ALL_CONSTRAINTS

Similar Questions

• Need to retrieve the names of columns with PK

  Hi all

  guys I need to get two columns (PK information and secondly with the column name) for the table. I see that's not so easy with Oracle ;(

  I have this for now:

  SELECT all_tab_cols.column_name,user_constraints.constraint_type
  FROM   all_tab_cols, user_cons_columns, user_constraints,user_ind_columns, user_indexes
   WHERE  all_tab_cols.column_name = user_cons_columns.column_name (+)
     AND  all_tab_cols.table_name = user_cons_columns.table_name (+)
     AND  user_cons_columns.constraint_name = user_constraints.constraint_name (+)
     AND  user_constraints.constraint_type (+) = 'P'
     AND  user_ind_columns.column_name (+) = all_tab_cols.column_name
     AND  user_ind_columns.table_name (+) = all_tab_cols.table_name
     AND  user_indexes.uniqueness (+) = 'UNIQUE'
     AND  user_indexes.index_name (+) = user_ind_columns.index_name
     AND  all_tab_cols.table_name = 'MYTABLE' 
  

  but, if KP is then take result duplicate me lines and there is not a simpler way? just need to list all columns of the table with information about the PK

  SELECT acc.column_name,
    ac.constraint_name
  FROM all_constraints ac,
    all_cons_columns acc
  WHERE ac.owner        =acc.owner
  AND ac.constraint_name=acc.constraint_name
  AND ac.table_name     =acc.table_name
  AND ac.constraint_type='P'
  AND ac.table_name     = 'MY_TABLE'
  UNION
  SELECT column_name,NULL FROM all_tab_columns WHERE table_name='MY_TABLE';
  

• SqlDevelopper Extension (V4.1.1)

  Hello

  I'm having a problem, define an extension to V4.1.1 SqlDeveloper: I want to show the chain of tables according to e table of data, here is my 'xml code:

  elements <>

  < item = "Editor" node vertical = "TableNode" type = "true" >

  < title > <! [CDATA [string FK Down]] > < / title >

  < query >

  < sql > <! [CDATA [with LIST as (select a.CONSTRAINT_NAME, a.TABLE_NAME, B.TABLE_NAME as R_TABLE_NAME

  of ALL_CONSTRAINTS a left join B on a.R_CONSTRAINT_NAME = B.CONSTRAINT_NAME ALL_CONSTRAINTS

  where a.OWNER =: proprietaire_objet

  and a.CONSTRAINT_TYPE = 'R')

  Select: OBJECT_NAME of the DOUBLE

  Union of all the

  Select rpad (' ', (level) * 5) | a.R_TABLE_NAME | '(' || CONSTRAINT_NAME | ')'

  the a list

  connect nocycle TABLE_NAME = prior R_TABLE_NAME

  [[Start by a.TABLE_NAME =: OBJECT_NAME]] > < / sql >

  < / query >

  < / point >

  < / object >

  The query gives the result that I wait, but once that I use it as an extension, the rows returned are duplicated 2 or 3 times. Try it with a table with a single CF.

  What I am doing wrong? It is very disturbing!

  Thanks in advance for your answers

  Philippe

  PS: Sorry for my bad English

  Hello

  Thanks for your reply,

  I want to display the foreign key chain from a table selected in the browser. Works very well just query and give me exactly what I want, but once defined in an XML file, so it appears as an extension, I get all the duplicate lines.

  Starting from a datasheet, I get (for a table TABLE_A with only FK on a TABLE_C without any FK table):

  TABLE_A

  TABLE_C

  Is what I get in the browser when I click on the table is:

  TABLE_A

  TABLE_C

  TABLE_C

  TABLE_C

  Best regards

  Philippe

• Primary key and foreign key between the different schemas

  Hi all;

  SCOTT user have a 'rank' of table-> it contains the primary key-> users tablespace

  The U1 user have a 'emp' table-> it contains the foreign key-> test tablespace

  U1 > select constraint_name, constraint_type, r_owner, owner, r_constraint_name of all_constraints where table_name = 'EMP ';

  OWNER CONSTRAINT_NAME C R_OWNER R_CONSTRAINT_NAME

  ------------ ------------------------------ - -------------------------- ----------------------- -----------------------------------------------------

  U1              EMP_EMPLEV_C12_FK R SCOTT GRADE_GRL_C1_PK

  If I have connection U1, no possibility to find the name of the primary key without connection scott table?

