Additional logging on unique indexes
HelloI enabled logging on a unique index on an extra table...
Table emp (id number, name varchar2 (20), varchar2 (20)) of the grid;
create an index unique emp_id on emp (id, name);
change the emp table add extra newspaper group emp_supp (id, name);
Now if I update the column in the grid for a record will it produce data of additional journal for the unique index columns?
Hello
Yes, he does.
refer to the doc: http://download.oracle.com/docs/cd/B13789_01/server.101/b10823/create_ls.htm
-Pavan Kumar N
Tags: Database
Similar Questions
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When I change a column is a primary key the associated non-unique index to become unique?
So basically I already tried this and it shows me that the associated index is not unique.
create table employees2 in select * from employees;
create index emp_idx on employees2 (employee_id);
ALTER employees2 table add primary key (employe_id) using index emp_idx;
Select * from user_indexes where index-name = "EMP_IDX";
I was wondering if I right assuming that when you change a column to a primary key or unique while using a given index that does not have the respective index become unique.
The textbooks I use are sometimes a little hard to understand because of the wording, also, I want to just ask someone with a little more experience than me.
Thank you.
your test did give the correct answer: the index is not unique if it serves to bear a unique or primary key constraint. Indeed, it is one of the benefits of the use of no unique indexes in support of UK/PK constraints (since it allows to set the unusable index before to make bulk loads; and, of course, they have also some disadvantages - for example, they need an additional logical reading to reach a line). Richard Foote explains the details in https://richardfoote.wordpress.com/2008/06/04/primary-keys-and-non-unique-indexes-whats-really-happening/ (and other items).
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How to find the unique index to break the record?
Hello
When I do an UPDATE on a table how can I accumulate documents violates a unique index on the table? Is there something like "EXCEPTIONS IN" when using ALTER TABLE MODIFY CONSTRAINT... ENABLE VALIDATE EXCEPTIONS IN...?
Oracle DB 10g
Look in the logging of DML errors
ORACLE-BASE - DML Oracle 10 g Release 2 of the database connection error
-
When we use a unique index for PK?
I was reading this part of the manual oracle:
http://docs.Oracle.com/CD/B28359_01/server.111/b28310/indexes003.htm#ADMIN11727
I got confused because I was trying to research why sometimes, we want to create a primary key by using a unique index.
CREATE A UNIQUE MYTABLE_PK ON MYTABLE INDEX
(START_DT, ANNUAL)
LOGGING
TABLESPACE TBS_INDEX01
NOPARALLEL;
ALTER TABLE MYTABLE ADD)
CONSTRAINT MYTABLE_PK
KEY ELEMENTARY SCHOOL
(START_DT, ANNUAL)
WITH THE HELP OF INDEX MYTABLE_PK);
And sometimes we simply create the primary key without using a unique index.
ALTER TABLE MYTABLE ADD)
CONSTRAINT PK_MYTABLE
KEY ELEMENTARY SCHOOL
(START_DT, ANNUAL)
THE HELP INDEX);
When we use a unique index for PK?
James, you have returned to the question thread.
I apologize: I'm sorry, user8875620, your son has been hijacked. A UK or PK constraint needs an index. You can create a (unique or non-unique) explicitly, or you can let Uncle Oracle create it implicitly when you define the constraint.
-
a unique index or unique constraint on the issue of view Matt
10.2.0.3
I have an OLTP table and a matte view to fast refresh of the table in the warehouse. I have unique indexes on the matte view just as I have on the OLTP table. Of course, it's a bad idea because the updating Oracle on mattress views mechanism does not apply to the dml in the same order that it occurred on the side of OLTP? Should I get rid of all the unique indexes on views mattress in my warehouse and create regular index because of their unique nature will just happen because the side OLTP has a unique index? What will be the impact on the performance of the queries? Here's the alert log...
Journal of owp2 alerts
=======================
ORA-12012: error on auto work 1595
ORA-12008: error path refresh materialized view
ORA-00001: unique constraint (SMS_AR. IU02_ROUTE_REF_MRKR) violated
ORA-06512: at "SYS." DBMS_SNAPSHOT", line 510
ORA-06512: at line 1
ORA-00001: unique constraint (SMS_AR. IU02_ROUTE_REF_MRKR) violated
ORA-00610: internal error Code
ORA-12012: error on auto work 260282
ORA-30439: updating of the ' ORA-30439: updating of the 'SMS_AR MV_ROUTE_REF_MRKR' failed due to the ORA-12008: error in the path of refresh materialized view
ORA-00001: unique constraint (SMS_AR. IU02_ROUTE_REF_MRKR) violated
ORA-06512: at "SYS." DBMS_SNAPSHOT", line 2254
ORA-06512: at "SYS." DBMS_SNAPSHOT", line 2460
ORA-06512: at "SYS." DBMS_SNAPSHOT", line 2429
ORA-06512: at "SMS_AR.PA_PIES_WAREHOUSE", line 44
ORA-06512: at line 2
ORA-20000: index 'SMS_AR '. "' I01_MV_PIES_INV_REFMKR ' or the partition of this index is unusableMark Reichman wrote:
I think that this problem is resolved... Unless someone has something else to add. I have not tried yet... But it seems to be valid. I did a test and a unique constraint can be delayed in fact creates a non-unique index. So I need to remove my unique index on my matte view and create unique constraints can be delayed.Or...
