, it may not work for some types of user accounts on a working group.

  A test, you can try to change the type of account for user accounts & check if it works.

  Reference: To change the type of user account 

  Hope the helps of information. Please post back and we do know.

  Concerning
  Joel S
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.

• Change the type of user account is not updated

  I changed my account type standard user principal and account invited to administrative yesterday. Now, I want to change it back but is not allow me to change my primary administrative standard. I can click on it, but it is not updated. What should I do to not having guest account my administrative account?

  Hello

  You receive an error message or code everything by trying to change the type of account?

  Note: Guest account cannot be defined as administrative account. There the option only to turn on or off.

  Reference: Change the type of user account

  http://Windows.Microsoft.com/en-us/Windows-Vista/change-a-users-account-type

  If there is an another account on your computer, and then log on to the administrative account and then try to change the account type.

  Method 1: Activate the default Administrator account, and then try to change the type of account and check if it helps:

  Enable and disable the built-in Administrator account

  http://TechNet.Microsoft.com/en-us/library/dd744293 (WS.10) .aspx

  Method 2: If the above mentioned method does not work then try the system restore:
  http://Windows.Microsoft.com/en-us/Windows-Vista/what-is-system-restore

• How to unlock the c: drive. I have only access to the folder users and subfolders.

  I have only access to the folder users and subfolders.  Everything I tried was "access denied."  I can't get to the root of c:.

  Hi, Scrivmark

  The default C: drive system is not intended to access directly by users and therefore users have restricted access to its root in the premeditated or premeditated damage prevention vital system files. If you are an administrator you can allow full access to your account to all or specific files on drive c (including a root folder) by editing its ' authorization of the lists by right-clicking on a file and choosing "Security."
  If you are not an administrator, you should ask another user whose account is Administrator (or equivalent) privileges to access the interesting files to your account.
  In both cases, you must understand damage system files, you can do.

  This suggestion is the intention that your computer is virus-free.

• Syntax to create the Type of registration at the schema level.

  Hello

  Could you let me know the syntax to create the type of registration at the schema level.

  I tried to help below.

  create or replace

  TYPE "SR_TBL_TYPE" AS THE SR_REC_TYPE TABLE;

  ----------------------------------------------------------------------------------------------------------------

  create or replace

  BODY OF TYPE 'SR_REC_TYPE' AS

  CONSTRUCTOR FUNCTION SR_REC_TYPE RETURN SELF AS RESULT

  IS

  BEGIN

  task_status: = NULL; -jtf_task_statuses_tl. Name % type

  task_type: = NULL; -jtf_task_types_tl. Name % type

  jt_new_res_id: = NULL; --jtf_task_assignments_audit_b.new_resource_id%type

  jt_source_name: = NULL; --jtf_rs_resource_extns.source_name%type

  jt_sch_start_date: = NULL; -VARCHAR2 (50)

  jt_task_number: = NULL; --jtf_tasks_b.task_number%type

  jt_appointment_scheduled_agent: = NULL; --fnd_user.user_name%type

  cs_old_prblm_code: = NULL; --cs_incidents_audit_b.old_problem_code%type

  cs_problem_code: = NULL; --cs_incidents_audit_b.problem_code%type

  qa_scenario_estimate_rec: = qa_scenario_est_type();

  qa_recall_rec: = qa_recall_type();

  RETURN;

  END SR_REC_TYPE;

  PROCEDURE of MEMBER log_sr_rec_values (SELF IN SR_REC_TYPE)

  IS

  BEGIN

  NULL;

  END log_sr_rec_values;

  END;

  Thank you

  Could you let me know the syntax to create the type of registration at the schema level.

  You do not have - record types are PL/SQL. In SQL, you create OBJECT types. It works for me:

  create or replace TYPE AS OBJECT SR_REC_TYPE)
  task_status varchar2(1),--jtf_task_statuses_tl.name%TYPE
  task_type varchar2(1),--jtf_task_types_tl.name%TYPE
  jt_new_res_id varchar2(1),--jtf_task_assignments_audit_b.new_resource_id%TYPE
  jt_source_name varchar2(1),--jtf_rs_resource_extns.source_name%TYPE
  qa_scenario_estimate_rec emp_table_type,
  qa_recall_rec emp_table_type,
  CONSTRUCTOR FUNCTION SR_REC_TYPE RETURN SELF AS RESULT
  )
  /

  create or replace TYPE of BODY SR_REC_TYPE AS
  CONSTRUCTOR FUNCTION SR_REC_TYPE RETURN SELF AS A RESULT
  BEGIN
  Self.task_status: = null;

  
  Self.task_type: = null;
  Self.jt_new_res_id: = null;
  Self.jt_source_name: = null;
  Self.qa_scenario_estimate_rec: = emp_table_type();
  Self.qa_recall_rec: = emp_table_type();
  return;
  END;
  END;
  /

  create or replace TYPE SR_TBL_TYPE AS TABLE OF SR_REC_TYPE;

  See 'Definition and Implementing User-Defined constructors' in the object-relational doc

  http://docs.Oracle.com/CD/B28359_01/AppDev.111/b28371/adobjadv.htm#sthref751

• Insufficient privileges in the creation of MV that he select another schema table

  Hello

  Before asking this question, I checked with similar questions in the forum, but I don't see my situation, or I'd say I'm not clear on the solution.

  I got the privileges CREATE MATERIALIZED VIEW and CREATE ANY MATERIALIZED VIEW and I want to create a MV in my schema, but the MV selects data in another schema, and I had the privilege to choose this table. Here is my code

  Create VIEW MATERIALISEE CPY_GL_HANDS_OFF_DTL

  UPDATE THE BEGINNING WITH THE LARGEST (SYSDATE, TO_DATE ('2013.10.30.23.30.00 ',' YYYY.)) MM DD. HH24.MI. THE NEXT SS SYSDATE')) + (50519 /(24*60*60)) FULL

  ENABLES QUERY REWRITE

  SELECT

  *

  Of

  User_a.GL_HANDS_OFF_DTL@dblink;

  I run it, and I get ORA-01031: insufficient privileges. According to my research so far, the schema of the latter requires the CREATE TABLE privilege, even though she already had RESOURCES (which already includes the CREATE TABLE). Is this true? That's my problem. I only have read access to the table of the dblink, I can't control the privileges of this scheme. Advise please if this is the real problem?

  Thanks and greetings

  acquired through ROLE privileges do NOT apply in the PL/SQL name procedures