  Thank you

  Hello

  So, you want to know what picture of the SCOTT schema has the constraint that is named "GRADE_GRL_C1_PK." Isn't it?

  If so,.

  SELECT table_name

  Of all_constraints

  Owner WHERE = 'SCOTT '.

  AND the argument constraint_name = 'GRADE_GRL_C1_PK. '

  ;

• dbms_xmlgen. GetXml with single quotes

  Can you get it someone please let me know what is wrong with this query. I try to convert the long and CLOB type. I wanted to convert long to varchar2 and to do this, I am to convert the long to clob or varchar2 clob.

  The query works fine when doing a rownum = 1 in the dynamic query but I would like to read carefully all the constraints so tried the underside and its failure with an error message for an unexpected end of SQL command.

  -with rownum

  SELECT dbms_lob.substr (longtoclob, 4000, 1) text

  of the double.

  (select (dbms_xmlgen.getxml ("SELECT t.search_condition ALIASLONG

  OF All_Constraints t WHERE rownum = 1')) longtoclob

  the double) Y where DBMS_LOB. GETLENGTH (Y.longtoclob) > 0;

  -generic query

  Select (SELECT (dbms_xmlgen.getxml (Q'[select search_condition in all_contstaints where cosntraint_name = ']' | constraint_name |))) Q '[']')) text, constraint_name from

  ALL_CONSTRAINTS

  where rownum < = 3;

  -generic query

  Select (SELECT (dbms_xmlgen.getxml (Q'[select search_condition in all_contstaints where cosntraint_name = ']' | constraint_name |))) Q '[']')) text, constraint_name from

  ALL_CONSTRAINTS

  where rownum<>

  'A few' bad stuff here:

  -keyword SELECT extra

  -typos in names of objects

  -DBMS_XMLGEN.getXML will give you a CLOB that represents a dataset XML to canonical format, not the search_condition directly necessary

  It is more what you are looking for, but know it's slow:

  select constraint_name
       , xmlcast(
           dbms_xmlgen.getxmltype(
             'select search_condition from all_constraints where constraint_name = ' || dbms_assert.enquote_literal(constraint_name)
           )
           as varchar2(4000)
         ) as text
  from all_constraints
  where rownum <= 3 ;
  

  (XMLCAST is 11g only, use the extractValue on lower versions)

• How can I disable all table constraints

  Hi all

  I use Oracle SQL Developer

  I am trying to disable all constraints of tables so I can truncate the tables.

  That's what I came with, but it does not work. Can someone help me please.

  Thanks in advance,

  Kevin

  Start

  for news (select fk.owner, fk.constraint_name, fk.table_name

  of all_constraints fk, pk all_constraints

  where fk. Constraint_type = 'R' and

  PK. Owner = "EIFILTERED" and

  FK.r_owner = pk.owner and

  FK. R_CONSTRAINT_NAME = pk. Constraint_name and

  PK. TABLE_NAME = 'ADDRESS', 'ALTERNATENAME', 'ACTIVITY', 'CASEEVENT.

  ) loop

  run immediately ' ALTER TABLE ' ' |. ' cur. Owner: ' "."' | cur.table_name |' "FORCED TO CHANGE" "|" " cur.constraint_name |' "DISABLE";

  end loop;

  end;

  Hello

  Try this;

  Start

  for news (select fk.owner, fk.constraint_name, fk.table_name

  of all_constraints fk, pk all_constraints

  where fk. Constraint_type = 'R' and

  PK. Owner = "EIFILTERED" and

  FK.r_owner = pk.owner and

  FK. R_CONSTRAINT_NAME = pk. Constraint_name and

  PK. Table-name in ('ADDRESS', 'ALTERNATENAME', 'ACTIVITY', 'CASEEVENT'( )

  ) loop

  run immediately ' ALTER TABLE ' ' |. ' cur. Owner: ' "."' | cur.table_name |' "FORCED TO CHANGE" "|" " cur.constraint_name |' "DISABLE";

  end loop;

  end;

  HTH,

  Pradeep

• Oracle 10g convert N column with the command lines.