forget the unqiue part and simply change the indexes not unique because the main table has a unique index and guarantees uniqueness for me and the matte view will simply copy whats in the main table.
Mark,
the solution seems reasonable. Just a note: If you use a "reportable" unique constraint Oracle ignores any attempt to perform a direct-path insert of access and still stations conventional insert generating undo and many more again.
As long as you do only a 'rapid' refresh, it should not matter, but in case you deal with refreshs full large MVs, this could make a difference when running not atomic refreshs (who can take advantage of the direct-path inserts / DML etc. at the same time)...
Then you can consider using only non-unique index rather than the constraint may be delayed if performance can matter and given the fact that you should never see duplicates in the MV because of the constraint on the base table.
Furthermore, you can use a non-unique index to apply a not reportable unique/primary key constraint as well, it is supported. You just need to create the index yourself before you set the constraint or using explicit syntax "CREATE INDEX" of the constraint clause.
For more information, I wrote a note on this problem "may be deferred" some time ago:
http://Oracle-Randolf.blogspot.com/2008/07/Deferrable-constraints-and-direct-path.html
Kind regards
RandolfOracle related blog stuff:
http://Oracle-Randolf.blogspot.com/SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676 /.
http://sourceforge.NET/projects/SQLT-pp/ -
Creation of a PK via Create Unique Index key more OR through PK restrict only
What is "significance" of the following difference: -.
Some PK indexes in the database that I deal with are scripted by creating a Unique index first, then adding the PK constraint with syntax "using the index.
Others simply create the PK using the addition of the primary key constraint syntax.
We're much better than the other or where in the documentation would review it? I can't find that he discusses more probably looking in the wrong book.
Thanks in advance. BillHi Bill,
If you create a unique index first then add PK constraint or create a PK constraint directly, one and the same.
Say, there is a unique index on the column 'a' and now you want to apply PK constraint on the same column, instead of dropping the index and re-create the same, you can use the existing one. It's ok if the amount of data is less, but for a huge amount of data, it is a killer.
Here's a little comparison of the two cases:
SQL> drop table t purge; Table dropped. SQL> create table t ( a number); Table created. SQL> create unique index t_idx on t(a); Index created. SQL> alter table t add constraint t_pk primary key (a) using index t_idx; Table altered. SQL> select uniqueness from user_indexes where index_name = 'T_IDX'; UNIQUENES --------- UNIQUE SQL> select constraint_name, constraint_type, index_name from user_constraints where table_name = 'T'; CONSTRAINT_NAME C INDEX_NAME ------------------------------ - ------------------------------ T_PK P T_IDX SQL> SQL> SQL> SQL> SQL> SQL> SQL> SQL> SQL> SQL> SQL> drop table t purge; Table dropped. SQL> create table t ( a number); Table created. SQL> alter table t add constraint t_pk primary key (a); Table altered. SQL> select uniqueness from user_indexes where index_name = 'T_PK'; UNIQUENES --------- UNIQUE SQL> select constraint_name, constraint_type, index_name from user_constraints where table_name = 'T'; CONSTRAINT_NAME C INDEX_NAME ------------------------------ - ------------------------------ T_PK P T_PK SQL>
I hope that the answer was clear.
Concerning
Asif Momen
http://momendba.blogspot.com -
What is happening to all 5 of my computers, all Windows 7 since I used Windows Update this AM. The interesting thing is that my Wifi network in my house does not require a "additional log in" and the internet was available. So, the "Additional log in" notification, which appears continually, even after opening a web page, is simply nothing more boring.
Disabling Open DNS seems to fix the problem, but I don't want to turn it off. Looking for an answer to this problem, I found a registry change that solved this problem for someone else. Changing the registry Disenabled the "Active sensor", which is the value of 'Enable Active Probe' fell 1-0. I could do that except that I use Open DNS crypt, who encrypts all communications between the computer and the open DNS, a Wi - Fi security feature servers, and since I use these laptops on Wifi networks in places like McDonalds and Starbucks, I think I need notification Active Probe actually connect to their networks.
