Add hours to a date?

Similar Questions

• How to add an hour to function date

  Hai All
  
  
  This is my select statement
  
  
  Select to_number (TO_DATE (TO_CHAR(Intime,'DD-MON-YYYY') |)) » '||
  To_char (0815, '0000'), "MON-DD-YYYY HH24") - respondent
  ) * 24 * 60 dail_Att;
  
  
  I had another table called Train_mast, the fields are
  
  
  TRAINCODE VARCHAR2 (4)
  TRAINNO VARCHAR2 (10)
  TRAIN VARCHAR2 (30)
  DATE OF V_DATE
  MAJ VARCHAR2 (2)
  LATE_HRS VARCHAR2 (4)
  REMARKS VARCHAR2 (10)
  REFNO VARCHAR2 (10)
  UNITID VARCHAR2 (2)
  
  
  Here is when the train is late, I entered the late hours
  
  For example, if the train is late 30 so I need to add with the start time 0815 + 30 0845 IE and I need to subtract from the respondent
  
  
  How can I do this
  
  Concerning
  
  Srikkanth.M

  Hi Srikkanth,

  I have no watch in your query, but in general what I feel, it's that you want to add the number of minutes to a date.

  To add minutes to a date, you can do all of this-

  SYSDATE + 30 / (24 * 60) - this will add 30 minutes at present.
  SYSDATE + 15 / (24 * 60) - this will add 15 minutes at present.

  I hope this helps.

  Best regards

  Arif Khadas

• How to add hours, Minutes in table

  How to add hours, Minutes to the table, I get an error time between 1 and 12 below is my code
  
  PACTUALOUTTME: = TO_DATE (' 17:00 "," HH: MI PM ');
  PROUNDEDINTIME: = TO_DATE (' 09:05 ',' HH: MI AM');
  PROUNDEDOUTTIME: = TO_DATE (' 16:12 ',' HH: MI PM ');
  PHRSWORKED: = TO_DATE('08:05','HH:MI');
  * PLATE: = TO_DATE('00:12','HH:MI'); **
  * PLEFTEARLY: = TO_DATE('00:05','HH:MI'); **
  POT: = TO_DATE('01:00','HH:MI');
  PCOMMENTS: = "left early."
  PREMARKS: = 'Permission ';
  PCREATEDBY: = '101';
  
  I want to insert hours with the minutes and the minutes, I used the DATE data type for date and time columns preceding
  
  I think that the highlight is making the error any help please

  Use HH24 during the day between 0 and 24 hours.
  Use HH for hour of day between 1 and 12.

  PLATE: = TO_DATE('00:12','HH24:MI');
  PLEFTEARLY: = TO_DATE('00:05','HH24:MI');

  Good luck

  Published by: user9251649 on 26.09.2012 00:25

• Cannot add hours in time correctly...

  I am trying to add hours to sysdate when it is formatted as HH24MMSS. I tried the following and not had any luck:
  

  select to_char(sysdate ,'HH24MMSS') + 7/24 from dual;

  Desired output:
  

  -- If select to_char(sysdate ,'HH24MMSS') from dual = 111026
  -- Then, I would want
  181026

  Can someone please advise here

  Hello

  Call TO_CHAR Finally, after all the manipulations of the date made:

  SELECT       TO_CHAR ( SYSDATE + (7 / 24)
                , 'HH24MISS'
              )     AS formatted_date
  FROM       dual;
  

  TO_CHAR (sysdate, 'HH24MMSS') + 7/24 does not work for the same reason that
  '112026' + 7/24 does not work: you cannot add a string to a number. It's okay if the string is the result of a function (and TO_CHAR, as the name suggests, returns a string) or literal; You cannot use the operator on a string (in Oracle).