  SQL > USER to see THE

  VEERA

  SQL > create table test (number n, fname varchar2 (10), the number of age (10), sal number (10));

  Table created.

  SQL > ALTER TABLE TEST ADD CONSTRAINT PK_TEST PRIMARY KEY (N, FNAME, AGE);

  Select

  table_name,

  RTrim (xmlagg (xmlelement (e, column_name |))) ') .extract ('/ / text()'), ',') COLUMN_NAME

  (SELECT ACC. TABLE_NAME, VAC. COLUMN_NAME

  OF ALL_CONSTRAINTS ACN, VAC ALL_CONS_COLUMNS

  WHERE THE VAC. TABLE_NAME = 'TEST '.

  AND ACN. CONSTRAINT_TYPE = 'P '.

  AND ACN. CONSTRAINT_NAME = ACC. CONSTRAINT_NAME

  AND ACN. OWNER = ACC. OWNER

  AND ACN. OWNER = 'VEERA '.

  )

  Table_name group

  /

  TABLE_NAME COLUMN_NAME

  ------------------------------ ----------

  TEST N, AGE, FNAME

  I have need of NAME of COLUMN must be of the order of position_colonne. [N, FNAME, AGE].

  Please tell us how can I get the result. Is this possible using CASE or also DECODE the number of constraints are unknown.

  Kind regards

  Veera.

  Select

  table_name,

  RTrim (xmlagg (xmlelement (e, column_name |))) ') order of position) .extract ('/ / text()'), ',') COLUMN_NAME

  (SELECT ACC. TABLE_NAME, VAC. Column_name, acc.position

  OF ALL_CONSTRAINTS ACN, VAC ALL_CONS_COLUMNS

  WHERE THE VAC. TABLE_NAME = 'TEST '.

  AND ACN. CONSTRAINT_TYPE = 'P '.

  AND ACN. CONSTRAINT_NAME = ACC. CONSTRAINT_NAME

  AND ACN. OWNER = ACC. OWNER

  AND ACN. OWNER = 'VEERA '.

  )

  Table_name group

  /

• Find related tables

  Hello, everyone.

  I have a file that I need to remove in a table, but I don't know if there are any related tables that might break if I just delete the record.

  Is there a way to determine if / what tables are related?  Can I use SQL Developer.

  V/r,

  JD

  And you won't see it directly. Query I posted shows the relationship between the constraints, not tables. So, if you want to check if table TBL scheme S has children tables:

  SELECT *.

  OF ALL_CONSTRAINTS

  WHERE)

  R_OWNER,

  R_CONSTRAINT_NAME

  ))

  SELECT THE OWNER

  CONSTRAINT_NAME

  OF ALL_CONSTRAINTS

  WHERE OWNER = S"

  AND TABLE_NAME = 'TBL '.

  )

  /

  SY.

• How to find child every column foreign keys of tables without index {worm 10 g}

  Hi Experts,

  I have need of a query to find child all the foreign keys of table columns, which are not having an index on the foreign key column.

  Try this.

  SELECT T1. OWNER,

  T1. CONSTRAINT_NAME,

  T1. TABLE_NAME,

  T2. COLUMN_NAME,

  T1. CONSTRAINT_TYPE

  OF ALL_CONSTRAINTS T1,.

  ALL_CONS_COLUMNS T2

  WHERE T1. CONSTRAINT_NAME = T2. CONSTRAINT_NAME

  AND T1. TABLE_NAME = T2. TABLE-NAME

  AND T1. OWNER = T2. OWNER

  AND T1. CONSTRAINT_TYPE = 'R '.

  AND T2. COLUMN_NAME NOT IN (SELECT COLUMN_NAME FROM ALL_IND_COLUMNS T WHERE TABLE_NAME = T1.) TABLE_NAME AND COLUMN_NAME = T2. COLUMN_NAME);

  Post edited by: Parth272025

• Why my function returns nothing when I create as a schema object

  I have the ABC's of the user who owns several paintings, some of which have foreign key constraints.