Any ideas or solutions?
Its for this reason
Open regedit and navigate as follows:
HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\services\NlaSvc\Parameters\Internet
Double-click on EnableActiveProbing
Change the value to 0. This is another site (what follows is OpenDNS). They are aware of this
In order to solve this problem, please log in to the dashboard and select settings. After that, select your network and choose "Customize" in the left menu. You will be taken to a page that you will allow you to toggle enabled "NX domain redirect. Please disable this option.
Then, clear your DNS resolution cache and the cache of the web browser on each device to ensure that your new configuration of DNS settings take effect immediately. Instructions to clear your cache of DNS resolution can be found here: http://www.opendns.com/support/article/68 and instructions to clear the cache of your web browser can be found here: http://www.opendns.com/support/article/67.
KB2750841 is the cause of it
-
What is the difference between primary key and unique indexes with forced not null?
Primary key is = unique index + not null?
The short answer is Yes.
However, even if the primary key, applying both uniquness and not null, there is a notion of "special".
You can only have one primary key in tables, but you can have multiple unique indexes and constraints not null.
See: https://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:8743855576462
-
How to find duplicate keys found when error ORA-01452: cannot CREATE a UNIQUE INDEX.
Hi gurus,
I fall for this stupid error
"cannot CREATE a UNIQUE INDEX; duplicate keys found.
It is that the Unique Index key is composed of multiple columns
CREATE A UNIQUE KEY001AUTORISATIONS_APPORT ON TFT_AUTORISATIONS_APPORT INDEX
(AUT_APPORTEUR, AUT_AGENCE, AUT_PRODUIT, AUT_OPTION, AUT_TARIF, AUT_DATE_AUTORISATION)
TABLESPACE KEYS_TFT NOPARALLEL NOLOGGING
Now,.
My question is, how to find duplicates keys blocking Index creation?
Thanks if you can help
Run this query to display the list of the duplicates already existing.
Select AUT_APPORTEUR, AUT_AGENCE, AUT_PRODUIT, AUT_OPTION, AUT_TARIF, AUT_DATE_AUTORISATION, count (1) as cnt
of TFT_AUTORISATIONS_APPORT
Group
AUT_APPORTEUR, AUT_AGENCE, AUT_PRODUIT, AUT_OPTION, AUT_TARIF, AUT_DATE_AUTORISATION
view count (1) > 1
Concerning
NJ
-
Duplicate display of unique indexes on diagram - how to remove?
Hey people,
A little new for the Modeler and I have a problem with a table I did where a unique index appears twice on my diagram. I can't understand how to remove it.
Any ideas?
Thanks for the help!
Eric
In fact you need to look at the bitty little next to each icon and you will see that they are different. What you have is a unique index and a unique key constraint. Different objects in the database named but identical by the Data Modeler (which is automatically generated index when you declared the constraint). If you go to the properties of the table and click on the index node you will see. Now, click on the single key node and you will see the same name. Right-click on the table in the diagram and choose the DOF preview. After the create table code, you should see a create index command and create a unique alter constraint table.
Why do you need both - constraint and different index information give the optimizer. You can do without one or the other - maybe. Tom Kyte wrote a note on this subject a while back on AskTom. If you're really curious, go here (I don't remember the details).
-
HelloI have a unique index associated with no doubt. Unique and not unique indexes are used B tree architecture. But I want to know if I create a non-unique index on a column that contains unique data.
When I query this table using this column, it scans each sheet or times found that value it scan stops and give us the result?
00125 wrote:
In a non-unique index, scans all the leaves... so what's the difference between full table scan and index ull. I went through a few articles they mentioned that a non-unique index to check with rowid. How she treated? I have clear knowledge in it.
Please help me with this.
Thanks in advance
If you go through architecture index B-tree you could easily understand how indexing works. The picture here shows how a look of column datatype NUMBER indexed as / stored internally. You can imagine that your indexed column TST_COLA this will look like in the internal process. In the B-tree indexes, you have 3 main structures 1. 2 root. Branch 3. Leaves and the database retrieves lines by browsing through the root of index-> branch-> leaves. If the photo if we wanted to retrieve the row whose value indexed column = 25. First data goes to the root and finds that plugs is set to 25, then he Stoops to this particular branch of find what block sheet retains the value 25. More far away after finding the leaves block then goes to this block of sheets and research the special value of 25.