• Calculate business hours between 2 dates with negative numbers

  Hi all

  I use a function to calculate the difference between 2 dates schedules. The function was taken and adapted from this thread:

  Calculate business hours between two dates in a cursor

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,
                                   p_end_date DATE
                                  )
    RETURN NUMBER
    IS
        v_return NUMBER;
    BEGIN
        with t as (
                   select  case level
                             when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                             else trunc(p_start_date) + level - 15 / 24
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(p_end_date,trunc(p_end_date) + 20 / 24)
                             else trunc(p_start_date) + level - 4 / 24
                           end end_dt
                     from  dual
                     connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                  )
        select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
        RETURN v_return;
    END;
    /

  I am running into an issue that when the p_end_date is before the p_start_date value the function returns the full time between the dates without regard for business hours. if the end_date is before the start date I get the expected result i.e. difference between the dates in business hours.

  Using example dates of start 19th October 2012 13:00:00 and end 22nd october 2012 13:21:00 the business minutes are 681. However if i reverse the dates I get -4341.

  


  Correct labour code is the following, I've annotated so that he could help someone else looking for a solution like this:

  CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,  --these are the 2 dates passed into the function
                                   p_end_date DATE     --these are the 2 dates passed into the function
)
RETURN NUMBER
IS
v_return NUMBER;

          l_start  DATE;

          l_end    DATE;

          l_factor NUMBER;
    BEGIN

          IF p_start_date <= p_end_date THEN            --this IF section checks which of the 2 dates is the greatest


             l_start  := p_start_date;                  -- and then assigns the earliest date to p_start_date


             l_end    := p_end_date;

             l_factor := 1;

          ELSE   -- swap the dates around, and multiply the result by -1

             l_start  := p_end_date;

             l_end    := p_start_date;

             l_factor := -1;

          END IF;


          with t as (
                   select  case level
                             when 1 then greatest(l_start,trunc(l_start) + 9 / 24)  -- this sets the start of working hours
                             else trunc(l_start) + level - 15 / 24  --if the start time is adjusted this value must also be adjusted
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(l_end,trunc(l_end) + 20 / 24)  -- this sets the end of working hours
                             else trunc(l_start) + level - 4 / 24  -- if the end time is adjusted this value must also be adjusted
                           end end_dt
                     from  dual
                     connect by level <= trunc(l_end) - trunc(l_start) + 1
                  )
        select  sum(end_dt - start_dt) * 24 * 60 work_minutes  -- this subtracts the 2 dates and then multiplies by hours and minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- this exclude weekends
        RETURN v_return * l_factor;  -- this gives the negative or positive results so you can see if it was completed before or after the required date.
    END;
    /

• Add months to ore.date

  Is it possible to add months on ore.date without ore.pull?

  Example:

  Version 1.4 of ore

  > DATE <-ore.push (seq (also. Date("1999/1/1"), by = "3 month", length = 2)) [2]

  > DATE

  [1] "1999-04-01.

  > class (DATE)

  [1] "ore.date".

  attr(,"package")

  [1] "OREbase".

  >

  > NEW_DATE <-seq (DATE = '3 month', length = 2)

  Error in seq.int (r1$ Lun, by =, length.out = length.out):

  "provenance" should be finished

  Currently the ore.datetime feature to perform aggregates and summaries, comparisons, extract values and constraints.

  In order to modify the datetime object, you can shoot locally using ore.pull:

  DATE<- ore.push(seq(as.date("1999/1/1"),="" by="3 months" ,="" length="">

  Date<->

  new_date<- seq(mydate,="" by="3 months" ,="" length="">

  NEW_DATE<->

  Class (NEW_DATE)

  R > NEW_DATE

  [1] "1999-04-01" "1999-07-01".

  R > class (NEW_DATE)

  [1] "ore.date".

  attr(,"package")

  [1] "OREbase".

  I'll add an improvement to enable this feature for a future version of ore.

  Sherry

• 2 writers can add to the same data staged?

  
  Hello

  How can we get 2 entries to write on the same data staged without data loss? I need to write the rejected records to a staging of data in 2 different processes before exporting.

  Kind regards

  Ravi

  No, you can not do this. Ecrire write to different sets of data on stage, then use a process with the merge data stream to bring together them.

  Otherwise, use two different sets of data staged or data interfaces and add to export. Data interfaces means that you never staged. The staged data: you can choose whether or not to step in the configuration of the task (or run profile).