  I have user XYZ who has access to all the tables belonging to the user ABC.

  When I create a user XYZ feature to use more I get no return when I run:

  Select XYZ.ztm_tables_depended_on ('ABC', 'A_TABLE_OWNED_BY_ABC') of double:

  Please see after the function definition.

  CREATE or REPLACE FUNCTION ZTM_TABLES_DEPENDED_ON (p_Owner VARCHAR2, nom_table_p VARCHAR2) RETURN VARCHAR2 IS

  CURSOR C1 IS

  SELECT CONSTRAINT_NAME, OWNER, R_CONSTRAINT_NAME, R_OWNER

  OF ALL_CONSTRAINTS

  WHERE OWNER = p_Owner

  AND TABLE_NAME = nom_table_p

  AND CONSTRAINT_TYPE = 'R '.

  ORDER BY OWNER, CONSTRAINT_NAME, R_OWNER, R_CONSTRAINT_NAME;

  --

  v_Referenced_Owner VARCHAR2 (31);

  v_Ret_Val VARCHAR2 (4000);

  --

  The FUNCTION CONSTRAINT_TABLE_NAME(p_Owner VARCHAR2, p_Constraint_Name VARCHAR2) RETURN VARCHAR2 IS

  CURSOR C1 IS

  SELECT TABLE_NAME

  OF ALL_CONSTRAINTS

  WHERE OWNER = p_Owner

  AND the argument CONSTRAINT_NAME = p_Constraint_Name;

  --

  v_Ret_Val ALL_CONSTRAINTS. TABLE_NAME % TYPE;

  BEGIN

  OPEN C1;

  FETCH C1 INTO v_Ret_Val;

  CLOSE C1;

  --

  RETURN v_Ret_Val;

  END;

  --

  BEGIN

  FOR R IN C1 LOOP

  IF (R.OWNER <>R.R_OWNER) THEN v_Referenced_Owner: = R.R_OWNER | '.';

  ANOTHER v_Referenced_Owner: = NULL;

  END IF;

  --

  v_Ret_Val: = v_Ret_Val | ', ' || v_Referenced_Owner | CONSTRAINT_TABLE_NAME (R.R_OWNER, R.R_CONSTRAINT_NAME);

  END LOOP;

  --

  RETURN LTRIM (v_Ret_Val, ',');

  END;

  /

  But if I enter the function within an anonymous block as follows, I get results:

  DECLARE
  CURSOR C1 IS
  Select owner, table_name
  From all_tables where owner = 'ABC ';

  --

  The FUNCTION ZTM_TABLES_DEPENDED_ON(p_Owner VARCHAR2, p_Table_Name VARCHAR2) RETURN VARCHAR2 IS
  CURSOR C1 IS
  SELECT CONSTRAINT_NAME, OWNER, R_CONSTRAINT_NAME, R_OWNER
  OF ALL_CONSTRAINTS
  WHERE OWNER = p_Owner
  AND TABLE_NAME = nom_table_p
  AND CONSTRAINT_TYPE = 'R '.
  ORDER BY OWNER, CONSTRAINT_NAME, R_OWNER, R_CONSTRAINT_NAME;
  --
  v_Referenced_Owner VARCHAR2 (31);
  v_Ret_Val VARCHAR2 (4000);
  --
  The FUNCTION CONSTRAINT_TABLE_NAME(p_Owner VARCHAR2, p_Constraint_Name VARCHAR2) RETURN VARCHAR2 IS
  CURSOR C1 IS
  SELECT TABLE_NAME
  OF ALL_CONSTRAINTS
  WHERE OWNER = p_Owner
  AND the argument CONSTRAINT_NAME = p_Constraint_Name;
  --
  v_Ret_Val ALL_CONSTRAINTS. TABLE_NAME % TYPE;
  BEGIN
  OPEN C1;
  FETCH C1 INTO v_Ret_Val;
  CLOSE C1;
  --
  RETURN v_Ret_Val;
  END;
  --
  BEGIN
  FOR R IN C1 LOOP
  IF (R.OWNER <>R.R_OWNER) THEN v_Referenced_Owner: = R.R_OWNER | '.';
  ANOTHER v_Referenced_Owner: = NULL;
  END IF;
  --
  v_Ret_Val: = v_Ret_Val | ', ' || v_Referenced_Owner | CONSTRAINT_TABLE_NAME (R.R_OWNER, R.R_CONSTRAINT_NAME);
  END LOOP;
  --
  RETURN LTRIM (v_Ret_Val, ',');
  END;