If the index is UNIQUE, the database knows that there must be only one value, where it performs INDEX UNIQUE SCAN. If the index is NOT UNIQUE it should check all values in this block of leaves to find who all are 25 - in this case INDEX RANGE SCAN is done - as you must check not only value, but all values in this block of sheets - given that the values are not unique. As you can see it that the sheet block contains the long side of the value of the column ROWID, using this database rowid, then goes to the table to retrieve that particular line.
Full table scan is a method of access where the database just to access the table directly (bypassing index structure) and analyze the ENTIRE table to satisfy the request.
-
Transform a no Unique Index in a single index
Hello
Version: 11.2.0.4.0 Enterprise Edition
We got a non-unique Index for a primary key constraint. I would like to change that in a unique index. I know that you can not change the index to change. Is the only way to disable the primary key, delete the index and re-enable the constraint or is there a better solution? It is a 24/7 platform.
sql_colder
Windows service exist for a reason.
You can also create clues online in an operational database.
There is no other method outside the use of DBMS_REDEFINITION.
Think about it: what is the business case to change the index?
-----------
Sybrand Bakker
Senior Oracle DBA
-
Unique index constraint Vs Unique
Dear all,
I just want to understand what is the difference between a Unique Index and uniqueness constraint
I can create indexes like that, it duplicates will be blocked
create table abhi_1 ( l_number number ) CREATE UNIQUE INDEX abhi_1_UK ON abhi_1 (l_number);
I can also use below syntax for duplicates blocking (index will be created internally)
create table abhi_1 ( l_number number, constraint abhi_1_UK UNIQUE (L_number) )
Please specify,
Hello
I would use a unique constraint. Allows you to create foreign key constraints referencing the single column.
As you said, when you create a unique constraint, Oracle automatically creates an index for it if necessary. You can explicitly set the attributes of that index (for example, the name and tablespace) If you wish.
-
Hello
I use OLIVIER 7.9.6.4
and EBS Instance ORA12.1.3
I get below error when I tried to run full load for the DAC order management
CREATE A UNIQUE INDEX
W_PROD_CAT_DH_U1
WE
W_PROD_CAT_DH
(
INTEGRATION_ID Asc
DATASOURCE_NUM_ID Asc
EFFECTIVE_FROM_DT Asc
)
NOLOGGING
ORA-01452: cannot CREATE a UNIQUE INDEX. duplicate keys found
Among the responsible 1,45,423 records 24 140 are duplicated.
Apart from the removal of duplicates of records in DB is there any changes that I can do in Informatica mapping to limit duplicate records to be loaded into DB.
Any question even face to face only one?
Kind regards
NN.
Hello
For those who have faced the question above.
Here is the Solution.
- Informatica PowerCenter Designer, place you in the SIL_Vert\Mappings folder and open the "SIL_ProductCategoryDimension_Hierarchy" mapping in the mapping Designer tool.
- Change the qualifier Source SQ_W_PRODCAT_DS to display the dialog box change Transformations and switch to the Properties tab.
- Select the name of the attribute processing Sql Query and edit the substitution of sql to change the status of outer join left in w_product_d as:
- DATABASE W_PRODCAT_DS
- LEFT OUTER JOIN W_PRODUCT_D PROD ON
- BASE. PROD_ID = PROD. INTEGRATION_ID AND PROD. CURRENT_FLG = 'Y '.
- Save the details and archive.
The changes described above helped me load management command successfully.
Kind regards
NN.
-
Hello
indexes and constraints are in different namespaces, so it should be possible to give them the same name.
In the following case that apparently does not work:
create unique index orders_year_show_uq on orders (year desc, show_orders asc); alter table orders add constraint orders_year_show_uq unique (year, show_order);
When I run these statement, I get a "SQL Error: ORA-00955: name is already used by an existing object". ""
If I clean and I execute the same instructions as above with the only difference on the 2 line, using "asc year" instead of "year desc":
on orders (year asc, show_orders asc);
then it success.
I can't explain it, you have an idea?
Thanks in advance.
Kind regards
Giovanni
First of all, you have show_orders in index and show_order in the constraint. I'll assume that it's a typo. Second, when you create constraint without index enhance the specification Oracle seeks indexes existing on the same set of columns in ascending order. If this index does not exist (and it's your case, since one of your columns to index is in descending order), Oracle tries to create one with the same name as the constraint. That's why you get ORA-00955: name is already used by an existing object. In general, you can specify explicitly the index name to force the Oracle by using the existing index. But it will not help you. If you issue
ALTER table orders add unique constraint (year, show_orders) orders_year_show_uq using index orders_year_show_uq;
You will get the ORA-14196: specified index cannot be used to apply the constraint.
In any case, Oracle does not support using index DESC for PK/UK.
SY.
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