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben

• Problems while extracting the hours of the Date field

  Hi guys,.
  
  We hope that you do well.
  
  I am facing some problems during extraction of the hours of the date field. Here is an example of my orders table:-
  
  Select * from orders;
  
  Arrival time of Order_NO product name
  1 computer Office November 20, 10 10:10
  2 November 21, 10 17:26:34 portable
  3 22 January 11 printer 08:10
  
  Earlier, it is stated that the daily number of orders take place in the roll of the order, I used to write a query
  
  arrival_time > = trunc ((sysdate-1), 'DD')
  and arrival_time < trunc ((sysdate), 'DD')
  
  The above query gives me yesterday how many orders have been been held.
  
  Now I have the new requirement to report on every 4 hours the number of orders will be held. For example if the current time is 08:00 IST then the query must extraction from 04:00 until 08:00 how many orders took place. The report will take place at 12:00 IST which will give me an order took place from 08:00 until 12:00.
  
  The report will be run every 4 hours per day and generate report of orders taken place for the past 4 hours. I have a programmer who will run this query every hour, but how to understand to get the order at the request of details who arrived for the past 4 hours. I'm not able to do this using trunc.
  
  Can you please help me how to make this happen. I checked "Extract" also, but I am not convinced.
  
  Help, please.
  
  Thanks in advance
  Aalami

  try something like

  with testdata as (
    select sysdate - level/24 t from dual
    connect by level <11
  )
  
  select
    to_char(sysdate, 'DD-MM-YYYY HH24:MI:SS') s
  , to_char(t, 'DD-MM-YYYY HH24:MI:SS') t from testdata
  where
  t >= trunc(sysdate, 'HH') - numtodsinterval(4, 'HOUR')
  
  S     T
  19-06-2012 16:08:21     19-06-2012 15:08:21
  19-06-2012 16:08:21     19-06-2012 14:08:21
  19-06-2012 16:08:21     19-06-2012 13:08:21
  19-06-2012 16:08:21     19-06-2012 12:08:21
  

  trunc (, 'HH') truncates the minutes and the seconds of the date.
  Extract the hour only works on timestamps
  concerning

  Published by: chris227 on 19.06.2012 14:13

• How can I add days to a Date value in a Script time?

  How can I add days to a Date value in a Script (XPATH) time?

  XPATH:

  Add Date:

  xs:dateTime($yourCurrentDateVar) + xs:dayTimeDuration($yourDuration)
  

  Difference in date:

  move "fn:days-from-duration(xs:dayTimeDuration(xs:date($yourCurrentDateVar) - xs:date($yourPrevDateVar)))" to $diff;
  

  You did not mention the version of the Framework, you can take advantage of the Business Service (BS) to perform Date calculations, for example, for FW2.2.x, you can use BS: C1-DateMath with such options as the 'Resistance' to add to the Date, "DIFF" for Date-Diff and FW4.x, you can use BS: F1-DateMath with options such as "F1AD" to add to the Date etc.

  Find out more about XPATH herefunction.

• Count the number of hours between the dates off holiday/weekend

  Hi all
  
  I've not worked with dates and was recently asked to create a report where I am looking for the number of hours between two dates only count business days.
  
  So for example I have given as follows
  
  Created on 2011-03-30 15:00
  Treaty of 2011-03-30 15:03:46
  Filled 2011-04-01 17:25:02
  Posted 2011-04-01 17:45
  
  For a total of looking for the CREATION and dates
  
  50 hours and 45 minutes
  
  IM also trying to exclude weekends and holidays, I read around and was able to also find an array of dates where I main date, the HOLIDAY_IND column, and the column WEEKDAY_IND
  
  If the calendar table I have looks like
  
  CALENDER_DATE HOLIDAY_IND WEEKDAY_IND
  2011-03-31 YY
  2011-04-01 N Y
  2011-04-02 N N
  
  IM really very puzzled to know where to start
  
  I thought I'd try to write with PL/SQL, but I don't have access of the user to create procedures/functions, so looks like right up to SQL
  
  Any help is appreciated!