  --

  BEGIN
  FOR R IN C1 LOOP
  DBMS_OUTPUT. Put_line (ztm_tables_depended_on (R.Owner, R.Table_Name));
  END LOOP;
  END;
  /

  Any ideas what is happening here?

  Any ideas what is happening here?

  Justin said the likely reason.

  See the section "How to exercise roles in PL/SQL blocks" the doc of database security for details

  http://docs.Oracle.com/CD/E25054_01/network.1111/e16543/authorization.htm#i1007304

  Operation of the roles in PL/SQL blocks

  The use of roles in a PL/SQL block depends on if it is an anonymous block, or a block named (stored procedure, function, or trigger), and if it runs with the rights of the author or the rights of the applicant.

  Roles used in the appointed with rights to define blocks

  All roles are disabled in any PL/SQL block named (stored procedure, function, or trigger) that runs with the rights of the author. Roles are not used to privilege control, and you cannot define roles within the procedure of a DEFINER rights.

  The SESSION_ROLES view shows all roles that are currently enabled. If a named PL/SQL block that runs with Definer Rights queries SESSION_ROLES , then the query will return no rows.

  Roles used in blocks named with the rights of the plaintiff and anonymous PL/SQL

  Named PL/SQL blocks that run with the rights of the applicant and the anonymous PL/SQL blocks are executed at the end of the privileges granted through active roles. Current roles are used for verification within rights Summoner of privilege the PL/SQL block. You can use dynamic SQL statements to define a role in the session.

  See this line beginning by "all roles are disables in any PL/SQL block named"?

• Find the name and the table constraint type based on the name of the field

  I have a field name or a column with me... I want to find the name of the table is a primary key... Any request to make this work so that the running costs are low...

  Currently, I mix dba_constraints and ALL_TAB_COLUMNS to get this... is possible to extract the data of a process cost effective single table/any other is appreciated

  You must include the USER/ALL_CONSTRAINTS with USER/ALL_CONS_COLUMNS to achieve your desired results. For your specific condition, you can try this query.

  Select constraint_name

  column_name

  de)

  Select c.constraint_name

  cc.column_name

  count on column_count (c.constraint_name score) (cc.column_name)

  from user_constraints c

  Join user_cons_columns cc

  on c.constraint_name = cc.constraint_name

  where constraint_type = 'P '.

  )

  where column_name = 'EMPNO '.

  and column_count = 1;

  I used USER_CONSTRAINTS and USER_CONS_COLUMNS. If you use ALL or DBA dictionary table add join OWNER condition as well.

• primary key of a synonym in Oracle

  Can we all know how I can describe a table to get the table structure and relationships. Relationships in the sense which column is used as a primary key and a foreign key in a particular table.

  DESC table provides details of the column. I executed under query, but it gives only the following points.

  award_reason / / DESC

  Name of Type Null

  --------------- -------- ------------

  AWARD_REASON_ID NOT NULL NUMBER (11)

  REASON_TYP NOT NULL VARCHAR2 (35)

  SORT_ORDR NOT NULL NUMBER (2)

  ASSETS NOT NULL NUMBER (1)

  Here 'award_reason' is a synonym.

  Can someone help me on this please.

  Here is a list of dictionary tables which have details on CONSTRAINTS.

  SQL > select table_name dictionary where table_name like ' % CONSTRAINT % ';

  TABLE-NAME
  ------------------------------
  DBA_CONSTRAINTS
  DBA_IAS_CONSTRAINT_EXP
  ALL_CONSTRAINTS
  USER_CONSTRAINTS

  SQL > select table_name dictionary where table_name like 'CONS\_COL% %' escape ' \';

  TABLE-NAME
  ------------------------------
  DBA_CONS_COLUMNS
  ALL_CONS_COLUMNS
  USER_CONS_COLUMNS

• SQL update error code

  Hi guys,.
  