  Hello

  Depeneding on your data and your needs, you can do something like this:

  SELECT     created_DATE,
  ,     mailed_date
  ,     24 * ( (mailed_date - created_date)
            - (
              SELECT  COUNT (*)
              FROM        table_o_dates
              WHERE    main_date > created_date
              AND        main_date < TRUNC (mailed_date)
              AND        (   holiday_ind = 'Y'
                       OR  weekday_ind = 'N'
                    )
            )
             )               AS hours_between
  FROM     table_x
  ;
  

  I hope that answers your question.
  If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all tables and also post the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always tell what version of Oracle you are using.

  What do you do if created_date or mailed_date is not a working day? Examples in you data and results.

• Add days to a date is to be indented by year.

  Hello
  
  I have the problem on Oracle 10 g. I have run the following statement that adds 1 to a date, but, unless I have format, the date is back with a year less than expected.
  

  SQL> select effective_date, (effective_date + interval '1' year(1)) as addyear, add_months(to_date(to_char(effective_date, 'MM/DD/YYYY HH24:MI:SS'), 'MM/DD/YYYY HH24:MI:SS'), 12) as addyearformat
     from price_change
          where
          price_change_id = '794328'   ;
  
  EFFECTIVE_DATE  ADDYEAR         ADDYEARFORMAT
  --------------- --------------- ---------------
  28-SEP-09       28-SEP-08       28-SEP-10

  Has anyone ever seen anything like that?
  
  Effective_date is of type date and has data in the format "MM/DD/YYYY HH24:MI:SS. I think it's something with the format, perhaps something to do with the zone - not sure. If I just insert a value into the table with the format ' MM/DD/YYYY HH24:MI:SS' I don't have this problem. I don't know how the date could have been modified to do that, but I know not to go through a time zone function before be inserted in this table, but I don't know if that is the cause of the problem.
  
  Don't know if it's important but nls_database_parameters...
  VALUE OF THE PARAMETER
  NLS_DATE_FORMAT dd-MON-rr
  NLS_TIMESTAMP_FORMAT-DD-MON-RR HH.MI. SSXFF AM
  NLS_TIMESTAMP_TZ_FORMAT DD-MON-RR HH.MI. SSXFF AM TZR
  NLS_TIME_FORMAT HH.MI. SSXFF AM
  NLS_TIME_TZ_FORMAT HH.MI. SSXFF AM TZR
  
  
  Thanks for any help in advance.
  
  Published by: amcgator on October 15, 2010 11:52

  amcgator wrote:
  In fact, this would explain why, if I do not pass the end of the year mark (IE if I just add 30 days), everything looks OK. How in the world that is possible, or how can I confirm this?

  Did you read my response? Question:

  select  to_char(effective_date,'mm/dd/yyyy bc')
    from  price_change
    where price_change_id = '794328'
  / 
  

  If you see bc - it's confirmed :).

  SY.

• How can I add multiple system restore dates?

  I want to do a system restore. There are several dates of restoration listed, but I need to pick a date more back that all listed. How can I do this? It seems to me that I used to be able to click on a date on the calendar. Thank you

  The number of restore points is limited by the amount of storage that are attributed to them.

  You can increase this space by typing create a restore point in the start search box and press ENTER.

  Then select your C: drive in the list and select Configure.

  Move the slider to add more storage space.

  There is no calendar in Windows 7 for restore points.

• lose 3 hours on the date/time stamp

  I have a hp Pavilion slimline desktop computer. Several times a month I'll lose 3 hours on time. No more and no less. I'll fix this issue (on change date and time settings). I have other things on the same outlet including a digital clock is not able to bound. I have this on a pavilion notebook pc in another part of the House, same thing happen 3 hours no not on the same day. The two units are almost 1 years. Any help?

  Bigfoot1950, when requesting help, you must always include the brand / model of the computer or the monitor. This information is necessary for us to review the specifications for them.

  In addition, they change the time zones?  It seems that the time zone differs from the Eastern Pacific or something similar.