  I am trying to execute the following statement
  
  UPDATE DOCSADM. FORMSTYLES
  STYLE = '"U" + STYLE N' GAME
  WHERE 22192063 > AND < 22192574 SYSTEM_ID SYSTEM_ID
  
  but getting the following strange error while there is no single constratint on the column.
  
  Error from the 1 in the command line:
  UPDATE DOCSADM. FORMSTYLES
  STYLE = '"U" + STYLE N' GAME
  WHERE 22192063 > AND < 22192574 SYSTEM_ID SYSTEM_ID
  Error report:
  SQL error: ORA-00001: unique constraint (DOCSADM. FORMSTYLESC) violated
  00001 00000 - "forced single (s.%s) violated."
  * Cause: An UPDATE or INSERT statement attempted to insert a duplicate key.
  For Trusted Oracle configured in DBMS MAC mode, you can see
  This message if there is an entry double at a different level.
  * Action: Either remove the single restriction or not to insert the key.
  
  Any idea?

  You can see ALL_CONSTRAINTS and ALL_INDEXES. (If you have access to DBA_ * views)

  To prove your statement - "there is no unique constraint on the column.

• find the foreign key data

  Hello
  
  I want to have the details as the tablename, volumn name of foreign key to a table of reference.
  

  SELECT a.column_name,  
          c_pk.table_name r_table_name, c_pk.constraint_name r_pk
    FROM all_cons_columns a
    JOIN all_constraints c ON a.owner = c.owner
                          AND a.constraint_name = c.constraint_name
    JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
                             AND c.r_constraint_name = c_pk.constraint_name
   WHERE c.constraint_type = 'R'
     AND a.table_name = :TableName

  Using this query, I get everything except the column name for reference.
  
  Can someone please help?
  
  Thanx

  You must add another join to ALL_CONS_COLUMNS:

  SELECT a.column_name,
          c_pk.table_name r_table_name, c_pk.constraint_name r_pk,
          c_pk_c.column_name
    FROM all_cons_columns a
    JOIN all_constraints c ON a.owner = c.owner
                          AND a.constraint_name = c.constraint_name
    JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
                             AND c.r_constraint_name = c_pk.constraint_name
    JOIN all_cons_columns c_pk_c ON c_pk_c.owner = c_pk.owner
                                AND c_pk_c.constraint_name = c_pk.constraint_name
   WHERE c.constraint_type = 'R'
     AND a.table_name = :TableName
  

• forced to deleted still apply the constraint

  I have a two-column table that has a couple of constraints which is to keep the pair of these two unique columns. When I insert the first record (the table is empty), I get the constraint violation. I wouldn't have this error. Disabling the constraint does not help so I remove the constraint. Now I can insert that record, but when I try to insert the same record, I this violation with the name of the deleted constraint.
  
  Here is the result: (the deleted constraint is EQ_FOR_QUOTE_HAZ_HAZMAT_RFQ)
  

  SQL> delete from req_for_quote_haz;
  
  1 row deleted.
  
  SQL> commit;
  
  Commit complete.
  
  SQL>  select constraint_name from all_constraints where table_name='REQ_FOR_QUOTE_HAZ';
  
  CONSTRAINT_NAME
  
  ------------------------------
  
  REQ_FOR_QUOTE_HAZ_HAZMAT_ID_FK
  
  
  
  SQL>  insert into REQ_FOR_QUOTE_HAZ values (1815,1);
  
  1 row created.
  
  
  
  SQL>  insert into REQ_FOR_QUOTE_HAZ values (1815,1);
  
   insert into REQ_FOR_QUOTE_HAZ values (1815,1)
  
  *
  
  ERROR at line 1:
  
  ORA-00001: unique constraint (ITS.REQ_FOR_QUOTE_HAZ_HAZMAT_RFQ) violated
  
  
  
  SQL> 

  Any ideas?
  
  Thank you
  View

  Perhaps you have a unique index on the columns. If not can you confirm that you are looking in HIS scheme.